Find the perimeter of the
polygon if ZB = D.
3 om
B
4 cm
D
5 cm
C
P = [?] cm

Answer:

X+6

Step-by-step explanation:

Sum means Addition.

Answer:

[tex]\frac{135}{15} =\frac{15(x+2)}{15}[/tex]

[tex]9=x+2[/tex]

[tex]x=7[/tex]

OAmalOHopeO

Answer:

yes it is. a polygon is any closed shape with at least 3 connected lines (eg. triangle, square, pentagon, hexagon, heptagon, octagon, etc)

Step-by-step explanation:

Answer:

29/3 is your answer

Step-by-step explanation:

pls mark as brainliest

Answer:

[tex]r'(t) = 298t -850[/tex]

Step-by-step explanation:

Given

[tex]q(t) = 1000t - 150t^2[/tex]

[tex]p(t) = 150t - t^2[/tex]

Required

[tex]r'(t)[/tex]

First, we calculate the revenue

[tex]r(t) = p(t) - q(t)[/tex]

So, we have:

[tex]r(t) = 150t - t^2 - (1000t - 150t^2)[/tex]

Open bracket

[tex]r(t) = 150t - t^2 - 1000t + 150t^2[/tex]

Collect like terms

[tex]r(t) = 150t^2 - t^2 + 150t - 1000t[/tex]

[tex]r(t) = 149t^2 -850t[/tex]

Differentiate to get the revenue change with time

[tex]r'(t) = 2 * 149t -850[/tex]

[tex]r'(t) = 298t -850[/tex]

Answer:

31/10,32/10,33/10,34/10,35/10

Step-by-step explanation:

a rational number is formed when any two integers p and q are expressed in the form of p/q

to find two two sets of rational numbers BETWEEN any two numbers

a and b we need to express a and b and rational numbers....let us express 3and4 as rational numbers 3=30/10 4=40/10

the list of rational numbers between 3and4,that is, 30/10,31/10,32/10,33/10,34/10,35/10,36/10,37/10,38/10,39/10,40/10.

therefore the five rational numbers between 3 and 4 are (31/10,32/10,33/10,34/10,35/10...

I hope that helps

Answer:

ok so you take m time h then like you count to h like a b c d e f g h and tgen with that you count 1 2 3 4 5 6 7 till h than you multiply that with 3

Answer:

15

Step-by-step explanation:

The measure of angle FGE is 52.5°.

Angles of Intersecting Secants Theorem states that, If two lines intersect outside a circle, then the measure of an angle formed by the two lines is one half the positive difference of the measures of the intercepted arcs.

Thus, applying the angles of intersecting secants theorem

m∠FGE = 1/2[(100 + 35) - 30]

m∠FGE = 1/2[(105]

m∠FGE = 52.5°

Learn more about angles of intersecting secants theorem here :

https://brainly.com/question/15532257

#SPJ2

Answer:

option a 5......

...

I hope it's correct

Answer:

5/8 ft^2

Step-by-step explanation:

The area of a rectangle is given by

A = l*w  where l is the length and w is the width

A = 5/6 * 3/4

A = 3/6 * 5/4

A = 1/2 * 5/4

A = 5/8 ft^2

Answer:

Bro what to do in this question I am not able to understand Hope you understand me

Answers:

================================================

Explanation:

If it's sold at a loss of 15%, then the store owner loses 0.15*330 = 49.50 dollars

So it was sold for 330- 49.50 =  280.50 dollars

----------------------------

An alternative method:

If the store owner loses 15%, then they keep the remaining 85% since 15%+85% = 100%.

85% of 330 = 280.50 dollars is the discount price

This means 330-280.50 = 49.50 dollars is the amount lost.

Answer:

x=13

Step-by-step explanation:

f(x) = sqrt(x-11)

The square root must be greater than or equal to zero

sqrt(x-11)≥0

Square each side

x-11≥0

x ≥11

The only answer that is greater than or equal to 11 is

x=13

Answer:

dont understand clearly

Step-by-step explanation:

dont understand clearly

Answer:

Following are the solution to the given points:

Step-by-step explanation:

As a result, Poisson for each driver seems to be the number of accidents.

Let X be the random vector indicating accident frequency.

Let, [tex]\lambda=[/tex]Expected accident frequency

[tex]P(X=0) = e^{-\lambda}[/tex]

For class 1:

[tex]P(X=0) = \frac{1}{(1-0.2)} \int_{0.2}^{1} e^{-\lambda} d\lambda \\\\P(X=0) = \frac{1}{0.8} \times [-e^{-1}-(-e^{-0.2})] = 0.56356[/tex]

For class 2:

[tex]P(X=0) = \frac{1}{(2-0.4)} \int_{0.4}^{2} e^{-\lambda} d\lambda\\\\P(X=0) = \frac{1}{1.6} \times [-e^{-2}-(-e^{-0.4})] = 0.33437[/tex]

For class 3:

[tex]P(X=0) = \frac{1}{(3-0.6)} \int_{0.6}^{3} e^{-\lambda} d\lambda\\\\P(X=0) = \frac{1}{2.4} \times [-e^{-3}-(-e^{-0.6})] = 0.20793[/tex]

The population is equally divided into three classes of drivers.

Hence, the Probability

[tex]\to P(X=0) = \frac{1}{3} \times 0.56356+\frac{1}{3} \times 0.33437+\frac{1}{3} \times 0.20793=0.36862[/tex]

Answer:

2,7

Step-by-step explanation:

Answer:

(-1,-2)

Step-by-step explanation:

(6 x -1) -(-2 x 5) = 4

-6 + 10 = 4

Answer:

It is (x - 3)³ - 9x(3 - x)

Step-by-step explanation:

Express 27 in terms of cubes, 27 = 3³:

[tex] = {x}^{3} - {3}^{3} [/tex]

From trinomial expansion:

[tex] {(x - y)}^{3} = (x - y)(x - y)(x - y) \\ [/tex]

open first two brackets to get a quadratic equation:

[tex] {(x - y)}^{3} = ( {x}^{2} - 2xy + {y}^{2} )(x - y)[/tex]

expand further:

[tex] {(x - y)}^{3} = {x}^{3} - y {x}^{2} - 2y {x}^{2} + 2x {y}^{2} + x {y}^{2} - {y}^{3} \\ {(x - y)}^{3} = {x}^{3} - {y}^{3} + 3x {y}^{2} - 3y {x}^{2} \\ {(x - y)}^{3} = {x}^{3} - {y}^{3} + 3xy(y - x) \\ \\ { \boxed{( {x}^{3} - {y}^{3} ) = {(x - y)}^{3} - 3xy(y - x)}}[/tex]

take y to be 3, then substitute:

[tex]( {x}^{3} - 3^3) = {(x - 3)}^{3} - 9x(3 - x)[/tex]

Answer:

A

Step-by-step explanation:

Its not a linear function; there is no consistent rate of change between each of the points.

Your question is not complete but I guess you want to know the total price to be paid. This will be:

= $145 + (5.5% × $145)

= $145 + (0.055 × $145)

= $145 + $7.975

= $152.975

Answer:

There are 750 more drama movies that children's movies.

Step-by-step explanation:

There are 1003 drama movies, and 253 children's movies.

1003 - 253 = 750

Answer:

see below

Step-by-step explanation:

{1} x+(y-z)=(x+y)+z   associative property of addition

2} (pq) * 1 = pq D  multiplicative identity

3} (5x)y-5(xy) H   associative property of multiplication

4} a+5b = 5b + a   commutative property of addition

5} a+0=a  I   additive identification property

6} gh - hg   C commutative property of multiplication

7} 8 + (-8)=0   A  additive inverse property

8} x * 0 = 0   J   zero property

9} 5 * (1/5)=1   B   multiplicative inverse property

10} 2(a+b)=2a * 2b   G  distributive property

Let's see

#a

x+(y-z)=(x+y)+z

#b

(pq) * 1 = pq

#c

(5x)y-5(xy)

#d

a+5b = 5b + a

#e

a+0=a

#f

gh - hg

#g

8 + (-8)=0

#h

x * 0 = 0

#i

5 * (1/5)=1

#j

2(a+h)=2a * 2b

Answer: it should be A

Step-by-step explanation:

Answer:

2.3

Step-by-step explanation:

.5 - .3 = .2

.8 - .5 = .3

1.2 - .8 = .4

1.7 - 1.2 = .5

We should add .6 next

1.7+.6 = 2.3

Step-by-step explanation:

tan Z=p/b

=48/14

=24/7

Keep smiling and hope u are satisfied with my answer.Have a good day :)

Answer:

Table C

Step-by-step explanation:

r = j+3

In table A

j = 12 so r = 12+3 = 15  not true so it does not fit the equation

In table B

j = 3 so r = 3+3 = 6  not true so it does not fit the equation

In table C

j = 6 so r = 9+3 = 9 this could be the table

In table D

j = 27 so r = 27+3 = 30  not true so it does not fit the equation

Answer:

997.5 is the answer to your question..

Answer:

Correct answer is 4 because the last 2 terms can be combined:

Step-by-step explanation:

4x3 + 9y2 – 3x + 2 – 1 = 4x3 – 3x + 9y2 + 1.

Answer:

Imaginary roots

Step-by-step explanation:

The discriminant of a quadratic in standard form [tex]ax^2+bx+c[/tex] is given by [tex]b^2-4ac[/tex].

Given [tex]7x^2+1=5x[/tex], subtract 5x from both sides so that the quadratic is in standard form:

[tex]7x^2-5x+1=0[/tex]

Now assign variables:

The discriminant is therefore [tex](-5)^2-4(7)(1)=25-28=\textbf{-3}[/tex].

What does this tell us about the roots?

Recall that the discriminant is what is under the radical in the quadratic formula. The quadratic formula is used to find the solutions of a quadratic. Therefore, the solutions of this quadratic would be equal to [tex]\frac{-b\pm \sqrt{-3}}{2a}[/tex] for some [tex]b[/tex] and [tex]a[/tex]. Since the number under the radical is negative, there are no real roots to the quadratic (whenever the discriminant is negative, the are zero real solutions to the quadratic). Therefore, the quadratic has imaginary roots.