Find the TWO integers whos product is -12 and whose sum is 1
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Answer:

w > -16

Step-by-step explanation:

Answer:

25

Step-by-step explanation:

you would do the total which is 45-20

Answer:

3/2

Step-by-step explanation:

formula k = y/x

comes from

y = kx

k = constant of variation

when y = 3 , x = 2

k = 3/2

Answer:

the first row in the table has x = -2 and f(x) = 1

therefore,

f(-2) = 1

f(x) = -2

when x = 4 as in 3rd row.

Answer:

The one of (L,b)= (5m, 10m) is the only correct answer.

Step-by-step explanation:

P= 2(L+b)

A= L×b

make b subject of formula in area we have;

b= A/L

in perimeter; p= 2(L +(A/L))

p= (L²+A)/L

pL= L²+A

L²-pL+A= 0

L²-30L+50=0

L²-25L-5L+50=0

L(L-25)-5(L-25)=0

(L-5)(L-25)= 0

L= 5 or 25m

substitute in A

50= 5b or 50= 25b

b= 10 or 2m

Answer:

I'm pretty sure the answers are options D , E and F .

Step-by-step explanation:

So here's how I did it , I got the original expression , solved it and the answer I found is -6.5. So then I solved all the others and D , E and F gave me -6.5.

Hope this helps lol

Answer:

sinA = ± [tex]\sqrt{1-cos^2A}[/tex]

Step-by-step explanation:

Using the Pythagorean identity

sin²A + cos²A = 1 ( subtract cos²A from both sides )

sin²A = 1 - cos²A ( take the square root of both sides )

sinA = ± [tex]\sqrt{1-cos^2A}[/tex]

Answer:

a

Step-by-step explanation:

thats not how u find the lengths

Answer:

33 units

Step-by-step explanation:

AB = BC

2x + 7 = 23

2x = 16

x = 8

DC = DA

DC = 4x + 1

DC = 4(8) + 1

DC = 33

Answer:

0.2 = n

Step-by-step explanation:

Since we want to express 3:15 as n:1, we can say that they are equal ratios, so

3:15 = n:1. Next, ratios can be written as fractions, so 3/15 = n/1 .

3/15 = n/1

Since anything divided by 1 equals itself, we can write this as

3/15 = n

0.2 = n

9514 1404 393

Answer:

  350, 5, 2668, 4

Step-by-step explanation:

a) mcm(35, 50) = 35·50/mcd(35, 50) = 35·50/5 = 350

__

b) mcd(35, 50) = 5

  35 = 5·7; 50 = 5·10

__

c) mcm(116, 92) = 116·92/mcd(116, 92) = 116·92/4 = 2668

__

d) mcd(116, 92) = 4

  116 = 4·29, 92 = 4·23

Answer:

(B) 30

Step-by-step explanation:

Imagine you drew a line from Point T until it touched Line PR. Let's call that point where it touched Line PR "Point Z".

That line (called Line TZ) would be perpendicular to PR, forming a 90 degree angle.

Now, TZW is a triangle.

To find x, we need to find the angle measurment of Angle ZTW.

This is where we use the hexagon.

A hexagon's interior angle sum is 720, meaning each interior angle is equal to 120 degrees. So Angle UTS would equal 120 degrees.

However, Line TZ bisects that 120 degree angle, so Angle ZTW would equal 60 degrees (because 120/2 = 60).

Now we have two angles of the triangle: 90 & 60.

A triangle's interior angle sum is 180.

Add 90 & 60, which is 150, and subtract 150 from 180.

The result is 30, which is the angle measurement of x.

Hope it helps (●'◡'●)

[tex]\displaystyle\ y^4 +5y^2+9=(y^2+3)^2-y^2=(y^2-y+3)(y^2+y+3)[/tex]

Answer:

Solution given;

[tex] y^{4}+5y²+9[/tex]

keeping [tex]y^{4} and 9 together [/tex]

[tex]y^{4}+9+5y²[/tex]

[tex](y²)²+3²+5y²[/tex].....[I]

we have

a²+b²=(a+b)²-2ab

or

a²+b²=(a-b)²+2ab

same like that

[tex](y²)²+3²=(y²+3)²-6y² or (y²-3)²+6y²[/tex]

remember that while adding or subtracting the left term 5y² either adding 6y²or subtracting 6y²

should make the term perfect square

while subtracting it makes perfect square

so

we take

(y²)²+3²=(y²+3)²-6y²

again

substituting value of

(y²)²+3² in equation 1 and it becomes

(y²+3)²-6y²+5y²

solve like terms

(y²+3)²-y²

again

we have

a²-b²=(a+b)(a-b)

by using this.

(y²+3+y)(y²+3-y)

rearrange it

(y²+y+3)(y²-y+3) is a required factorisation form.

Answer:

10 square meters will have a standard deviation of 1.897.

Step-by-step explanation:

Standard deviation for n instances of a variable:

If the standard deviation for one instance of a variable is [tex]\sigma[/tex], for n instances of the variable, the standard deviation will be of [tex]s = \sigma\sqrt{n}[/tex]

The standard deviation of the number of flaws per square yard is 0.6

This means that [tex]\sigma = 0.6[/tex]

For the 10 square yards will a standard deviation of

[tex]n = 10[/tex], so:

[tex]s = \sigma\sqrt{n} = 0.6\sqrt{10} = 1.897[/tex]

10 square meters will have a standard deviation of 1.897.

this was incorrect.

im sorry :(

Answer:

35

Step-by-step explanation:

We know that the numbers have to be in ascending order. If, for example, the first digit is 0, and second digit is 1, then we would have 5 other numbers in the ones place that would be larger. If the second digit is 2, then would would have 4 other numbers that would be larger, and so on. So if 0 is the first digit, then we would have 5+4+3+2+1=15 combinations. If 1 is the first digit, then we would have 4+3+2+1 combinations. Eventually, we would get 35.

Answer: D

Step-by-step explanation:

360° - 90° - 90° - 108° = 72°

(Sum of angles in a quadrilateral = 360°)

This triangle is an isosceles triangle because it has two congruent sides. Therefore, the two bottom angles are also congruent. And, the sum of the interior angles of a triangle is 180 degrees.

180 = 104 + (9x - 25) + (9x - 25)

180 = 104 + 18x - 50

180 = 54 + 18x

126 = 18x

x = 7

Hope this helps!

⟶ 2³ × 3² is the prime factorization for which one of these choices?

Let's check,

1) 6 = 3 × 2 [So, obviously not this choice]

2) 25 = 5 × 5 = 5² [Not this either]

3) 36 = 3 × 2 × 2 × 3 = 3² × 2² [Doesn't match with 2³ × 3²]

4) 72 = 2 × 2 × 2 × 3 × 3 = 2³ × 3² [Matches]

⟶ The answer is, choice 72.

[tex]\underbrace{ \overbrace{ \mathfrak{Carry \: On \: Learning}}}[/tex]

Answer:

x=44°..

Step-by-step explanation:

Answer:

the value of x is 44 i hope it will help you

Answer:

Step-by-step explanation:

If a point (x, y) is translated by 4 units horizontally right and 1 unit upwards, coordinates of the image point will be,

(x, y) → (x + 4. y + 1)

Therefore, vertices of the image triangle ABC will be,

A(2, 2) → A'(2+4, 2+1)

           → A'(6, 3)

B(5, -1) → B'(5+4, -1+1)

           → B'(9, 0)

C(1, -2) → C'(1+4, -2+1)

           → C'(5, -1)

Then reflected across y-axis.

Rule for the reflection across y-axis will be,

(x, y) → (-x, y)

A'(6, 3) → A"(-6, 3)

B'(9, 0) → B"(-9, 0)

C'(5, -1) → C"(-5, -1)

Answer:

A"(-6, 3)

B"(-9, 0)

C"(-5, -1)

Step-by-step explanation:

Answer:

y=43x-210

Step-by-step explanation:

Distribute 43

then add five on each side

you get y=43x-210, 43 and 210 cannot be sipilified so that is the answer.

Answer:

y=43x-210

Step-by-step explanation:

Distribute 43 through the parenthesis.

y-5=43x-215

Move the constant to the right and change its sign.

y=43x-215+5

Calculate sum.

y=43x-210

Hope i helped :)

Answer:

so the correct asnwer is c

Answer:

Step-by-step explanation:

9.75 ft is the answer

[tex]By \: Pythagoras \: Theorem, \\ \boxed{ {hyotenuse}^{2} = {base}^{2} + {height}^{2} } \\ \\ here \\ hypotenuse = 12ft \\ base = 7 ft\\ height = x\ \\ \\ \ {12}^{2} = {7}^{2} + {x}^{2} \\ \implies144 = 49 + {x}^{2} \\ \implies {x}^{2} = 144 - 49 \\ =95 \\ x = \sqrt{95 } \\ = 9.75 ft\\ \\ \\ [/tex]

Answer:

V=1/3(pi)*r^2*h

Step-by-step explanation:

Think about a cylinder. If you combine 3 cones, you get a cylinder. Find the volume of a cylinder

Answer:

Step-by-step explanation:

V = 1/3 r^2 * π * h

3V = r^2 *π * h

3V/π = r^2 * h

h = 3V/(r^2 * π)

Answer:

20 minutes on the stationary bike

10 minutes on the treadmill

Step-by-step explanation:

x = minutes on bike

y = minutes on treadmill

x + y = 30

12x + 15y = 390

x = 30-y

12(30-y) + 15y = 390

360 - 12y + 15y = 390

3y = 30

y = 10

x + 10 = 30

x = 20

Answer:

[tex]T' = (-7,10)[/tex]

Step-by-step explanation:

Given

[tex]T = (10,7)[/tex]

[tex]r = 270^o[/tex] counterclockwise

Required

Graph of T'

The rule to this is:

[tex](x,y) \to (-y,x)[/tex]

So, we have:

[tex]T(10,7) \to T' (-7,10)[/tex]

Hence:

[tex]T' = (-7,10)[/tex]

See attachment for graph

Answer:

Step-by-step explanation:

From the given trapezium, the following can be observed:

           i. trapezium ABCD

           ii. AB || DC

           iii. EF || AB

           iv. EF || DC

Let AD ≅ BC, then:

AD = AE + ED

BC = BF + FC

So that with the condition that;

AE ≅ BF

and

ED ≅ CF

So then;

AE:ED ≅ BF:FC

Which implies that;

[tex]\frac{AE}{ED}[/tex] = [tex]\frac{BF}{FC}[/tex]