Find the values of the sine, cosine, and tangent for ZA C A 36ft B
24ft
Answers
Find the values of the sine, cosine, and tangent for ∠A
a. sin A = [tex]\frac{\sqrt{13} }{2}[/tex], cos A = [tex]\frac{\sqrt{13} }{3}[/tex], tan A = [tex]\frac{2 }{3}[/tex]
b. sin A = [tex]3\frac{\sqrt{13} }{13}[/tex], cos A = [tex]2\frac{\sqrt{13} }{13}[/tex], tan A = [tex]\frac{3}{2}[/tex]
c. sin A = [tex]\frac{\sqrt{13} }{3}[/tex], cos A = [tex]\frac{\sqrt{13} }{2}[/tex], tan A = [tex]\frac{3}{2}[/tex]
d. sin A = [tex]2\frac{\sqrt{13} }{13}[/tex], cos A = [tex]3\frac{\sqrt{13} }{13}[/tex], tan A = [tex]\frac{2 }{3}[/tex]
Answer:d. sin A = [tex]2\frac{\sqrt{13} }{13}[/tex], cos A = [tex]3\frac{\sqrt{13} }{13}[/tex], tan A = [tex]\frac{2 }{3}[/tex]
Step-by-step explanation:The triangle for the question has been attached to this response.
As shown in the triangle;
AC = 36ft
BC = 24ft
ACB = 90°
To calculate the values of the sine, cosine, and tangent of ∠A;
i. First calculate the value of the missing side AB.
Using Pythagoras' theorem;
⇒ (AB)² = (AC)² + (BC)²
Substitute the values of AC and BC
⇒ (AB)² = (36)² + (24)²
Solve for AB
⇒ (AB)² = 1296 + 576
⇒ (AB)² = 1872
⇒ AB = [tex]\sqrt{1872}[/tex]
⇒ AB = [tex]12\sqrt{13}[/tex] ft
From the values of the sides, it can be noted that the side AB is the hypotenuse of the triangle since that is the longest side with a value of [tex]12\sqrt{13}[/tex] ft (43.27ft).
ii. Calculate the sine of ∠A (i.e sin A)
The sine of an angle (Ф) in a triangle is given by the ratio of the opposite side to that angle to the hypotenuse side of the triangle. i.e
sin Ф = [tex]\frac{opposite}{hypotenuse}[/tex] -------------(i)
In this case,
Ф = A
opposite = 24ft (This is the opposite side to angle A)
hypotenuse = [tex]12\sqrt{13}[/tex] ft (This is the longest side of the triangle)
Substitute these values into equation (i) as follows;
sin A = [tex]\frac{24}{12\sqrt{13} }[/tex]
sin A = [tex]\frac{2}{\sqrt{13}}[/tex]
Rationalize the result by multiplying both the numerator and denominator by [tex]\sqrt{13}[/tex]
sin A = [tex]\frac{2}{\sqrt{13}} * \frac{\sqrt{13} }{\sqrt{13} }[/tex]
sin A = [tex]\frac{2\sqrt{13} }{13}[/tex]
iii. Calculate the cosine of ∠A (i.e cos A)
The cosine of an angle (Ф) in a triangle is given by the ratio of the adjacent side to that angle to the hypotenuse side of the triangle. i.e
cos Ф = [tex]\frac{adjacent}{hypotenuse}[/tex] -------------(ii)
In this case,
Ф = A
adjacent = 36ft (This is the adjecent side to angle A)
hypotenuse = [tex]12\sqrt{13}[/tex] ft (This is the longest side of the triangle)
Substitute these values into equation (ii) as follows;
cos A = [tex]\frac{36}{12\sqrt{13} }[/tex]
cos A = [tex]\frac{3}{\sqrt{13}}[/tex]
Rationalize the result by multiplying both the numerator and denominator by [tex]\sqrt{13}[/tex]
cos A = [tex]\frac{3}{\sqrt{13}} * \frac{\sqrt{13} }{\sqrt{13} }[/tex]
cos A = [tex]\frac{3\sqrt{13} }{13}[/tex]
iii. Calculate the tangent of ∠A (i.e tan A)
The cosine of an angle (Ф) in a triangle is given by the ratio of the opposite side to that angle to the adjacent side of the triangle. i.e
tan Ф = [tex]\frac{opposite}{adjacent}[/tex] -------------(iii)
In this case,
Ф = A
opposite = 24 ft (This is the opposite side to angle A)
adjacent = 36 ft (This is the adjacent side to angle A)
Substitute these values into equation (iii) as follows;
tan A = [tex]\frac{24}{36}[/tex]
tan A = [tex]\frac{2}{3}[/tex]
Related Questions
Linda found that the cost to get a swimming pool installed in her backyard is a linear function of the pool's area. A swimming pool with an area of 1,000 square feet can be installed for $50,000, whereas the installation of an 800 square foot swimming pool costs $35,000. Select the correct graph that models the given relationship.
Answers
Answer:
$35,000
Step-by-step explanation:
if $50,000 is to install an area of 1,000 square feet swimming pool and $35,000 can be used to install an 800 square foot swimming pool I think the best graph model is 800 square feet for $35,000 for a cost cut of $15,000 is a good bargain
In 2013, the Public Religion Research Institute conducted a survey of 1,033 adults, 18 years of age or older, in the continental United States. One of the questions on their survey was as follows:
Answers
Answer:
Probability[Number of people from church] = 0.26 (Approx.)
Step-by-step explanation:
Given:
Total number of adult in survey = 1,033
Missing information:
Number of people from church = 269
Find:
Probability[Number of people from church]
Computation:
Probability of an event = Number of favourable outcomes / Number of total outcomes
Probability[Number of people from church] = Number of people from church / Total number of adult in survey
Probability[Number of people from church] = 269 / 1,033
Probability[Number of people from church] = 0.2604
Probability[Number of people from church] = 0.26 (Approx.)
If ABC is reflected across the y-axis, what are the coordinates of C?
A. (-8, -4)
B. (8,-4)
C. (-8,4)
D. (4,-8)
Answers
Answer:
c....................
2(-x-4)+3=-7x+5+5x
Pls help!!!!!!!!
Answers
1 Simplify
−
7
x
+
5
+
5
x
−7x+5+5x to
−
2
x
+
5
−2x+5.
2
(
−
x
−
4
)
+
3
=
−
2
x
+
5
2(−x−4)+3=−2x+5
2 Expand.
−
2
x
−
8
+
3
=
−
2
x
+
5
−2x−8+3=−2x+5
3 Simplify
−
2
x
−
8
+
3
−2x−8+3 to
−
2
x
−
5
−2x−5.
−
2
x
−
5
=
−
2
x
+
5
−2x−5=−2x+5
4 Cancel
−
2
x
−2x on both sides.
−
5
=
5
−5=5
5 Since
−
5
=
5
−5=5 is false, there is no solution.
No Solution
You need
1
1
4
feet of string to make 20 holiday ornaments.
To make 14 holiday ornaments, you will need
feet of string.
Answers
Answer:
79.8
Step-by-step explanation:
math
Question 2
A force F=5i+3j-2k is applied to move a block of cement from A(0,1,1) to B(4.-1,3).
Determine the work done by the force.
Answers
The work is simply the dot product of the force and displacement (which I assume are given in Newtons and meters, respectively):
W = F • d
W = (5i + 3j - 2k) N • ((4i - j + 3k) m - (j + k) m)
W = (5i + 3j - 2k) • (4i - 2j + 2k) Nm
W = (20 - 6 - 4) Nm
W = 10 J
6. Aerial photography is to be taken of a tract of land that is 8 x 8 mi2. Flying height will be 4000 ft above average terrain, and the camera has focal length of 6 inches. If the focal plane opening is 9 x 9 in., and minimum side overlap is 30%, how many flight lines will be needed to cover the tract for the given data
Answers
Answer:
the number of flight lines needed is approximately 72
Step-by-step explanation:
Given the data in the question;
Aerial photography is to be taken of a tract of land that is 8 x 8 mi²
L × B = 8 x 8 mi²
Flying height H = 4000 ft = ( 4000 × 12 )inches = 48000 in
focal length f = 6 in
[tex]l[/tex] × b = 9 × 9 in²
side overlap = 30% = 0.3
meaning remaining side overlap = 100% - 30% = 70% = 0.7
{ not end to end overlap }
we take 100% { remaining overlap }
[tex]l[/tex]' = 9 × 100% = 9 in
b' = 9 × 70% = 6.3 in
Now the scale will be;
Scale = f/H
we substitute
Scale = 6 in / 48000 in = 1 / 8000
so our scale is; 1 : 8000
⇒ 1 in = 8000 in
⇒ 1 in = (8000 / 63360)mi
⇒ 1 in = 0.126 mi
so since
L × B = 8 x 8 mi²
[tex]l[/tex]' = ( 9 × 0.126 mi ) = 1.134 mi
b' = ( 6.3 × 0.126 mi ) = 0.7938 mi
Now we get the flight lines;
N = ( L × B ) / ( [tex]l[/tex]' × b' )
we substitute
N = ( 8 mi × 8 mi ) / ( 1.134 mi × 0.7938 mi )
N = 64 / 0.9001692
N = 71.0977 ≈ 72
Therefore, the number of flight lines needed is approximately 72
what is the value of -2(7-15)/4
Answers
WILL GIVE BRAINLIEST!!!
Write as a polynomial: 14b + 1 - 6(2 - 11b)
Answers
Answer:
80b-11
Step-by-step explanation:
14b + 1 - 6(2 - 11b)
Distribute
14b+1-12+66b
Combine like terms
80b-11
Answer:
80b - 11
Step-by-step explanation:
what is the problem ?
just multiply it out and combine terms.
14b + 1 - 6(2 - 11b) = 14b + 1 - 12 + 66b = 80b - 11
A cat is running away from a dog at a speed of 3m/s. originally, the distance between them was 48 meters. What should be the speed of the dog to catch with the cat in 1 minute?
Answers
Answer:
[tex]3.8\:\mathrm{m/s}[/tex]
Step-by-step explanation:
Use the formula [tex]d=rt[/tex] (distance is equal to rate/speed multiplied by time) to solve this problem.
We know that one minute is equal to 60 seconds. Therefore, the distance travelled by the cat in 1 minute is equal to [tex]d=3\cdot 60=180\text{ meters}[/tex].
To catch the cat, the dog needs to also cover an additional 48 meters, because the cat was initially 48 meters away from the dog and it ran away from the dog. Hence, the dog will need to cover [tex]180+48=228[/tex] meters in one minute.
Therefore, we have:
[tex]228=60r,\\r=\frac{228}{60}=\boxed{3.8\:\mathrm{m/s}}[/tex]
Answer:
[tex] \boxed{3.8 \: m/s} [/tex]
Explanation
The first step is to set the speed and the distance equal to the unknown rate of the dog.
3 m/s + 48 m = x m/60s.
Then substitute 60s in for both rates to get distance.
180m + 48m = x m/60
228m = 60x m
÷60 ÷60
3.8m = x m/s.
x = 3.8m/s
Which choice correctly shows the line y = -x?
А
B
NOW
-
1 2 3 4
NH
-4 -3 -2 -1 1 2 3 4
UN
С
2
1 2 3 4
-4-3-2/4 1 2 3 4
-4 -3 -2 -3
NA
2
At
2
Answers
Answer:
The answer is A
Step-by-step explanation:
Hope this helps
Please help, been stuck on this for a while.
Answers
Answer:its blurry
Step-by-step explanation:
cant see it
Answer:
x = 34.6
Step-by-step explanation:
[tex]x\:=\:\frac{\left(20\cdot \:sin\left(60\right)\right)}{sin\left(30\right)}[/tex]
Find the product of the given polynomials. (5 x +8 -6x) (4+ 2x 87)
a. -2x2+19x -24
b-2x2 -24x +19
c- 2x2 +19x +24
d- 2x2 +13x -24
Answers
Answer:
[tex]- 2x^2 +19x -24[/tex]
Step-by-step explanation:
Given
[tex](5x + 8 - 6x)(4 + 2x - 7)[/tex]
Required
Evaluate
We have:
[tex](5x + 8 - 6x)(4 + 2x - 7)[/tex]
Collect like terms
[tex](5x - 6x+ 8 )(4 - 7+ 2x )[/tex]
[tex](- x+ 8 )(- 3+ 2x )[/tex]
Expand
[tex]3x - 2x^2 -24 + 16x[/tex]
Rewrite as:
[tex]- 2x^2 + 3x+ 16x -24[/tex]
[tex]- 2x^2 +19x -24[/tex]
PLEASE HELP I WILL MARK YOUR ANSWER AS BRAINLIEST PLEASE BE CORRECT BEFORE ANSWERING
LOOK AT THE BOTTOM
Answers
9514 1404 393
Answer:
y = 2
Step-by-step explanation:
The figure must be flipped top-to-bottom, so the line of reflection must be a horizontal line. Point B must be reflected to itself, so it is on the line of reflection. That means the line of reflection is y = 2.
__
You can draw the line of reflection using any two points that have y-coordinates of 2, for example, (0, 2) and (2, 2).
Is this a function? Yes or no?
Answers
Answer:
NO
Step-by-step explanation:
NO
Solve the system, or show that it has no solution. (If there is no solution, enter NO SOLUTION. If there are an infinite number of solutions, enter the general solution in terms of x, where x is any real number.)
20x − 80y = 100
−14x + 56y = −70
(x, y) =
Answers
Answer:
The system has an infinite set of solutions [tex](x,y) = (x, \frac{x-5}{4})[/tex]
Step-by-step explanation:
From the first equation:
[tex]20x - 80y = 100[/tex]
[tex]20x = 100 + 80y[/tex]
[tex]x = \frac{100 + 80y}{20}[/tex]
[tex]x = 5 + 4y[/tex]
Replacing on the second equation:
[tex]-14x + 56y = -70[/tex]
[tex]-14(5 + 4y) + 56y = -70[/tex]
[tex]-70 - 56y + 56y = -70[/tex]
[tex]0 = 0[/tex]
This means that the system has an infinite number of solutions, considering:
[tex]x = 5 + 4y[/tex]
[tex]4y = x - 5[/tex]
[tex]y = \frac{x - 5}{4}[/tex]
The system has an infinite set of solutions [tex](x,y) = (x, \frac{x-5}{4})[/tex]
CAN SOMEONE HELP ME ON ANALYZING DOT PLOTS!!!
Answers
Answer:
yes
Step-by-step explanation:
but I can't see them here
which is the correct answer ?
Answers
Answer:
11/12 cups
Step-by-step explanation:
2/3+1/4 = ( 2x4 + 3x1 )/( 3x4 ) = ( 8+3 )/12 = 11/12
solve the inequality 4t^2 ≤ 9t-2 please show steps and interval notation. thank you!
Answers
Answer:
[0.25, 2]
Step-by-step explanation:
We have
4t² ≤ 9t-2
subtract 9t-2 from both sides to make this a quadratic
4t²-9t+2 ≤ 0
To solve this, we can solve for 4t²-9t+2=0 and do some guess and check to find which values result in the function being less than 0.
4t²-9t+2=0
We can see that -8 and -1 add up to -9, the coefficient of t, and 4 (the coefficient of t²) and 2 multiply to 8, which is also equal to -8 * -1. Therefore, we can write this as
4t²-8t-t+2=0
4t(t-2)-1(t-2)=0
(4t-1)(t-2)=0
Our zeros are thus t=2 and t = 1/4. Using these zeros, we can set up three zones: t < 1/4, 1/4<t<2, and t>2. We can take one random value from each of these zones and see if it fits the criteria of
4t²-9t+2 ≤ 0
For t<1/4, we can plug in 0. 4(0)²-9(0) + 2 = 2 >0 , so this is not correct
For 1/4<t<2, we can plug 1 in. 4(1)²-9(1) +2 = -3 <0, so this is correct
For t > 2, we can plug 5 in. 4(5)²-9(5) + 2 = 57 > 0, so this is not correct.
Therefore, for 4t^2 ≤ 9t-2 , which can also be written as 4t²-9t+2 ≤ 0, when t is between 1/4 and 2, the inequality is correct. Furthermore, as the sides are equal when t= 1/4 and t=2, this can be written as [0.25, 2]
what is the value of 24 * 0.03
Answers
Answer:
The value of 24x0.03 is gong to be, "800"
Which expression has a value of 15 when it equals
2
49-57
3--5
61-28
28
19
Answers
Answer:
it is 61-28 but I not sure u can scan for any application to make sure u get it ur answer thx for
Children arrive at a house to do Halloween trick-or- treating according to a Poisson process at the unlucky rate of 13/hour. What is the probability that the time between the 15th and 16th arrivals will be more than 4 minutes ? (Hint: Think exponential.)
a) e e-2 = 0.1353
b) e-13/15 = 0.4204
c) e-1 = 0.3679
d) 1-2-1 = 0.6321
Answers
Answer:
0.4204 probability, option b.
Step-by-step explanation:
Exponential distribution:
The exponential probability distribution, with mean m, is described by the following equation:
[tex]f(x) = \mu e^{-\mu x}[/tex]
In which [tex]\mu = \frac{1}{m}[/tex] is the decay parameter.
The probability that x is lower or equal to a is given by:
[tex]P(X \leq x) = \int\limits^a_0 {f(x)} \, dx[/tex]
Which has the following solution:
[tex]P(X \leq x) = 1 - e^{-\mu x}[/tex]
The probability of finding a value higher than x is:
[tex]P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}[/tex]
Children arrive at a house to do Halloween trick-or- treating according to a Poisson process at the unlucky rate of 13/hour
13 arrivals during an hour, which means that the mean time between arrivals, in minutes is of [tex]\mu = \frac{13}{60} = 0.2167[/tex]
What is the probability that the time between the 15th and 16th arrivals will be more than 4 minutes ?
This is P(X > 4). So
[tex]P(X > 4) = e^{-0.2167*4} = 0.4204[/tex]
So the correct answer is given by option b.
How many orders are possible to view 6 videos from a stack of 8 videos?
Answers
Answer:
28
Step-by-step explanation:
We know that ,
n C r = n! / ( n - r)! r! 8! / ( 8 - 6)! 6!8! / 2! × 6! 7 × 8 / 2 × 1 28Q.No.4. Ali is hiking on the hill, whose height is given by f(u,v)=n^2 e^((u+n)/(v+n)). Currently, he is positioned at point (3,5). Find the direction at which he moves down the hills quickly. (5 points) Where n is the product of first and second digit of your arid number e.g. 19-arid-435 take n=4x3=12
Answers
Answer:
///////
Step-by-step explanation:
A radio transmission tower is 180 feet high. How long should a guy wire be if it is to be attached to the tower 11 feet from the top and is to make an angle of 45° with the ground?
Answers
Answer:
Step-by-step explanation:
A three-dimensional object's measurement(s) include which of the following?
Check all that apply.
A. Width
B. Length
C. Height
D. None of these
Answers
Answer:
A.
B.
C.
Step-by-step explanation:
all three are used in 3 dimensional objects hence the name 3 dimensions.
Find two positive numbers whose product is 64 and whose sum is a minimum. (If both values are the same number, enter it into both blanks.) (smaller number) (larger number)
Answers
Answer:
Both the numbers are 8.
Step-by-step explanation:
Let the two numbers are p and 64/p.
The sum is given by
[tex]S = p +\frac{64}{p}\\\\\frac{dS}{dp}= 1 - \frac{64}{p^2}\\\\\frac{dS}{dp}=0\\\\\frac{64}{p^2}=1\\\\p= \pm 8[/tex]
So, the sum is minimum for p = 8 0r - 8, so the two numbers 8.
Consider the following game: You reach into a jar of money, and select a single bill at random to keep. There are 9 five-dollar bills, 5 ten-dollar bills, and 3 twenty-dollar bills in the jar. What should the cost of this game be in order for the game to be fair
Answers
Answer:
[tex]E(x)=\$9.118[/tex]
Step-by-step explanation:
From the question we are told that:
Available bills
[tex]\$5=N0 9\\\\\$10=N0 5[/tex]
[tex]\$20=N0 3[/tex]
Therefore
Total Bills
[tex]n=5+9+3[/tex]
[tex]n=17[/tex]
Probability of selecting each bill
[tex]For\$5[/tex]
[tex]P(\$5)=\frac{9}{17}[/tex]
[tex]For\$10[/tex]
[tex]P(\$10)=\frac{5}{17}[/tex]
[tex]For\$20[/tex]
[tex]P(\$20)=\frac{3}{17}[/tex]
Generally the equation for Expected winning is mathematically given by
[tex]E(x)=\sum(X)*P(X)[/tex]
[tex]E(x)=5*\frac{9}{17}+10*\frac{5}{17}+20*\frac{3}{17}[/tex]
[tex]E(x)=\$9.118[/tex]
Using the digits 2 through 8, find the number of different 5-digit numbers such that, digits can be used more than once.
Answers
Answer:
7 digits can be used for each position
There are a total of 5 positions
N = 7^5 = 16,807 numbers
You have 7 choices for the first position, second position, etc.
Here are the test scores for 8 students in Mr. M's class. 87, 55, 96, 38, 83, 64, 44, 81. What is the percentage of these test scores that are less than 84?
Answers
Answer:
75%
Step-by-step explanation:
Given that the score of 8 students in Mr. M's class are 87, 55, 96, 38, 83, 64, 44, 81, the scores less than 84 are 55, 38, 83, 64, 44, 81.
These means that 6 student had scores less that 84 of the 8 students hence the percentage of these test scores that are less than 84
= 6/8 * 100%
= 75%
This means that 75% of the students had scores less than 84
