For a popular Broadway music the theater box office sold 356 tickets at $80 a piece275 tickets at $60 a piece and 369 tickets at $ 45 a piece. How much money did the box office take in?

9514 1404 393

Answer:

  D.  $584.43

Step-by-step explanation:

Using the given formula with the given values, we find ...

  A(17) = 150·e^(0.08·17) = 584.43

Answer:

612,300

600,000

10,000

2,000

300

00

0

Answer:

Step-by-step explanation:

#include <stdio.h>

int main()

{

  int num1, num2, flag_var, i, j;

  /* Ask user to input the from/to range

   * like 1 to 100, 10 to 1000 etc.

   */

  printf("Enter two range(input integer numbers only):");

  //Store the range in variables using scanf

  scanf("%d %d", &num1, &num2);

  //Display prime numbers for input range

  printf("Prime numbers from %d and %d are:\n", num1, num2);

  for(i=num1+1; i<num2; ++i)

  {

     flag_var=0;

     for(j=2; j<=i/2; ++j)

     {

        if(i%j==0)

        {

           flag_var=1;

           break;

        }

     }

     if(flag_var==0)

        printf("%d\n",i);

 }

 return 0;

}

Answer:

cannot understand the language man

but please follow

Step-by-step explanation:

When adding two fractions with different bases (bottom numbers), we can use this function:

[tex]\frac{a}{b} + \frac{c}{d} = \frac{ad + cb}{bd}[/tex]

So, to apply this to the given question:

[tex]\frac{x+3}{x-6} +\frac{1}{x-2}[/tex]

= [tex]\frac{(x+3)(x-2)+(1)(x-6)}{(x-6)(x-2)}[/tex]

From the given answers, we see we don't need to simplify the resulting base number, which makes things a lot easier.

= [tex]\frac{[(x*x) + (x*-2)+(3*x)+(3*-2)]+(x-6)}{(x-6)(x-2)}[/tex]

= [tex]\frac{[x^2 -2x+3x-6]+(x-6)}{(x-6)(x-2)}[/tex]

= [tex]\frac{x^2 -2x+3x-6+x-6}{(x-6)(x-2)}[/tex]

= [tex]\frac{x^2 +2x-12}{(x-6)(x-2)}[/tex]

Now if we wanna be a little smart, we can see that from here, the only answer that has x^2 and something else, is A. But, just for show, lets factor.

= [tex]\frac{x(x+2)}{(x-6)(x-2)}[/tex]

Answer:

A) [tex]\frac{x(x+2)}{(x-6)(x-2)}[/tex]

Answer:

[tex]a_5= 14[/tex]

[tex]a_{20}= 80[/tex]

[tex]a_{18}= 340[/tex]

Step-by-step explanation:

Solving (a):

We have:

[tex]a_1=2[/tex] --- first term

[tex]d = 5 -2 = 3[/tex] common difference

The 5h term is:

[tex]a_n= a_1 + (n - 1)d[/tex]

[tex]a_5= 2+ (5 - 1)*3[/tex]

[tex]a_5= 14[/tex]

Solving (b):

We have:

[tex]a_1 = 4[/tex] --- first term

[tex]d = 8 -4 = 4[/tex] common difference

The 20h term is:

[tex]a_n= a_1 + (n - 1)d[/tex]

[tex]a_{20}= 4+ (20 - 1)*4[/tex]

[tex]a_{20}= 80[/tex]

Solving (c):

We have:

[tex]a_1 = 0[/tex] --- first term

[tex]d = 20 -0 = 20[/tex] common difference

The 18th term is:

[tex]a_n= a_1 + (n - 1)d[/tex]

[tex]a_{18}= 0+ (18 - 1)*20[/tex]

[tex]a_{18}= 340[/tex]

Answer:

The butter for one portion cost $ 0.375.

Step-by-step explanation:

Given that you buy butter for $ 3 a pound, and one portion of onion compote requires 2 oz of butter, to determine how much does the butter for one portion cost, the following calculation must be performed:

2 oz = 0.125 lb

1 = 3

0.125 = X

3 x 0.125 = X

0.375 = X

Therefore, the butter for one portion cost $ 0.375.

Answer:

c. 2

Step-by-step explanation:

 2 (3x – y = -2)               6x - 2y = -4

6x - 2y = -4

9514 1404 393

Answer:

  94.9

Step-by-step explanation:

It is straightforward addition to find the sum of the two numbers to be 94.871. Perhaps you're interested in rounding to the appropriate precision.

Here, the number with the fewest digits right of the decimal point is 10.9. In order to round the addition result appropriately, that "exact" result must be rounded so it has this same number of digits to the right of the decimal point (1 digit).

  94.871 ≈ 94.9

_____

Additional comment

When you're asked to round a sum (or difference) to the appropriate precision, always first compute the exact result using the full precision of all contributors. Then determine the contributor with the least precision (least significant digit is farthest to the left), and round the result to that same precision.

Answer:

length = 20 inches

width = 13 inches

Step-by-step explanation:

l = length

w = width

area = l×w

perimeter = (2×l) + (2×w)

l = w + 7

l×w = 4×(2×l + 2×w) - 4

(w+7)×w = 4×(2×(w+7) + 2×w) - 4

w² + 7w = 4×(2w + 14 + 2w) - 4

w² + 7w = 8w + 56 + 8w - 4 = 16w + 52

w² - 9w - 52 = 0

the solution for a quadratic equation is

x = (-b ± sqrt(b² - 4ac))/(2a)

here we use now w instead of x.

and a=1

b=-9

c=-52

w = (9 ± sqrt(81 - -208))/2 = (9 ± sqrt(81+208))/2 =

= (9 ± sqrt(289))/2 = (9 ± 17)/2

w1 = (9+17)/2 = 26/2 = 13

w2 = (9-17)/2 = -8/2 = -4

and a negative length does not make any sense for a geometric shape.

so, only w1 = 13 applies.

l = w + 7 = 13 + 7 = 20

Answer:

4^5/4^2

Step-by-step explanation:

We know 1/a^b = a^-b

a^b/ a^c = a^(b-c)

1/4^3   = 4^-3

4^2/4^5 = 4^(2-5) = = 4^-3

4^5/4^2 = 4^(5-2) = 4^3

4^-3

Answer:

[tex]4^{5}/5^{2}[/tex] = not the same

Step-by-step explanation:

you have the equations

[tex]1/4^{3} = 0.015625\\\\4^{2}/4^{5} = 16/1024 = 0.015625\\\\4^{5}/4^{2} = 1024/16 = 65\\\\4^{-3} = 0.015625[/tex]

please mark this answer as brainlist

Answer:

y = 3x

Step-by-step explanation:

abscissa is the x coordinate

ordinate is the y coordinate

y = 3x

Answer:x2.2

Step-by-step explanation:

First

[tex]\\ \sf\longmapsto BD^2=AD\times DC[/tex]

[tex]\\ \sf\longmapsto BD^2=18^2+7^2[/tex]

[tex]\\ \sf\longmapsto BD^2=324+49[/tex]

[tex]\\ \sf\longmapsto BD^2=363[/tex]

[tex]\\ \sf\longmapsto BD=\sqrt{363}[/tex]

[tex]\\ \sf\longmapsto BD=19.2[/tex]

Now

Using Pythagorean theorem

[tex]\\ \sf\longmapsto BD^2+CD^2=m^2[/tex]

[tex]\\ \sf\longmapsto m^2=7^2+19.2^2[/tex]

[tex]\\ \sf\longmapsto m^2=49+363[/tex]

[tex]\\ \sf\longmapsto m^2=412[/tex]

[tex]\\ \sf\longmapsto m=\sqrt{412}[/tex]

[tex]\\ \sf\longmapsto m=20.3[/tex]

Nearest value in options is 18

Hence option a is correct

Step-by-step explanation:

Hope it is helpful.

Thank you.

9514 1404 393

Answer:

  55 units

Step-by-step explanation:

If two angles have the same measure, the triangle is isosceles. That means two sides have the same measure. Since the two given sides are different measures, the remaining side must be one of those. The perimeter will be greatest if the congruent sides are the longest. The greatest perimeter is ...

  15 + 20 + 20 = 55 . . . units

Answer:

im not sure but i do have a tip when you go to goo gle i want you to simplify your question (not what you asked on here) then copy your question as it is simple then search it on here because its slightly  for others to understand

Step-by-step explanation:

.

Answer: Missing segment = 45

Step-by-step explanation:

Concept:

Here, we need to know the idea of a similar triangle, ratio, and cross-multiplication.

In similar triangles, one can be obtained from the other by uniformly scaling (enlarging or reducing), possibly with additional translation, rotation and reflection. If two objects are similar, each is congruent to the result of a particular uniform scaling of the other.

A ratio is a quantitative relation between two amounts showing the number of times one value contains or is contained within the other.

Cross-multiplication means multiplying the numerator of each fraction by the other's denominator or the other way round.

If you are still confused, please refer to the attachment below for a graphical explanation.

Solve:

Let x be the length of missing segment

Step One: write the proportion ratio

56 / 56 + 24 = 105 / 105 + x

Step Two: Cross-multiplication

56 (105 + x) = 105 ( 56 + 24)

Step Three: Simplify parenthesis and expand it

56 ( 105 + x) = 105 (80)

5880 + 56x = 8400

Step Four: Subtract 5880 on both sides

5880 + 56x - 5880 = 8400 - 5880

56x = 2520

Step Five: Divide 56 on both sides

56x / 56 = 2520 / 56

x = 45

Hope this helps!! :)

Please let me know if you have any questions

Step-by-step explanation:

[tex]\triangle{ABC}[/tex] is similar to [tex]\triangle{ADE}[/tex] so we can write the ratio

[tex]\dfrac{x}{6+4} = \dfrac{2}{6}[/tex]

Solving for x, we get

[tex]x = \left(\dfrac{2}{6}\right)(10) = \dfrac{10}{3}[/tex]

Answer:

a. Relative Growth rate = 10% (6/60 * 100)

b. Number of cells after t hours = 50 * 1.1^t

c. Rate of growth after 6 hours = 77.2% (1.1⁶ - 1)

d. The number of cells after 6 hours is

= 89 cells

Step-by-step explanation:

A cell divides into two cells every 20 minutes

In one hour, the cell will divide into 60/20 * 2 = 6 cells

Each cell growth 6 cells per hour

Initial population of a culture = 50 cells

t = time in hours

a. Relative Growth rate = 10% (6/60 * 100)

b. Number of cells after t hours = 50 * 1.1^t

c. Rate of growth after 6 hours = 77.2% (1.1⁶ - 1)

d. The number of cells after 6 hours = initial population * growth factor

= 50 * 1.772

= 88.6

= 89 cells

Answer:

I think you can go with:

The margin of error is equal to half the width of the entire confidence interval.

so  try .74 ± [tex]\frac{.032}{2}[/tex]  =   [ .724 , .756] as the confidence interval

Step-by-step explanation:

Answer: Choice A

The number line graph is visually showing every number that is 19 or smaller; hence [tex]x \le 19[/tex]

Note the use of a closed or filled in circle at the endpoint (in contrast to an open circle). This indicates we are including the endpoint 19 as part of the solution set, and that's why we go for "or equal to" as part of the inequality sign.

Step-by-step explanation:

xx is the Roman number of 20

Answer:

(0.3478, 0.5522)

Step-by-step explanation:

Given:

Total number of red marbles, x = 45

Total number of marbles, n = 100

Phat = x / n = 45 / 100 = 0.45

The confidence interval, C.I is given by :

Phat ± Zcritical * standard error

Phat ± Zcritical * √Phat(1 - Phat) / n

Zcritical at 96% = 2.0537

The standard error = √Phat(1 - Phat) / n

S.E = √(0.45 * 0.55) / 100 = 0.0497493

C.I = 0.45 ± (2.0537 * 0.0497493)

C.I = 0.45 ± 0.10217013741

C. I = (0.3478, 0.5522)

on 220 acres

66 ⅔% is just ⅔ of 100%

330 * 2 / 3 = 220

There is no any image of rectangle

[tex]\large{\underline {\underline {\pmb {\sf {\pink{Answer:}}}}}}[/tex]

Answer:

The largest whole number is the approximate of positive infinity ( to the nearest ones digit )