Find the missing side of the triangle. Round your answers to the nearest tenth if necessary.

6.5 cm

17.4 cm

14.6 cm

9.4 cm

Step-by-step explanation:

180°+63°

=243°

holp it help

Answer:

A two-column proof uses a table to present a logical argument and assigns each column to do one job, and then the two columns work in lock-step to take a reader from premise to conclusion.

Step-by-step explanation:

Basically in simple terms, one side is the statements, and the otherside is the reasoning

Answer:it’s x

Step-by-step explanation:

Sry if I’m wrong

Answer:

B. [tex]^{5} P_{5}[/tex] × [tex]^{20} P_{15}[/tex]

Step-by-step explanation:

No. of students from first grade = 15

No. of students from second grade = 5

There are 5 rows of seats

Each row contains 5 seats

Total seats = 25

No. of ways for second-grade students to occupy the first row (i.e first 5 seats) = [tex]^{5} P_{5}[/tex]

Remaining seats = 20

So, now we are left with 15 first grade students  

So, No. of ways for first-grade students occupy remaining seats = [tex]^{20} P_{15}[/tex]

Using the counting rule principle,

No. of ways for the students can be seated if all of the second-grade students occupy the first row = [tex]^{5} P_{5}[/tex] × [tex]^{20} P_{15}[/tex]

So, Option B is the correct answer

Hence, no. of ways for the students can be seated if all of the second-grade students occupy the first row is ×

There are ¹⁵P₁₅ x ¹⁰P₅ possible way to seat, if all of the second-grade students occupy the first row.

A permutation in math is the number of ways in which a set of data or objects can be ordered or arranged, where the order matters.

Given that, a school bus has 25 seats, with 5 rows of 5 seats. 15 students from the first grade and 5 students from the second-grade travel in the bus.

Since you have to place all first-grade students in the first three rows,

Therefore,

For the 15 first-graders of the first three rows (15 seats), we have ¹⁵P₁₅ since all 15 places have to be occupied by all 15 first-graders.

Then we have 10 remaining seats left to be assigned to the 5 second-graders = ¹⁰P₅

We then multiply the permutation numbers of those two arrangements to get the total ways:

¹⁵P₁₅ x ¹⁰P₅

Hence there are ¹⁵P₁₅ x ¹⁰P₅ possible way to seat, if all of the second-grade students occupy the first row.

Learn more about permutation click;

https://brainly.com/question/30649574

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Answer:

if its addition then it will be 79cm

Answer:

B

Step-by-step explanation:

Have a wonderful day

Answer:

38sq yards

Step-by-step explanation:

Separate it into parts

3x2 for the top section

8x4 for the bottom

6+32=38

Answer:

n = 28 degree

Step-by-step explanation:

2n + 17 + 2n - 5 + 2n = 180 degree (sum of interior angles of a triangle)

6n +12 = 180

6n = 180 - 12

n = 168/6

n = 28 degree

Answer:

2ft

Step-by-step explanation:

Depth = volume / ( length x width)

11.81 / (2.8 x 1.7)

11.81 / 4.76

depth = 2.48

2 ft (to the nearest whole number)

Answer:

4,8,12 hope that helps heeeeheheʘ‿ʘ

Hi there!  

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I believe your answer is:  

C. (5, –23)

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Here’s why:  

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Hope this helps you. I apologize if it’s incorrect.  

Answer: it b y’all

Step-by-step explanation: I took the test

Answer:

B

Step-by-step explanation:

To determine the maxima and minima of the polynomial, differentiate the given based on x and equate to 0.                                   C(x) = 400x - 0.2x²                               dC(x) / dt = 400 - 0.4 x = 0 The value of x is 1000. This is the value of the maxima. As the value of C(x) continously becomes lesser as the value of x is set higher, the minima is not identified. Substitute x to the original equation,                               C(x) = (400)(1000) - 0.2(1000²) = $ 200,000Thus, the answer is letter B. 

Answer:

The expanded form of 6,398 is 6000 + 300 + 90 + 8

Answer

“The LCM of three numbers is 360“ The prime factors of 360 are 2³×3²×5¹. That means:

At least one of the numbers contains 2³ in its factorization list.

At least one of the numbers contains 3² in its factorization list.

At least one of the numbers contains 5 in its factorization list.

“One of the numbers is 40“ The factorization list of 40 is 2³×5, so 1) and 3) are satisfied.

“The GCD of the same numbers is 2“ This implies that all 3 numbers are even, and that at least one number only has one 2.

The candidates for the 2nd number, that has 3², are: 18, 12, 72 (3²×2³), 120, 180, or 360.

The candidates for the 3rd number depends on how many 2s the 2nd number has.

If more than one: 2, 6, 18, 10, 30, 90

If only 1, those plus 4, 8, 12, 36, 72, 20, 40, 120, 180, 360

Answer:

18

Step-by-step explanation:

Calculation to determine how many coloured paper are there

Let 3x represent the number of coloured papers

Let 8x represent the number of white papers

Given that 8x=48

Hence,

x=48/8

x=6

Now let determine how many coloured paper are there

Coloured paper=3x

Coloured paper=3(6)

Coloured paper=18

Thereffore the number of coloured paper that are there is 18

Answer:

b = - 1.09

Step-by-step explanation:

- 2.9 + b ÷ 0.1 = - 39.9

- 2.9 + b ÷ 0.1 × 0.1 = - 39.9 × 0.1

- 2.9 + b = - 3.99

- 2.9 + 2.9 + b = - 3.99 + 2.9

b = - 1.09

Answer:

Exact form

b=-37/10

Decimal form

b=-3.7

Mixed Number form

b+-3 7/10

Step-by-step explanation:

-2.9+b/1/10+-39.9

-2.9+10b+-39.9

10b=-39.9+2.9

10b=-37

b=-37/10