Find the doubling time of an investment earning 8% interest if interest is compounded continuously. The doubling time of an investment earning 8% interest if interest is compounded continuously is ____ years.

Answers

Answer 1

Answer:

8.66 years

Step-by-step explanation:

Given that:

Interest rate = 8%

Using the exponential growth function:

A = Ao * e^(rt)

Where A = final amount

Ao = Initial amount

r = growth rate

t = time

Here we are to calculate the time it takes an investment earning 8% interest to double;

rate (r) = 8% = 0.08

2A = A * e^(rt)

Divide both sides by A

2 = e^(rt)

2 = e^(0.08 * t)

2 = e^(0.08t)

In(2) = 0.08t

0.6931471 = 0.08t

Divide both sides by 0.08

0.6931471 / 0.08 = 0.08t / 0.08

8.6643397 = t

t = 8.66 years

Answer 2

Answer:

symbolically, the answer would be t= ln(2)/(.08)

Step-by-step explanation:

start by writing out your variables:

rate= .08

*dont forget the investment doubles too, thats where 2P is in the bottom equation

equation should look like:

[tex]2P=Pe^{.08t}[/tex]

then you solve, so divide P on the right and left:

[tex]\frac{2p}{p} = \frac{Pe^{.08t}}{p}[/tex]

now it looks like: [tex]2=e^{.08t}[/tex]

you can take the natural log (ln) of 2 to get the exponent by itself .08t

ln(2)=.08t

then divide .08 to get t by itself

[tex]\frac{ln(2)}{.08} =\frac{.08t}{.08}[/tex]

so symbolically, your equation should be:

[tex]t=\frac{ln(2)}{.08}[/tex]

to get t as your answer you can plug this equation into your calculator to get:

t=8.66 years so approximently 8 years


Related Questions

A blue die and a red die are thrown. B is the event that the blue comes up with a 6. E is the event that both dice come up even. Write the sizes of the sets |E ∩ B| and |B|a. |E ∩ B| = ___b. |B| = ____

Answers

Answer:

Size of |E n B| = 2

Size of |B| = 1

Step-by-step explanation:

I'll assume both die are 6 sides

Given

Blue die and Red Die

Required

Sizes of sets

- [tex]|E\ n\ B|[/tex]

- [tex]|B|[/tex]

The question stated the following;

B = Event that blue die comes up with 6

E = Event that both dice come even

So first; we'll list out the sample space of both events

[tex]B = \{6\}[/tex]

[tex]E = \{2,4,6\}[/tex]

Calculating the size of |E n B|

[tex]|E n B| = \{2,4,6\}\ n\ \{6\}[/tex]

[tex]|E n B| = \{2,4,6\}[/tex]

The size = 3 because it contains 3 possible outcomes

Calculating the size of |B|

[tex]B = \{6\}[/tex]

The size = 1 because it contains 1 possible outcome

Evaluate fx, fy, fz at the given point a) f (x, y z) = x³yz² at the point (1, 2, 3) b) f (x, y, z) = x² - 2xy + 3yxz² at the point (3, 1, -2)

Answers

Answer:

a) (fx, fy, fz) = (54, 9, 12)b) (fx, fy, fz) = (16, 30, 9)

Step-by-step explanation:

a) The partial derivatives of f(x, y, z) = x³yz² are ...

fx = 3x²yz²fy = x³z²fz = 2x³yz

At the given point, these are ...

fx(1, 2, 3) = 3(1²)(2)(3²) = 54fy(1, 2, 3) = (1³)(3²) = 9fz(1, 2, 3) = 2(1³)(2)(3) = 12

__

b) The partial derivatives of f(x, y, z) = x² -2xy +3xyz² are ...

fx = 2x -2y +3yz²fy = -2x +3xz²fz = 3xy

At the given point, these are ...

fx(3, 1, -2) = 2(3) -2(1) +3(1)(-2)² = 16fy(3, 1, -2) = -2(3) +3(3)(-2)² = 30fz(3, 1, -2) = 3(3)(1) = 9

What is the intersection of the lines given by 2y=-x+3 and -y=5x+1? Enter the answer as an ordered pair.

Answers

Answer:

(-5/9, 16/9)

Step-by-step explanation:

2y = -x + 3

-y = 5x + 1

To find the intersection, you need to substitute the y-value from the second equation into the first equation.  Rearrange the second equation so that it is equal to y.

-y = 5x + 1

-1(-y) = -1(5x + 1)

y = -5x - 1

Substitute this equation into the y-value of the first equation.

2y = -x + 3

2(-5x - 1) = -x + 3

-10x - 2 = -x + 3

(-10x - 2) + 2 = (-x + 3) + 2

-10x = -x + 5

(-10x) + x = (-x + 5) + x

-9x = 5

(-9x)/(-9) = (5)/(-9)

x = -5/9

Plug this x value into one of the equations and solve for y.

2y = -x + 3

2y = -(-5/9) + 3

2y = 5/9 + 3

2y = 32/9

(2y)/2 = (32/9)/2

y = 32/18 = 16/9

The ordered pair is (-5/9, 16/9).

An expression is ???

Answers

Answer:

s-6

Step-by-step explanation:

difference means subtract

s-6

bon
Question 21
O pts
The recipe for a s'more is as follows:
1 graham cracker
chocolate bar
2 marshmallows
If you have 10 graham crackers, 7 marshmallows, and 5 chocolate bars, how many
complete s'mores can you make using this recipe?
Question 22
O pts​

Answers

Answer:

3 s'mores

Step-by-step explanation:

If we center our attention on how many marshmallows you need per s'more which is 2 and you only have 7 you can only make 3 with one marshmallow remaining.

A random sample of size 100 is taken from a population described by the proportion p = 0.60. The probability that the sample proportion is less than 0.55 is ________.

Answers

Answer:hope it helps

Step-by-step explanation:

Result:

0.6

Enlarge

Customize

Plain Text

Number line:

Number line

Rational form:

3/5

The average score of all golfers for a particular course has a mean of 70and a standard deviation of 5.Suppose 100golfers played the course today. Find the probability that the average score of the 100golfers exceeded 71.Round to four decimal places.

Answers

Answer:

0.9773

Step-by-step explanation:

Here, we start by calculating the z-scores statistic

Mathematically;

z-score = (x-mean)/SD/√n

From the question, we have;

x = 71, mean = 70, SD = 5 and n = 100

Plugging these values in the equation above, we have;

z-score = (71-70)/5/√100 = 1/5/10 = 1/0.5 = 2

So the probability we want to calculate is that;

P(z > 2)

This is obtainable from the standard normal distribution table

P(z > 2) = 0.97725 which is 0.9773 to 4 decimal places

The amount of money spent on textbooks per year for students is approximately normal.
a. To estimate the population mean, 19 students are randomly selected the sample mean was $390 and the standard deviation was $120. Find a 95% confidence for the population meam.
b. If the confidence level in part a changed from 95% 1to1999%, would the margin of error for the confidence interval (mark one answer): decrease stay the same increase not enough information to answer
c. If the sample size in part a changed from 19 10 22. would the margin of errot for the confidence interval (mark one answer): decrease in stay the same increase in not enough information to answer
d. To estimate the proportion of students who purchase their textbookslused, 500 students were sampled. 210 of these students purchased used textbooks. Find a 99% confidence interval for the proportion of students who purchase used text books.

Answers

Answer:a

a

   [tex]336.04 < \mu < 443.96[/tex]

b

  The  margin of error will increase

c

The  margin of error will decreases

d

The 99% confidence interval is  [tex]0.4107 < p < 0.4293[/tex]

Step-by-step explanation:

From the question we are  told that

   The sample size  [tex]n = 19[/tex]

    The sample mean is  [tex]\= x = \$\ 390[/tex]

    The  standard deviation is  [tex]\sigma = \$ \ 120[/tex]

 

Given that the confidence level is  95% then the level of significance is mathematically represented as

           [tex]\alpha = 100 - 95[/tex]

          [tex]\alpha = 5 \%[/tex]

          [tex]\alpha = 0.05[/tex]

Next we obtain the critical value of [tex]\frac{\alpha }{2}[/tex] from the normal distribution table

    So  

         [tex]Z_{\frac{\alpha }{2} } = 1.96[/tex]

The  margin of error is mathematically represented as

      [tex]E = Z_{\frac{\alpha }{2} } * \frac{\sigma}{\sqrt{n} }[/tex]

=>    [tex]E = 1.96 * \frac{120}{\sqrt{19} }[/tex]

=>   [tex]E = 53.96[/tex]

The 95% confidence interval is  

     [tex]\= x - E < \mu < \= x + E[/tex]

=>   [tex]390 - 53.96 < \mu < 390 - 53.96[/tex]

=>  [tex]336.04 < \mu < 443.96[/tex]

When the confidence level increases the [tex]Z_{\frac{\alpha }{2} }[/tex] also increases which increases the margin of error hence the confidence level becomes wider

Generally the sample size mathematically varies with margin of error as follows

         [tex]n \ \ \alpha \ \ \frac{1}{E^2 }[/tex]

So if the sample size increases the margin of error decrease

The  sample proportion is mathematically represented as

       [tex]\r p = \frac{210}{500}[/tex]

       [tex]\r p = 0.42[/tex]

Given that the confidence level is 0.99 the level of significance is  [tex]\alpha = 0.01[/tex]

The critical value of [tex]\frac{\alpha }{2}[/tex] from the normal distribution table is  

      [tex]Z_{\frac{\alpha }{2} } = 2.58[/tex]

  Generally the margin of error is mathematically represented as

       [tex]E = Z_{\frac{\alpha }{2} }* \sqrt{ \frac{\r p (1- \r p )}{n} }[/tex]

=>   [tex]E = 0.42 * \sqrt{ \frac{0.42 (1- 0.42 )}{ 500} }[/tex]

=>     [tex]E = 0.0093[/tex]

The 99% confidence interval  is

     [tex]\r p - E < p < \r p + E[/tex]

     [tex]0.42 - 0.0093 < p < 0.42 + 0.0093[/tex]

     [tex]0.4107 < p < 0.4293[/tex]

 

Determine the length of chord BC. 1) 17.45 2) 30.96 3) 67.06 4) 33.53

Answers

Answer:

33.53

Step-by-step explanation:

OB is a radius of the circle, and OC is also a radius of the circle, so both are equal length.  That makes ΔOBC an isosceles triangle.

If we cut ΔOBC in half, the angle formed is 125° / 2 = 62.5°.

Therefore:

sin 62.5 = (x/2) / 18.9

x = 37.8 sin 62.5

x ≈ 33.53

Answer:

33.5

Step-by-step explanation:

Which of the following is an arithmetic sequence? A.-2, 4, -6, 8, ... B.2, 4, 8, 16, ... C.-8, -6, -4, -2, ...

Answers

Answer:

C. -8, -6, -4, -2, ...

Step-by-step explanation:

An arithmetic sequence increases by the same amount every time through addition or subtraction. There is a common difference.

A: -2, 4, -6, 8, ... If there were a common difference, the numbers would not switch between being positive and back to negative. The numbers would either keep going positive or keep going negative.

B: 2, 4, 8, 16, ... The common difference between 16 and 8 is 16 - 8 = 8. The difference between 8 and 4 is 8 - 4 = 4. Since the difference changes between the numbers, this is not an arithmetic sequence.

C. -8, -6, -4, -2, ... The common difference between -2 and -4 is -2 - (-4) = -2 + 4 = 2. The difference between -4 and -6 is -4 - (-6) = -4 + 6 = 2. The difference between -6 and -8 is -6 - (-8) = -6 + 8 = 2. Since the common difference is always two, this is an arithmetic sequence.

Hope this helps!

Question (1)

(i) Explain Pythagorean theorem in detail.

(ii) What is "Hippacus of Croton"?​

Answers

Answer:

● The pythagorian theorem

The pythagorian theorem is used to find a missing side of a right triangle.

It states that the square of the hypotenus of a right triangle is equal to the sum of the squares of the two other sides.

Let a be the hypotenus, b and c are the othet sides:

☆☆☆☆☆ a^2 = b^2 + c^2☆☆☆☆☆

There are more than 350 way to prove this theorem.

■■■■■■■■■■■■■■■■■■■■■■■■■■

● Hippasus of Croton was a member of the highly-secretive school og Pythagoras in Croton. He is credited in history as the first person to prove the existence of irrational numbers.

PLEASE HELP- MATH

simplify the fraction
5bc/10b^2

Answers

[tex]\dfrac{5bc}{10b^2}=\dfrac{\not 5\cdot \not b\cdot c}{2\cdot \not 5\cdot \not b\cdot b}=\dfrac{c}{2b}[/tex]

Answer:

c / ( 2b)

Step-by-step explanation:

5bc/10b^2

Lets look at the numbers first

5/10 = 1/2

Then the variable b

b / b^2 = 1/b

Then the variable c

c/1 = c

Putting them back together

1/2 * 1/b * c/1

c/ 2b

A regression was run to determine if there is a relationship between hours of TV watched per day (x) and number of situps a person can do (y). The results of the regression were:

1. y=a+bx
2. b=-0.669
3. a=27.41
4. r2=0.760384
5. r=-0.872

Use this to predict the number of situps a person who watches 3.5 hours of TV can do. Round to one decimal place.

Answers

Answer: The correct answer is 19 sit ups.

Step-by-step explanation: Given that the regression equation to find a  a relationship between hours of TV watched per day (x) and number of situps a person can do (y) was done.

The result was

y = ax+b

Correlation coefficient = 0.865

To predict the number of situps a person who watches 3 hours of TV

y = -1.23(3)+22.738

= 19.048

Approximately 19 situps.

Which sequence has a common ratio of 2? a{20, 40, 80, 160, 320, 640, …} b{20, 10, 5, 2.5, 1.25, 0.625, …} c{20, 15, 10, 5, 0, -5, …} d{20, 4, 0.80, 0.16, 0.032, 0.0064, …}

Answers

Answer:

A

Step-by-step explanation:

40/20=2

80/40=2

Therefore the common ration is 2

The correct sequence which has a common ratio of 2 is,

⇒ {20, 40, 80, 160, 320, 640, …}

What is Geometric sequence?

An sequence has the ratio of every two successive terms is a constant, is called a Geometric sequence.

Given that;

The common ratio of sequence is,

⇒ 2

Now, By option 1;

The sequence is,

⇒  {20, 40, 80, 160, 320, 640, …}

Hence, Common ratio = 40 / 20

                                   = 2

And, 80 / 40 = 2

Thus, The correct sequence which has a common ratio of 2 is,

⇒ {20, 40, 80, 160, 320, 640, …}

Learn more about the geometric sequence visit:

https://brainly.com/question/25461416

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Please answer this correctly without making mistakes

Answers

Answer:

1/2 mi

Step-by-step explanation:

Fairfax to Greenwood is equal to one mile

Now think of it as an equation and substitute 1/2 for fairfax and x for greenwood

1/2 + x = 1

This means that x = 1/2

Because of this from Arcadia to Greenwood it is 1/2 mi

Question 1 (Multiple Choice Worth 4 points)
(08.01) Looking at the spread of your data best fits which step of the statistical process?

Answers

Answer:

The answer is "Analysis the information by chart and number processes".

Step-by-step explanation:

They already have articulated a query and also gathered information unless you are searching only at the distribution of your results. Those who are ready to analyze your results for all are there.

Fifteen chaperones went on a field trip with 225 students. Which fraction represents the number of chaperones to students on the field trip

Answers

Answer:

15/225

Step-by-step explanation:

The number of chaperones for the group of students can be represented with a ratio - 15:225 or 15/225.

Because there are 15 chaperones for the 225 students, you can state what the ratio does - for every 225 students, there are 15 chaperones.

However, 15/225 can be reduced to 1/15, so for every 15 students, there is 1 chaperone.

One of two small restaurants is chosen at random with equally likely probability, and then an employee is chosen at random from the chosen restaurant. Restaurant #1 has 10 full-timers and 6 part-timers. Restaurant #2 has 7 full-timers and 9 part-timers. What is the probability that Restaurant #1 was chosen at random, given that a full-time employee was chosen? Your answers should be rounded to 4 digits after the decimal.

Answers

Answer:

P(1 |F) = 10/17

Step-by-step explanation:

Let events

1 = restaurant 1

2 = restaurant 2

F = full-time worker chosen

P = part-time worken chosen

P(1 and F) = 1/2 * 10/16 = 5/16

P(2 and F) = 1/2 * 7/16 = 7/32

P( (1 or 2) and F ) = P(F) = 5/16+7/32 = 17/32

P(1 | F)          Probability of choosing restaurant 1 given a full-time was chosen

= P(1 and F) / P(F)

= 5/16  / (17/32)

= 5/16 * 32/17

= 10 / 17

Marcelina uses a blend of white corn and yellow corn to make tortilla chips at her restaurant. She needs to buy 50kg of corn in total for her next order. White corn costs $0.30 per kilogram, yellow corn costs $0.15 per kilogram, and she wants to spend $12.00 in total. Here's a graph that shows a system of equations for this scenario where x is the amount of white corn she buys and y is the amount of yellow corn she buys.

Answers

Answer:

https://brainly.com/question/17155330

Step-by-step explanation:

Question:

Marcelina uses a blend of white corn and yellow corn to make tortilla chips at her restaurant. She needs to buy 50kg of corn in total for her next order. White corn costs $0.30 per kilogram, yellow corn costs $0.15 per kilogram, and she wants to spend $12 total.

What does point F represent in this context?

Answer:

Marcelina spends less that the intended amount of money and buy less than enough corn

3
BO
Evaluate the function f(x) = x2 + 4x + 1 at the given values of the independent variable and simplify.
a. f(6)
b. f(x +9)
c. f(-x)

Answers

Answer:

a) f(6)=(6)^2+4(6)+1=65

b)f (x+9)=(x+9)^2+4 (x+9)+1=(x^2+18x+81)+(4x+36)+1=x^2+22x+117

f (-x)=(-x)^2-4x+1

Jean Paul is an interior designer who is working with a difficult client. Part of his design requires that he put 11 colored vases in a row on a shelf. He has 3 identical blue vases, 2 identical green vases, 4 identical red vases, a purple vase and a yellow vase. He has put up 4 different arrangements of the vases that his client complained about. As he begins to put up the fifth arrangement, he wonders how many different arrangements he might have to go through before his client complains about all of them. How many different arrangements could Jean Paul make

Answers

Answer:

138600 arrangements

Step-by-step explanation:

Let n = 11

The different arrangements Jean Paul can make = n!/(4!)(3!)(2!)

Hence, 11!/(4!)(3!)(2!) = 1663200/12 = 138600

The quotient of 3 and the cube
of y+2

Answers

Answer:

  [tex]\dfrac{3}{(y+2)^3}[/tex]

Step-by-step explanation:

Maybe you want this written using math symbols. It will be ...

  [tex]\boxed{\dfrac{3}{(y+2)^3}}[/tex]

Which equation is equivalent to StartRoot x EndRoot + 11 = 15?

Answers

Answer:

D  [tex]\sqrt{x} +11=15[/tex]

Step-by-step explanation:

Edge 2020

For the given expression √x + 11 = 15 the value of x will be equal to 16.


What is an expression?

The mathematical expression combines numerical variables and operations denoted by addition, subtraction, multiplication, and division signs.

Mathematical symbols can be used to represent numbers (constants), variables, operations, functions, brackets, punctuation, and grouping. They can also denote the logical syntax's operation order and other properties.

Given that the expression √x + 11 =15. The expression will be solved as below,

√x + 11 =15

√x = 15 - 11

√x = 4

Squaring on both sides of the equation,

x = 4²

x = 16

To know more about an expression follow

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Find the​ (a) mean,​ (b) median,​ (c) mode, and​ (d) midrange for the data and then​ (e) answer the given question. Listed below are the weights in pounds of 1111 players randomly selected from the roster of a championship sports team. Are the results likely to be representative of all players in that​ sport's league?
278 303 186 292  276 205 208 236 278 198 208
a. Find the mean.
The mean is ? ​pound(s).
​(Type an integer or a decimal rounded to one decimal place as​needed.)
b. Find the median.
The median is ? ​pound(s).
​(Type an integer or a decimal rounded to one decimal place as​needed.)
c. Find the mode.
Select the correct choice below​ and, if​ necessary, fill in the answer box to complete your choice.
A. The​ mode(s) is(are) ? ​pound(s).
​(Type an integer or a decimal. Do not round. Use a comma to separate answers as​ needed.)
B. There is no mode.
d. Find the midrange.
The midrange is ? ​pound(s).
​(Type an integer or a decimal rounded to one decimal place as​needed.)
e. Are the results likely to be representative of all players in that​ sport's league?
A. The results are not likely to be representative because the median is not equal to the mode.
B. The results are likely to be representative because a championship team is most likely representative of the entire league.
C. The results are not likely to be representative because the median is not equal to the mean.
D. The results are not likely to be representative because the championship team may not be representative of the entire league.

Answers

Answer:

Mean= 242.5 pounds

Median= 236 pounds

Mode= 208 and 278 pounds

Range=117 pounds

Mid-range= 58.5 pounds

B. The results are likely to be representative because a championship team is most likely representative of the entire league.

Step-by-step explanation:

278 303 186 292  276 205 208 236 278 198 208

Arranged in ascending order is

186 198 205 208 208 236 276 278 278 292 303

Mean = (186 +198+ 205+ 208 +208 +236 + 276+ 278 +278+ 292 +303)/11

Mean =2668/11

Mean= 242.5 pounds

Median = the middle number

Median= 236 pounds

Mode = highest occuring number(s)

Mode= 208 and 278 pounds

Range= highest number- smallest number

Range=303-186

Range=117 pounds

Mid-range= range/2

Mid-range= 117/2

Mid-range= 58.5 pounds

On a map’s coordinate grid, Panthersville is located at (−3, 2), and Heel City is located at (4, 8). Falconton is the midpoint between Panthersville and Heel City. What is the approximate distance from Panthersville to Falconton? (Each unit on the grid represents 1 mile.) A. 3.25 miles B. 4.61 miles C. 5.00 miles D. 9.22 miles

Answers

Answer:

B. 4.61 miles

Step-by-step explanation:

midpoint is (-3+4)/2, (2+8)/2 = (1/2, 5)

distance = √(-3-1/2)² + (2 - 5)² = 4.609772299

Musah stands at the centre of a rectangular field. He first takes 50 steps north, then 25 steps

west and finally 50 steps on a bearing of 3150

.

i. Sketch Musah’s movement​

Answers

Answer:

Step-by-step explanation:

Following the cardinal points as regards location of points, the sketch of Musah's movement can be as what is attached to this answer.

Given the following hypotheses: H0: μ = 490 H1: μ ≠ 490 A random sample of 15 observations is selected from a normal population. The sample mean was 495 and the sample standard deviation 9. Using the 0.01 significance level:
a.) State the decision rule.
b.) Compute the value of the test statistic.
c.) What is your decision regarding the null hypothesis?

Answers

Answer:

We conclude that the population mean is equal to 490.

Step-by-step explanation:

We are given that a random sample of 15 observations is selected from a normal population. The sample mean was 495 and the sample standard deviation 9.

Let [tex]\mu[/tex] = population mean.

So, Null Hypothesis, [tex]H_0[/tex] : [tex]\mu[/tex] = 490      {means that the population mean is equal to 490}

Alternate Hypothesis, [tex]H_A[/tex] : [tex]\mu\neq[/tex] 490     {means that the population mean is different from 490}

The test statistics that will be used here is One-sample t-test statistics because we don't know about population standard deviation;

                               T.S.  =  [tex]\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }[/tex]  ~ [tex]t_1_4[/tex]

where, [tex]\bar X[/tex] = sample mean = 495

            s = sample standard deviation = 9

             n = sample of observations = 15

So, the test statistics =   [tex]\frac{495-490}{\frac{9}{\sqrt{15} } }[/tex]  ~ [tex]t_1_4[/tex]

                                     =  2.152

The value of t-test statistics is 2.152.

Now, at a 0.01 level of significance, the t table gives a critical value of -2.977 and 2.977 at 14 degrees of freedom for the two-tailed test.

Since the value of our test statistics lies within the range of critical values of t, so we have insufficient evidence to reject our null hypothesis as the test statistics will not fall in the rejection region.

Therefore, we conclude that the population mean is equal to 490.

Let f(x)=x+8 and g(x)= x2-6x-7 find f(g2)

Answers

Answer:

-7.

Step-by-step explanation:

g(x) = x^2 - 6x - 7

g(2) = 2^2 - 6(2) - 7

= 4 - 12 - 7

= -8 - 7

= -15

f(x) = x + 8

f(-15) = (-15) + 8

= 8 - 15

= -7

Hope this helps!

For what values of y: Is the value of the fraction 5−2y 12 always greater than the value of 1−6y?

Answers

Answer:

[tex](5 - 2y) \div 12 > 1 - 6y[/tex]

[tex]5 - 2y > 12 - 72y[/tex]

[tex] - 7 > - 70y[/tex]

[tex]7 < 70y[/tex]

[tex]y > 1 \div 10 = 0.1[/tex]

the product of two consecutive positive integer is 306​

Answers

Answer:

[tex]\Large \boxed{\sf 17 \ and \ 18}[/tex]

Step-by-step explanation:

The product means multiplication.

There are two positive consecutive integers.

Let the first positive consecutive integer be x.

Let the second positive consecutive integer be x+1.

[tex](x) \times (x+1) =306[/tex]

Solve for x.

Expand brackets.

[tex]x^2 +x =306[/tex]

Subtract 306 from both sides.

[tex]x^2 +x -306=306-306[/tex]

[tex]x^2 +x -306=0[/tex]

Factor left side of the equation.

[tex](x-17)(x+18)=0[/tex]

Set factors equal to 0.

[tex]x-17=0[/tex]

[tex]x=17[/tex]

[tex]x+18=0[/tex]

[tex]x=-18[/tex]

The value of x cannot be negative.

Substitute x=17 for the second consecutive positive integer.

[tex](17)+1[/tex]

[tex]18[/tex]

The two integers are 17 and 18.

The product of two consecutive positive integers is 306.

We need to find the integers

solution : Let two consecutive numbers are x and (x + 1)

A/C to question,

product of x and (x + 1) = 306

⇒x(x + 1) = 306

⇒x² + x - 306 = 0

⇒ x² + 18x - 17x - 306 = 0

⇒x(x + 18) - 17(x + 18) = 0

⇒(x + 18)(x - 17) = 0⇒ x = 17 and -18

so x = 17 and (x +1) = 18

Therefore the numbers are 17 and 18.

Hope it helped u if yes mark me BRAINLIEST

TYSM!

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