Find the scale factor and the value of x. HELP !

Answer:

Value of x:

[tex]{ \tt{(7x + 1) \degree + (18x + 4) \degree = 180 \degree}} \\ { \tt{25x + 5 = 180}} \\ { \tt{25x = 175}} \\ x = 7[/tex]

Finding m‹2 :

[tex]{ \tt{m \angle2 = (7x + 1) \degree}} \\ { \tt{m \angle2 = (7 \times 7) + 1}} \\ { \bf{m \angle2 = 50 \degree}}[/tex]

Answer:

m∠2 = 50

Step-by-step explanation:

7x + 1 and 18x + 4 are angles in a linear pair.

Sum of linear pair angles is supplementary.

7x + 1 + 18x + 4 = 180

7x + 18x + 1 + 4 = 180

25x + 5 = 180

25x = 180 - 5

25x = 175

x = 175 / 25

x = 7

Substitute x = 7 in 7x + 1,

7x + 1

= 7 ( 7 ) + 1

= 49 + 1

= 50

7x + 1 and ∠2 are vertically opposite angles and vertically opposite angles are equal.

∠2 = 7x + 1

∠2 = 50

Answer:

u here then today the thats yjvfh dfnrugevc5hdb

Answer:

Step-by-step explanation:

[tex]a^{-m}=\frac{1}{a^{m}}\\\\6x^{-2}=6*\frac{1}{x^{2}}=\frac{6}{x^{2}}[/tex]

Answer:

I believe that it is the first one.

Step-by-step explanation:

Answer:

A’ will be located on ray Ray B A.

B and B’ are the same point.

Line segment A B and Line segment BC will be part of the image’s sides.

Step-by-step explanation:

Given that the dilation is made through point B, B and B’ are the same point, A’ will be located on Ray BA, C’ will be located on Ray BC, line segment B'C' will be double than line segment BC, line segment B'A' will be double than line segment BA, and the pre-image (triangle ABC) will be inside the image (triangle A'B'C').

Answer:

A B D is your answer

Step-by-step explanation:

Answer:

bigger number minus larger number plus 1

430-421 = 9 + 1 = 10

573 - 567 = 6+1 = 7

898 - 890 = 8+ 1 = 9

Step-by-step explanation:

======================================================

Explanation:

The notation <-5,2> is the same as writing the translation rule [tex](x,y) \to (x-5,y+2)[/tex]

It says: move 5 units to the left and 2 units up

The point (6,2) moves to (1,2) when moving five units to the left. Then it ultimately arrives at (1, 4) after moving 2 units up. You could move 2 units up first and then 5 units to the left later on, and you'd still arrive at (1, 4). In this case, the order doesn't matter (some combinations of transformations this won't be the case and order will matter).

---------

Or you could write out the steps like so

[tex](x,y) \to (x-5, y+2)\\\\(6,2) \to (6-5, 2+2)\\\\(6,2) \to (1, 4)\\\\[/tex]

We see that (6,2) moves to (1, 4)

Answer:

Step-by-step explanation:

I'm assuming you need the age of the bowl. Start with the fact that you have remaining 28% of the original amount before any of it decayed. You always start with 100% of something unless you're told differently. That means that the equation looks like this:

[tex]28=100e^{-.0001t}[/tex] and begin by dividing both sides by 100 to get

[tex].28=e^{-.0001t}[/tex] . To solve for t we have to be able to bring it down from its current position of exponential. To do this we would either take the log or the natural log since the rules for both are the same. However, the natural log is the inverse of e, so they undo each other. We take the natural log of both sides which allows us to pull down the -.0001t. At the same time remember that the natural log and e are inverses of each other so they are both eliminated when we do this.

ln(.28) = -.0001t Now it's easy to solve for t.

[tex]\frac{ln(.28)}{-.0001}=t[/tex] and

[tex]\frac{-1.272965676}{-.0001}=t[/tex] so

t = 12729.65676 years or rounded, 12730 years.

Answer:

Ecosystem: Trees

Ways to protect are as follows:-

Answer:

10 quarters and 12 dimes :)

Step-by-step explanation:

Answer:

30 degrees.

Step-by-step explanation:

DC is given as 120, so start off by finding arc BC.

180-120= Semicircle-DC=60.

BC=60.

Inscribed angles are half of their arcs.

60/2=30.

Answer:

D. 38.5 sq. units

Step-by-step explanation:

The formula for the area of a triangle is A=bh(1/2)

So to solve, first multiply the base, by the height: 11*7=77

Then, multiply by 1/2 or divide by 2.

You get 38.5

That's your answer!

Hope this helps!

Answer:

D is the correct answer.

Please thank me

Step-by-step explanation:

Answer:

d

Step-by-step explanation:

vertical angles are congruent , so

∠ B = ∠ A  = 43°

Hello,

A:

[tex]\begin{array}{c|ccc|c}&x^3&x^2&x&1\\&1&-a&b&c\\x=-1&&-1&a+1&-a-b-1\\---&---&---&---&---\\&1&-a-1&a+b+1&-a-b+c-1\\\end{array}\\\\\\\begin{array}{c|ccc|c}&x^3&x^2&x&1\\&1&-a&b&c\\x=2&&2&-2a+4&-4a+2b+8\\---&---&---&---&---\\&1&-a+2&-2a+b+4&-4a+2b+c+8\\\end{array}\\\\\\\\-a-b+c-1=-4a+2b+c+8\\\\\boxed{b=a-3}\\[/tex]

B:

[tex](2x-1)^3+6(3+4x^2)\\\\=8x^3-12x^2+6x-1+18+24x^2\\\\=8x^3+12x^2+6x+17\\\\\\\begin{array}{c|ccc|c}&x^3&x^2&x&1\\&8&12&6&17\\x=-\dfrac{1}{2} &&-4&-4&-1\\---&---&---&---&---\\&8&8&2&16\\\end{array}\\\\\\(2x-1)^3+6(3+4x^2)=(2x+1)(4x^2+4x+1)+16[/tex]

Answer:

a.) 5¹⁰

b.) 6¹⁷

Step-by-step explanation:

a.) 5⁸ × 25

Write 25 in the exponential form with the base of 5.

To calculate product use exponent rule

b.) 6¹⁵ × 36

Similarly, 6¹⁵ × 36

Write 25 in the exponential form with the base of 6.

To calculate product use exponent rule.

Answer:

[tex] \displaystyle {5}^{10} [/tex]

[tex] \displaystyle {6}^{17} [/tex]

Step-by-step explanation:

we want to rewrite the following expression as an exponent

[tex] \displaystyle {5}^{8} \times {25}[/tex]

remember that 25 is the square of 5 therefore

[tex] \displaystyle {5}^{8} \times {5}^{2} [/tex]

recall that,

[tex] \displaystyle {x}^{m} \times {x}^{n} = {x}^{m + n} [/tex]

with that law we obtain:

[tex] \displaystyle {5}^{8 + 2} [/tex]

simplify addition:

[tex] \displaystyle {5}^{10} [/tex]

likewise Question-1 36 is the square of 6 Thus,

[tex] \displaystyle {6}^{15} \times {6}^{2} [/tex]

similarly apply law of exponent:

[tex] \displaystyle {6}^{15 + 2} [/tex]

simplify addition:

[tex] \displaystyle {6}^{17} [/tex]

hence,

we have written the expression as an exponent

Answer:

[tex]q < 33[/tex]

Step-by-step explanation:

[tex]q < 11 \times 3[/tex]

[tex]q < 33[/tex]

Answer:

33

Step-by-step explanation:

q/3<11

q=11×3

q=33

:. The answer is 33.

36%

Step-by-step explanation:

28 + 16 = 44 Football players

Of those, 16 are on the lacrosse team.

16 / 44 × 100 = 36.36% (We round to 36%)

To verify:

44 × 36.36% = 15.84 (Which we can round to 16)

Pardon me if it's wrong

Answer:

[tex]\sqrt{90^2 + 90^2}[/tex]

= 127.2792206

Step-by-step explanation:

Answer: 127.28 feet.

Step-by-step explanation:

It’s actually 127.2792206 feet, but rounded to the nearest hundredth, it’s 127.28 feet. Hope I helped!

Answer:

the answer is more strokes since the farther away you are the more strokes it takes

Hope This Helps!!!

Answer:

the percentage of 690 out of 800 is 86.25%

Step-by-step explanation:

690/800 = 0.8625

0.8625*100 = 86.25

hope it helped :)

mark me brainliest

Answer:

86.25%

Step-by-step explanation:

Answer:

50kg de café torrado

30kg de café arábico

Step-by-step explanation:

Queremos obtener un total de 80kg de café molido.

Se utilizarán:

Café arábico, que cuesta $18 el kg

Café torrado, que cuesta $10 el kg

Queremos que el precio, por kilo, de la mezcla de 80kg sea $13.

Ok, primero debemos definir las variables:

Definamos:

x = cantidad de café arábico usado

y = cantidad de café torrado usado.

Entonces, como la mezcla deberá tener 80kg en total, tenemos:

x + y = 80kg

Y el costo total de esta mezcla será:

x*$18 + y*$10

Si lo dividimos por el peso total, tendremos el costo por kilo, que es:

(x*$18 + y*$10)/80kg

Y queremos que esto sea igual a $13, entonces tenemos la ecuación

(x*$18 + y*$10)/80kg = $13

Ok, ahora tenemos dos ecuaciones, es decir, tenemos un sistema de ecuaciones:

x + y = 80kg

(x*$18 + y*$10) = $13*80kg

(donde reescribimos levemente la segunda ecuación)

Ok, para resolver este sistema trataremos de reemplazar variables, para ello, el primer paso es aislar una de las variables en una de las ecuaciones.

Aislemos x en la primera:

x = 80kg - y

Ahora reemplazamos esto en la otra ecuación:

(x*$18 + y*$10) = $13*80kg

(( 80kg - y)*$18 + y*$10) = $13*80kg

Ahora podemos resolver esto para la variable y:

$18*80kg - $18*y + $10*y = $13*80kg

$18*80kg - $13*80kg = $18*y - $10*y

($18 - $13)*80kg = ($18 - $10)*y

$5*80kg = $8*y

($5*80kg)/$8 = y

50kg = y

Se usan 50kg de café torrado.

y como:

x + y = 80kg

x = 80kg - y

x = 80kg - 50kg = 30kg

Entonces los 30kg restantes serán de café arábico.

y la estrategia utilizada fue el remplazo de variables.

Answer:

A

Step-by-step explanation:

Answer:

[tex]2\sqrt{55}\text{ m/s or }\approx 14.8\text{m/s}[/tex]

Step-by-step explanation:

The vertical component of the initial launch can be found using basic trigonometry. In any right triangle, the sine of an angle is equal to its opposite side divided by the hypotenuse. Let the vertical component at launch be [tex]y[/tex]. The magnitude of [tex]40\text{ m/s}[/tex] will be the hypotenuse, and the relevant angle is the angle to the horizontal at launch. Since we're given that the angle of elevation is [tex]60^{\circ}[/tex], we have:

[tex]\sin 60^{\circ}=\frac{y}{40},\\y=40\sin 60^{\circ},\\y=20\sqrt{3}[/tex](Recall that [tex]\sin 60^{\circ}=\frac{\sqrt{3}}{2}[/tex])

Now that we've found the vertical component of the velocity and launch, we can use kinematics equation [tex]v_f^2=v_i^2+2a\Delta y[/tex] to solve this problem, where [tex]v_f/v_i[/tex] is final and initial velocity, respectively, [tex]a[/tex] is acceleration, and [tex]\Delta y[/tex] is distance travelled. The only acceleration is acceleration due to gravity, which is approximately [tex]9.8\:\mathrm{m/s^2}[/tex]. However, since the projectile is moving up and gravity is pulling down, acceleration should be negative, represent the direction of the acceleration.

What we know:

Solving for [tex]v_f[/tex]:

[tex]v_f^2=(20\sqrt{3})^2+2(-9.8)(50),\\v_f^2=1200-980,\\v_f^2=220,\\v_f=\sqrt{220}=\boxed{2\sqrt{55}\text{ m/s}}[/tex]

Answer:

So the prime factorization of 24 is 24 = 2 · 2 · 2 · 3 = 23 · 3. A good way to check the result is to multiply it out and make sure the product is 24.

Step-by-step explanation:

Answer:

θ ≈ 50°, AB ≈ 15.6

Step-by-step explanation:

Using the tangent ratio in the right triangle

tanθ = [tex]\frac{opposite}{adjacent}[/tex] = [tex]\frac{BC}{AC}[/tex] = [tex]\frac{11.9}{10}[/tex] = 1.19 , then

θ = [tex]tan^{-1}[/tex] (1.19 ) ≈ 50° ( to the nearest degree

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Using the cosine ratio in the right triangle

cos50° = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{AC}{AB}[/tex] = [tex]\frac{10}{AB}[/tex] ( multiply both sides by AB )

AB × cos50° = 10 ( divide both sides by cos50° )

AB = [tex]\frac{10}{cos50}[/tex] ≈ 15.6 ( to 1 dec. place )