For which of the following transitions would a hydrogen atom absorb a photon with the longest wavelength?

a. n = 1 to n = 2
b. n = 3 to n = 2
c. n = 5 to n = 6
d. n = 7 to n = 6

The question is incomplete, the complete question is;

Suppose 0.377g of potassium acetate is dissolved in 250.mL of a 57.0mM aqueous solution of ammonium sulfate.

Calculate the final molarity of acetate anion in the solution. You can assume the volume of the solution doesn't change when the potassium acetate is dissolved in it.

Round your answer to 3 significant digits.

Answer:

0.0152 M

Explanation:

The equation of the reaction is;

2CH3COOK(aq) + (NH4)2SO4(aq)------> K2SO4(aq) + 2CH3COONH4(aq)

Number of moles of potassium acetate = 0.377g/98.15 g/mol = 0.0038 moles

Number of moles of ammonium sulphate = 250/1000L × 57 × 10^-3 = 0.014 moles

2 moles of potassium acetate yields 2 moles of ammonium acetate

Hence;

0.0038 moles of potassium acetate yields 0.0038 moles of ammonium acetate

Also

1 mole of potassium sulphate yields 2 moles of ammonium acetate

0.014 of potassium sulphate yields 0.014 × 2/1 = 0.028 moles of ammonium acetate

So potassium acetate is the limiting reactant.

Since 0.0038 moles of ammonium acetate is produced, the final concentration of potassium acetate is = 0.0038 moles of ammonium acetate/0.25L = 0.0152 M

Hence final concentration of acetate ions =0.0152 M

Answer:

Hindi ko po ma gets sinasabi nyu pwedeng pakiayus

Answer: Please, this question is not complete. I have attached the complete question.

The answer is in the attached picture below

Explanation:

The explanation is in the attached picture below

The structure of the alkene with the molecular formula [tex]C_6H_1_0[/tex] that reacts with [tex]Br_2[/tex]to give this compound is an alkene  called 1-hexene

The alkene is called 1-hexene. It has a double bond between the first and second carbon atoms. When it reacts with Br2, the bromine atoms add to the double bond, resulting in the formation of 1,2-dibromohexane.

The reaction is a radical addition reaction. The first step is the formation of a radical by the homolytic cleavage of one of the bromine atoms in Br2. This radical then adds to the double bond in the alkene, forming a new radical. The second bromine atom then adds to the radical, forming 1,2-dibromohexane

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Complete Question

Determine the end (final) value of n in a hydrogen atom transition, if the electron starts in n=4 and the atom emits a photon of light with a wavelength of 486 nm. Group of answer choices

Answer:

[tex]n=2[/tex]

Explanation:

From the question we are told that:

Wavelength [tex]\lambda=486nm=>486*10^{-9}[/tex]

Generally the equation for Atom Transition is mathematically given by

[tex]\frac{1}{\lambda}=R_{\infty }(\frac{1}{n_1^2}-\frac{1}{n_2^2})[/tex]

Where

Rydberg constant [tex]R_{\infty}=1.097*10^7[/tex]

Therefore

[tex]\frac{1}{486*10^{-9}}=1.097*10^7*(\frac{1}{n_1^2}-\frac{1}{4^2})[/tex]

[tex](\frac{1}{n_1^2}-\frac{1}{4^2})=\frac{1}{486*10^{-9}*1.097*10^7}[/tex]

[tex]n_1^2=3.98[/tex]

[tex]n=1.99[/tex]

[tex]n=2[/tex]

Using the Rydberg formula, the final state of the electron is n=2.

Using the Rydberg formula;

1/λ = R(1/nf^2 - 1/ni^2)

Where;

λ = wavelength

nf = final state

ni = initial state

R = Rydberg constant

When λ =  486 × 10^-9 m and ni = 4, R = 1.097  × 10^7 m-1

1/486 × 10^-9 =  1.097  × 10^7(1/nf^2 - 1/4^2)

0.188 = 1/nf^2 - 0.0625

1/nf^2 = 0.188 +  0.0625

nf = 2

Missing parts;

Determine the end (final) value of n in the hydrogen atom transition, if electron starts in n-4 and the atom emits a photon of light with a wavelength of 486.

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Answer:

2700 kg/m³

Explanation:

First let's convert 2.7 g/cm³ to kg/cm³, keeping in mind that 1 kilogram equals 1000 grams:

Finally we need to convert 0.0027 kg/cm³ to kg/m³, keeping in mind that 1 meter equals 100 centimeters, as follows:

The answer is 2700 kg/m³.

Answer:

As either mass increases, the gravitational force between them

increases.

Explanation:

According to Newton's law of universal gravitation;

F α m1m2/r^2

That is, the force between two masses in a gravitational field is directly proportional to the product of the two masses and inversely proportional to their distance apart.

Hence, as either of the masses increase, the force of gravitation between the two masses increases. Hence the answer.

Answer:

9.5x10¹⁷ s

Explanation:

First we convert 3.41 cubic micrometers (um³) to liters (L), as such:

With the converted rate of 3.41x10⁻¹⁵ L/min, we can calculate how many minutes it would take to fill a 54 L vessel:

Finally we convert 1.58x10¹⁶ minutes to seconds:

Answer:

8.61 %

Explanation:

The percent of sodium hypochlorite in the bleach sample can be calculated using the following formula:

We input the data given by the problem:

Answer: A Bronsted-Lowry acid is defined as a substance that acts as a proton donor.

Explanation:

A substance that is able to donate a proton or hydrogen ion to another substance is a Bronsted-Lowry acid.

For example, HCl is a Bronsted-Lowry acid as it dissociates to give a hydrogen ion.

[tex]HCl \rightleftharpoons H^{+} + Cl^{-}[/tex]

Thus, we can conclude that a Bronsted-Lowry acid is defined as a substance that acts as a proton donor.

Answer:

n = 2.23 moles

Explanation:

Given the following data;

Standard temperature = 273 K

Standard pressure = 101.325 kPa

Volume = 50 liter

R = 8.314 J/mol·K  

To find the number of moles, we would use the ideal gas law formula;

PV = nRT

Where;

Making n the subject of formula, we have;

[tex] n = \frac {PV}{RT} [/tex]

Substituting into the formula, we have;

[tex] n = \frac {101.325*50}{8.314*273} [/tex]

[tex] n = \frac {5066.25}{2269.722} [/tex]

n = 2.23 moles

Therefore, 2.23 moles of carbon dioxide at STP will fit in a 50 liter container.

Answer:

v2=5.11L

Explanation:

given

v1=2.58L

N1=0.118mol

N2=0.234

v2=x

according to charles law V1/N1=V2/N2

2.58/0.118=V2/0.234

21.86=V2/0.234

21.86×0.234= v2

5.116L=v2

5.116L is the

answer or u can simplify it and make 5.1 L

Answer:

Classify each of the following as either macroscopic, microscopic or particulate:

a. a red blood cell.

b. a sugar molecule.

c. baking powder.

Explanation:

a. A red blood cell is a microscopic particle.

It can be viewed under a microscope.

b. A sugar molecule is also a microscopic substance.

It can be viewed under a microscope.

c. Baking powder is macroscopic substance.

Answer:

See explanation

Explanation:

Since we have to fill five subshells in moving from Og to the next noble gas in the eight period, we have to know the maximum electrons contained in each of those subshells;

s= 2, p=6, d= 10, f= 14, g = 18

This means that we need a total of 50 electrons to fill all the five subshells.

Hence, the element just below Sg in the eight period will have an atomic number of 156.

Answer: it will be basic

pH that ranges from 0-6 are acid

pH of EXACTLY 7 is neutral

pH greater than 7 are strongly basic or base

Answer:

15 mL of the solute

Explanation:

From the question given above, the following data were obtained:

Solution = 50 mL

Solvent = 35 mL

Solute =?

Solution is simply defined as:

Solution = solute + solvent

With the above formula, we can easily obtain the solute in the solution as follow:

Solution = 50 mL

Solvent = 35 mL

Solute =?

Solution = solute + solvent.

50 = solute + 35

Collect like terms

50 – 35 = solute

15 = solute

Solute = 15 mL

Therefore, 15 mL of the solute is required.

Answer:

The uncertainty principle is one of the most famous (and probably misunderstood) ideas in physics. It tells us that there is a fuzziness in nature, a fundamental limit to what we can know about the behavior of quantum particles and, therefore, the smallest scales of nature.

Answer:

volume = mass/density

Here, volume = 80g/1.59gcm-3 → 50.314 cm3

Explanation:

Answer:

26.9 g

81%

Explanation:

The equation of the reaction is;

4 KO2(s) + 2 CO2(g) → 3 O2(g) + 2 K2CO3(s)

Number of moles of KO2= 27.9g/71.1 g/mol = 0.39 moles

4 moles of KO2 yields 2 moles of K2CO3

0.39 moles of KO2 yields 0.39 × 2/4 = 0.195 moles of K2CO3

Number of moles of CO2 = 57g/ 44.01 g/mol = 1.295 moles

2 moles of CO2 yields 2 moles of K2CO3

1.295 moles of CO2 yields 1.295 × 2/2 = 1.295 moles of K2CO3

Hence the limiting reactant is KO2

Theoretical yield = 0.195 moles of K2CO3 × 138.205 g/mol = 26.9 g

Percent yield = actual yield/theoretical yield × 100

Percent yield = 21.8/26.9 × 100

Percent yield = 81%

Answer:

The appropriate answer is "1.96 mol".

Explanation:

The given values are:

Volume,

V = 26.5 L

Pressure,

P = 1.7 atm

Temperature,

T = 280 K

Now,

The number of moles (n) will be:

= [tex]\frac{PV}{RT}[/tex]

By substituting the values, we get

= [tex]\frac{1.7\times 26.5}{0.0821\times 280}[/tex]

= [tex]\frac{45.05}{22.988}[/tex]

= [tex]1.96 \ mol[/tex]

Answer:

a. eletrophile

b. able to impose regioselectivity and stereo selectivity.

c. faster

Explanation:

Necleophile reaction is chemical reaction in which electron rich chemical specie replaces functional group with another electron deficient molecule. Lewis acid catalyst is organic chemical reaction which lewis acid act as electron pair acceptor. Nucleophile reaction proceeds about 25 times more faster than benzene.

Answer:

cell

chloroplast and cell wall

nucleus

life processes

cell membrane

shape and size

vacuole

Hope it helps

Water is in the solid phase at 0.25 atm and 0°C.

A pressure of 50 kPa and a temperature of 50 °C correspond to the “water” region—here, water exists only as a liquid. At 25 kPa and 200 °C, water exists only in the gaseous state.

Under standard atmospheric conditions, water exists as a liquid. But if we lower the temperature below 0 degrees Celsius, or 32 degrees Fahrenheit, water changes its phase into a solid called ice.

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Answer:

e−(Ea/RT): the fraction of the molecules present in a gas which have energies equal to or in excess of activation energy at a particular temperature

Answer:

D. Temperature and activation energy is the correct answer

Explanation:

^_^

Answer:

3-hexanol

1 -butanol

2-pentanol

Explanation:

Let us recall that chromic acid or chromate are strong oxidizing agents. When they are oxidized, their colour changes from orange to green.

This shows a reduction in chromic acid or chromate. The reaction of chromic acid or chromate with a primary alcohol yields a carboxylic acid while reaction with a secondary substrate yields an alkanal.

Note that Tertiary alkyl halides are not be oxidized hence reactions involving a point where invitation carried along occur.

3-ethyl-3-pentanol is a tertiary alkyl halide hence it can not be oxidized.

Answer:

1) volumetric

2) graduated

3) volumetric

Explanation:

A volumetric glassware is a glassware that is marked at a particular point. A typical example of a volumetric glassware is the volumetric flask. A volumetric glassware is capable of measuring only a specific volume of a liquid.

On the other hand, graduated glassware can measure a range of volumes of liquid. However, a volumetric glassware is still required where a high degree of accuracy is important.

Answer:

A metal M readily forms water-soluble sulphate MSO4, water-insoluble hydroxide M(OH)2 and oxide MO. The oxide and hydroxide are soluble in NaOH. The M is:

Answer:

Depends on molecule.

Explanation:

The number of the polypeptide chains present in the oligomer depends on the molecule. Some molecules have more polypeptide chains whereas some of them have less polypeptide chains. For example, Hemoglobin is a oligomer that consists of four Polypeptide Chains, two of these Polypeptide Chains are α-globin molecules, each comprise of 141 amino acids, and the other two are (β, γ, δ, or ε) globins, each consist of 146 amino acids.

Answer:

The rate law for the following reaction:

H2SiF6(aq)+2NaF(aq)+3H2O(aq)⟶Na2SiO3(s)+8HF(aq)

is second order in H2SiF6, zero order in NaF and first order in H2O.

Answer:

The entropy change of carbon dioxide = 0.719 kJ/k

Explanation:

Given:

1.5 m - 3 insulated rigid tank contains 2.7 kg of carbon dioxide at 100 kPa

The objective is to determine the entropy change of carbon dioxide

Formula used:

ΔS=

Solution:

On considering,

[tex]C_{P} =0.846 kJ/kg K\\C_V=0.657 kJ/kg k\\[/tex]

ΔS=[tex]mc_{v} lu\frac{p_{2} }{P_{1} }[/tex]

On substituting the values,

ΔS=[tex]2.7*0.657lu\frac{150}{100}[/tex]

ΔS=0.719 kJ/k

The entropy change is "0.719 kJ/K".

Given values are:

Mass of tank,

Pressure,

Rised pressure,

Assumption of constant specific heat is,

As we know the formula,

→ [tex]\Delta S = mC_v \ ln(\frac{P_2}{P_1} )[/tex]

         [tex]= (2.7)(0.657) \ ln (\frac{150}{100} )[/tex]

         [tex]= 1.7739\times 0.4055[/tex]

         [tex]= 0.7193 \ kJ/K[/tex]

Thus above answer is right.

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