Answer:
0
Step-by-step explanation:
-18-(-18)
= -18+18 [(+) + (+)=(+)]
=0 [(-) + (-)=(-)]
THE DISTANCE OF A PARTICLE FROM
IT'S STARTING POINT AT TIME T
SECONDS IS GIVEN BY S= 80T - 1672.
WHAT IS THE VELOCITY OF THE
PARTICLE AFTER 2 SECONDS?
Answer:
the answer will be 3.........
[tex]\sqrt{25}[/tex]=?
[tex]Hello[/tex] [tex]There[/tex]
The answer is...
[tex]5.[/tex]
[tex]HopeThisHelps!![/tex]
[tex]AnimeVines[/tex]
Probability of picking a blue marble and a yellow marble when 2 marbles are picked (without replacement) from a bag containing 4 blue and 4 yellow marbles
Answer:
9/49
Step-by-step explanation:
that is the procedure above
Researchers wanting to assess skin irritation associated with a new sunscreen developed for those with photosensitivity. They randomly sample 240 men with a history of photosensitivity and 240 men without a history of photosensitivity and ask them to apply the cream and report the level of skin irritation they experience after spending 20 minutes in the sun using a scale of 0-10. The average skin irritation score for the group with a history photosensitivity was 1.2 and the average skin irritation score for the group without a history of photosensitivity was 1.4. The Levene's test for equality of variances had a p value of 0.08. You know this means:
A. The researchers should report the t test results assuming equal variances. Select The researchers should report the t test results NOT assuming equal variances. as your answer
B. The researchers should report the t test results NOT assuming equal variances.
C. The researchers should reject the null hypothesis and report there is a difference in the average skin irritation score.
D. The researchers should fail to reject the null hypothesis and conclude there is NOT a difference in the average skin irritation score.
Answer:
Blablabka
Step-by-step explanation:
Blablabla
A bacteria culture grows with a constant relative growth rate. After 2 hours there are 400 bacteria and after 8 hours the count is 50,000.
(a) Find the initial population. P(0) = 80 )ãbacteria
(b) Find an expression for the population after t hours. r(t) = 180( 125(6 Plt) =180(125(2))-
(c) Find the number of cells after 7 hours. (Round your answer to the nearest integer.) P(7)=72.358- bacteria
(d) Find the rate of growth after 7 hours. (Round your answer to the nearest integer.) P(7) 2x bacteria/hour
(e) When will the population reach 200,000? (Round your answer to one decimal place.) hours
Answer:
a) P(0) = 80
b) [tex]P(t) = 80(2.2361)^t[/tex]
c) 22,363 cells.
d) The rate of growth after 7 hours is of 18,000 bacteria per hour.
e) 9.7 hours.
Step-by-step explanation:
A bacteria culture grows with a constant relative growth rate.
This means that the population is given by:
[tex]P(t) = P(0)(1+r)^t[/tex]
In which P(0) is the initial population and r is the growth rate, as a decimal.
After 2 hours there are 400 bacteria and after 8 hours the count is 50,000.
This means that in 6 hours, the population went from 400 bacteria to 50,000 bacteria. We use this to find r. So
[tex]50000 = 400(1+r)^6[/tex]
[tex](1+r)^6 = \frac{50000}{400}[/tex]
[tex](1+r)^6 = 125[/tex]
[tex]\sqrt[6]{(1+r)^6} = \sqrt[6]{125}[/tex]
[tex]1 + r = 125^{\frac{1}{6}}[/tex]
[tex]1 + r = 2.2361[/tex]
So
[tex]P(t) = P(0)(2.2361)^t[/tex]
(a) Find the initial population. P(0)
We have that P(2) = 400. We use this to find P(0). So
[tex]P(t) = P(0)(2.2361)^t[/tex]
[tex]400 = P(0)(2.2361)^2[/tex]
[tex]P(0) = \frac{400}{(2.2361)^2}[/tex]
[tex]P(0) = 80[/tex]
So
[tex]P(t) = 80(2.2361)^t[/tex]
(b) Find an expression for the population after t hours.
[tex]P(t) = 80(2.2361)^t[/tex]
(c) Find the number of cells after 7 hours.
This is P(7). So
[tex]P(7) = 80(2.2361)^7 = 22363[/tex]
22,363 cells.
(d) Find the rate of growth after 7 hours.
We have to find the derivative when t = 7. So
[tex]P(t) = 80(2.2361)^t[/tex]
[tex]P^{\prime}(t) = 80\ln{2.2361}(2.2361)^t[/tex]
[tex]P^{\prime}(7) = 80\ln{2.2361}(2.2361)^7 = 18000[/tex]
The rate of growth after 7 hours is of 18,000 bacteria per hour.
(e) When will the population reach 200,000?
This is t for which [tex]P(t) = 200000[/tex]. So
[tex]P(t) = 80(2.2361)^t[/tex]
[tex]200000 = 80(2.2361)^t[/tex]
[tex](2.2361)^t = \frac{200000}{80}[/tex]
[tex](2.2361)^t = 2500[/tex]
[tex]\log{(2.2361)^t} = \log{2500}[/tex]
[tex]t\log{2.2361} = \log{2500}[/tex]
[tex]t = \frac{\log{2500}}{\log{2.2361}}[/tex]
[tex]t = 9.7[/tex]
So 9.7 hours.
Mary spent $4 more than 1/8 of her original amount of money on a bag. She then
Spent $12 more than 2/3 of her remaining money on groceries.Given that Mary had $24 left,how much did the bag cost?
Answer:
464 $
Step-by-step explanation:
This graph describes which of the expressions given?
1. On the set of axes below, graph . State the roots of
Is this question complete?
Functions f and g are defined for all real
numbers. The function f has zeros at -2, 3, and 7:
and the function g has zeros at -3, -1, 4, and 7.
How many distinct zeros does the product
function f g have?
9514 1404 393
Answer:
6
Step-by-step explanation:
The number of distinct zeros in the product will be the union of the sets of zeros. Duplicated values are not distinct, so show in the union of sets only once.
F = {-2, 3, 7}
G = {-3, -1, 4, 7}
F∪G = {-3, -2, -1, 3, 4, 7} . . . . . . a 6-element set
The product has 6 distinct zeros.
_____
As you may notice in the graph, the duplicated zero has a multiplicity of 2 in the product.
Find the missing side of the triangle
Answer:
x = 2[tex]\sqrt{5}[/tex]
Step-by-step explanation:
Pytago:
[tex]2^2 + 4^2 = x^2\\x = \sqrt{2^2 + 4^2} \\x = 2\sqrt{5}[/tex]
Answer:
4.47
Step-by-step explanation:
x²= 2² + 4²
x² = 4 + 16
x²= 20
x = √20
x= 4.47
Express 5 cm in metre and kilometre.in decimals........................ ncert maths class 7 pls
will be marked as brainliest trust me
Answer:
Converting into metre (1m=100cm)= 5/100=0.05m.. Converting into km. (1km=100000cm). so 5 cm=5/100000=0.00005km.
Answer:
5cm in meters = 0.05 metre
5cm in kilometres = 0.00005km
Find the solution of the exponential equation, as in Example 1. (Enter your answers as a comma-separated list.)
e1 − 3x = e4x − 3
x=_______
Answer:
Hello,
Very bad written!!!
Step-by-step explanation:
[tex]e^{1-3x}=e^{4x-3}\\\\1-3x=4x-3\\\\7x=4\\\\\boxed{x=\dfrac{4}{7} }\\[/tex]
Find the fractal dimension of the object.
Answer:
maaqqqf aku ngak tau soal jawaban in
Determine the degree of the term 2^3x2yz4
Answer:
7
Step-by-step explanation:
It looks like the term is [tex]2^3}x^2}yz^4[/tex]
First simplify
[tex]8x^2}yz^4[/tex]
[y has an exponent of 1 btw]
Then to find the degree of a term, just add up the values of all the exponents
2+1+4=7
I hope this helps!
Suppose a professional baseball player hit 55 home runs his first season, 58 his second,
and 69 his third. How many home runs would he need to hit in the current season so that
his average for the 4 years is no less than 59?
Answer:
About 54
Step-by-step explanation:
To work backwards from average, you need to multiply the average by the total number of cases, which is 4, since there are 3 current cases/seasons and you want the 4th.
59 * 4 = 236
You then subtract the total home runs that you know of from 236.
236 - 55 - 58 - 69 = 54
To find average, you are adding to the total and then dividing by the number of groups, which is essentially mean (mean is basically the average).
1106.666667 To the nearest whole number
Answer:
1107.
You are rounding up because the number in the tenths slot is over 5.
Determine whether the following relationship is a linear inequality or not
1. Y < 3
2. x ≥ 6
3. x² > -3
4. x -3 > 1/2
5. xy + 5 ≤ 7
Answer:
What is a linear inequality ? A linear inequality has the same condition as a linear equality, but instead of the equal sign, we have for example this one ≤ wish means less than or equal to.
But what are the condition of a linear equality ? There are many ways of writing linear equations but they usually have constants (like "2" or "c") and must have simple variables (like "x" or "y") BUT the variables (x and y) on a linear equation do NOT have Exponents (like the 2 in x²) and square roots,
1. y < 3
Yes, this is a linear inequation. Frequently, the term linear equation refers implicitly to the case of just one variable (here y).
2. x ≥ 6
Yes.
3. x² > - 3
No, remember the rule the variable (here x) must not have exponents.
4. x - 3 > 1/2
Yes.
5. xy + 5 ≤ 7
This one is nice. If both x and y are variables then the answer is no, it's not a linear inequation. Why ?The linear equation is a sum of terms like "Ax" where x is a variable, and A is a number or a constant. On the other hand if x or y was a constant (like e or π), it could be treated as a number and the whole expression would become linear.
You can also have fun and write :
xy ≤ 2
for y > 0 we write:
x ≤ 2/y
x ≤ 2[tex]y^{-1}[/tex]
and then simply say exponents are not allowed so not a linear inequation.
Use the distributive property to find the product of the rational number.
5/2 (- 8/5 + 7/5)
9514 1404 393
Answer:
-1/2
Step-by-step explanation:
The factor outside parentheses multiplies each term inside.
5/2(-8/5 +7/5)
= (5/2)(-8/5) +(5/2)(7/5)
= -8/2 +7/2 = -1/2
Write the point-slope form of an equation of the line through the points (-4, 7) and (5,-3).
0
A. Y+4= -1; (1 – 7)
B.Y-5 = = 10 (x+3)
OC. y +3 = = 10 (2+5)
D. y - 7= -5° (x+4)
Answer:
Step-by-step explanation:
There are two possible equations, but neither matches the the choices you listed. The choices seem to have several typographical errors.
Point-slope form of an equation of the line through the points (-4, 7) and (5,-3) is y - 7 =(-10/9)(x + 4).
How to estimate the point-slope form of an equation of the line through the points (-4, 7) and (5,-3)?Slope
[tex]$= \frac{y_{2} -y_{1}}{x_{2} -x_{1}}[/tex]
= (-3 - 7) / (5 - (-4))
= -10/9
The point-slope equation for the line of slope -(10/9) that passes through the point (5, -3).
y + 3 = (-10/9)(x - 5)
Point slope equation for the line of slope -(10/9) that passes through the point (-4, 7)
Point-slope form of an equation of the line through the points (-4, 7) and (5,-3) is y - 7 = (-10/9)(x + 4).
Therefore, the correct answer is y - 7 = (-10/9)(x + 4).
To learn more about the equation of a line refer to:
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What is the value of log,1252
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3
5
Ο ΟΟΟ
15
Mark this and return
Save and Exit
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2. What amount of money must Kurt Blixen invest at 4.75% to have it earn $10,000 in 90 days?
Kurt Blixen must invest $85,2296.94.
Given the following data;
Interest rate = 4.75%Simple interest = $10,000Time = 90 daysTo find how much money Kurt Blixen must invest;
Mathematically, simple interest is given by the formula;
[tex]S.I = \frac{PRT}{100}[/tex]
Where:
S.I is the simple interest.P is the principal amount.R is the interest rate.T is the time measured in years.First of all, we would convert the time in days to years.
Conversion:
365 days = 1 year
90 days = x year
Cross-multiplying, we have;
[tex]365 * x = 90\\\\x = \frac{90}{365}[/tex]
x = 0.247 year
Making P the subject of formula;
[tex]P = \frac{S.I(100)}{RT}[/tex]
Substituting the values into the formula, we have;
[tex]P = \frac{10000(100)}{4.75*0.247}\\\\P = \frac{1000000}{1.1733}[/tex]
P = $85,2296.94
Therefore, Kurt Blixen must invest $85,2296.94.
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Sharla invests $275 in a simple interest bearing account for 16 years. The annual interest rate is 8%. Using the simple
interest formula, / -Prt, how much interest will Sharla's initial investment earn over the 16 year period?
$297
$319
$352
$627
Answer:
352
Step-by-step explanation:
I = PRT where P is the principle, I is the interest rate, T is the time
I = 275 ( .08) ( 16)
I = 352
if 10x=1/0.001 find the value of x
[tex]\\ \sf\longmapsto 10x=\dfrac{1}{0.001}[/tex]
Turn over the decimal[tex]\\ \sf\longmapsto 10x=\dfrac{1}{\dfrac{1}{1000}}[/tex]
[tex]\\ \sf\longmapsto 10x=1000[/tex]
[tex]\\ \sf\longmapsto x=\dfrac{1000}{10}[/tex]
[tex]\\ \sf\longmapsto x=100[/tex]
log_c(A)=2
log_c(B)=5,
solve log_c(A^5B^3)
We know that [tex]\log_a(bc)=\log_a(b)+\log_a(c)[/tex].
Using this rule,
[tex]\log_c(A^5B^3)=\log_c(A^5)+\log_c(B^3)[/tex].
We also know that [tex]\log_c(a^b)=b\log_c(a)[/tex].
Using this rule,
[tex]\log_c(A^5)+\log_c(B^3)=5\log_c(A)+3\log_c(B)[/tex]
Now we know that [tex]\log_c(A)=2,\log_c(B)=5[/tex] so,
[tex]5\cdot2+3\cdot5=10+15=\boxed{25}[/tex].
Hope this helps :)
Please help me please please help ASAP
Step-by-step explanation:
70 + 45 = 115
180 - 115 = 65
angle c = 65
use sohcahtoa
cos angle = adjacent
hypotenuse
cos 65 = 2.5
b
b cos 65 = 2.5
use the calc for further answers
hope that helped
URGENT!! (Picture included)
Answer:
-85
Step-by-step explanation:
You can use calculator for this question
if k = p+2q/3 , find the value of p when k=7 and q=3
Answer:
p = 5
Step-by-step explanation:
hopefully it is clear and understandable :)
Give a vector parametric equation for the line through the point (−2,−4,0) that is parallel to the line ⟨−2−3t,1−4t,−5t⟩:
The tangent vector for the given line is
T(t) = d/dt ⟨-2 - 3t, 1 - 4t, -5t⟩ = ⟨-3, -4, -5⟩
On its own, this vector points to a single point in space, (-3, -4, -5).
Multiply this vector by some scalar t to get a whole set of vectors, essentially stretching or contracting the vector ⟨-3, -4, -5⟩. This set is a line through the origin.
Now translate this set of vectors by adding to it the vector ⟨-2, -4, 0⟩, which correspond to the given point.
Then the equation for this new line is simply
L(t) = ⟨-3, -4, -5⟩t + ⟨-2, -4, 0⟩ = ⟨-2 - 3t, -4 - 4t, -5t⟩
The vector parametric equation for the line through the point is [tex]r = (-2, \ -4, \ 0) +(-3, \ -4, \ -5)t\\\\[/tex].
GivenGive a vector parametric equation for the line through the point (−2,−4,0) that is parallel to the line ⟨−2−3t,1−4t,−5t⟩.
What is a parametric equation vector?Parametric equations of the line segment are defined by its endpoints.
To find the vector equation of the line segment, we’ll convert its endpoints to their vector equivalents.
Two lines are parallel if they have the same direction, and in the parametric form, the direction of a line is always the vector of constants that multiply t (or the parameter).
The vector equation of a line is given by:
[tex]\rm v = r_0+tv[/tex]
Where v is the direction vector and [tex]\rm r_0[/tex] is a point of the line.
The tangent vector for the given line is
T(t) = d/dt ⟨-2 - 3t, 1 - 4t, -5t⟩ = ⟨-3, -4, -5⟩
Here,
[tex]\rm r_0 = (-2,-4,0) \ and \ v=(-3, \ -4, \ -5)t\\\\[/tex]
Then,
[tex]r = (-2, \ -4, \ 0) +(-3, \ -4, \ -5)t\\\\[/tex]
x = -2-3t, y = -4-4t, and z = 0-5t
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How many numbers multiple of 3 are in the range [2,2000]?
Answer: so there are 666 multiples of 3 between 2 and 2000.
Step-by-step explanation:
the smallest number = 3 which is 3*1. The largest number is = 1998 = 3*666
multiples of 3 between {2,2000} = 666-1+1 = 666
Solve this inequality:
-9 > 3b + 6
Answer:
- 5 > b
Step-by-step explanation:
- 9 > 3b + 6
- 9 - 6 > 3b
- 15 > 3b
Divide 3 on both sides,
- 5 > b
Answer:
-5 >b
Step-by-step explanation:
-9 > 3b + 6
Subtract 6 from each side
-9-6 > 3b + 6-6
-15 > 3b
Divide each side by 3
-15/3 > 3b/3
-5 >b