Find the greatest common factor of 15 x²y³ and -18 x³yz .

9514 1404 393

Answer:

  (c)  x = 12.5

Step-by-step explanation:

  -0.2(x -4) = -1.7

  -0.2x +0.8 = -1.7 . . . eliminate parentheses using the distributive property

  -0.2x = -2.5 . . . . . . subtract 0.8

 x = 12.5 . . . . . . . . divide by -0.2

Answer:

$ 1943

Step-by-step explanation:

You two congruent trapezoids.

Find the area of one and multiply by 2.

A = [tex]\frac{base_{1} + base_{2} }{2}[/tex] x  h

  = [tex]\frac{28+39}{2}[/tex] x 14.5

  = [tex]\frac{67}{2}[/tex] x 14.5

  = 33.5 x 14.5

  = 485.75

  = 485.75 x 2 (Two trapezoids)

  = 971.50

  = 971.50 x 2 (two dollars a square foot)

  = 1943.00

Divide total miles by speed:

360 / 50 = 7.2 hours

Answer:

the correct answer is 3

hope it helps

have a nice day

Answer:

what is the question

pls mark me as brainlist

Thank you for the points

Answer:

The function that passes through (0, 0) is [tex]f(x) = \frac{1}{6}\cdot e^{2\cdot x^{3}} - \frac{1}{6}[/tex].

Step-by-step explanation:

Firstly, we integrate the function by algebraic substitution:

[tex]\int {x^{2}\cdot e^{2\cdot x^{3}}} \, dx[/tex] (1)

If [tex]u = 2\cdot x^{3}[/tex] and [tex]du = 6\cdot x^{2} dx[/tex], then:

[tex]\int {e^{2\cdot x^{3}}\cdot x^{2}} \, dx[/tex]

[tex]\frac{1}{6}\int {e^{u}} \, du[/tex]

[tex]f(u) = \frac{1}{6}\cdot e^{u} + C[/tex]

[tex]f(x) = \frac{1}{6}\cdot e^{2\cdot x^{3}} + C[/tex]

Where [tex]C[/tex] is the integration constant.

If [tex]x = 0[/tex] and [tex]f(0) = 0[/tex], then the integration constant is:

[tex]\frac{1}{6}\cdot e^{2\cdot 0^{3}} + C= 0[/tex]

[tex]C = -\frac{1}{6}[/tex]

Hence, the function that passes through (0, 0) is [tex]f(x) = \frac{1}{6}\cdot e^{2\cdot x^{3}} - \frac{1}{6}[/tex].

Answer:

The 98% confidence interval for the mean amount spent on their child's last birthday gift is between $40.98 and $43.02.

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 24 - 1 = 23

98% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 23 degrees of freedom(y-axis) and a confidence level of [tex]1 - \frac{1 - 0.98}{2} = 0.99[/tex]. So we have T = 2.5

The margin of error is:

[tex]M = T\frac{s}{\sqrt{n}} = 2.5\frac{2}{\sqrt{24}} = 1.02[/tex]

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 42 - 1.02 = $40.98.

The upper end of the interval is the sample mean added to M. So it is 42 + 1.02 = $43.02.

The 98% confidence interval for the mean amount spent on their child's last birthday gift is between $40.98 and $43.02.

Answer:

The answer for both linear equations is A. x = 2, y = 7

Step-by-step explanation:

First start by plugging in the variables with the given numbers (2,7). We'll start with 6x + 3y = 33.

6x + 3y = 33

6 (2) + 3 (7 )= 33 <--- This is the equation after the numbers are plugged in.

12 + 10 = 33

33 = 33 <---- This statement is true, therefore it is the correct pair.

Now we are not done, to confirm that this pair works with both equations we need to solve for 4x + y = 15 to see if it works. Linear Equations must have the variables work on both equations.

4x + y = 15 <----- We are going to do the exact same thing to this equation.

4(2) + 7 = 15

8 + 7 = 15

15 = 15  <-- 15=15 is a true statement therefore this pair works for this equation.

Therefore,

A. x = 2, y = 7 is the correct answer

Sorry this is a day late, I hope it helps.

Answer:

3.15 seconds is the answer.

Explanation

when the ball touches the ground, h =0

hence,

0=255-21t-16t²

16t²+21t-225=0

here a=16 ,b=21, c= -225

[tex]t= \frac{ - b± \sqrt{ {b }^{2} - 4ac} }{2a} \\ \\ t= \frac{ - 21± \sqrt{ {21}^{2} - 4 \times 16 \times - 225} }{2 \times 16} \\ = \frac{ - 21 ± \sqrt{441 - ( - 14400)} }{32} \\ = \frac{ - 21± \sqrt{14841} }{32} \\ = \frac{ - 21±121.82}{32} \\ \\ t = \frac{ - 21 + 121.82}{32} \: or \: \: t = \frac{ - 21 - 121.82}{32} \\ t = 3.15 \: \: or \: \: t = - 4.46[/tex]

time cannot be negative, hence t = -4.46 can be avoided

The ball takes 3.15 seconds to hit the ground.

Answer:

$138.72

Step-by-step explanation:

(1-0.999578)*$240,000 = $101.28

$240 - $101.28 = $138.72

Answer:

D. It will increase by 1%.

Step-by-step explanation:

Given

[tex]u_1 = 5\%[/tex] --- initial rate

[tex]u_2 = 3\%[/tex] --- final rate

Required

The effect on the GDP

To calculate this, we make use of:

[tex]\frac{\triangle Y}{Y} = u_1 - 2\triangle u[/tex]

This gives:

[tex]\frac{\triangle Y}{Y} = 5\% - 2(5\% - 3\%)[/tex]

[tex]\frac{\triangle Y}{Y} = 5\% - 2(2\%)[/tex]

[tex]\frac{\triangle Y}{Y} = 5\% - 4\%[/tex]

[tex]\frac{\triangle Y}{Y} = 1\%[/tex]

This implies that the GDP will increase by 1%

Answer: A. It will increase by 7%.

Step-by-step explanation: I took this course!

12.8, pythagorean theorem.

Answer:

y= (-6/5)x+3

Step-by-step explanation:

6x+5y=15

Divide everything by 5

(6/5)x + y = 3

Move (6/5)x to the other side of the = sign by subtracting

y= (-6/5)x + 3

That's your answer!

Hope it helps!

Answer:

Where is the diagram though..

Step-by-step explanation:

Answer:

[tex]\implies \dfrac{2}{10}< \dfrac{3}{10} [/tex]

Step-by-step explanation:

We need to compare the given two fractions .The given fractions are ,

[tex]\implies \dfrac{3}{10} [/tex]

[tex]\implies \dfrac{1}{5} [/tex]

Firstly let's convert them into like fractions . By multiplying 1/5 by 2/2 . We have ,

[tex]\implies \dfrac{1}{5} =\dfrac{1*2}{5*2}=\dfrac{2}{10} [/tex]

Now on comparing 2/10 and 3/10 we see that ,

[tex]\implies 2< 3 [/tex]

Therefore ,

[tex]\implies \dfrac{2}{10}< \dfrac{3}{10} [/tex]

The power consumed in the lamp marked 100W - 110V is 15.68W

The power consumed in the lamp marked 100W - 220V is 62.73W

Given:

First lamp rating

Power (P) = 100W

Voltage (V) = 110V

Second lamp rating

Power (P) = 100W

Voltage (V) = 220V

Source

Voltage = 220V

i. Get the resistance of each lamp.

Remember that power (P) of each of the lamps is given by the quotient of the square of their voltage ratings (V) and their resistances (R). i.e

P = [tex]\frac{V^2}{R}[/tex]

Make R subject of the formula

⇒ R = [tex]\frac{V^2}{P}[/tex]             ------------------(i)

For first lamp, let the resistance be R₁. Now substitute R = R₁, V = 110V and P = 100W into equation (i)

R₁ = [tex]\frac{110^2}{100}[/tex]

R₁ = 121Ω

For second lamp, let the resistance be R₂. Now substitute R = R₂, V = 220V and P = 100W into equation (i)

R₂ = [tex]\frac{220^2}{100}[/tex]

R₂ = 484Ω

ii. Get the equivalent resistance of the resistances of the lamps.

Since the lamps are connected in series, their equivalent resistance (R) is the sum of their individual resistances. i.e

R = R₁ + R₂

R  = 121 + 484

R = 605Ω

iii. Get the current flowing through each of the lamps.

Since the lamps are connected in series, then the same current flows through them. This current (I) is produced by the source voltage (V = 220V) of the line and their equivalent resistance (R = 605Ω). i.e

V = IR [From Ohm's law]

I = [tex]\frac{V}{R}[/tex]

I = [tex]\frac{220}{605}[/tex]

I = 0.36A

iv. Get the power consumed by each lamp.

From Ohm's law, the power consumed is given by;

P = I²R

Where;

I = current flowing through the lamp

R = resistance of the lamp.

For the first lamp, power consumed is given by;

P = I²R           [Where I = 0.36 and R = 121Ω]

P = (0.36)² x 121

P = 15.68W

For the second lamp, power consumed is given by;

P = I²R           [Where I = 0.36 and R = 484Ω]

P = (0.36)² x 484

P = 62.73W

Therefore;

The power consumed in the lamp marked 100W - 110V is 15.68W

The power consumed in the lamp marked 100W - 220V is 62.73W

Answer:

4g+2x=r

Step-by-step explanation:

4g+r=2r-2x

collecting like terms

4g+2x=2r-r

4g+2x=r

Answer:

x P(x)

0 0.4167

1 0.5

2 0.0833

3 0

Step-by-step explanation:

The speedometers are chosen without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

[tex]P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}[/tex]

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

In this question:

7 + 2 = 9 speedometers, which means that [tex]N = 9[/tex]

2 are not correctly calibrated, which means that [tex]k = 2[/tex]

3 are chosen, which means that [tex]n = 3[/tex]

Complete the probability distribution table.

Probability of each outcome.

So

[tex]P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}[/tex]

[tex]P(X = 0) = h(0,9,3,2) = \frac{C_{2,0}*C_{7,3}}{C_{9,3}} = 0.4167[/tex]

[tex]P(X = 1) = h(1,9,3,2) = \frac{C_{2,1}*C_{7,2}}{C_{9,3}} = 0.5[/tex]

[tex]P(X = 2) = h(2,9,3,2) = \frac{C_{2,2}*C_{7,1}}{C_{9,3}} = 0.0833[/tex]

Only 2 defective, so [tex]P(X = 3) = 0[/tex]

Probability distribution table:

x P(x)

0 0.4167

1 0.5

2 0.0833

3 0

Answer:

0.5759

Step-by-step explanation:

Answer:

50,000 : 0.01

multiply by 100...

5000000 : 1

 1:5,000,000

Step-by-step explanation:

Answer:

0.3758 = 37.58% probability that at most one of her first 10 arrows hits the target

Step-by-step explanation:

For each shot, there are only two possible outcomes. Either they hit the target, or they do not. The probability of a shot hitting the target is independent of any other shot, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

And p is the probability of X happening.

Each arrow with a probability 0.2

This means that [tex]p = 0.2[/tex]

First 10 arrows

This means that [tex]n = 10[/tex]

What is the probability that at most one of her first 10 arrows hits the target?

This is:

[tex]P(X \leq 1) = P(X = 0) + P(X = 1)[/tex]

So

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 0) = C_{10,0}.(0.2)^{0}.(0.8)^{10} = 0.1074[/tex]

[tex]P(X = 1) = C_{10,1}.(0.2)^{1}.(0.8)^{9} = 0.2684[/tex]

Then

[tex]P(X \leq 1) = P(X = 0) + P(X = 1) = 0.1074 + 0.2684 = 0.3758[/tex]

0.3758 = 37.58% probability that at most one of her first 10 arrows hits the target

Answer:

[tex]x=6\\y=4[/tex]

Step-by-step explanation:

Elimination method:

[tex]x+5y=26[/tex]

[tex]-x+7y=22[/tex]

Add these equations to eliminate x:

[tex]12y=48[/tex]

Then solve [tex]12y=48[/tex] for y:

[tex]12y=48[/tex]

[tex]y=48/12[/tex]

[tex]y=4[/tex]

Write down an original equation:

[tex]x+5y=26[/tex]

Substitute 4 for y in [tex]x+5y=26[/tex]:

[tex]x+5(4)=26[/tex]

[tex]x+20=26[/tex]

[tex]x=26-20[/tex]

[tex]x=6[/tex]

{ [tex]x=6[/tex] and [tex]y=4[/tex] }    ⇒ [tex](6,4)[/tex]

hope this helps...

Answer:

x = 6, y = 4

Step-by-step explanation:

x + 5y = 26

- x + 7y = 22

_________

0 + 12y = 48

12y = 48

y = 48 / 12

y = 4

Substitute y = 4 in eq. x + 5y = 26,

x + 5 ( 4 ) = 26

x + 20 = 26

x = 26 - 20

x = 6

Answer:

A. 18 calls

B. 0.9

C. 20

Step-by-step explanation:

Number of representatives=2,

Number of extension lines=2,

Average calls each representative can accommodate per hour = 15 calls,

Arrival rate per hour = 30 calls

(a) 90% of the arrival rate = 0.09 × 20 = 18 calls

To handle 18 calls immediately, 18 extension lines should be used

(b) Probability is given by number of possible outcomes ÷ number of total outcomes

Number of possible outcomes = 18, number of total outcomes = 20

Probability (call will receive busy signal) = 18/20 = 0.9

(c) For one extension line, numbers of calls to receive busy signal = 20 - 10 = 10 calls

Number of calls to receive busy signal for the current telephone system with two extension lines = 2 × 10 = 20 calls

Answer:

The motion of the particle describes an ellipse.

Step-by-step explanation:

The characteristics of the motion of the particle is derived by eliminating [tex]t[/tex] in the parametric expressions. Since both expressions are based on trigonometric functions, we proceed to use the following trigonometric identity:

[tex]\cos^{2} t + \sin^{2} t = 1[/tex] (1)

Where:

[tex]\cos t = \frac{y-3}{2}[/tex] (2)

[tex]\sin t = x - 1[/tex] (3)

By (2) and (3) in (1):

[tex]\left(\frac{y-3}{2} \right)^{2} + (x-1)^{2} = 1[/tex]

[tex]\frac{(x-1)^{2}}{1}+\frac{(y-3)^{2}}{4} = 1[/tex] (4)

The motion of the particle describes an ellipse.

The answer is D

Hope that was fast enough

Answer:

For the perimeters, x must be equal to 2.

For the areas, it is either undefined, or something.

Step-by-step explanation:

You can first find the perimeters for both sides.

For the left shape, we add the two sides of 6 and x + 4 to get x + 10.

Then we multiply x + 10 by 2 because there are 4 sides, and we only got 2 sides.

The perimeter of the first shape is 2x + 20.

The second shape can be solved by doing the same thing by adding 2 and 3x + 4 to get 3x + 6.

3x + 6 times 2 is 6x + 12.

The second perimeter is 6x + 12.

If both sides are supposed to be equal, then we can write these two expressions we solved for like:

6x + 12 = 2x + 20.

Subtraction property of equality

6x + 12 - 12 = 2x + 20 - 12

Simplify

6x = 2x + 8

Again

6x - 2x = 2x - 2x + 8

Simplify

4x = 8

Division property of equality

4/4x = 8/4

Simplify

x = 2

So if x = 2, the perimeters will be the same.

You can confirm this by plugging it back into either equation.

For the areas, we just multiply the length and width for both shapes, so we get

6(x+4)  =  2(3x+4)

Since they are supposed to be equal.

We simplify and get

6x + 24 = 6x + 8

We know this is false and is not possible, since we can remove the 6x because it is on both sides.

We also know that 24 is not equal to 8 (who thought!)

:D

24 ≠ 8

So it is undefined or whatever you call it.

Answer:

x=70

Step-by-step explanation:

First, we know that the mode is the number that is the most common. As each value in the set so far only has one of each number, we know that x must be one of the current numbers, making that the mode.

Next, because x is the mode and has to be the median as well, and our number line so far is

(10, 70, 80, 120), x must be either 70 or 80 to make it the median. This is because if x is 10 or 120, we would end up with (10, 10, 70, 80, 120) with 70 as the median or (10, 70, 80, 120, 120) with 80 as the median.

Finally, to calculate the mean, we have

mean = sum / count

The mean must be x, as it is equal to the mode, so we have

x = (10+70+80+120 + x)/5 (as there are 5 numbers including x)

multiply both sides by 5 to remove the denominator

5 * x = 10+70+80+120+x

5 * x = 280 + x

subtract x from both sides to isolate the x and the coefficient

4 * x = 280

divide both sides by 4 to get x

x= 70

We see that x is 70 or 80 and is one of the current numbers, checking off all boxes.