Find the other endpoint of the line segment with the given endpoint and midpoint. I
nearest tenth.
Endpoint (-8, 8) Midpoint (5,-3)

[tex]\large {\text {$ \sf \cfrac{1}{2x^2} -2 = 0 $}}[/tex]

[tex]\large {\text {$ \sf \cfrac{1}{2x^2}\cdot \:2x^2-2\cdot \:2x^2=0\cdot \:2x^2 $}[/tex]

                 [tex]\searrow[/tex]

                     [tex]\large {\text {$ \sf 1-4x^2=0$}}[/tex]

[tex]\large {\text {$ \sf -4x^2+1 = 0 $}}[/tex]

[tex]\large {\text{$\sf x=\cfrac{-b\pm\sqrt{b^2-4ac}}{2a} \quad\rightarrow\quad x=\cfrac{-0\pm\sqrt{0^2-4\cdot (-4) \cdot1} }{2\cdot (-4) } \:\rightarrow\:\: x=\cfrac{-0^2 \pm4}{2 \cdot(-4)} $}}[/tex]  

                                                             [tex]\huge {\text {$ \sf \downarrow$}}[/tex]

           [tex]\large {\text {$\sf {\bf x_1} = \cfrac{-0+4}{2\left(-4\right)}= \cfrac{-1}{2} $}}[/tex]                        [tex]\large {\text {$\sf {\bf x_2 }=\cfrac{-0-4}{2\left(-4\right)} = \cfrac{1}{2} $}}[/tex]

[tex]\large {\boxed {\boxed { \bf x_1 + x_2= -\cfrac{1}{2}+ \cfrac{1}{2} = 0} }}[/tex]

                                           [tex]\huge {\text {$ \it Alternative \: A $}}[/tex]

Answer:

[tex]\$6[/tex]

Step-by-step explanation:

Given

See comment for complete question

Required

The difference in the cost of 600 text messages plan

Representing the given data as; Cost to Number of text messages, we have:

[tex]Dial\ Up = \$5 : 100[/tex]

and

[tex]Ring\ Ring= \$8 : 200[/tex]

Multiply the dial-up by 6 to get the cost of 600

[tex]Dial\ Up = \$5 *6 : 100 * 6[/tex]

[tex]Dial\ Up = \$30 : 600[/tex]

So, the cost of 600 text messages is $30 --- for dial-up

Multiply the Ring Ring by 3 to get the cost of 600

[tex]Ring\ Ring= \$8 *3: 200*3[/tex]

[tex]Ring\ Ring= \$24: 600[/tex]

So, the cost of 600 text messages is $24 --- for Ring Ring

The difference (d) is:

[tex]d = \$30 - \$24[/tex]

[tex]d = \$6[/tex]

Answer:

In picture

Step-by-step explanation:

Brainliest please~

[tex](0,3)[/tex] and [tex](1,-2)[/tex]

Equation: (refer the image below)

Slope:

[tex]m=\frac{3+2}{0-1}[/tex]

[tex]m=-5[/tex]

Equation:

[tex]y=5x-b[/tex]

[tex]3=b[/tex]

Substitute (0,3)

Point: [tex](1,-2)[/tex]

Answer:

x^4+4x^3+6x^2+7x+2

im sorry i dont know the answer

Answer:

65.76 m

Step-by-step explanation:

This figure is split into three shapes: a right triangle, a rectangle, and a semi- circle. To find the area of the figure you can start by figuring out the area of each of the three shapes mentioned above, then adding their areas together. I'll write the numbers without the unit to make it simpler since it won't cancel out or anything.

Starting with the triangle:

1/2(b*h)=a

We see the base is 3, and the height is 5 (because the two opposite sides of a rectangle will be congruent) so if you plug the numbers into the formula you get:

1/2*15=a or 15/2=a

a=7.5

Then we calculate the area of the rectangle:

l*w=a

5*6=a

30=a

Then the area of the semi circle:

First we find the area as if it were a full circle by the equation using 3.14 as pi and 3 as r (since the denominator is 6 and half of 6 is 3):

3.14*r^2=a

3.14*3^2=a

3.14*9=a

28.26=a

Finally, we add all three areas from above:

7.5+30 + 28.26 = 65.76

Answer:

They are parallel so also -4/3

Answer:

3

Step-by-step explanation:

We are going to be using cofunction identity cos(90-x)=sin(x).

Apply to either side but not both.

cos(22f − 1) = sin(7f + 4)

sin(90-[22f-1])=sin(7f+4)

90-[22f-1]=7f+4

Distribute

90-22f+1=7f+4

Combine like terms

91-22f=7f+4

Add 22f on both sides

91=29f+4

Subtract 4 on both sides

87=29f

Divide 29 on both sides

3=f

f=3 is between 0 and 90

Answer:

The answer is "3."

Step-by-step explanation:

Just submitted the test and got the answer correct!

Answer:

27%

Step-by-step explanation:

Answer:

p(j)=27% is correct answer

Answer:

x = 3

Step-by-step explanation:

2(5x - 3) = 24

Divide both sides by 2.

5x - 3 = 12

Add 3 to both sides.

5x = 15

Divide both sides by 5.

x = 3

Answer:

True

Step-by-step explanation:

This is the case when the result is True. The substituted variables in the argument must equal a conclusion that is also True. For example, if the premises are True, then the conclusion of the valid argument form needs to output a True conclusion as well. This makes the argument valid. Otherwise, the argument would be invalid if two True premises output a conclusion that is equal to False.

Answer:

d

Step-by-step explanation:

Answer:

1 hour

Step-by-step explanation:

hope it helps ....

Answer:

In a product like:

a*b = 0

says that one of the two terms (or both) must be zero.

Here we have our equation:

x^2 + 12 = 7x

x^2 + 12 - 7x = 0

Let's try to find an equation like:

(x - a)*(x - b) such that:

(x - a)*(x - b)  = x^2 + 12 - 7x

we get:

x^2 - a*x - b*x  -a*-b = x^2 - 7x + 12

subtracting x^2 in both sides we get:

-(a + b)*x + a*b = -7x + 12

from this, we must have:

-(a + b) = -7

a*b = 12

from the first one, we can see that both a and b must be positive.

Then we only care for the option with positive values, which is x =3 or x = 4

replacing these in both equations, we get:

-(3 + 4) = -7

3*4 = 12

Both of these equations are true, then we can write our quadratic equation as:

(x - 3)*(x - 4) = x^2 + 12 - 7x

The correct option is the last one.

Answer:

d

Step-by-step explanation:

Answer:

G

Step-by-step explanation:

I did this on edge and it was right

Answer:

O  Point G

Step-by-step explanation:

A = -6

B = 8

To find the midpoint, calculate how much would it take for both points to have a value of zero.

-6 + ? = 0

-6 + 6 = 0

8 - ? = 0

8 - 8 = 0

so the midpoint will be about 7 (between 6 & 8)

Now which of the points best shows 7 units apart of AB

Answer: point G

Answer:

x < 0.5

Step-by-step explanation:

Given

2(1 - x) > 2x ( divide both sides by 2 )

1 - x > x ( add x to both sides )

1 > 2x ( divide both sides by 2 )

[tex]\frac{1}{2}[/tex] > x , that is

x < [tex]\frac{1}{2}[/tex] OR x < 0.5

Answer:

I am a piano so yeah I'm just typing to fill the character requirement

Step-by-step explanation:

get got

Answer:

[tex]P(x = 3) = 0.048[/tex]

Step-by-step explanation:

Given

[tex]n = 10[/tex]

[tex]p=59\% = 0.59[/tex]

Required

[tex]P(x = 3)[/tex] --- probability that 3 are afflicted

This question illustrates binomial probability and it is calcuated using:

[tex]P(x) = ^nC_x * p^x * (1 - p)^{n-x}[/tex]

So, we have:

[tex]P(x = 3) = ^{10}C_3 * 0.59^3 * (1 - 0.59)^{10-3}[/tex]

[tex]P(x = 3) = ^{10}C_3 * 0.59^3 * 0.41^7[/tex]

[tex]P(x = 3) = 120 * 0.59^3 * 0.41^7[/tex]

[tex]P(x = 3) = 0.048[/tex]

Step-by-step explanation:

hi friend I can help you in this geometry work via Wazapp

Answer:

31

Step-by-step explanation:

[tex]3+7[/tex] × 4        Multiply first

3 + 28           Then add

31

Answer:

Traversable because it has exactly two odd nodes

Step-by-step explanation:

There is a rule that says it is traversable if it has exactly 2 odd nodes. The are other rule where it can be traversable is if has no odd nodes.

Also if we let the starting point be D and the ending point be B we can travel the network in such way that each edge is only traveled once which is the definition that the network is traversable.

So I will do this by starting at D, then travel to A using the outside edge, then travel to back to D using inside edge, then travel to C, then travel to B, then travel to A using outside edge, and then back to B from A using inside edge.

Answer:

The circumference of Earth's equator is 40,080 km.

Step-by-step explanation:

Given that every 24 hours, Earth makes a full rotation around its axis, and Earth's speed of rotation at the equator is 1,670 km per hour, to determine what is the circumference of Earth's equator the following calculation must be performed:

24 x 1,670 = X

40,080 = X

Therefore, the circumference of Earth's equator is 40,080 km.

Hello,

[tex]z=\dfrac{X-69}{3.5} \\\\For\ X=72.5, \\\\z=\dfrac{72.5-69}{3.5} =1\\[/tex]

Using table of a normal reduced law:

p(z≤1)=0.8413

Thus p(z≥1)=1-0.8413=0.1587

There are 80*0.1587=12.696 ≈13 (frogs)

Answer:

12 frogs

Step-by-step explanation:

Hello,

Using table of a normal reduced law:

p(z≤1)=0.8413

Thus p(z≥1)=1-0.8413=0.1587

There are 80*0.1587=12.696 ≈12 (frogs) you don't round up because you cant have .7 percent of a frog.

ps. I copy and pasted caylus's response but corrected their answer because it was correct except the rounding up part.

Answer:

the angle <ABC is equal to 65°

Answer:

12^(3/2)

Step-by-step explanation:

(2x6)^3/2

2x6=12

12^3/2= 41.5692193817

Answer:

A) 0.019

B) 0.563

Step-by-step explanation:

a) We will use Poisson distribution formula to solve this;

The formula is given as;

P(X = x) = ((e^-λ) × (λˣ))/x!

Mean is 1. Thus;

λ = 1 aircraft/hour.

Thus, the probability that more than three aircrafts will arrive within an hour is written as; P(X > 3)

Thus;

P(X > 3) = 1 - P(X ≤ 3)

Thus;

1 - P(X ≤ 3) = 1 - [P(X=0) + P(X=1) + P(X=2) + P(X=3)]

Solving through online calculator, we have;

P(X > 3) = 1 - 0.98101

P(X > 3) = 0.01899

To 3 decimal places, we have; P(X > 3)= 0.019

b) Probability of one 1-hour interval not containing more than 3 arrivals is, let's first find;

P(X ≤ 3) = 1 - P(X > 3)

P(X ≤ 3) = 1 - 0.01899

P(X ≤ 3) = 0.98101

Since there are 30 one-hour intervals, then we have;

Probability that none of the thirty 1-hour intervals will contain more than 3 arrivals;

(P ≤ 3) = (0.98101)³⁰

(P ≤ 3) = 0.5626

Approximating to 3 decimal places, we have;

(P ≤ 3) = 0.563

Given:

For en exponential function f(a):

[tex]f(-3)=18[/tex]

[tex]f(1)=59[/tex]

To find:

The value of f(0).

Solution:

The general form of an exponential function is:

[tex]f(x)=ab^x[/tex]          ...(i)

Where, a is the initial value and b is the growth/ decay factor.

We have, [tex]f(-3)=18[/tex]. Substitute [tex]x=-3,f(x)=18[/tex] in (i).

[tex]18=ab^{-3}[/tex]            ...(ii)

We have, [tex]f(1)=59[/tex]. Substitute [tex]x=1,f(x)=59[/tex] in (i).

[tex]59=ab^{1}[/tex]            ...(iii)

On dividing (iii) by (ii), we get

[tex]\dfrac{59}{18}=\dfrac{ab^{1}}{ab^{-3}}[/tex]

[tex]3.278=b^{1-(-3)}[/tex]

[tex]3.278=b^{4}[/tex]

[tex](3.278)^{\frac{1}{4}}=b[/tex]

[tex]1.346=b[/tex]

Substituting the value of b in (iii).

[tex]59=a(1.346)^1[/tex]

[tex]\dfrac{59}{1.346}=a[/tex]

[tex]43.83358=a[/tex]

[tex]a\approx 43.83[/tex]

The initial value of the function is 43.83. It means, [tex]f(0)=43.83[/tex].

Therefore, the value of f(0) is 43.83.