For the following reaction of N2O4, the equilibrium constant is 0.593 at a particular temperature.
N2O4(g) ⇌ 2 NO2(g)
If the initial concentration of N2O4 is 0.880M, what are the equilibrium concentrations?

Please show work!

Answers

Answer 1

Answer:

"0.583" is the appropriate answer.

Explanation:

Let,

The initial constant of [tex]N_2O_4[/tex] be "C".

Amount of [tex]N_2O_4[/tex] dissociated into [tex]NO_2[/tex] be "x".

now,

                                     [tex]N_2O_4 \rightleftharpoons 2NO_2[/tex]

Initial constant               C            -

Equilibrium constant     C          2x

The Kc is given as:

⇒ [tex]K_c = \frac{[NO_2]^2}{[N_2O_4]}[/tex]

         [tex]=\frac{(2x)^2}{C-x}[/tex]

[tex]0.593=\frac{4x^2}{0.88-x}[/tex]

  [tex]4x^2=0.593(0.88-x)[/tex]

  [tex]4x^2=0.512-0.593\ x[/tex]

     [tex]x=0.291[/tex]

hence,

The constant of [tex]NO_2[/tex] will be:

= [tex]2x[/tex]

= [tex]0.583[/tex]


Related Questions

The solubility of gases
when the temperature is
increased.

A. increases
B. decreases
C. does not change

Answers

Answer:

B. decreases

Explanation:

The solubility of gases in a liquid is inversely proportional to the temperature, it means that if you increase the temperature, the solubility decreases.

How many moles of Cd and of N are contained in 132.4 g of Cd(N03)2-4H20? (b) How many molecules of water of hydration are in this same amount?

Answers

Answer: The given amount of [tex]Cd(NO_3)_2.4H_2O[/tex] contains 0.430 moles of Cd, 0.860 moles of N and [tex]2.59\times 10^{23}[/tex] molecules of water.

Explanation:

The number of moles is defined as the ratio of the mass of a substance to its molar mass. The equation used is:

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex] ......(1)

Given mass of [tex]Cd(NO_3)_2.4H_2O[/tex] = 132.4 g

Molar mass of [tex]Cd(NO_3)_2.4H_2O[/tex] = 308.5 g/mol

Plugging values in equation 1:

[tex]\text{Moles of }Cd(NO_3)_2.4H_2O=\frac{132.4g}{308.5g/mol}=0.430 mol[/tex]

1 mole of [tex]Cd(NO_3)_2.4H_2O[/tex] contains 1 mole of Cd, 2 moles of nitrogen atom (N), 10 moles of oxygen atom (O) and 8 moles of hydrogen atom (H).

So, 0.430 moles of [tex]Cd(NO_3)_2.4H_2O[/tex] will contain = [tex](1\times 0.430) = 0.430mol[/tex] of Cd and [tex](2\times 0.430)=0.86mol[/tex] of N

According to the mole concept:

1 mole of a compound contains [tex]6.022\times 10^{23}[/tex] number of molecules

So, 0.430 moles of [tex]Cd(NO_3)_2.4H_2O[/tex] will contain = [tex]\frac{6.022\times 10^{23}}{1mol}\times 0.430mol=2.59\times 10^{23}[/tex] number of water molecules.

Hence, the given amount of [tex]Cd(NO_3)_2.4H_2O[/tex] contains 0.430 moles of Cd, 0.860 moles of N and [tex]2.59\times 10^{23}[/tex] molecules of water.

I need help on this question asap!
You are in a lab and you use 11.50 g of Na(s) to react with Cl(g). Below is the reaction that happens from this.

Na + Cl2 → NaCl

Your percent yield is 95%. From this info what is the actual yield?

Answers

Answer:

27.79 g to the nearest hundredth.

Explanation:

2Na + Cl2 ---> 2NaCl

Using the molar masses , the theoretical yield is:

46 g of Na yields  46 + 35.5*2 g NaCl

46 g ---> 117 g NaCl  so

11.5 g ----> 117 * 11.5 / 46 g NaCl

But, as the yield is 90%

the actual yield is 0.95 * 117 * 11.5 / 46

= 27.79 g.

Two glasses labeled A and B had equal amounts of water. Ted heated the water in one of the glasses. He then put two drops of food coloring into each of the two glasses. The table shows the time taken by the food coloring in the two glasses to spread out.

Which of the following statements is correct?

A - The water in Glass B was heated; therefore, the particles in Glass B have greater kinetic energy and move faster.
B - The water in Glass A was heated; therefore, the particles in Glass A have greater kinetic energy and move faster.
C - The water in Glass B was heated; therefore, the particles in Glass B move slower.
D - The water in Glass A was heated; therefore, the particles in Glass A move slower.

Answers

Answer:

The answer is A: The water in Glass B was heated; therefore, the particles in Glass B have greater kinetic energy and move faster.

Explanation:

Think about it, if you boil water, whatever you put in the water is going to move around faster than if you put something in standing water.

(PLEASE mark Brainliest!)

The water in Glass B was heated; therefore, the particles in Glass B have greater kinetic energy and move faster. The correct answer is A.

What is food coloring?

Food coloring, or color additive, is any dye, pigment, or substance that imparts color when it is added to food or drink.

The food coloring we add to the water is pushed around by the water molecules. Since the molecules in warm water move around faster, the food coloring spreads out quicker in warm water than in cold water.

From the table, we can say that the water in glass B was heated by Ted and the molecules of food coloring spread out quickly in warm water and they have greater kinetic energy and move faster.

On the other hand, in glass A, the water is cold, so food coloring will not dissolve quickly.

Therefore, The water in Glass B was heated; therefore, the particles in Glass B have greater kinetic energy and move faster. The correct answer is A.

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how many atoms of gold are present in 0.6 gm of 18 caral gold? ( 24 caral gold in 100% pure) atomic weight of gold = 197?​

Answers

Answer:

HERE'S YOUR ANSWER

We are given that the ring is made up of 20 carrat gold. 20 carrat gold means 20 parts of gold and 4 parts of other metal (usually copper or silver). Thus, the percentage of gold in 20 carrat gold will be

= (20 / 24) X 100

= 83.333 %

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= (83.333 / 100) X 300

= 250 mg

Thus, the mass of gold in 300 mg of the ring is 250 mg.

Now the molar mass of gold is 197 g. This means that there are 6.023 X 1023 atoms of gold in 197g of gold. Thus

197g of gold = 6.023 X 1023 atoms of gold

1g of gold = (6.023 X 1023 ) / 197 atoms of gold

250 mg or 0.25g of gold = (6.023 X 1023 X 0.25) / 197 atoms of gold

= 7.643 X 1020 atoms of gold

HOPE IT HELPS MAN ☺️

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Answer:

reactivity is NOT a physical property

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Answers

The heat of hydration is defined as the heat absorbed or evolved when one mole of a substance undergoes hydration. The heat of solution is the enthalpy change associated with he dissolution of a solute. The lattice energy is the heat. Lattice energy is the energy released when the components of the lattice are brought together from infinity.

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Given that;

Heat of hydration = ΔH solution – ΔH lattice energy

Where,

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ΔH lattice energy = Lattice energy of the solution

The heat of solution or enthalpy of dissolution is defined as the enthalpy change associated with the dissolution of a solute in a solvent

From the formula above;

ΔH solution = Heat of hydration + ΔH lattice energy

Heat of hydration = [(-431) + (-499)] = -930 kJ/mol

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Hence the heat of solution for LiF → Li^+ + F- is -1966  kJ/mol

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Answers

Answer: Newton's Third Law of Motion.

Explanation:

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Answers

Answer:

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Answer:

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Explanation:

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What is said to have happened to the electrons in an atom in its ground state absorbs a quantum of energy from light

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The electron from the ground state to occupy a next energy level. In this case,we say that the electron is excited

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Answer:

I hope that the link above will be helpful

▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓

[tex]\boxed{\pmb{\green{\sf{2Mg +H_{2}SO_{4}\dashrightarrow H _{2}+Mg_{2}SO_{4}}}}}[/tex]

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Which phrase correctly describes the molecular structure within a molecule?

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Same molecular structure and same properties.

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Unknown # 29

Flame Test Color: Green
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Addition of HNO3(aq) and AgNO3(aq): White precipitate

What is the unknown ionic compound molecular formula?

Answers

Answer:

I think it's a sulphate ion, because when you add hydrochloric acid to it it produces bubbles and when you add barium chloride it then produces a white precipitate.its formula is SO4

I hope this helps

which is the answer?

Answers

Answer:

I could be wrong letter c

giúp tớ với, mình học lớp 9 ạ

Answers

Answer: broooo what is this

Explanation:

in h-atom if x is radius of first bohrs orbit de broglie wavelength of an atom in 3rd orbit is a.3πx b.6πx c.9x/2 d.x/2
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Answers

Answer:

can you type question properly.

Give the relation of energy (E) and frequency (v) as given by Planck. Calculate the frequency and energy of a photon of radiation having wavelength 3000°A.
Pls answer correctly,need it urgently...

Answers

Solution:-1

[tex]\\ \sf\longmapsto E=hv[/tex]

E denotes to Energy h denotes to planks constantv denotes to frequency.

Solution:-2

Wavelength=3000Å

[tex]\boxed{\sf \lambda=\dfrac{c}{v}}[/tex]

[tex]\\ \sf\longmapsto v=\dfrac{c}{\lambda}[/tex]

[tex]\\ \sf\longmapsto v=\dfrac{3\times 10^8m/s}{3000\times 10^{-10}m}[/tex]

[tex]\\ \sf\longmapsto v=0.001\times 10^{18}s^{-1}[/tex]

[tex]\\ \sf\longmapsto v=1.0\times 10^{15}s^{-1}[/tex]

Now

[tex]\\ \sf\longmapsto E=hv[/tex]

[tex]\\ \sf\longmapsto E=6.626\times 10^{-34}Js\times 1.0\times 10^{15}s^{-1}[/tex]

[tex]\\ \sf\longmapsto E=6.6\times 10^{-19}J[/tex]

what is the reactant(s) in the chemical equation below

3CO(g) + Fe2O3(s) 2Fe(s) + 3CO2(g)

Answers

Answer:

the reactants are carbon dioxide ,iron, oxygen


Which of the following are held together by nonpolar covalent bonds?
The Periodic Table
A. Atoms of phosphorus (P) and chlorine (CI)
B. Atoms of chlorine (CI)
C. Atoms of chlorine (CI) and magnesium (Mg)
D. Atoms of magnesium (Mg)

Answers

Answer:

Answer: Atoms of chlorine (CI) and magnesium (Mg)

Answer: Atoms of chlorine (CI) and magnesium (Mg)is your answer

Predict the approximate Ksp of Cuz(AsO4)2 based on the measured potential of Cell 7. Use the equation given in the Background.

a. 1 x 10^-35

b. 4 x 10^14

c. 5 x 10^-17

d. 2 x 10^-21

Answers

Answer:

a. 1 x 10^-35

Explanation:

The correct compound given is: [tex]\mathsf{Cu_3(AsO_4)}_2[/tex]

To predict the approximate Ksp value of the given compound, we will need to express the oxidation-reduction half-reaction of the compound and its dissociation, then, we will use the Nernst equation to determine the approximate Ksp value.

To start with the reduction half-reaction:

[tex]\mathsf{Cu_3(AsO_4)_{2}(s) + 6e^- \to 2As O_{4}^{3-}_{(aq)}+3Cu(s) }[/tex]

The oxidation half-reaction is:

[tex]\mathsf{3Cu(s) \to 3CU^{2+}_{(aq)} + 6e^-}[/tex]

The overall cell reaction now is:

[tex]\mathsf{Cu_3(AsO_4)_{2}(s) \to 3Cu^+ (aq) + 2As O_{4}^{3-}_{(aq)} }[/tex]

From the reduction half-reduction, the number of moles of electrons (n) transferred is 6 moles.

By applying the Nernst equation:

[tex]\mathsf{E_{cell} = E^0_{cell} -\dfrac{0.0591V}{n}log [Cu^{2+}]^3[AsO_4^{3-}]^2 }[/tex]

At standard conditions;

The standard cell potential [tex]\mathsf{E^0_{cell} = -0.342 \ V}[/tex]

and [tex]\mathsf{E_{cell} = 0 \ V}[/tex] since it is at equilibrium.

[tex]\mathsf{0 = -0.342 -\dfrac{0.0591V}{6}log [Cu^{2+}]^3[AsO_4^{3-}]^2 } \\ \\ \\ \mathsf{0.342 = -\dfrac{0.0591V}{6}log [Cu^{2+}]^3[AsO_4^{3-}]^2 }[/tex]

[tex]\mathsf{log [Cu^{2+}]^3[AsO_4^{3-}]^2 = \dfrac{-(0.342)*6}{0.0591 }}[/tex]

[tex]\mathsf{log [Cu^{2+}]^3[AsO_4^{3-}]^2 = -34.7}[/tex]

[tex]\mathsf{log [Cu^{2+}]^3[AsO_4^{3-}]^2 \simeq -35}[/tex]

[tex]\mathsf{[Cu^{2+}]^3[AsO_4^{3-}]^2 = 10^{-35}}[/tex]

[tex]\mathbf{K_{sp} = [Cu^{2+}]^3[AsO_4^{3-}]^2 = 1\times 10^{-35}}[/tex]

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