Find the volume of the solid lying between two planes perpendicular to the x-axis at x = −1 and x = 1. The cross sections perpendicular to the x-axis are squares whose diagonals run from y = x 2 to y = 2 − x 2
Answers
I've attached a sketch of one such cross section (light blue) of the solid (shown at x = 0). The planes x = ±1 are shown in gray, and the two parabolas are respectively represented by the blue and orange curves in the (x, y)-plane.
For every x in the interval [-1, 1], the corresponding cross section has a diagonal of length (2 - x ²) - x ² = 2 (1 - x ²). The diagonal of any square occurs in a ratio to its side length of √2 : 1, so the cross section has a side length of 2/√2 (1 - x ²) = √2 (1 - x ²), and hence an area of (√2 (1 - x ²))² = 2 (1 - x ²)².
The total volume of the solid is then given by the integral,
[tex]\displaystyle\int_{-1}^1 2(1-x^2)^2\,\mathrm dx = \int_{-1}^1 (2-4x^2+4x^4)\,\mathrm dx = \boxed{\frac{32}{15}}[/tex]
Related Questions
Olivia rides her scooter 3/4 mile in
1/3 hour. How fast, in miles per hour,
does she ride her scooter?
Answers
Answer:
2.25 miles per hr
Answer:
2.25 miles per hour
Step-by-step explanation:
speed = distance / time
speed = [tex]\frac{3}{4} / \frac{1}{3}[/tex] (take the reciprocal of [tex]\frac{1}{3}[/tex])
= [tex]\frac{3}{4} * 3[/tex]
= [tex]\frac{9}{4}[/tex] = 2.25 miles per hour
Please answer!<333 xx
Answers
12. X= 6
14. B= -11
16. N= 15
Answer:
q12. [tex]x=6[/tex]
q14. [tex]b=-11[/tex]
q16. [tex]n=15[/tex]
Step-by-step explanation:
Q12.
[tex]-1=\frac{x}{-6}[/tex]
Flip the equation:
[tex]\frac{x}{-6} =-1[/tex]
Multiply both sides by 6/(-1)
[tex](\frac{6}{-1} )[/tex] × [tex](\frac{-1}{6}x )[/tex] = [tex](\frac{6}{-1} )[/tex] × [tex](-1)[/tex]
[tex]x=6[/tex]
Q14.
[tex]5b=-55[/tex]
[tex]b=\frac{-55}{5}[/tex]
[tex]b=-11[/tex]
Q16.
[tex]-3n=-45[/tex]
[tex]n=\frac{-45}{-3}[/tex]
[tex]n=15[/tex]
hope this helps.....
Help differentiate this
Answers
Answer:
[tex]\displaystyle y' = 20x^3 + 6x^2 + 70x + 9[/tex]
General Formulas and Concepts:
Pre-Algebra
Distributive PropertyAlgebra I
Terms/CoefficientsExpand by FOILFunctionsFunction NotationCalculus
Derivatives
Derivative Notation
Derivative Property [Multiplied Constant]: [tex]\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)[/tex]
Derivative Property [Addition/Subtraction]: [tex]\displaystyle \frac{d}{dx}[f(x) + g(x)] = \frac{d}{dx}[f(x)] + \frac{d}{dx}[g(x)][/tex]
Basic Power Rule:
f(x) = cxⁿ f’(x) = c·nxⁿ⁻¹Derivative Rule [Product Rule]: [tex]\displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)[/tex]
Step-by-step explanation:
Step 1: Define
Identify
[tex]\displaystyle y = (x^3 + 7x - 1)(5x + 2)[/tex]
Step 2: Differentiate
Product Rule: [tex]\displaystyle y' = \frac{d}{dx}[(x^3 + 7x - 1)](5x + 2) + (x^3 + 7x - 1)\frac{d}{dx}[(5x + 2)][/tex]Basic Power Rule [Derivative Property - Addition/Subtraction]: [tex]\displaystyle y' = (3x^{3 - 1}+ 7x^{1 - 1} - 0)(5x + 2) + (x^3 + 7x - 1)(5x^{1 - 1} + 0)[/tex]Simplify: [tex]\displaystyle y' = (3x^2+ 7)(5x + 2) + 5(x^3 + 7x - 1)[/tex]Expand: [tex]\displaystyle y' = 15x^3 + 6x^2 + 35x + 14 + 5(x^3 + 7x - 1)[/tex][Distributive Property] Distribute 5: [tex]\displaystyle y' = 15x^3 + 6x^2 + 35x + 14 + 5x^3 + 35x - 5[/tex]Combine like terms: [tex]\displaystyle y' = 20x^3 + 6x^2 + 70x + 9[/tex]Topic: AP Calculus AB/BC (Calculus I/I + II)
Unit: Derivatives
Book: College Calculus 10e
I am having trouble with this problem. If anyone could help that would be great.
Let M be the capped cylindrical surface which is the union of two surfaces, a cylinder given by x^2+y^2=16, 0≤z≤1, and a hemispherical cap defined by x^2+y^2+(z−1)^2=16, z≥1. For the vector field F=(zx+z^2y+4y, z^3yx+3x, z^4x^2), compute ∬M(∇×F)⋅dS in any way you like.
Answers
Answer:
Ok... I hope this is correct
Step-by-step explanation:
Let M be the capped cylindrical surface which is the union of two surfaces, a cylinder given by x^(2)+y^(2)=16
Center: ( 0 , 0 )
Vertices: ( 4 , 0 ) , ( − 4 , 0 )
Foci: ( 4 √ 2 , 0 ) , ( − 4 √ 2 , 0 )
Eccentricity: √ 2
Focal Parameter: 2 √ 2
Asymptotes: y = x , y = − x
Then 0≤z≤1, and a hemispherical cap defined by x^2+y^2+(z−1)^2=16, z≥1.
Simplified
0 ≤ z ≤ 1 , x ^2 + y ^2 + z ^2 − 2 ^z + 1 = 16 , z ≥ 1
For the vector field F=(zx+z^2y+4y, z^3yx+3x, z^4x^2), compute ∬M(∇×F)⋅dS in any way you like.
Vector:
csc ( x ) , x = π
cot ( 3 x ) , x = 2 π 3
cos ( x 2 ) , x = 2 π
Since
( z x + z ^2 y + 4 y , z ^3 y x + 3 x , z ^4 x ^2 ) is constant with respect to F , the derivative of ( z x + z ^2 y + 4 y , z ^3 y x + 3 x , z ^4 x 2 ) with respect to F is 0 .
______are used to represent an unknown quantity in a mathematical expression.
Answers
Answer:
Variables are used to represent an unknown quantity in a mathematical expression.
Step-by-step explanation:
Variables are used to represent an unknown quantity in a mathematical expression.For example : x + 2 = 4, here x is the variable.We can denote variable by any alphabet i.e, a,b,c,d etc.Round 0.485 to the nearest hundredth
Answers
Decimals start at tenths, then hundredths, then thousandths, and so on. When we round, we look at the place value that is one smaller than the one we want to round to.
So, let's take a look at the thousandths place in 0.485. The value in the thousandths place is 5. When rounding, if the value is 5 or over we round up and if the value is 4 or lower we round down. Since the value in the thousandths place is 5, we will round the hundredths place up one.
0.485 rounded to the nearest hundredth is 0.49
Hope this helps!
Answer:
0.49
Step-by-step explanation:
[tex]0<x<5=[/tex] Round down
[tex]x\geq5=[/tex] Round up
In this case, it's a round up, so the answer would be...
0.49
Hope this helped! Please mark brainliest!
Question 3
A 70kg patient has approximately 8 pints of blood. The patient donates 470mL of blood.
Approximately what fraction of his body's blood is this? (one pint = 568mL)
Answers
Step-by-step explanation:
Given that,
The mass of a patient = 70 kg
A 70kg patient has approximately 8 pints of blood.
The patient donates 470mL of blood.
We know that,
1 pint = 568 mL
8 pints = 4544 mL
Required fraction,
[tex]\dfrac{470}{4544}=0.1\\\\=\dfrac{1}{10}[/tex]
So, the required fraction is approximately [tex]\dfrac{1}{10}[/tex].
Jonas builds a snow fort. He tells his friends it is 0.8 meters tall inside, but he rounded the height to the nearest tenth.
Which could be the height of the snow fort before Jonas rounded it?
2 answers
A. 0.85
B. 0.82
C. 077
Answers
Answer:
B. 0.82
C. 077
Step-by-step explanation:
Given
[tex]Number = 0.8[/tex] -- approximated
Required
The possible value of Number
Since [tex]Number = 0.8[/tex] is approximated, then the possible values of Number that can be gotten from the preparation
The approximated value 0.8 has the following range: 0.75 to 0.84
Options B and C are in this category.
Ralph bought a computer monitor with an area of 384 square inches. The length of the monitor is six times the quantity of five less than half its width.
Complete the equation that can be used to determine the dimensions of the monitor in terms of its width, w.
Answers
Answer:
w= 103.5 inches
Step-by-step explanation:
384=w+3w-30
414=4w
w=414/4=103.5 inches
Answer:
first drop box 384
second drop box 3
third drop boc 30
384 = 3 [tex]w^{2}[/tex] – 30 w
Step-by-step explanation:
Correct answer on Plato/Edmentum test
The difference between seven times a number and 9 is equal to five times
the sum of the number and 2. Find the number. Hint: There will be
parenthesis in your equation.
Answers
Answer:
The number is 9.5
Step-by-step explanation:
Look at the picture above, it explains everything
1^2 +2^2+••••+n^2=1/6n(n+1)(2n+1)
using maths induction
Answers
Hello,
[tex]if\ n=1\ then\ 1^2=1\ and\ \dfrac{1}{6}*1*2*3=1:\ true\ for\ n=1\\[/tex]
We suppose the property true for n:
1²+2²+...+n²=n(n+1)(2n+1) / 6
and we are going to demonstrate that the property is true for n+1:
1²+2²+..+(n+1)²=(n+1)*(n+2)*(2n+3)/6
[tex]1^2+2^2+...+n^2+(n+1)^2\\\\=n*(n+1)*(2n+1)/6+(n+1)^2\\\\=(n+1)/6*[n(2n+1)+6n+6]\\\\=(n+1)/6*(2n^2+7n+6)\\\\=(n+1)(n+2)(2n+3)/6\\[/tex]
Brian, the gorilla, was planning a party for his zoo friends. He sent his elves Jamie and Nancy into the North Pole exhibit to count the penguins and reindeer. Jamie said there were 40 legs and Nancy said there were 14 heads. How many penguins and reindeer were in the exhibit?
Answers
Answer:
There are 8 penguins and 6 reindeers.
Step-by-step explanation:
Since Brian, the gorilla, was planning a party for his zoo friends, and he sent his elves Jamie and Nancy into the North Pole exhibit to count the penguins and reindeer, and Jamie said there were 40 legs and Nancy said there were 14 heads To determine how many penguins and reindeer were in the exhibit, the following calculation must be performed:
Penguins: 1 head and 2 legs
Reindeers: 1 head and 4 legs
40 - (14 x 2) = X
40 - 28 = X
12 = X
12/2 = 6
14 - 6 = 8
8 x 2 + 6 x 4 = X
16 + 24 = X
40 = X
Therefore, there are 8 penguins and 6 reindeers.
A student has test scores of 75 and 82respectively. What is the student’s average score for a third test
Answers
Answer:
78.5 (I think 90% sure)
Step-by-step explanation:
sum of both scores
75+82 = 157
average for a third test
157÷2=78.5
remove bracket and simplify 6x-(3x+2)
Answers
Answer: 3x - 2
Step-by-step explanation:
First to solve this, we need to know some basic information such as:
1. (-) × (-) = +
2. (+) × (-) = -
3. (+) × (+) = +
Therefore, 6x-(3x+2)
= 6x - 3x - 2
= 3x - 2
The answer to the question after removing the bracket will be 3x - 2.
09:30 am - 4:30 pm minus 30 minutes?
How many hours is that ?
Answers
0.9.30 am to 4.30 p.m. is 7 hours.
If we minus 30 minutes from it then it is 6 hours 30 minutes.
Given n(A) = 1300, n(A U B) = 2290, and n(A n B) = 360, find n(B).
Answers
Answer:
n(B) = 1350
Step-by-step explanation:
Using Venn sets, we have that:
[tex]n(A \cup B) = n(A) + n(B) - n(A \cap B)[/tex]
Three values are given in the exercise.
The other is n(B), which we have to find. So
[tex]n(A \cup B) = n(A) + n(B) - n(A \cap B)[/tex]
[tex]2290 = 1300 + n(B) - 360[/tex]
[tex]940 + n(B) = 2290[/tex]
[tex]n(B) = 2290 - 940 = 1350[/tex]
So
n(B) = 1350
A simple random sample of students could be achieved by stopping every other student who enters the library.
a. True
b. False
Answers
The function f is defined by the following rule. f(x) = 5x+1 Complete the function table.
Answers
Answer:
[tex]-5 \to -24[/tex]
[tex]-1 \to -4[/tex]
[tex]2 \to 11[/tex]
[tex]3 \to 16[/tex]
[tex]4 \to 21[/tex]
Step-by-step explanation:
Given
[tex]f(x) = 5x + 1[/tex]
Required
Complete the table (see attachment)
When x = -5
[tex]f(-5) = 5 * -5 + 1 = -24[/tex]
When x = -1
[tex]f(-1) = 5 * -1 + 1 = -4[/tex]
When x = 2
[tex]f(2) = 5 * 2 + 1 = 11[/tex]
When x = 3
[tex]f(3) = 5 * 3 + 1 = 16[/tex]
When x = 4
[tex]f(4) = 5 * 4 + 1 = 21[/tex]
So, the table is:
[tex]-5 \to -24[/tex]
[tex]-1 \to -4[/tex]
[tex]2 \to 11[/tex]
[tex]3 \to 16[/tex]
[tex]4 \to 21[/tex]
Read the following scenario, and then answer the question.
Juan assumes that the temperature of the hot tea cooling on his desk can be modeled with an exponential function like this one: T(t)=179(0.92)t. He bases his assumption on the following: The tea cools about 8% every minute. The tea's current temperature is around 179 degrees Fahrenheit.
Which explanation correctly addresses Juan's assumption?
He is incorrect. The tea will cool linearly since it cools at the same number of degrees every minute.
He is correct. The tea will cool exponentially since it cools at a percentage rate every minute.
He is incorrect. The tea will cool along the curve of a parabola since it cools at an increasing percentage rate every minute.
Answers
9514 1404 393
Answer:
(b) He is correct. The tea will cool exponentially since it cools at a percentage rate every minute.
Step-by-step explanation:
Newton's Law of Cooling says the change in temperature is proportional to the temperature. This relation gives rise to an exponential function describing the temperature.
In this description, the temperature referred to is the difference between the temperature of the object and the temperature of the environment to/from which heat is being transferred.
Juan is only partially correct. The function is exponential, but the temperature that should be used in his equation is not the temperature of the tea, but the temperature difference between the tea and his desk.
__
The curve is not linear and not parabolic, excluding the other answer choices.
PLS HELP
The holding tanks are congruent in size, and both are in the shape of a cylinder that has been cut in half vertically. The bottom of the tank is a curved surface. What is the volume of both tanks if the radius of tank #1 is 15 feet and the height of tank #2 is 120 feet? You must explain your answer using words, and you must show all work and calculations.
Answers
9514 1404 393
Answer:
42,412 ft³ each tank
84,823 ft³ both tanks added together
Step-by-step explanation:
"Congruent in size" means both tanks have the same dimensions. Each has a radius of 15 ft and a length of 120 ft. Each has half the volume of a cylinder with those dimensions.
The formula for the volume of a cylinder is ...
V = πr²h
where r is the cylinder radius, and h is the length of its axis.
We want the volume of half a cylinder with r=15 and h=120 (dimensions in ft). We can compute that using ...
V = 1/2π(15 ft)²(120 ft) = π(225 ft²)(60 ft)= 13500π ft³
If we want the volume to the nearest cubic foot, we need a value of pi that is at least 7 significant digits (3.14 isn't appropriate). Then the volume is about ...
(13,500)(3.141593) ft³ ≈ 42,411.5 ft³ ≈ 42,412 ft³
Both tanks have a volume of 42,412 ft³ each.
_____
Additional comment
The question, "What is the volume of both tanks?" is ambiguous. We're not sure if the combined volume is intended, or if the volume of each of the two tanks is intended. Both numbers are provided, so you can sort it out as you see fit.
A scientist claims that 4% of viruses are airborne. If the scientist is accurate, what is the probability that the proportion of airborne viruses in a sample of 662 viruses would be greater than 6%
Answers
Answer:
The probability that the proportion of airborne viruses in a sample of 662 viruses would be greater than 6%=0.00427
Step-by-step explanation:
We are given that
[tex]\mu_{\hat{p}}=p=4%=0.04[/tex]
n=662
We have to find the probability that the proportion of airborne viruses in a sample of 662 viruses would be greater than 6%.
q=1-p=1-0.04=0.96
[tex]\sigma_{\hat{p}}=\sqrt{p(1-p)/n}[/tex]
[tex]\sigma_{\hat{p}}=\sqrt{\frac{0.04(1-0.04)}{662}}[/tex]
[tex]\sigma_{\hat{p}}=0.0076[/tex]
Now,
[tex]P(\hat{p}>0.06)=1-P(\hat{p}<0.06)[/tex]
[tex]=1-P(\frac{\hat{p}-\mu_{\hat{p}}}{\sigma_{\hat{p}}}<\frac{0.06-0.04}{0.0076})[/tex]
[tex]=1-P(Z<2.63)[/tex]
[tex]=1-0.99573[/tex]
[tex]P(\hat{p}>0.06)=0.00427[/tex]
Hence, the probability that the proportion of airborne viruses in a sample of 662 viruses would be greater than 6%=0.00427
Can I get the answer for those
Answers
Answer:
1) 5.64
2) 17.321
1) [tex]\frac{21}{28}[/tex]
2) [tex]\frac{16}{34}[/tex]
3) [tex]\frac{28}{35}[/tex]
4) [tex]\frac{32}{24}[/tex]
Step-by-step explanation:
SOH - CAH - TOA
Sin = [tex]\frac{O}{H}[/tex] Cos = [tex]\frac{A}{H}[/tex] Tan = [tex]\frac{O}{A}[/tex]
O = opposite, A = adjacent, H = hypotenuse
First two, use Pythagorean Theorem
If you want to calculate the angle on the last 4, use inverse of function and put in the ratio.
For example :
1) Tan Z = [tex]\frac{21}{28}[/tex]
[tex]Tan^{-1}[/tex] ( [tex]\frac{21}{28}[/tex])
Z = 36.9°
જ્યારે જહાંગીરની ઉંમર 18 વર્ષ થશે ત્યારે અકબરની ઉંમર 50 વર્ષ થર્શ.
જ્યારે અકબરની ઉંમર જહાંગીરની ઉંમર કરતા 5 ઘણી હશે ત્યારે
અકબરની ઉમર કેટલી હશે?
A) 36
B) 40
C) 44
D) 48
Answers
Answer:
C: 44
Step-by-step explanation:
A polynomial function has a root of -6 with multiplicity 1, a root of -2 with multiplicity 3, a root of 0 with multiplicity 2, and a
root of 4 with multiplicity 3. If the function has a positive leading coefficient and is of odd degree, which statement about
the graph is true?
O The graph of the function is positive on (-6, -2).
O The graph of the function is negative on (-0, 0).
O The graph of the function is positive on (-2, 4).
O The graph of the function is negative on (4.co).
Answers
9514 1404 393
Answer:
(a) the graph is positive on (-6, -2)
Step-by-step explanation:
The roots, left to right, are ...
-6, -2, 0, 4
The odd-multiplicity roots, where the sign changes, are ...
-6, -2, 4
The function is negative to the left of -6, and positive to the right of +4. It is positive on the interval (-6, -2) and negative on the intervals (-2, 0) and (0, 4).
Answer:it’s a!!!
edge please stop deleted my answer ;)
Step-by-step explanation:
Which of the following numbers is rational? Assume that the decimal patterns continue.
Answers
Answer:
[tex]\sqrt{49}[/tex]
Step-by-step explanation:
Define a rational number by a number able to expressed a fraction where the denominator is not 0 or 1.
Non-terminating (never-ending) decimals cannot be expressed as a fraction and therefore are irrational. However, recall that [tex]\sqrt{49}=7[/tex], which can be expressed as a fraction (e.g. [tex]\frac{14}{2}[/tex], etc). Thus, the answer is [tex]\boxed{\sqrt{49}}[/tex].
The graph of y=x^3 is transformed as shown in the graph below. Which equation represents the transformed function?
y = x cubed minus 4
y = (x minus 4) cubed
y = (negative x minus 4) cubed
y = (negative x) cubed minus 4
Answers
Answer:
y = (-x)^3 - 4
Step-by-step explanation:
Ok, for the function:
y = x^3
When x = 0, we have:
y = 0^3 = 0
So the original graph passes through the point (0, 0)
If we look at the given graph, we can see that the y-intercept (the value of y when x = 0) is:
y = -4
So, this is the graph of y = x^3 moved down 4 units.
You can also see that the graph goes downward as x increases (and up as x decreases) while for the function:
y = x^3
as x increases, we should see that y also increases.
Then we have a reflection across the x-axis.
Ok, now let's describe a vertical shift.
For a general function f(x), a vertical shift of N units is written as:
g(x) = f(x) + N
if N is positive, the shift is upwards
if N is negative, the shift is downwards.
And for a function f(x), a reflection across the x-axis is written as:
g(x) = - f(x)
Here we first apply the reflection across the x-axis, so we get:
g(x) = -f(x)
now we apply the shift 4 units downwards
g(x) = - f(x) - 4
replacing f(x) by our function, x^3
we get:
g(x) = -x^3 - 4
And because of the odd power, we can write:
-x^3 = (-x)^3
Then the function is:
g(x) = (-x)^3 - 4
The correct option is the last one.
y = (-x)^3 - 4
HELP FAST PLEASEEEEEE
Which of the tables represents a function?
Table AInput
Output
3
1
3
4
2
3
Table BInput
Output
2
7
5
6
2
9
Table CInput
Output
1
5
7
2
7
3
Table DInput
Output
3
4
1
5
8
5
Select one:
a. Table A
b. Table B
c. Table C
d. Table D
Answers
Answer:
d.......................
In a survey, 24 people were asked how much they spent on their child's last birthday gift. The results were roughly bell-shaped with a mean of $42 and standard deviation of $2. Construct a confidence interval at a 98% confidence level.
Answers
Answer:
The 98% confidence interval for the mean amount spent on their child's last birthday gift is between $40.98 and $43.02.
Step-by-step explanation:
We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 24 - 1 = 23
98% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 23 degrees of freedom(y-axis) and a confidence level of [tex]1 - \frac{1 - 0.98}{2} = 0.99[/tex]. So we have T = 2.5
The margin of error is:
[tex]M = T\frac{s}{\sqrt{n}} = 2.5\frac{2}{\sqrt{24}} = 1.02[/tex]
In which s is the standard deviation of the sample and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 42 - 1.02 = $40.98.
The upper end of the interval is the sample mean added to M. So it is 42 + 1.02 = $43.02.
The 98% confidence interval for the mean amount spent on their child's last birthday gift is between $40.98 and $43.02.
Which statements below represent the situation? Select three options.
Answers
Answer:
where is the statement
Step-by-step explanation:
its incomplete po
A teacher has a 2-gallon (52 cup) container of juice. She gives each student z cup of juice. Which equation represents the amount of juice that remains, y, after x students are served?
Answers
Answer:
[tex]y = 32 - \frac{1}{2}x[/tex]
Step-by-step explanation:
Given
[tex]Cups = 32[/tex] ---- not 52
[tex]Students = x[/tex]
[tex]Remainder = y[/tex]
[tex]Each = \frac{1}{2}[/tex] --- not z
Required
The equation for y
The remainder y is calculated as:
[tex]y = Cups - Students * Each\\[/tex]
[tex]y = 32 - \frac{1}{2}x[/tex]
