Find the slope of the line passing through the pair of points or state that the slope is undefined. Then indicate whether the line
through the points rises, falls, is horizontal, or is vertical
(2,9) and (-2,9)

Answer:

Step-by-step explanation:

Hope this helps :)!

Hi there!  

»»————-　★　————-««

I believe your answer is:  

18in³

»»————-　★　————-««  

Here’s why:  

⸻⸻⸻⸻

Assuming that the figure is a rectangular prism:

⸻⸻⸻⸻

[tex]\boxed{\text{Volume of a rectangular prism is:}}\\\\V = l * w * h\\-----------\\V = 2 * 2.25 * 4\\\\\boxed{V = 18}[/tex]

⸻⸻⸻⸻

»»————-　★　————-««  

Hope this helps you. I apologize if it’s incorrect.    

Answer:

7.5 inches wide. I wasnt wrong. for a second i thought it was asking for the width of each individual sneaker.

Answer:

each pair of sneakers are 7.5 inches wide

Answer:

f(x) = 2.25x + 5

Step-by-step explanation:

The cost from the weight in pounds of the box can be represented by 2.25x, since the charge is $2.25 per pound.

The flat fee of $5 can be represented in the function by adding 5 to 2.25x.

Put these together in function notation:

f(x) = 2.25x + 5

So, the equation is f(x) = 2.25x + 5

Answer:

Hypothenus = 22

Step-by-step explanation:

From the question given above, we were told that the triangles are congruent (i.e same size). Thus,

AC = EF

BC = DE

To obtain the length of each Hypothenus, we shall determine the value of y and x. This can be obtained as follow:

For y:

AC = y + 3

EF = 2y + 1

AC = EF

y + 3 = 2y + 1

Collect like terms

3 – 1 = 2y – y

2 = y

y = 2

For x:

BC = 5x + 7

DE = 6x + 2y

y = 2

DE = 6x + 2(2)

DE = 6x + 4

BC = DE

5x + 7 = 6x + 4

Collect like terms

7 – 4 = 6x – 5x

3 = x

x = 3

Finally, we shall determine the length of each Hypothenus. This can be obtained as follow:

Hypothenus = BC

Hypothenus = 5x + 7

x = 3

Hypothenus = 5x + 7

Hypothenus = 5(3) + 7

Hypothenus = 15 + 7

Hypothenus = 22

OR

Hypothenus = DE

DE = 6x + 2y

y = 2

x = 3

Hypothenus = 6(3) + 2(2)

Hypothenus = 18 + 4

Hypothenus = 22

Answer:

dbcjchdiskcnbcksksnnckdkxnn

Answer: maybe 20 % at least because it might me adding

A: 25.

Explanation: Check the attached image.

For synthetic division, you just need to multiply the 1st number of the polynomial by the divisior, and then, add it up to the next number; then, the coefficient will be multiplied by the divisor, and so on and so forth until you reach the last number... that last coefficient at the end is the reminder that you've been asked for

Answer:

Step-by-step explanation:

Answer:

Sin (theta) has the same value for the both value of theta, so both applies.

Answered by GAUTHMATH

Answer:

D. No, the triangles don't share two pairs of congruent angles.

Step-by-step explanation:

Two triangles can only be proven similar from the AA (Angle-Angle) similarity theorem if it can be deduced that they share two congruent angles.

In this case, both triangles share one angle, however no other angles can be deduced to be congruent. Therefore, the triangles cannot be proven similar from the AA similarity theorem because they do not share two pairs of congruent angles (corresponds with answer choice D).

Answer:

D.No, the triangles don't share two pairs of congruent angles.

Step-by-step explanation:

We know that angle M equals angle H  and that angle I equals the unmarked angle.

We do not know that angle N equals angle O so we cannot state that the triangles are similar

Answer:

2, x, 2x

Step-by-step explanation:

A) 2

They are even numbers, so it is going to be 2.

B) x

It is going to only be x because the exponents are even and odd.

C) 2x

It is going to be 2x because the numbers are even but the exponents are even and odd.

Hope this helps.

Answer:

228 feet

Step-by-step explanation:

Since M represents the number of lessons he completes,

sub M=8 into S=26M+20

S=26(8)+20

=228

I think 'D' is the correct answer.

Answer and Explanation:

Odds ratio is the odds that an outcome would happen given a level of exposure in comparison to the occurrence of that outcome without exposure. Odds ratio is calculated by dividing odds of event occurring with exposure(the first group) by odds of event(usually disease) occurring without exposure. Odds is different from probability(denoted p/1-p). While probability is the number of favorable events divided by total number of events, odds is number of favorable events/number of unfavorable events.

Relative risk, also measuring relationship between exposure and outcome, is the ratio of the probability that an outcome would occur without exposure and probability that an outcome would occur with exposure.

Answer:

the next number is going to be46

Answer:

the next number will be 46

Hello!

$52 ..... 800kWh

$x ..... 650kWh

_____________

52/x = 800/650 <=>

<=> 52 × 650 = 800x <=>

<=> 33800 = 800x <=>

<=> 800x = 33800 <=>

<=> x = 33800/800 <=>

<=> x = 338/8 <=>

<=> x = 169/4 <=>

<=> x = 42,25$

Good luck! :)

Answer:

y = -3x - 5

Step-by-step explanation:

First find the slope:  (-20 - 1) / (5 - (-2))  = -3

Then plug in one set of points into the equation y = mx + b.

1 = -3(-2) + b

1 = 6 + b

b = -5

So you can get the equation:  y = -3x - 5

f(x) = 2x² + x - 5

f(-6) = 2(-6)² + (-6) -5

=> f(-6) = 2(36) -11

=> f(-6) = 72 - 11

=> f(-6) = 61

To find S or T add them together:

3/5 + 1/3

Rewrite the fractions to have a common denominator

9/15 + 5/15 = 14/15

Answer: 14/15

Step-by-step explanation:

Here is your answer . Hope it helps.

Answer:

exponential decay

Step-by-step explanation:

The function is in the form

y = ab^x  where a is the initial value and b is the growth or decay rate

If b >1 then it is growth

b < 1 then it is decay

f(x) = 5(2/3)^x

a = 5

b = 2/3

2/3 <1 so it is decay

Answer:

C. 5

Step-by-step explanation:

To find the degree of the polynomial, all you have to do is find the largest degree. (aka the largest lil number above the x)

In this case, it's 5.

Answer:

B. 20 Units

Step-by-step explanation:

unit test review edge 2021

The area of rhombus WXYZ as shown in the diagram given with the given vertices is: 24 units².

Area of a rhombus = pq/2, where p and q are the diagonals of the rhombus.

Find the lengths of diagonals XZ and WY:

XZ = |4 -(-2)| = 6 units

WY = |-3 - 5| = 8 units

Area of rhombus WXYZ = 1/2(XZ × WY) = 1/2(6 × 8)

Area of rhombus WXYZ = 24 units².

Learn more about the area of a rhombus on:

https://brainly.com/question/2456096

#SPJ2

Complete Question

Complete Question is attached below

Answer:

[tex]UCL= 0.25[/tex]

Step-by-step explanation:

From the question we are told that:

Sample size[tex]n=150[/tex]

Sample Variants [tex]s=7[/tex]

Sigma control limits  [tex]Z = 3[/tex]

Therefore

Total number of observations is Given as

[tex]T_o=n*s[/tex]

[tex]T_o=150 *7[/tex]

[tex]T_0=1050[/tex]

Generally

Summation of defectivee

[tex]\sum np=23+34+15+30+25+22+18[/tex]

[tex]\sum np= 167[/tex]

Generally the equation for P-bar is mathematically given by

[tex]P-bar=\frac{\sum np}{T_o}[/tex]

[tex]P-bar=\frac{167}{1050}[/tex]

[tex]P-bar=0.16[/tex]

Therefore

[tex]Sp=\sqrt{\frac{P-bar(1-P-bar)]}{ n}}[/tex]

[tex]Sp=\sqrt{\frac{[0.159(1-0.159)]}{150}}[/tex]

[tex]Sp=0.03[/tex]

Generally the equation for 3-sigma upper control limit of the process is mathematically given by

[tex]UCL = P-bar + Z*Sp[/tex]

[tex]UCL= 0.16 + 3*0.03[/tex]

[tex]UCL= 0.25[/tex]

Answer:

a. [tex]B+S = 1 [/tex]

[tex]0.06B+0.1S \geq 0.075 [/tex]

[tex]B \geq 0.3 [/tex]

Objective function:

[tex]R=0.06B+0.1S[/tex]

b) See Attached picture

30% in bonds and 70% in stocks

Step-by-step explanation:

a.

In order to solve the first part of the problem we need to take into account that the problem wants us to determine the percentage that should be allocated to each of the possible investment alternatives. In that case, the sum of the percentages must be equal to 1 (which means that we will have 100 of the trust fund)

so that gives us our first restriction for the problem.

B+S=1

Next, the problem tells us that the projected returns over the life of the investments are 6% for the bond fund and 10% for the stock fund. It also states that he wants to select a mix that will enable him to obtain a total return of at least 7.5%, so we can take this information and get the second restriction from it:

[tex]0.06B+0.1S \geq 0.075 [/tex]

Next, the problem tells us that whatever portion of the inheritance he finally decides to commit to the trust fund, he wants to invest at least 30% of that amount in the bond fund, so that's where the last restriction comes from:

[tex]B \geq 0.3 [/tex]

now, the idea is to optimize the investment, this is get the greatest amount of money out of the trust fund, so the objective function is:

[tex]R=0.06B+0.1S[/tex]

which represents the return on the investment.

b)

For part b we can start by graphing each of the restrictions:

[tex]B+S = 1 [/tex]

This will be a single line, you can draw the line by setting B=0 first so you get:

0+S=1

S=1

So the first point to plot will be (0,1)

next, we can set s=0 to get:

B+0=1

B=1

so the second point to plot will be (1,0)

so you can plot the two points and connect them with a straight line. This is the green line on the uploaded graph.

Next we can graph the second restriction:

[tex]0.06B+0.1S \geq 0.075 [/tex]

we can use the same procedure we used for the previous graph, in this case the points would be:

(0 , 0.75) and (1.25, 0)

and again connect the two points with a straight line. Next we need to decide which region of the graph to shade for which we can pick two arbitrary points on each side of the line, for example we can pick:

(0,0) and (2,2) and see which one makes the inequality true:

for (0,0) we get:

[tex]0.06B+0.1S \geq 0.075 [/tex]

[tex]0.06(0)+0.1(0) \geq 0.075 [/tex]

[tex]0 \geq 0.075 [/tex]

Which is false, therefore we need to shade the other region of the graph:

for (2,2) we get:

[tex]0.06B+0.1S \geq 0.075 [/tex]

[tex]0.06(2)+0.1(2) \geq 0.075 [/tex]

[tex]0.32 \geq 0.075 [/tex]

Which is true, so we shade the region of the graph that contains that point. (see red graph)

now we graph the third restriction:

[tex]B \geq 0.3 [/tex]

In order to graph this third restriction we just need to draw a vertical line at B=0.3 and shade everything to the right of that line. (Blue graph)

Now, we can analyze the graph, in this case we need to locate the points where the green line crosses the red and the blue line which gives us the following coordinates:

(0.3, 0.7) and (0.625, 0.375)

these two points can be found by setting the first restriction equal to each of the other two restrictions if you are to do it algebraically. If you are using a graphing device, you can directly read them from the graphs.

So once we got those points, we can see which one gives us the greatest percentage of return.

let's test the first point (0.3, 0.7)

[tex]R=0.06B+0.1S[/tex]

[tex]R=0.06(0.3)+0.1(0.7)[/tex]

R=0.088

so this distribution gives us 8.8% in return, let's test the second point:

(0.625, 0.375)

[tex]R=0.06B+0.1S[/tex]

[tex]R=0.06(0.625)+0.1(0.375)[/tex]

R=0.075

so this distribution gives us 7.5% in return.

In this case the best distribution for us is 30% in bonds and 70% in the stock fund to get a return of 8.8%

Answer:

Rate of slower bus; 90 km/h

Rate of faster bus; 102 km/b

Step-by-step explanation:

We know that formula do distance is;

Distance = speed/time

We are told that One bus travels 12h slower than the other.

Let speed of slower bus be x.

Thus;

Speed of faster bus = x + 12

Speed of slower bus = x

After 3 hours, distance by faster bus = 3(x + 12)

Speed of slower bus = 3x

Since the towns are 576 km apart, then;

3(x + 12) + 3x = 576

Divide through by 3 to get;

x + 12 + x = 192

2x + 12 = 192

2x = 192 - 12

2x = 180

x = 180/2

x = 90 km/h

Faster bus speed = 90 + 12 = 102 km/h

Answer:

These asymptotes are very important characteristics of the function just like holes. Both holes and vertical asymptotes occur at x values that make the denominator of the function zero.

Answer:

x(12y+4)

2 0 l e t t e r s

Answer:

0.0064

0.00032

Step-by-step explanation:

Given the details:

P(X > 3), n = 5, p = 0.2

The binomial distribution is related using the formula:

P(x = x) = nCx * p^x * q^(n-x)

q = 1 - p = 1 - 0.2 = 0.8

P(X > 3) = p(x = 4) + p(x = 5)

P(x = 4) = 5C4 * 0.2^4 * 0.8^1 = 5 * 0.2^4 * 0.8^1 = 0.0064

P(x = 5) = 5C5 * 0.2^5 * 0.8^0 = 1 * 0.2^5 * 0.8^0 = 0.00032