Answer:
696.8 mm^2
Step-by-step explanation:
Does this make sense?
The surface area of figure is 696.8[tex]mm^{2}[/tex].
To understand more, check below explanation.
Surface area of figure:The given figure is combination of a triangular shape and cuboid.
We have to find surface area of given figure.
The surface area of combined figure is summation of area of four triangle and area of cuboid excluding top of cuboid.
The base of triangle = 13mm
Height of triangle = 10.3 mm
Area of 4 triangle [tex]=4*\frac{1}{2}*13*10.3=267.8mm^{2}[/tex]
Surface area of cuboid excluding top is computed as,
Area = (2*13*5) + (2*13*5) + (13 * 13)
Area = 130 + 130 + 169 = 429 square millimeters.
Hence, surface area of figure = 267.8 + 429 = 696.8[tex]mm^{2}[/tex]
Learn more about the surface area here:
https://brainly.com/question/76387
Somebody know how to do this?
Answer:
x=1
Step-by-step explanation:
55+70=125
sum of angles in a triangle is 180 so
180-125=55
54x+1=55
x=1
Solve for x. 2x + 3 =9
Answer:
x=3
Step-by-step explanation:
- 3 on both sides
2x=6
divide by 2 on both sides
x=3
Answer:
x = 3
Step-by-step explanation:
[tex]2x+3=9[/tex]
Subtract 3.
[tex]2x=9-3\\2x=6[/tex]
Divide by 2.
[tex]x=\frac{6}{2}\\ x=3[/tex]
Compare the ordered pairs of the pre-image to the
image to answer these questions.
Is the dilation an enlargement or reduction?
The point of dilation is about what coordinate?
What is the scale factor?
Pre-image
Answer: Reduction
(0,0)
1/3
Step-by-step explanation:
Answer:
1-reduction
2-(0,0)
3-1/3
Step-by-step explanation:
Secant TQ and tangent TR intersect at point T. Chord SR and chord PQ intersect at point V. Find the values of x and y. If necessary, round to the nearest tenth.
Answer:
x=4, y=9.6
Step-by-step explanation:
Using Theorem of Intersecting Secant and Tangent
[tex]TP X TQ=TR^2[/tex]
[tex]9(9+12+x)=15^2\\9(21+x)=225\\189+9x=225\\9x=225-189\\9x=36\\x=4[/tex]
Next, we apply Theorem of Intersecting Chords
SV X VR=PV X VQ
5 X y = x X 12
Recall: x=4
5y=4 X 12
5y=48
y=48/5=9.6
Therefore: x=4, y=9.6
Jamal and Cleo mow lawns together, Jamal can mow an average lawn in 60 minutes by
himself. Cleo would take 90 minutes for the same job. How long would it take both of
them together to mow one (1) lawn
Which point on the number line best represents
V10?
3.0 3.1 3.2 3.3 3.4 3.5 3.6 3.7 3.8 3.9 4.0
tohoto
E F G H
F
G
E
H
Answer: The answer is F
Step-by-step explanation:
Someone is visiting a wildlife center to gather information for their term paper. The center has a circular pin with a diameter of 20 meters. What is the approximate area of the pond?
Answer:
300 meters^2
Step-by-step explanation:
10 meters radius
10^2 x pi is about 100 x 3=300
Find the volume of the figure
Answer:
450
Step-by-step explanation:
Which expression is equivalent to (4 + 7(3 + 41)?
-16+37i
12-28i
16-37i
37+16i
Answer:
C
Step-by-step explanation:
I have 8 red Valentine card and 2 pink. How many reds and pinks would I need to add to my collection so that the proportion of pink is 44%?
Answer:
88%
Step-by-step explanation:
how much money does ron have each month
Answer:
after paying all expenses Ron will have $10 leftover each month.
Answer:
10 on edge
Step-by-step explanation:
1. If 5tanA=4, Find the value of (5sinA-3cosA)/(4cosA+5sinA)
2. Solve for θ, sinθ/(1+cosθ) + (1+cosθ)/sinθ =4, 0°<θ<90°
3. Prove that tan〖θ-cotθ 〗 = (〖2sin〗^2 θ-1)/sinθcosθ
4. Without using trigonometric tables ,show that
tan 10°tan15°tan75°tan80°=1
5. If x=acosθ-bsinθ and y=asinθ + bcosθ prove that x^2+y^2=a^2+b^2
Answer:
1. (5·sin(A) - 3·cos(A)/(4·cos(A) + 5·sin(A)) = 1/8
2. θ = 30°
3. tan(θ) - cot(θ) = (2·sin²(θ) -1)/((cos(θ)×sin(θ))
from tan(θ) - 1/tan(θ) = sin(θ)/cos(θ) - cos(θ)/sin(θ) and sin²(θ) + cos²(θ) = 1
4. tan10°·tan15°·tan75°·tan80°= 1 from;
sin(α)·sin(β) = 1/2[cos(α - β) - cos(α + β)]
cos(α)·cos(β) = 1/2[cos(α - β) + cos(α + β)]
5. x² + y² = a² + b² where x = a·cosθ - b·sinθ and y = a·sinθ + b·cosθ from;
cos²θ + sin²θ = 1
Step-by-step explanation:
1. Here we have 5·tan(A) = 5·sin(A)/cos(A) = 4
∴ 5·sin(A) = 4·cos(A)
Hence to find the value of (5·sin(A) - 3·cos(A)/(4·cos(A) + 5·sin(A)) we have;
Substituting the value for 5·sin(A) = 4·cos(A) into the above equation in both the numerator and denominator we have;
(4·cos(A) - 3·cos(A)/(4·cos(A) + 4·cos(A)) = cos(A)/(8·cos(A)) = 1/8
Therefore, (5·sin(A) - 3·cos(A)/(4·cos(A) + 5·sin(A)) = 1/8
2. For the equation as follows, we have
[tex]\frac{sin \theta}{1 + cos \theta} + \frac{1 + cos \theta}{sin \theta} = 4[/tex] this gives
[tex]\frac{2sin (\theta/2) cos (\theta/2) }{2 cos^2 (\theta/2)} + \frac{2 cos^2 (\theta/2)}{2sin (\theta/2) cos (\theta/2) } = 4[/tex]
[tex]tan\frac{\theta}{2} + \frac{1}{tan\frac{\theta}{2} } = 4[/tex]
[tex]tan^2\frac{\theta}{2} + 1 = 4\times tan\frac{\theta}{2}[/tex]
[tex]tan^2\frac{\theta}{2} - 4\cdot tan\frac{\theta}{2} + 1 = 0[/tex]
We place;
[tex]tan\frac{\theta}{2} = x[/tex]
∴ x² - 4·x + 1 = 0
Factorizing we have
(x - (2 - √3))·(x - (2 + √3))
Therefore, tan(θ/2) = (2 - √3) or (2 + √3)
Solving, we have;
θ/2 = tan⁻¹(2 - √3) or tan⁻¹(2 + √3)
Which gives, θ/2 = 15° or 75°
Hence, θ = 30° or 150°
Since 0° < θ < 90°, therefore, θ = 30°
3. We have tan(θ) - cot(θ) = tan(θ) - 1/tan(θ)
Hence, tan(θ) - 1/tan(θ) = sin(θ)/cos(θ) - cos(θ)/sin(θ)
∴ tan(θ) - 1/tan(θ) = (sin²(θ) - cos²(θ))/(cos(θ)×sin(θ))...........(1)
From sin²(θ) + cos²(θ) = 1, we have;
cos²(θ) = 1 - sin²(θ), substituting the value of sin²(θ) in the equation (1) above, we have;
(sin²(θ) - (1 - sin²(θ)))/(cos(θ)×sin(θ)) = (2·sin²(θ) -1)/((cos(θ)×sin(θ))
Therefore;
tan(θ) - cot(θ) = (2·sin²(θ) -1)/((cos(θ)×sin(θ))
4. tan10°·tan15°·tan75°·tan80°= 1
Here we have since;
sin(α)·sin(β) = 1/2[cos(α - β) - cos(α + β)]
cos(α)·cos(β) = 1/2[cos(α - β) + cos(α + β)]
Then;
tan 10°·tan15°·tan75°·tan80° = tan 10°·tan80°·tan15°·tan75°
tan 10°·tan80°·tan15°·tan75° = [tex]\frac{sin(10^{\circ})}{cos(10^{\circ})} \times \frac{sin(80^{\circ})}{cos(80^{\circ})} \times \frac{sin(15^{\circ})}{cos(15^{\circ})} \times \frac{sin(75^{\circ})}{cos(75^{\circ})}[/tex]
Which gives;
[tex]\frac{sin(10^{\circ}) \cdot sin(80^{\circ})}{cos(10^{\circ})\cdot cos(80^{\circ})} \times \frac{sin(15^{\circ}) \cdot sin(75^{\circ})}{cos(15^{\circ})\cdot cos(75^{\circ})}[/tex]
[tex]=\frac{1/2[cos(80 - 10) - cos(80 + 10)]}{1/2[cos(80 - 10) + cos(80 + 10)]} \times \frac{1/2[cos(75 - 15) - cos(75 + 15)]}{1/2[cos(75 - 15) + cos(75 + 15)]}[/tex]
[tex]=\frac{1/2[cos(70) - cos(90)]}{1/2[cos(70) + cos(90)]} \times \frac{1/2[cos(60) - cos(90)]}{1/2[cos(60) + cos(90)]}[/tex]
[tex]=\frac{[cos(70)]}{[cos(70) ]} \times \frac{[cos(60)]}{[cos(60) ]} =1[/tex]
5. If x = a·cosθ - b·sinθ and y = a·sinθ + b·cosθ
∴ x² + y² = (a·cosθ - b·sinθ)² + (a·sinθ + b·cosθ)²
= a²·cos²θ - 2·a·cosθ·b·sinθ +b²·sin²θ + a²·sin²θ + 2·a·sinθ·b·cosθ + b²·cos²θ
= a²·cos²θ + b²·sin²θ + a²·sin²θ + b²·cos²θ
= a²·cos²θ + b²·cos²θ + b²·sin²θ + a²·sin²θ
= (a² + b²)·cos²θ + (a² + b²)·sin²θ
= (a² + b²)·(cos²θ + sin²θ) since cos²θ + sin²θ = 1, we have
= (a² + b²)×1 = a² + b²
PLZ HELP I ONLY HAVE 11 points left and I need help with this question plz :( It's URGENT
Answer:
16 units
Step-by-step explanation:
The y intercept is when the x value is 0
f(0) = 2(0)+8 = 8
The y intercept of f(x) is 8
g(0) = -8
The y intercept of g(x) is -8
The distance between f(0) and g(0)
8 - -8 = 8+8 = 16
What is the range for the number of cars, new and used, that were sold from July to December?
Answer:
75
Step-by-step explanation:
87-12= 75
edg2020
How do I solve this problem? I need to find the volume of this composite figure.
Step-by-step explanation:
V = (12*4*5) + (2*3*5) + (5*3*5) + (12*4*5)
V = 240 + 30 + 75 + 240
V = 585 cm^3
Which expressions are equivalent to g+h+(j+k) Check all that apply
Answer:
g+h+(j+k)
Step-by-step explanation:
(g+h)+j+k
(g+k)+j+h
(g+j)+h+k
(k+h)+j+h
(j+h)+g+k
Answer:
1 and 3
Step-by-step explanation:
dont mind me this needed to be longer wait still needs no be longer
mean median and mode of 14, 10, 12, 15, and 13
Answer:
mean= 12.8
median=13
mode=there is no mode
Step-by-step explanation:
mean/average=14+10+12+15+ 13=64/5=12.8
median=10,12,13,14,15=13
mode= is the number that repeats more often. = there is no mode
Margo can purchase tile at a store for $0.89 per tile and rent a tile saw for $45. At another store she can borrow the tile saw for free if she buys tiles there for $1.39 per tile. How many tiles must she buy for the cost to be the same at both stores?
Margo must buy ____ tiles for the cost to be the same at both stores.
Answer:
She must buy 90 tiles for the cost to be the same at both stores
Step-by-step explanation:
Let x be the no. of tiles bought for the cost to be the same at both stores
Margo can purchase tile at a store for $0.89 per tile at shop 1
Cost of x tiles =0.89x
She rent a tile saw for $45.
So, total cost at Store 1 = 0.89x+45
At another store she can borrow the tile saw for free if she buys tiles there for $1.39 per tile.
So, cost of 1 tile = 1.39
Cost of x tiles = 1.39x
ATQ
0.89x+45=1.39x
45=1.39x-0.89x
45=0.5x
[tex]\frac{45}{0.5}=x[/tex]
90=x
Hence She must buy 90 tiles for the cost to be the same at both stores
Divya’s recipe calls for 3.25 pounds of beef, 0.65 pounds of onions, 0.2
pounds of potatoes, 0.15 pounds of tomatoes, and 0.33 pounds of asparagus.
How much will Divya pay for all the ingredients in the recipe? Show your work.
The beef price is $10.65
Onions price is $2.49
Potatoes are $3.29
Tomatoes are $8.45
Asparagus is $4.99
3.25 pounds of beef is 3.25 * 10.65 = 34.61
0.65 pounds of onions is 0.65 * 2.49 = 1.62
0.2 pounds of potatoes is 0.2 * 3.29 = 0.66
0.15 pounds of tomatoes is 0.15 * 8.45 = 1.27
0.33 pounds of asparagus is 0.33 * 4.99 = 1.65
Adding these up we get 34.61 + 1.62 + 0.66 + 1.27 + 1.65
This is equal to 39.81
A recipe is mixture of ingredients.
Divya will pay $39.81 for all the ingredients in the recipe.
The beef price is $10.65 per pound
So, price of 3.25 pounds of beef is , [tex]3.25 * 10.65 = 34.61[/tex]
Onions price is $2.49 per pound
So, price of 0.65 pounds of onions is, [tex]0.65 * 2.49 = 1.62[/tex]
Potatoes are $3.29 per pound
So, price of 0.2 pounds of potatoes is , [tex]0.2 * 3.29 = 0.66[/tex]
Tomatoes price are $8.45 per pound.
So, price of 0.15 pounds of tomatoes is , [tex]0.15 * 8.45 = 1.27[/tex]
Asparagus price is $4.99 per pound.
So, price 0.33 pounds of asparagus is , [tex]0.33 * 4.99 = 1.65[/tex]
Hence, total amount paid by Divya is,
[tex]=34.61 + 1.62 + 0.66 + 1.27 + 1.65=39.81[/tex]
Thus, Divya will pay $39.81 for all the ingredients in the recipe.
Learn more:
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Find the surface area of the cylinder with a height of 4 and a radius of 9
Answer:
735.13268 units^2
Step-by-step explanation:
A=2πrh+2πr2=2·π·9·4+2·π·92≈735.13268
I am donating packages for Christmas drive. After the first week, I spent 126 to donate three children packages and 8 adult packages. After two weeks I spent 108 to donate six children packages and 4 adult packages. What is the price of each type of package
Answer:
Step-by-step explanation:
Let the price for children and adults package be represented with x and y respectively.
For the first week the sum of the package will be as follows:
3x+8y = 126
For the two weeks after:
6x+4y= 108
So, we will be having two equations
3x+8y = 126..... (1)
6x+4y= 108.......(2)
These are simultaneous equations
From equation 1
3x+8y = 126
3x = 126-8y
X = 126-8y/3 ............. (3)
Put equation 3 into 2
6 ( 126-8y)/3 +4y = 108
756-48y/3 +4y = 108
756-48y+12y/3 = 108
Cross multiplying
756-48y+12y= 108×3
756-48y+ 12y = 324
Collecting like terms
756-324 = 48y-12y
432= 36y
Divide both sides by 36
432/36 = 36y/36
y= 12
Substituting y into equation 1
3x+8= 126
3x+96=126
3x= 126-96
3x= 30
Divide both sides by 3
3x/3 = 30/3
x = 10
Hence for each of the packages for children and adults. It will be 10 and 12 respectively.
The leaning Tower of Pisa was completed in 1372 and makes 86 degree angle with the ground. The tower is 50 meters tall, measured vertically from the ground to the highest point. If you were to climb to the top then accidentally drop your keys, where would you start looking for them?
How far from the base of the tower would they land?
I made having no luck in figuring this out.
Answer:
The distance where the keys would drop from the base is 3.5m
Step-by-step explanation:
Height of the tower = 50m
Angle it makes to the ground = 86°
To solve this question, you have to understand that the tower isn't vertically upright and the height of the tower is different from the distance from the top of the tower to the ground.
The tower makes an angle 86° to the ground and that makes it not vertically straight because a vertically straight building is at 90° to the ground.
See attached document for better illustration.
The distance from where the keys drop to the base of the tower can be calculated using SOHCAHTOA
We have to use cosθ = adjacent / hypothenus
θ = 86°
Adjacent = ? = x
Hypothenus = 50m
Cos θ = x / hyp
Cos 86 = x / 50
X = 50 × cos 86
X = 50 × 0.06976
X = 3.488 = 3.5m
The distance where the keys would drop from the base of the tower is approximately 3.5m
what is a=1/4 b if b is the subject?
Answer:
b = 4a
Step-by-step explanation:
Given
a = [tex]\frac{1}{4}[/tex] b
Multiply both sides by 4 to clear the fraction
4a = b
Please help me now I will mark you brainliest
Answer:
Out side the circle
Step-by-step explanation:
This is because the center is 0 and if the point 6, square root seven is on the circle that mean that as far as the circle goes on each side.
solve the equation 18=n-18
n=_____
Answer:
36
Step-by-step explanation:
Find the surface area of the prism. Write your answer as a fraction or mixed number.
Answer:
The surface area of the prism is 8/3ft²
Step-by-step explanation:
To calculate the surface area of the prism we have to use the following formula:
a = area
w = side = 2/3 ft
h = height = 2/3 ft
l = length = 2/3 ft
a = 2 * (w * h) + 2 * (w * l) + 2 * (h * l)
we replace the values that we know
v = 2 * (2/3 ft * 2/3 ft) + 2 * (2/3 ft * 2/3 ft) + 2 * (2/3 ft * 2/3 ft)
v = 2 * 4/9ft² + 2 * 4/9ft² + 2 * 4/9ft²
v = 8/9ft² + 8/9ft² + 8/9ft²
v = 24/9ft²
v = 8/3ft²
The surface area of the prism is 8/3ft²
Answer:
2⅔ ft²
Step-by-step explanation:
A cube has 6 square faces
6 × (⅔)²
6 × 4/9
8/3
2⅔
If the product of two whole numbers is zero then one number will be (ii) If the product of two whole numbers is zero then both number will be zero (a) OnlyIcanbetrue(b)onlyiicanbetrue(c)Bothcanbetrue(d)botharefalse
Answer:
If the product of two numbers is zero, there are two possibilities, namely;
1. One of the numbers is zero.
2. Both of the numbers are zero.
Step-by-step explanation:
As a rule in mathematics, when zero is used in multiplying any given whole number, the only result that would be obtained is zero.
Therefore,
1. If one of the numbers is zero, then the product of the two numbers is also zero. For example,
153, 000 * 0 = 0
2. If both of the numbers are zero, then the product of the two numbers is zero. For example,
0 * 0 = 0.
So we can say that both can be true.
Need help ASAP, marking first as brainliest. Rlly appreciate it.
Answer:
Choose answers B and D
Step-by-step explanation:
Answer:
Choose answers B and D.
Step-by-step explanation:
A box in the shape of a rectangular prism has a length of 3 inches, a width of 2, inches,
and a height of 4 inches. What is the volume of the box?
Answer:
24
Step-by-step explanation:
What is the distance between points A(13, 2) and B(7, 10)
Answer:
distance = sqrt((x2-x1)^2 + (y2-y1))
distance = sqrt((7-13)^2 + (10-2)^2)
distance = sqrt( -6^2 + 8^2)
distance = sqrt(36+64)
distance = 10
Step-by-step explanation:
Answer:
10 units
Step-by-step explanation:
d = [tex]\sqrt{(x2 - x1)^2 + (y2 - y1)^2}[/tex]
d = [tex]\sqrt{(13 - 7)^2 + (2 - 10)^2}[/tex]
d = [tex]\sqrt{(6)^2 + (-8)^2}[/tex]
d = [tex]\sqrt{36 + 64}[/tex]
d = [tex]\sqrt{100}[/tex]
d = 10 units