Answer:
k = 5/3
x = 21
Step-by-step explanation:
Here, we have two similar shapes
The scale factor here would be the ratio of the corresponding similar sides
so we have k as 15/9 = 5/3
To find the value of x
When two shapes are similar, the ratio of the sides corresponding are equal
So we have it that;
x/35 = 9/15
= 15 * x = 9 * 35
15x = 315
x = 315/15
x = 21
1. Students were surveyed and asked if they play lacrosse and/or football. The results are shown below.
What percent of football players also play lacrosse?
36%
Step-by-step explanation:
28 + 16 = 44 Football players
Of those, 16 are on the lacrosse team.
16 / 44 × 100 = 36.36% (We round to 36%)
To verify:
44 × 36.36% = 15.84 (Which we can round to 16)
Pardon me if it's wrong
Solve The inequality
Answer:
D is the correct answer.
Please thank me
Step-by-step explanation:
What is the vertex of the graph of the function f(x) = (x + 2)^2 − 3?
Find the constant of proportionality if y is
proportional to x.
A. 25
B. 21
C. 26
D. 28
HELPPP!!!!!!
What is the area of the obtuse triangle given below?
Answer:
D. 38.5 sq. units
Step-by-step explanation:
The formula for the area of a triangle is A=bh(1/2)
So to solve, first multiply the base, by the height: 11*7=77
Then, multiply by 1/2 or divide by 2.
You get 38.5
That's your answer!
Hope this helps!
given that O is the center of the circle, find the measure of angle BAC of arc DC = 120
Answer:
30 degrees.
Step-by-step explanation:
DC is given as 120, so start off by finding arc BC.
180-120= Semicircle-DC=60.
BC=60.
Inscribed angles are half of their arcs.
60/2=30.
I need help figuring out what the answer is.
Answer:
A
Step-by-step explanation:
Write the expression as an exponent:
5^8 x 25
6^15 x 36
Answer:
a.) 5¹⁰
b.) 6¹⁷
Step-by-step explanation:
a.) 5⁸ × 25
Write 25 in the exponential form with the base of 5.
5⁸ × 5²To calculate product use exponent rule
5⁸+²5¹⁰b.) 6¹⁵ × 36
Similarly, 6¹⁵ × 36
Write 25 in the exponential form with the base of 6.
6¹⁵ × 6²To calculate product use exponent rule.
6¹⁵ + ²6¹⁷Answer:
[tex] \displaystyle {5}^{10} [/tex]
[tex] \displaystyle {6}^{17} [/tex]
Step-by-step explanation:
Question-1:we want to rewrite the following expression as an exponent
[tex] \displaystyle {5}^{8} \times {25}[/tex]
remember that 25 is the square of 5 therefore
[tex] \displaystyle {5}^{8} \times {5}^{2} [/tex]
recall that,
[tex] \displaystyle {x}^{m} \times {x}^{n} = {x}^{m + n} [/tex]
with that law we obtain:
[tex] \displaystyle {5}^{8 + 2} [/tex]
simplify addition:
[tex] \displaystyle {5}^{10} [/tex]
Question-2:likewise Question-1 36 is the square of 6 Thus,
[tex] \displaystyle {6}^{15} \times {6}^{2} [/tex]
similarly apply law of exponent:
[tex] \displaystyle {6}^{15 + 2} [/tex]
simplify addition:
[tex] \displaystyle {6}^{17} [/tex]
hence,
we have written the expression as an exponent
A cyclist travels 5 miles in 15 minutes.
What is her average speed in mph?
Point A (6,2) is translated using the vector <-5,2>. Where is the new point located?
======================================================
Explanation:
The notation <-5,2> is the same as writing the translation rule [tex](x,y) \to (x-5,y+2)[/tex]
It says: move 5 units to the left and 2 units up
The point (6,2) moves to (1,2) when moving five units to the left. Then it ultimately arrives at (1, 4) after moving 2 units up. You could move 2 units up first and then 5 units to the left later on, and you'd still arrive at (1, 4). In this case, the order doesn't matter (some combinations of transformations this won't be the case and order will matter).
---------
Or you could write out the steps like so
[tex](x,y) \to (x-5, y+2)\\\\(6,2) \to (6-5, 2+2)\\\\(6,2) \to (1, 4)\\\\[/tex]
We see that (6,2) moves to (1, 4)
What is dummy variable? Explain interaction effects using dummy variables? Explain Autoregressive Conditional Heteroskedasticity (ARCH) and Generalized Autoregressive Conditional Heteroskedasticity (GARH) models. What to do when find problem of Autocorrelation?
Answer:
u here then today the thats yjvfh dfnrugevc5hdb
If < A and < B are vertical angles, and < A is 43 ° , then what is the measure of < B?
Select one:
a. 47 °
b. 137 °
c. 21 °
d. 43 °
Answer:
d
Step-by-step explanation:
vertical angles are congruent , so
∠ B = ∠ A = 43°
Situation:
Find the age of
A student in Greece discovers a pottery
bowl that contains 28% of its original
amount of C-14.
Ent
N= Noekt
No
= inital amount of C-14 (at time
t = 0)
N = amount of C-14 at time t
k = 0.0001
t = time, in years
Answer:
Step-by-step explanation:
I'm assuming you need the age of the bowl. Start with the fact that you have remaining 28% of the original amount before any of it decayed. You always start with 100% of something unless you're told differently. That means that the equation looks like this:
[tex]28=100e^{-.0001t}[/tex] and begin by dividing both sides by 100 to get
[tex].28=e^{-.0001t}[/tex] . To solve for t we have to be able to bring it down from its current position of exponential. To do this we would either take the log or the natural log since the rules for both are the same. However, the natural log is the inverse of e, so they undo each other. We take the natural log of both sides which allows us to pull down the -.0001t. At the same time remember that the natural log and e are inverses of each other so they are both eliminated when we do this.
ln(.28) = -.0001t Now it's easy to solve for t.
[tex]\frac{ln(.28)}{-.0001}=t[/tex] and
[tex]\frac{-1.272965676}{-.0001}=t[/tex] so
t = 12729.65676 years or rounded, 12730 years.
1) Find the measure of 0. (imagine that is an x) 2) Then, find the measure of AB. (the length from A to B)
Answer:
θ ≈ 50°, AB ≈ 15.6
Step-by-step explanation:
Using the tangent ratio in the right triangle
tanθ = [tex]\frac{opposite}{adjacent}[/tex] = [tex]\frac{BC}{AC}[/tex] = [tex]\frac{11.9}{10}[/tex] = 1.19 , then
θ = [tex]tan^{-1}[/tex] (1.19 ) ≈ 50° ( to the nearest degree
-----------------------------------------------------------------
Using the cosine ratio in the right triangle
cos50° = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{AC}{AB}[/tex] = [tex]\frac{10}{AB}[/tex] ( multiply both sides by AB )
AB × cos50° = 10 ( divide both sides by cos50° )
AB = [tex]\frac{10}{cos50}[/tex] ≈ 15.6 ( to 1 dec. place )
find the distance between the points (-3,-2) and (1,-5)
Joseph is creating a dilation through point B with a scale factor of 2. Which statements about the dilation are correct? Check all that apply.
Triangle A B C. Angle B is a right angle.
A’ will be located on ray Ray B A.
B and B’ are the same point.
Line segment B prime C prime will be One-half as long as Line segment B C.
Line segment A B and Line segment B C will be part of the image’s sides.
The image will be inside the pre-image.
Answer:
A’ will be located on ray Ray B A.
B and B’ are the same point.
Line segment A B and Line segment BC will be part of the image’s sides.
Step-by-step explanation:
Given that the dilation is made through point B, B and B’ are the same point, A’ will be located on Ray BA, C’ will be located on Ray BC, line segment B'C' will be double than line segment BC, line segment B'A' will be double than line segment BA, and the pre-image (triangle ABC) will be inside the image (triangle A'B'C').
Answer:
A B D is your answer
Step-by-step explanation:
what is the measure of 2?
Answer:
Value of x:
[tex]{ \tt{(7x + 1) \degree + (18x + 4) \degree = 180 \degree}} \\ { \tt{25x + 5 = 180}} \\ { \tt{25x = 175}} \\ x = 7[/tex]
Finding m‹2 :
[tex]{ \tt{m \angle2 = (7x + 1) \degree}} \\ { \tt{m \angle2 = (7 \times 7) + 1}} \\ { \bf{m \angle2 = 50 \degree}}[/tex]
Answer:
m∠2 = 50
Step-by-step explanation:
7x + 1 and 18x + 4 are angles in a linear pair.
Sum of linear pair angles is supplementary.
7x + 1 + 18x + 4 = 180
7x + 18x + 1 + 4 = 180
25x + 5 = 180
25x = 180 - 5
25x = 175
x = 175 / 25
x = 7
Substitute x = 7 in 7x + 1,
7x + 1
= 7 ( 7 ) + 1
= 49 + 1
= 50
7x + 1 and ∠2 are vertically opposite angles and vertically opposite angles are equal.
∠2 = 7x + 1
∠2 = 50
Simplify. 6x-2
A.6/x^2
B.x²/6
C.1/6x^2
D.1/36x^2
Answer:
Step-by-step explanation:
[tex]a^{-m}=\frac{1}{a^{m}}\\\\6x^{-2}=6*\frac{1}{x^{2}}=\frac{6}{x^{2}}[/tex]
A baseball diamond is a square that is 90 feet on each side. How far is it from home plate to second base? Round to the nearest hundredth.
90.50 feet
97.50 feet
107.28 feet
127.28 feet
Answer:
[tex]\sqrt{90^2 + 90^2}[/tex]
= 127.2792206
Step-by-step explanation:
Answer: 127.28 feet.
Step-by-step explanation:
It’s actually 127.2792206 feet, but rounded to the nearest hundredth, it’s 127.28 feet. Hope I helped!
what is the product of the prime factors of 24
Answer:
So the prime factorization of 24 is 24 = 2 · 2 · 2 · 3 = 23 · 3. A good way to check the result is to multiply it out and make sure the product is 24.
Step-by-step explanation:
Class 3 question ,pls help
Answer:
bigger number minus larger number plus 1
430-421 = 9 + 1 = 10
573 - 567 = 6+1 = 7
898 - 890 = 8+ 1 = 9
Step-by-step explanation:
Solve the inequality. q/3 < 11
Answer:
[tex]q < 33[/tex]
Step-by-step explanation:
[tex] \frac{q}{3} < 11[/tex][tex]q < 11 \times 3[/tex]
[tex]q < 33[/tex]
Hope it is helpful....Answer:
33
Step-by-step explanation:
q/3<11
q=11×3
q=33
:. The answer is 33.
The number of strokes in which a hole is designed to be played. [ Choose ] The person who is farthest away from the hole is said to have _____.
Answer:
the answer is more strokes since the farther away you are the more strokes it takes
Hope This Helps!!!
what is the percentage of 690 out of 800
Answer:
the percentage of 690 out of 800 is 86.25%
Step-by-step explanation:
690/800 = 0.8625
0.8625*100 = 86.25
hope it helped :)
mark me brainliest
Answer:
86.25%
Step-by-step explanation:
(A) Given that the expression x^3-ax^2+bx+c leaves the same remainder when divided by x+1 or x-2, find a in term of b.
(B) (2x-1)^3+6(3+4x^2) is divided by 2x+1.
Answer those two question please. I need it quickly. No silly answers would not be allowded.
Hello,
A:
[tex]\begin{array}{c|ccc|c}&x^3&x^2&x&1\\&1&-a&b&c\\x=-1&&-1&a+1&-a-b-1\\---&---&---&---&---\\&1&-a-1&a+b+1&-a-b+c-1\\\end{array}\\\\\\\begin{array}{c|ccc|c}&x^3&x^2&x&1\\&1&-a&b&c\\x=2&&2&-2a+4&-4a+2b+8\\---&---&---&---&---\\&1&-a+2&-2a+b+4&-4a+2b+c+8\\\end{array}\\\\\\\\-a-b+c-1=-4a+2b+c+8\\\\\boxed{b=a-3}\\[/tex]
B:
[tex](2x-1)^3+6(3+4x^2)\\\\=8x^3-12x^2+6x-1+18+24x^2\\\\=8x^3+12x^2+6x+17\\\\\\\begin{array}{c|ccc|c}&x^3&x^2&x&1\\&8&12&6&17\\x=-\dfrac{1}{2} &&-4&-4&-1\\---&---&---&---&---\\&8&8&2&16\\\end{array}\\\\\\(2x-1)^3+6(3+4x^2)=(2x+1)(4x^2+4x+1)+16[/tex]
Plss Answer!!!!!!!!!
Answer:
Ecosystem: Trees
Ways to protect are as follows:-
Control over Forest FireDon't waste paper. Plant a treeHelp, I have a time limit for this
Answer:
I believe that it is the first one.
Step-by-step explanation:
A particle is projected with a velocity of [tex]40ms^-^1[/tex] at an elevation of 60°. Calculate the vertical component of its velocity at a height of 50m. (Take g = [tex]9.8ms^-^2[/tex])
A. [tex]25\sqrt{3} ms^-^1\\\\B.20\sqrt{3} ms^-^1\\\\c. 2\sqrt{545} ms^-^1[/tex]
Answer:
[tex]2\sqrt{55}\text{ m/s or }\approx 14.8\text{m/s}[/tex]
Step-by-step explanation:
The vertical component of the initial launch can be found using basic trigonometry. In any right triangle, the sine of an angle is equal to its opposite side divided by the hypotenuse. Let the vertical component at launch be [tex]y[/tex]. The magnitude of [tex]40\text{ m/s}[/tex] will be the hypotenuse, and the relevant angle is the angle to the horizontal at launch. Since we're given that the angle of elevation is [tex]60^{\circ}[/tex], we have:
[tex]\sin 60^{\circ}=\frac{y}{40},\\y=40\sin 60^{\circ},\\y=20\sqrt{3}[/tex](Recall that [tex]\sin 60^{\circ}=\frac{\sqrt{3}}{2}[/tex])
Now that we've found the vertical component of the velocity and launch, we can use kinematics equation [tex]v_f^2=v_i^2+2a\Delta y[/tex] to solve this problem, where [tex]v_f/v_i[/tex] is final and initial velocity, respectively, [tex]a[/tex] is acceleration, and [tex]\Delta y[/tex] is distance travelled. The only acceleration is acceleration due to gravity, which is approximately [tex]9.8\:\mathrm{m/s^2}[/tex]. However, since the projectile is moving up and gravity is pulling down, acceleration should be negative, represent the direction of the acceleration.
What we know:
[tex]v_i=20\sqrt{3}\text{ m/s}[/tex] [tex]a=-9.8\:\mathrm{m/s^2}[/tex] [tex]\Delta y =50\text{ m}[/tex]Solving for [tex]v_f[/tex]:
[tex]v_f^2=(20\sqrt{3})^2+2(-9.8)(50),\\v_f^2=1200-980,\\v_f^2=220,\\v_f=\sqrt{220}=\boxed{2\sqrt{55}\text{ m/s}}[/tex]
Evidencia de aprendizaje Se desea obtener 80 kilogramos de café molido mezclando café arábico de S/18 el kilogramo y café torrado de S/10 el kilogramo. Si se quiere que el precio del kilogramo de mezcla sea de S/13, ¿Qué cantidad de café de S/18 debe usar? Responde las siguientes preguntas: ¿Qué estrategias utilicé para validar la solución al sistema de ecuaciones? ¿Para qué me servirá lo que aprendí?, ¿Qué dificultades encontraron en este aprendizaje? A partir de la situación planteada ¿A qué conclusión puedo llegar?
Answer:
50kg de café torrado
30kg de café arábico
Step-by-step explanation:
Queremos obtener un total de 80kg de café molido.
Se utilizarán:
Café arábico, que cuesta $18 el kg
Café torrado, que cuesta $10 el kg
Queremos que el precio, por kilo, de la mezcla de 80kg sea $13.
Ok, primero debemos definir las variables:
Definamos:
x = cantidad de café arábico usado
y = cantidad de café torrado usado.
Entonces, como la mezcla deberá tener 80kg en total, tenemos:
x + y = 80kg
Y el costo total de esta mezcla será:
x*$18 + y*$10
Si lo dividimos por el peso total, tendremos el costo por kilo, que es:
(x*$18 + y*$10)/80kg
Y queremos que esto sea igual a $13, entonces tenemos la ecuación
(x*$18 + y*$10)/80kg = $13
Ok, ahora tenemos dos ecuaciones, es decir, tenemos un sistema de ecuaciones:
x + y = 80kg
(x*$18 + y*$10) = $13*80kg
(donde reescribimos levemente la segunda ecuación)
Ok, para resolver este sistema trataremos de reemplazar variables, para ello, el primer paso es aislar una de las variables en una de las ecuaciones.
Aislemos x en la primera:
x = 80kg - y
Ahora reemplazamos esto en la otra ecuación:
(x*$18 + y*$10) = $13*80kg
(( 80kg - y)*$18 + y*$10) = $13*80kg
Ahora podemos resolver esto para la variable y:
$18*80kg - $18*y + $10*y = $13*80kg
$18*80kg - $13*80kg = $18*y - $10*y
($18 - $13)*80kg = ($18 - $10)*y
$5*80kg = $8*y
($5*80kg)/$8 = y
50kg = y
Se usan 50kg de café torrado.
y como:
x + y = 80kg
x = 80kg - y
x = 80kg - 50kg = 30kg
Entonces los 30kg restantes serán de café arábico.
y la estrategia utilizada fue el remplazo de variables.
Johnny asks you to guess the specific coins he has in his pocket if he has $3.70 in change. You say you need a little
more information, to guess. So he tells you all he has is quarters and dimes and that he has 22 colns in all.
Answer:
10 quarters and 12 dimes :)
Step-by-step explanation: