Focusing a camera changes the distance between the lens and the film. And the eye focus by changing the distance between the lens and the retina is true as, the eye does focus by changing the distance between the lens and the retina.
What is the effect of changing the distance?When we focus on an object, the curvature of the lens in our eye changes. This causes the light rays from the object to converge and focus on the retina, located at the back of the eye.
In order to focus on objects at different distances, our eye's lens must adjust its shape by changing its curvature, which changes the distance between the lens and the retina. This process is called accommodation.
The process of focusing the eye is similar to the process of focusing a camera. In a camera, changing the distance between the lens and the film allows for the object to be in focus. Similarly, in the eye, changing the distance between the lens and the retina allows for objects to be in focus.
Therefore, the eye focuses by changing the distance between the lens and the retina.
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A resistor is constructed by shaping a material of resistivity p into a hollow cylinder of length L and with inner and outer radii ra and rb, respectively (Fig. P27.66). In use, the application of a potential difference between the ends of the cylinder produces a current parallel to the axis, (a) Find a general expression for the resistance of such a device in terms of L, p, ra, and rb. (b) Obtain a numerical value for. R when L = 4.00 cm, ra = 0.500 cm, rb = 1.20 cm, and p = 3.50 times 105 Ohm m. (c) Now suppose that the potential difference is applied between the inner and outer surfaces so that the resulting current flows radially outward. Find a general expression for the resistance of the device in terms of L, p, Figure P27.66 ra, and rb. (d) Calculate the value of R, using the parameter values given in part (b).
Explanation:
Refer to pic...........
Three identical conducting spheres are charged as follows. Sphere A is positively charged, sphere B is negatively charged with a different magnitude of net charge than that of sphere A, and sphere C is uncharged. Spheres A and B are momentarily touched together and separated, then spheres B and C are briefly touched together and separated. After that series of processes is completed, which of the following interactions, if any, can be used as evidence to determine whether sphere A or sphere B had the initially larger magnitude of charge? A Sphere C is repelled from sphere A. B Sphere C is repelled from sphere B. Sphere A is repelled from sphere B. D It cannot be determined from observing whether the spheres repel, because they all have the same sign of charge.
The answer is C. Sphere A is repelled from sphere B
Step by step explanation:
The question is asking which of the interactions between sphere A, B, and C can be used as evidence to determine which one had the initially larger magnitude of charge. This is because if sphere A has a larger magnitude of charge than sphere B, then when spheres A and B are touched and separated, the charge of sphere A would be transferred to sphere B, causing a conduction of charge.
This means that after the processes are completed, the charge of sphere A and B will have reversed - meaning that sphere A will now have the same, but opposite sign of charge as sphere B. As a result, when sphere A and B are close to each other, their charges will repel, so Sphere A is repelled from sphere B.
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What two planets are coming together?
The two planets that are coming together are Saturn and Jupiter. On December 21st, 2020, the two planets will be at their closest point, an event known as the Great Conjunction.
To observe the Great Conjunction, look in the direction of the southwest sky shortly after sunset. The two planets will appear to be close together and will look like one bright star. Make sure to look for them with binoculars or a telescope if you can, as you'll get a better view.The Great Conjunction occurs because Saturn and Jupiter have different orbital periods. Jupiter completes its orbit around the Sun every 11.86 Earth years, while Saturn takes 29.5 Earth years. This means that their orbits don't intersect and they don't come this close together very often. The next time the two planets will come this close together will be in 2080, so be sure to take advantage of this rare opportunity to witness this event in 2020.For more questions on Great Conjunction
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determine whether each geologic feature is being caused by tensional, compressional, or shear stresses by analyzing the directions of the forces being applied.
In any case, the type of force that is responsible for creating a particular geological feature depends on the direction and magnitude of the forces that are acting on it.
Geological features are landforms that are made up of natural formations. A wide variety of geological features exist in nature, including mountains, valleys, canyons, caves, and others.
There are a variety of geological features that can be created as a result of tensional, compressional, or shear stresses.
Let's take a closer look at each type of stress:
Tensional: Tensional forces act to pull rocks apart. This can result in the formation of fault-block mountains, valleys, and rifts.
Compressional: Compressional forces act to push rocks together. This can lead to the creation of mountain ranges, folded mountains, and plateaus.
Shear Stresses: Shear stresses act to twist or bend rocks. This can result in the formation of faults, folds, and other geological features.
The forces that create geological features are typically produced by the movement of tectonic plates beneath the earth's surface.
When two tectonic plates come together, they can create compressional forces. When they move apart, they can create tensional forces.
When they slide past each other, they can create shear stresses. Other forces can also play a role, such as erosion or the buildup of sediment over time.
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A 200 g air-track glider is attached to a spring. The glider is pushed 10.0 cm against the spring, then released. A student with a stopwatch finds that 10 oscillations take 12.0 s. What is the spring constant? A 200 g ball is tied to a string. It is pulled to an angle of 8.00degree and released to swing as a pendulum. A student with a stopwatch finds that 10 oscillations take 12.0 s. How long is the string?
The spring constant of spring is 39.9 N/m and the length of the string is about 47.5 meters.
What is spring constant?Mass of the air-track glider (m) = 200 g = 0.2 kg
Displacement of the air-track glider (x) = 10.0 cm = 0.1 m
Number of oscillations (n) = 10
Time taken for 10 oscillations (t) = 12.0 s
T = 2π√(m/k)
where, T is the time period of oscillation. Substituting the given values, we get:
12 s = 2π√(0.2 / k)
Solving for k, we get:
The spring constant is 39.9 N/m.
Mass of the ball (m) = 200 g = 0.2 kg
Angle of displacement (θ) = 8.00°
Number of oscillations (n) = 10
Time taken for 10 oscillations (t) = 12.0 s
T = 2π√(L/g)
where, T is the time period of oscillation and g is the acceleration due to gravity. Substituting the given values, we get:
12 s = 2π√(L/9.8)
Solving for L, we get:
L = (12/2π)² × 9.8 = 47.5 m
Therefore, the length of the string is 47.5 meters.
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Imagine sitting on a merry-go-round and riding along as it spins. Assuming you are not grabbing it anywhere and are not moving with respect to the platform,
A. static friction (directed inwards) causes you to accelerate.
B. you are not accelerating because you aren't moving on the platform.
C. static friction (directed outwards) causes you to accelerate.
D. sliding friction makes you accelerate inwards.
The correct option is: Static friction (directed outwards) causes you to accelerate. (Option C)
When you sit on a merry-go-round, you are not moving relative to the platform. Therefore, you are not in motion in respect to the reference frame of the platform.
The question is asking you to determine the force that causes you to accelerate as the merry-go-round spins.
Static friction is the force that keeps an object at rest or keeps it moving in a straight line when a force is applied to it.
When you're riding a merry-go-round and it starts to spin, static friction force helps you move outwards. This force opposes the force that pulls you towards the center of the platform, i.e., centripetal force.
So the correct option is C: Static friction (directed outwards) causes you to accelerate.
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yoda is 500km above the surface of the earth. if yoda have a mass of 96kg, what speed must he have to stay in a circular orbit around the earth at that altitude.
To stay in a circular orbit around the Earth at 500 km altitude, Yoda must have a speed of 7.9 km/s. Yoda must be moving at a speed of approximately 7,901 m/s to stay in a circular orbit around the Earth at an altitude of 500 km.
The altitude of Yoda above the surface of the Earth is 500km. To stay in a circular orbit around the Earth at that altitude, Yoda needs a certain speed. What is that speed? The answer is that the speed that Yoda needs to stay in a circular orbit around the Earth at an altitude of 500km is 7793.61 m/s.To stay in a circular orbit around the Earth at a constant altitude of 500 km, Yoda must be moving at a specific speed, known as the orbital velocity. This velocity is determined by the gravitational force between Yoda and the Earth, which must balance the centrifugal force of Yoda's motion around the Earth.
The orbital velocity can be calculated using the following equation:
v = sqrt(GM/r)
where v is the orbital velocity, G is the gravitational constant, M is the mass of the Earth, and r is the distance from the center of the Earth to Yoda's position, which is the sum of the Earth's radius and Yoda's altitude above the surface.
Substituting the given values, we have:
v = sqrt((6.6743 x 10^-11 m^3 kg^-1 s^-2) x (5.9722 x 10^24 kg) / (6,371 km + 500 km))
Note that we have converted the altitude of Yoda into kilometers and added it to the radius of the Earth (6,371 km) to obtain the distance from the center of the Earth to Yoda's position.
Simplifying the equation, we get:
v = sqrt(3.986 x 10^14 m^3 s^-2)
v ≈ 7,901 m/s
Therefore, Yoda must be moving at a speed of approximately 7,901 m/s to stay in a circular orbit around the Earth at an altitude of 500 km.
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three forces applied to a trunk that moves leftward by 3.010 m over a frictionless floor. The force magnitudes are F1 = 5.86 N, F2 = 9.180 N, and F3 = 3.850 N, and the indicated angle is θ = 67.8°. During the displacement, what is the net work done on the trunk by the three forces? (Note that there are other forces acting on the block, but we only care about the net work done by these three forces.) And by how much does the kinetic energy of the trunk increase (enter a positive value) or decrease (negative value)?
The kinetic energy of the trunk increases by ½ mvf² = ½ m(10.65 m/s)²= 71.44 J during the displacement.
Net work = ΔK
W = Fd cosθ
W1 = F1d cosθ = (5.86 N)(3.010 m) cos(67.8°) = 6.99 J
W2 = F2d cosθ = (9.180 N)(3.010 m) cos(67.8°) = 10.97 J
W3 = F3d cosθ = (3.850 N)(3.010 m) cos(67.8°) = 4.58 J
Net work = W1 + W2 + W3 = 6.99 J + 10.97 J + 4.58 J = 22.54 J
Therefore, the net work done on the trunk by the three forces is 22.54 J.
ΔK = ½ mvf² - ½ mvi²
Since the trunk moves a distance of 3.010 m and is initially at rest, we can use the equation:
vf² = 2ad
where a is the acceleration of the trunk, which is given by:
a = ΣF / m
where ΣF is the net force on the trunk, which we can find using:
ΣF = F1 + F2 + F3
ΣF = (5.86 N + 9.180 N + 3.850 N) = 18.89 N
Therefore, the acceleration of the trunk is:
a = ΣF / m = 18.89 N / m
Since the trunk moves leftward, the acceleration is also leftward, so we can use a negative value for a.
Substituting the values for a and d, we get:
vf² = -2(-18.89 N / m)(3.010 m) = 113.51 (m/s)²
Taking the square root, we get:
vf = 10.65 m/s
Therefore, the change in kinetic energy of the trunk is:
ΔK = ½ mvf² - ½ mvi² = ½ m(10.65 m/s)²- 0 = ½ mvf²
Kinetic energy is a type of energy that an object possesses by virtue of its motion. It is defined as the energy an object has due to its motion and is proportional to the mass of the object and the square of its velocity. The formula for kinetic energy is KE = 1/2mv^2, where m is the mass of the object and v is its velocity.
Kinetic energy is a scalar quantity and has units of joules in the International System of Units (SI). It is a fundamental concept in physics and is used to describe many physical phenomena, including the motion of particles, the behavior of gases, and the motion of waves. In many cases, kinetic energy can be transformed into other forms of energy. For example, when a ball is thrown upwards, its kinetic energy is gradually converted into gravitational potential energy as it moves higher and higher.
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A solar sailplane is going from Earth to Mars. Its sail is oriented to give a solar radiation force of FRad = 7.70 × 102 N. The gravitational force due to the Sun is 173 N and the gravitational force due to Earth is 1.00 × 102 N. All forces are in the plane formed by Earth, Sun, and sailplane. The mass of the sailplane is 14,900 kg. What is the magnitude of the acceleration on the sailplane? Answer in m/s2
The sailplane which is going from Earth to Mars is accelerating at 0.033 m/s² in the direction of solar radiation force.
The force of gravity is a force that arises as a consequence of the mutual attraction of two objects. This gravitational force is usually exerted between two physical objects. Newton's law of universal gravitation states that every point mass in the universe attracts every other point mass with a force that is proportional to the product of their masses.
Acceleration is the rate at which an object changes its speed or direction. Acceleration is a vector quantity that can be positive or negative. If the acceleration is negative, the object slows down. If the acceleration is positive, the object speeds up.
The acceleration on the sailplane can be determined using the following formula:
[tex]F_{net} = ma[/tex]
Where Fnet is the net force acting on the sailplane, m is the mass of the sailplane a is the acceleration on the sailplane.[tex]F_{net} = ma[/tex]
The net force acting on the sailplane can be calculated as:
[tex]F_{net} = F_{rad} - F_{gravitySun} - F_{gravityEarth}[/tex]
Where [tex]F_{rad}[/tex] is the solar radiation force, [tex]F_{gravitySun}[/tex] is the gravitational force due to the sun, and [tex]F_{gravityEarth}[/tex] is the gravitational force due to Earth.
Putting the given values in the above formula:
[tex]F_{net} = 7.70 \times 10^2 N - 173 N - 1.00 \times 10^2 N = 497 N[/tex]
The acceleration on the sailplane is given as:
[tex]a = F_{net} / ma = (497\ N) / 14,900 \ kg = 0.033 \ m/s^2[/tex]
The magnitude of the acceleration on the sailplane is 0.033 m/s² (rounded to three significant figures).
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if two tiny identical spheres attract each other with a force of 2.0 nn when they are 29 cm apart, what is the mass of each sphere? express your answer with the appropriate units.
The mass of each sphere with the appropriate units are the 0.6 kg by the two tiny identical spheres attract each other with a force of 2.0 nn when they are 29 cm apart.
Let's consider the following scenario: Two tiny identical spheres attract each other with a force of 2.0 nn when they are 29 cm apart. The mass of each sphere is what we need to calculate. The formula for calculating the mass of each sphere. F = Gm1m2 / r²Where:F = Force. G = Gravitational constantm1 and m2 = the masses of the object sr = the distance between the objects.
Substitute the given values: Force (F) = 2.0 nn. Distance (r) = 29 cm = 0.29 m. Gravitational constant (G) = 6.67 × 10-11 N.m²/kg²Find the mass of each sphere.m1 = m2 = m. Multiply the entire equation by ][tex]r² / G:m² = F × r² / G = (2.0 nn) × (0.29 m)² / 6.67 × 10-11 N.m²/kg²= 0.6 kg.[/tex]
Therefore, each sphere's mass is 0.6 kg.
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A horizontal force of magnitude 35.0N pushes a block of mass 4.00kg across a floor where the coefficient of kinetic friction is 0.600. (a) how much work is done by the applied force on the block-floor system when the block slides through a displacement of 3.00m across the floor? (b) during that displacement the thermal energy if the block increases by 40.0J. what is the increase in thermal energy of the floor? (c) what is the increase in the kinetic energy of the block?
Answer to following (a) , (b) and (c) question are: 63.00 J, 40.0 J, 63.00 J
(a) The work done by the applied force on the block-floor system when the block slides through a displacement of 3.00m across the floor can be calculated by multiplying the applied force (35.0 N) and the displacement (3.00 m), with a coefficient of kinetic friction (0.600) for the system. Thus, the work done is 35.0N * 3.00m * 0.600 = 63.00 J.
(b) The increase in the thermal energy of the floor during the displacement of 3.00m is equal to the thermal energy of the block (40.0 J), since the total thermal energy of the block-floor system remains constant. Therefore, the increase in thermal energy of the floor is 40.0 J.
(c) The increase in the kinetic energy of the block is equal to the work done by the applied force, i.e., 63.00 J.
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Taking the following list on an item-by-item basis (i.e., without considering the other listed factors), a maintenance expenditure should be capitalized if the expenditure:
increases the salvage value of the asset.
extends the useful life of the asset.
A maintenance expenditure should be capitalized if it increases the salvage value of the asset or extends the useful life of the asset.
An expenditure is a payment made in return for a product or service. Capital expenditure is money spent by a company on long-term assets like equipment and buildings.
Capitalizing refers to recording a cost or expense on the balance sheet for a future period rather than recognizing it immediately in the current period.
Capitalizing expenditure means the company will recognize the expenditure as an asset, which will be amortized over its useful life as opposed to expenses in the current period.
Therefore, a maintenance expenditure should be capitalized if the expenditure increases the extends the useful life of the asset.
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A marble rolled down an inclined ramp with an acceleration of 0.500 m/s for 7.00 seconds will travel meters from the point where it was released, A. 12.3 B. 24.5 C. 1.80 D. None of the above
The marble that rolled down an inclined ramp with an acceleration of 0.500 m/s for 7.00 seconds will travel 12.3 meters from the point where it was released. Thus, the correct option is A.
What is the distance covered by marble?An inclined ramp is a simple machine that reduces the amount of force needed to move an object up an incline. The force that makes the marble move is gravity. When a ball is rolled down an inclined ramp, it gains speed and momentum due to gravity. The formula for the distance travelled by a ball is given by:
d = (1/2) × a × t²
where, a is the acceleration of the ball, t is the time for which the ball is rolled down the ramp, d is the distance travelled by the ball.
Using the above formula, we can calculate the distance travelled by the ball. So, substituting the given values in the formula:
d = (1/2) × 0.500 m/s² × (7.00 s)²
d = (1/2) × 0.500 m/s² × 49.00 s²
d = 12.3 meters
Therefore, the correct option is A.
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in addition to hundreds of smaller objects they have been discovering in the kuiper belt recently, astronomers were surprised to find
In addition to hundreds of smaller objects they have been discovering in the Kuiper Belt recently, astronomers were surprised to find dwarf planet Eris.
The first object that was bigger than Pluto was Eris. The initial estimate of Eris' size was 1,240 miles (2,000 kilometers) in diameter. It was later discovered to be a bit smaller, with a diameter of 1,163 miles (1,864 kilometers). Its moon, Dysnomia, was also discovered.Eris' orbit is far more eccentric than Pluto's, ranging from 38 to 97 astronomical units (AU) from the Sun.
Eris takes 557 Earth years to orbit the Sun. Despite the fact that Pluto's path also varies in shape, it is always closer to the Sun than Eris. Pluto and Eris were both discovered in the early 21st century, in 1930 and 2005, respectively. Because it was the largest known body in the Kuiper Belt, Pluto was formerly classified as the Solar System's ninth planet. Following the discovery of Eris and other trans-Neptunian objects, Pluto was reclassified as a dwarf planet.
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a very long straight wire carries current 32 a. in the middle of the wire a right-angle bend is made. the bend forms an arc of a circle of radius 14 cm, as show. determine the magnetic field at the center of the arc.
Therefore, the magnetic field at the center of the arc is 1.005 × 10^-5 T.The formula to determine the magnetic field at the center of the arc of a circle is given by: B = μ₀ I / (4πr)Where,B = magnetic fieldI = current in the wirer = radius of the arc of a circleμ₀ = permeability of free space.
Let P1, P2, and P3 be the three points on the wire as shown in the diagram above, where the bend is at point P2.
The current element dl is pointing out of the page, perpendicular to the plane of the diagram. The magnetic field at point P, which is the center of the arc, is pointing upwards, also perpendicular to the plane of the diagram.
Using the right-hand rule for the cross product, we can see that the direction of the magnetic field due to this current element is clockwise around the current element. Therefore, the contribution of this current element to the magnetic field at point P is pointing downwards.
The distance from the current element dl to point P is the radius of the arc, which is 14 cm. Therefore, we can write:
dB = (μ₀/4π) * (I dl / r²)
We can now integrate this expression over the length of the arc, which is half the circumference of a circle of radius 14 cm:
B = 2 * ∫[0,π] dB = 2 * ∫[0,π] (μ₀/4π) * (I dl / r²)
where the limits of integration are from 0 to π because we are only considering half of the arc.
Since the arc is a quarter of a circle, the length of the arc is (π/2) * 2r, where r is the radius of the arc. Therefore, we can write:
dl = (π/2) * 2r * dθ
where dθ is a small angle element. Substituting this into the integral, we get:
B = 2 * ∫[0,π] (μ₀/4π) * (I (π/2) * 2r * dθ / r²)
Simplifying, we get:
B = (μ₀I/4) * ∫[0,π] dθ
Integrating, we get:
B = (μ₀I/4) * [π - 0]
Finally, substituting the values, we get:
B = (4π × 10^-7 T m/A × 32 A/4) * π
B = 1.005 × 10^-5 T
Therefore, the magnetic field at the center of the arc is 1.005 × 10^-5 T.
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member bc exerts on member ac a force p directed along line bc. knowing that p must have a 325-n horizontal component, determine (a) the magnitude of the force p, (b) its vertical component.
(a) The magnitude of the force p=325 / cos θPart, (b) Vertical component is 325 tanθ
(a) Given: Force F = P And horizontal component Fcos θ = 325N. Here, θ is the angle made by the force with the horizontal, and θ is unknown. According to the figure, member AC is inclined at an angle θ to the horizontal.
Let's resolve the force P into vertical and horizontal components. So, vertical component Fsine θ and horizontal component Fcos θ, where θ is the angle made by the force with the horizontal, and θ is unknown.
Thus, we get: Fcos θ = 325Fcos θ / F = 325 / cos θPart
(b) Vertical component = Fsine θ = (F)(sinθ)Vertical component = (325 / cosθ)(sinθ) = 325 tanθ
Thus, the magnitude of the force p is 325 / cosθ, and the vertical component of the force is 325 tanθ.
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you have an rc circuit with a time constant of 5.35 s. if the total resistance in the circuit is 231.2 k , what is the capacitance of the circuit (in f)? don't type the units into the answer box.
The capacitance of the circuit (in f) is 2.31×10⁻⁵F for the rc circuit with a time constant of 5.35 s. if the total resistance in the circuit is 231.2 k.
What is the capacitance of the circuit?The capacitance of an RC circuit can be calculated using the equation C = τ/(R), where τ is the time constant, R is the total resistance, and C is the capacitance. For this RC circuit, the time constant is 5.35s and the total resistance is 231.2 k. Therefore, the capacitance is 5.35s/(231.2k) = 2.31×10⁻⁵F.
Time constant of the RC circuit, τ = 5.35s
Total resistance in the circuit, R = 231.2 kΩ = 231200 Ω
Capacitance of the circuit = ?
We know that, Time constant (τ) of a RC circuit = R × C.
where, R is the resistance in ohms, C is the capacitance in farads. Substitute the given values in the above equation:
τ = RC
5.35 s = R × C231200 Ω × C = 5.35 s
C = 5.35 s / 231200 Ω
C = 2.31 × 10⁻⁸ F.
Therefore, the capacitance of the circuit is 2.31 × 10⁻⁸ F.
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a) When we blow air with our mouth narrow open, we feel the air cool. When the mouth
is made wide open, we feel the air warm. What are the thermodynamic processes involved in these processes? Explain. [2]
As the air is compressed, the work done on the air causes its temperature to increase.
What is Thermodynamic Process?
A thermodynamic process is a physical change that occurs in a system as it exchanges heat and/or work with its surroundings. It involves a change in one or more thermodynamic variables, such as temperature, pressure, volume, or entropy. There are four main types of thermodynamic processes: isothermal, adiabatic, isobaric, and isochoric.
When we blow air with our mouth narrow open, we feel the air cool because of the adiabatic expansion of the air. Adiabatic expansion is a thermodynamic process in which the air expands rapidly without losing or gaining any heat to or from the surroundings. As the air expands, it does work against the pressure of the surrounding atmosphere, and this work causes the temperature of the air to decrease. This is known as the Joule-Thomson effect.
On the other hand, when the mouth is made wide open, we feel the air warm because of the adiabatic compression of the air. Adiabatic compression is a thermodynamic process in which the air is compressed rapidly without losing or gaining any heat to or from the surroundings.
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a big block of mass m(10kg) slides down a frictionless inclined at an angle 30 with the horizontal table. initially the block is at the top of the incline at rest. determine the speed of the block at the bottom of the incline
When the big block of mass m(10kg) slides down a frictionless inclined at an angle 30 with the horizontal table, the speed of the block at the bottom of the incline is 3.14 m/s.
Given that
Mass of the block, m = 10 kg.
Angle of inclination, θ = 30°
Initial velocity, u = 0.
Frictional force, f = 0.
Using the formula for gravitational force, F = mg
where, g = 9.8 m/s² (acceleration due to gravity)
F = mg= 10 kg × 9.8 m/s²= 98 N
The component of gravitational force that acts parallel to the incline, Fsinθ is responsible for the acceleration of the block. Fsinθ = ma; Where a is the acceleration of the block.
a= (98 N)sin 30° / 10 kg= 4.9 m/s²
Using the formula for speed, v = u + at where,
u = initial velocity = 0m/s
t = time taken = time taken to slide from top to bottom of the incline.= √(2h/g) where,
h = height of the incline = 2 m (since the mass is at rest initially at the top of the incline).
Therefore, t = √(2 × 2 m / 9.8 m/s²)= 0.64 s
Substituting the values in the above formula, v = u + at= 0 + (4.9 m/s² × 0.64 s)= 3.14 m/s.
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spherical capacitor contains a charge of 3.20nCwhen connected to a potential difference of250V. If its plates are separated by vacuum and theinner radius of the outer shell is 4.60cm.
A) Calculate the capacitance.
B) Calculate the radius of the inner sphere.
C) Calculate the electric field just outside the surface of theinner sphere.
A) The capacitance of the spherical capacitor is 1.45 pF (picofarads), B) The radius of the inner sphere is 3.60 cm. and C) The electric field just outside the surface of the inner sphere is [tex]2.36 * 10^6 V/m[/tex] (volts per meter).
To calculate the capacitance, we can use the formula C = Q/V, where Q is the charge and V is the potential difference. Plugging in the values, we get [tex]C = (3.20 * 10^{-9} C)/(250 V) = 1.28 * 10^{-11} F[/tex].
However, since the capacitor is a spherical one, we need to use the formula for the capacitance of a spherical capacitor, which is [tex]C = (4\pi \epsilon_0)(r_1 r_2)/(r_2-r₁)[/tex], where r₁ and r₂ are the radii of the two shells and ε0 is the permittivity of free space.
Rearranging the formula and plugging in the values, we get [tex]r_1 = (C/4\pi \epsilon_0)(r_2-r_1)/r_2,[/tex] which gives us r₁ = 3.60 cm.
To calculate the electric field just outside the surface of the inner sphere, we can use the formula
E = [tex]\frac{Q}{4\pi\epsilon_0 r^2}[/tex], where r is the radius of the inner sphere.
Plugging in the values, we get [tex]E = (3.20 * 10^{-9} C)/(4\pi\epsilon_0(0.0460 m)^2) = 2.36 * 10^6 V/m.[/tex]
This electric field arises due to the charge on the inner sphere and induces an opposite charge on the outer shell of the capacitor.
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While you stand on the floor you are pulled downward by gravity and supported upward by the floor. Gravity pulling down and the support force pushing up
answer choicesa. make an action-reaction pair of forces.
b. do not make an action-reaction pair of forces.
c. need more information
While you stand on the floor you are pulled downward by gravity and supported upward by the floor. Gravity pulling down and the support force pushing up make an action-reaction pair of forces (option A)
What is an action-reaction pair of forces?Action-reaction pair of forces is a term that refers to a pair of forces that are the same in size but opposite in direction. The action force is applied by an object on another object, whereas the reaction force is the force that the second object exerts on the first object in response to the action force. As an illustration, if an object A exerts a force on object B, then object B exerts a force back on object A which is equal in size but opposite in direction.
The given statement "While you stand on the floor you are pulled downward by gravity and supported upward by the floor" is describing a situation that involves two forces: gravity and the support force exerted by the floor.
Gravity is pulling you downward, while the support force exerted by the floor is pushing you upward.The force exerted by the floor on you and the force exerted by you on the floor are action-reaction pairs. This is because the support force exerted by the floor on you and the force you exert on the floor are equal in magnitude but opposite in direction, and they are both part of the same interaction.
Therefore, the correct option is (a) make an action-reaction pair of forces.
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A block of mass m is at rest at the origin at t=0. It is pushed with constant force F0 from x=0 to x=Lacross a horizontal surface whose coefficient of kinetic friction is μk=μ0(1−x/L). That is, the coefficient of friction decreases from μ0 at x=0 to zero at x=L.
Part A
We would like to know the velocity of the block when it reaches some position x. Finding this requires an integration. However, acceleration is defined as a derivative with respect to time, which leads to integrals with respect to time, but the force is given as a function of position. To get around this, use the chain rule to find an alternative definition for the acceleration ax that can be written in terms of vx and dvxdx. This is a purely mathematical exercise; it has nothing to do with the forces given in the problem statement.
Express your answer in terms of the variables vx and dvxdx.
I got the answer:
ax =
dvxdxvx
And this was correct, but Im having trouble with Part B:
Now use the result of Part A to find an expression for the block's velocity when it reaches position x=L.
Express your answer in terms of the variables L, F0, m, μ0, and appropriate constants.
To start, let's examine the forces that the block is subjected to as it moves from x=0 to x=L.
The block is at rest at the beginning of the motion (x=0), thus there is no net force acting on it. F0 is the force pushing the block, and f = k N = k mg, where N is the normal force and g is the acceleration brought on by gravity, is the force of kinetic friction acting in the opposite direction. The block is stationary, thus we have:
F0 - μ0 mg = 0
The force pushing the block must thus be equal to and in opposition to the force of friction.
The coefficient of kinetic friction changes as the block travels over the surface.
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The colors on an oil slick are caused by reflection and (explain why)
a. Diffraction
b. Interference
c. Refraction
d. Polarization
e. Ionization
"The colours on an oil slick are caused by reflection and interference." Correct option is B.
Different bands of the oil slick create different colours as the oil film progressively thins from the centre to the edges.
Interference is what gives an oil slick drifting on water or a soap bubble in the sun their vibrant colours. The colours that interact most positively are the ones that are most vibrant. Thin film interference is the name given to the phenomenon because it occurs when light reflected from various thin film surfaces interferes with one another.
The most crucial interfering principle is the superposition principle.
This hair colour procedure primarily uses jewel tones and rainbow colours, including burgundy, royal blue, deep purple, green, and deep red. Alternating the colours that give your hair an oil spill appearance is the best method to make your skin tone and hair look good together. Best choice is B.
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When current flows through a conductor, it develops a magnetic field of concentric circles expanding ? and outward from the conductor. a. circularly b. parallel c. perpendicular d. wavy
When a current travels through a conductor in a circular motion, a magnetic field with growing concentric circles is created.
What happens when current flows through a conductor?Electromagnetism is established when an electrical current flows through a simple conductor, such as a length of wire or cable.
What magnetic field is created when current travels through a conductor?As magnetic fields produced by moving charges are proportional to the current, a conductor carrying current creates a magnetic field around it. Generally speaking, the sub-atomic particles in the conductor, such as the moving electrons in the atomic orbitals, are responsible for this magnetic field.
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When a ball bounces against a wall there will be large change in velocity in short period of time. This means the ____ is large, hence the net ___ must be proportionately large as well.
A change in velocity in short period of time means the acceleration is large, hence the net force must be proportionately large as well.
What is a force?A force is a physical quantity that induces a body to undergo an alteration in speed, direction of motion, or shape. A force can be classified as a push or a pull. When forces are equal, the forces are balanced and the object is not moving. Otherwise, if the forces are not equal, making it unbalanced will not give the object any movement.
The force that induces the change in the speed or direction of an object is referred to as a net force. The net force is equal to the product of the mass of the object and its acceleration. Newton (N) is the unit of measurement for force.
When a ball bounces against a wall, there will be a large change in velocity in a short period of time. This means the acceleration is large, hence the net force must be proportionately large as well.
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at what angle above the horizon is the sun when light reflecting off a smooth lake is polarized most strongly?
The sun is at an angle of approximately 37 degrees above the horizon when light reflecting off a smooth lake is polarized most strongly.
When unpolarized light reflects off a smooth surface, such as a lake, it becomes polarized in a direction perpendicular to the surface. The angle at which this polarization is strongest is known as the Brewster angle, and can be calculated using the formula:
θB = arctan(n2/n1)
where θB is the Brewster angle, n1 is the index of refraction of the medium the light is coming from, and n2 is the index of refraction of the medium the light is entering.
For water, the index of refraction is approximately 1.33, and for air it is approximately 1.00. Plugging these values into the formula, we get:
θB = arctan(1.33/1.00) = 53.1 degrees
However, this is the angle at which the light is reflected off the surface in a direction perpendicular to the surface. To find the angle above the horizon at which the light is polarized most strongly, we need to subtract 90 degrees from the Brewster angle:
37 degrees = 90 degrees - 53.1 degrees
Therefore, the sun is at an angle of approximately 37 degrees above the horizon when light reflecting off a smooth lake is polarized most strongly.
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Galena's specific gravity is 7.5, that of quartz 2.65, and that of liquid mercury 13.6. Given equal-sized samples (volumes) of galena and quartz, which will feel heavier? Choose one: A. galena B. The same volume of water will feel heavier than both of them. C. They will feel about equal. D. quartz
Given equal-sized samples (volumes) of galena and quartz, the Galena sample will feel heavier because of its higher specific gravity. Thus, the correct option is A.
What is the Specific gravity of a substance?Specific gravity is the ratio of the density of a substance to the density of a standard substance in physics. It's typically applied to liquids and solids, but it may also be applied to gases. The most often utilized standard material for liquids and solids is water at 4°C. A substance's specific gravity is dimensionless and is often represented by the Greek symbol ρ.
Relative Density of the given substances:
Galena's specific gravity is 7.5, Quartz's specific gravity is 2.65, and Liquid mercury's specific gravity is 13.6. An object with a specific gravity greater than 1 sinks in water, while one with a specific gravity less than 1 floats in water. The specific gravity of water is 1.0. An object with a specific gravity greater than 1 sinks in water, while one with a specific gravity less than 1 floats in water.
We can conclude from the values above that liquid mercury is heavier than galena, which is in turn heavier than quartz. Therefore, since both quartz and galena are being measured with equal sizes or volumes, galena will feel heavier than quartz.
Therefore, the correct option is A.
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Problem 1. In this problem, you need to determine the additive inverse1of each given vector in the appropriate vector space. (a)[ 23]inR 2. (b)−1+3x−8x 2inP 2. (c)[ 12−20]inM 2×2.
The additive inverse of each given vector in the appropriate vector space are
(a) The additive inverse of [2, 3] in [tex]R_2[/tex] is [-2, -3].
(b) The additive inverse of [tex]-1 + 3x - 8x^2[/tex] in P2 is [tex]1 - 3x + 8x^2[/tex].
(c) The additive inverse of [1, 2; - 2, 0] in [tex]M_{2\times2[/tex] is [-1, -2; 2, 0].
The additive inverse of a vector [tex]\mathbf{v}[/tex] in a vector space is the vector [tex]-\mathbf{v}[/tex] that, when added to [tex]\mathbf{v}[/tex], gives the zero vector.
(a) The additive inverse of the vector [tex][2, 3] \in \mathbb{R}^2[/tex] is [tex][-2, -3][/tex] since [tex][2, 3] + [-2, -3] = [0, 0][/tex].
(b) The vector space [tex]P_2[/tex] consists of all polynomials of degree at most [tex]2[/tex]. The vector [tex]-1 + 3x - 8x^2 \in P_2[/tex] has additive inverse [tex]1 - 3x + 8x^2[/tex], since [tex](-1 + 3x - 8x^2) + (1 - 3x + 8x^2) = 0[/tex].
(c) The vector space [tex]M_{2 \times 2}[/tex] consists of all [tex]2 \times 2[/tex] matrices. The matrix [tex][1, 2; -2, 0] \in M_{2 \times 2}[/tex] has additive inverse [tex]$[-1, -2; 2, 0]$[/tex], since [tex]\begin{bmatrix} 1 & 2 \ -2 & 0 \end{bmatrix} + \begin{bmatrix} -1 & -2 \ 2 & 0 \end{bmatrix} = \begin{bmatrix} 0 & 0 \ 0 & 0 \end{bmatrix}[/tex].
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Acceleration due to gravity is 9.8 m/s2 on the surface of Earth, and at orbits 200 miles above the surface of Earth, where the space shuttle orbits, the acceleration is
Acceleration due to gravity is 9.8 m/s2 on the surface of Earth, and at orbits 200 miles above the surface of Earth, where the space shuttle orbits, the acceleration is 8.78 m/s².
What is gravitational force?The reason for this difference in acceleration is that the gravitational force on an object is inversely proportional to the square of the distance between them.
Thus, the further an object is from the Earth's surface, the weaker the gravitational force acting on it. This is why objects in orbit around the Earth experience less acceleration due to gravity than objects on the surface of the Earth.
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The straight section of the line in figure 10 can be used to calculate the useful power output of the kettle explain how
Using the line's straight segment in figure 10, it is possible to determine the usable power output of the kettle.
The period that the kettle is heating the water up until it reaches boiling point is depicted by the straight segment of the line in figure 10. Both the power input to the kettle and the rate of energy transfer to the water remain constant throughout this period. Hence, by dividing the energy that was transmitted to the water during this period by the whole amount of time, the usable power output of the kettle can be determined. The straight section's slope, which reflects the rate of energy transfer, and horizontal distance, which indicates the elapsed time, may be used to calculate this. The energy transmitted is calculated by dividing the rate of energy transmission by the amount of time.
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