For your senior project, you would like to build a cyclotron that will accelerate protons to 10% of the speed of light. The largest vacuum chamber you can find is 54 cm in diameter. What magnetic field strength will you need?

Answer:

3.034 m

Explanation:

From the law of conservation of energy, the energy at the top of the incline equals the energy at the bottom of the incline since at the top of the incline, the horizontal surface is frictionless and along the incline there is no friction.

The work done in moving the crate a distance, d = 2.7 m with a force of F = 121 N to the top of the incline is W = Fd = 121 N × 2.7 m = 326.7 J.

From work-kinetic energy principles, this work W = kinetic energy of the crate at the top of the incline, K₁.

Now, the total mechanical energy at the top of the incline, E equals the total mechanical energy at the bottom of the incline E' since there is no friction along the incline.

So, E = E'

U₁ + K₁ = U₂ + K₂ where U₁ = potential energy of crate at top of incline = mgh where m = mass of crate = 28.9 kg, g = acceleration due to gravity = 9.8 m/s², h = height of incline = 1.8 m, K₁ = kinetic energy of crate at top of incline = 326.7 J, U₂ = potential energy of crate at bottom of incline = 0 J(since it is at an elevation h = 0) and K₂ = kinetic energy of crate at bottom of incline

So, substituting the values of the variables into the equation, we have

U₁ + K₁ = U₂ + K₂

mgh + K₁ = U₂ + K₂

28.9 kg × 9.8 m/s² × 1.8 m + 326.7 J = 0 J + K₂

509.796 J + 326.7 J = K₂

K₂ = 836.496 J

K₂ ≅ 836.5 J

Now since the vertical wall is a distance d2 away and the long ideal spring has a length dy = 3.4 m, let x be the compression of the spring. So, the distance moved by the crate is thus D = d2 - dy - x.

Now, the change in kinetic energy of the crate ΔK equals the work done by friction and that done by the spring W.

So ΔK = -W (from work-kinetic energy principles)

Let W' = work done by friction = μmgD where  μ = coefficient of kinetic friction between surface and crate = 0.41, m = mass of crate = 28.9 kg, g = acceleration due to gravity = 9.8 m/s² and D = distance moved by crate = D = d2 - dy - x = 5.2 m - 3.4 m - x = 1.8 - x

So, W' = μmgD

W' = 0.41 × 28.9 kg × 9.8 m/s² (1.8 - x)

W' = 116.12(1.8 - x)

W' = 2090.16 - 116.12x

The work done by the spring W" = 1/2k(x₀² - x²) where k = spring constant = 154 N/m, x₀ = initial spring length = dy = 3.4 m and x = final spring compression.

So,  W" = 1/2k(x₀² - x²)

W" = 1/2 × 154 N/m[(3.4 m)² - x²]

W" = 77 N/m[11.56 m² - x²]

W" = 890.12  - 77x²

So, W = W' + W"

W = 2090.16 - 116.12x + 890.12  - 77x²

W = 2980.28 - 116.12x - 77x²

Since the crate stops, final kinetic energy K₃ = 0. So, ΔK = K₃ - K₂ = 0 - 836.5 J = -836.5 J

Also, ΔK = -W

-836.5 = -(2980.28 - 116.12x - 77x²)

836.5 = 2980.28 - 116.12x - 77x²

77x² + 116.12 -2980.28 + 836.5 = 0

77x² + 116.12x -2143.78 = 0

dividing through by 77, we have

x² + 1.508x -27.841 = 0

Using the quadratic formula to find x, we have

[tex]x = \frac{-1.508 +/-\sqrt{1.508^{2} - 4 X 1 X (-27.841)} }{2 X 1.508} \\x = \frac{-1.508 +/-\sqrt{2.274064 + 111.364} }{3.016} \\x = \frac{-1.508 +/-\sqrt{113.638064} }{3.016} \\x = \frac{-1.508 +/- 10.66}{3.016} \\x = \frac{-1.508 - 10.66}{3.016} or x = \frac{-1.508 + 10.66}{3.016} \\x = \frac{-12.168}{3.016} or x = \frac{9.152}{3.016} \\x = -4.03 or 3.034[/tex]

x = -4.03 or 3.034

Since the compression of the spring is positive, we choose x = 3.034

So, the crate compresses the spring 3.034 m

Answer:

B = 2.9 mT

Explanation:

Given that,

The distance between the wires, r = 2 cm

Distance halfway between them d = 1 cm = 0.01 m

The current in the wires, I = 145 A

We need to find the strength of the magnetic field they produce, halfway between them. The formula for the magnetic field in the wire is given by :

[tex]B=\dfrac{\mu_o I}{2\pi d}\\\\B=\dfrac{4\pi \times 10^{-7}\times 145}{2\pi \times 0.01}\\\\B=2.9\ mT[/tex]

So, the required magnetic field is 2.9 mT.

Explanation:

a) [tex]I=\displaystyle \sum_{i}m_ir_i^2[/tex]

where [tex]r_i[/tex] is the distance of the mass [tex]m_i[/tex] from the axis of rotation. When the axis of rotation is placed at the end of the rod, the moment of inertia is due only to one mass. Therefore,

[tex]I= mr^2 = (2\:kg)(3\:m)^2 = 18\:kg-m^2[/tex]

b) When the axis of rotation is placed on the center of the rod, the moment is due to both masses and the radius r is 1.5 m. Therefore,

[tex]\displaystyle I= \sum_{i}m_ir_i^2 = 2(2\:kg)(1.5\:m)^2 = 9\:kg-m^2[/tex]

A neutron changes into a proton during a radioactive decay process called beta decay (positron), which is option D.

A beta decay in physics is a nuclear reaction in which a beta particle (electron or positron) is emitted.

A positron is an electron with a positive charge.

During a beta decay, a neutron in the nucleus of the radioactive material suddenly changes into a proton, causing an increase in the atomic number of an element.

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#SPJ1

Answer:

8 N

Explanation:

Applying,

(F'+F) = ma............... Equation 1

Where F' = Amhed's force, F = Rashid's force, m = mass of the box, a = acceleration of the box.

From the question,

Given: F = 12 N, m = 4 kg, a = 5 m/s²

Substitute these values into equation 1

(F'+12) = 4×5

(F'+12) = 20

F' = 20-12

F' = 8 N.

Hence Ahmed's force is 8 N

Answer:

option C

30m/s

Explanation:

preciesly 29.4

Answer:

The answer would be B. 30 m/s

Explanation:

Acceleration due to gravity is 9.8m/s per second.

So 9.8 × 3 = 29.4

closest to 29.4 is 30

Answer:

the average force exerted by the rain on the roof is 1.065 N

Explanation:

Given;

speed of the rainfall, v = 15 m/s

the mass of the rate of the rainfall, m' (m/t) = 0.071 kg

Let the average force exerted by the rain on the roof  = F

The average force exerted by the rain on the roof  is calculated by Newton's second law of motion;

[tex]F = ma = m \frac{v}{t} = \frac{m}{t} \times v \\\\Recall, \ m' = \frac{m}{t} \\\\F = m'\times v\\\\F = 0.071 \times 15\\\\F = 1.065 \ N[/tex]

Therefore, the average force exerted by the rain on the roof is 1.065 N

Answer:

the force applied to the smaller piston is 600 N

Explanation:

Given;

weight of the car, F = 15,000 N

radius of the lager piston, R = 0.2 m

radius of the smaller piston, r = 0.04 m

let the force applied to the smaller piston = f

The pressure applied on both piston is constant;

[tex]P = \frac{F}{A} = \frac{f}{a} \\\\\frac{F}{R^2} = \frac{f}{r^2} \\\\f = \frac{F\times r^2}{R^2} = \frac{15,000 \times (0.04)^2}{(0.2)^2} = 600 \ N[/tex]

Therefore, the force applied to the smaller piston is 600 N

(a) Attached to the response as Figure 1.

(b) 35.0Ω

(c) Across 5.0Ω = 1.3V

   Across 10.0Ω = 2.6Ω

   Across 20.0Ω = 5.2Ω

(a) The labelled circuit using the correct symbols (for the resistors and battery) has been attached to this response.

(b) Since the resistors are hooked up in series, their equivalent resistance R, is found by adding the individual resistances of the resistors (R₁, R₂ and R₃). i.e

R = R₁ + R₂ + R₃               -------------------(i)

Where;

R₁ = 5.0 Ω

R₂ = 10.0 Ω

R₃ = 20.0 Ω

Substitute these values into equation (i) as follows;

∴ R = 5.0 Ω + 10.0 Ω + 20.0 Ω

∴ R = 35.0 Ω

Therefore, the equivalent resistance is ∴ R = 35.0Ω

(c) When resistors are connected in series, the same current passes through them. To get the current through each resistor;

i. First, replace the resistors by their equivalent resistor as calculated above. The diagram has been attached to this response.

ii. As seen in the diagram, the current flowing through the equivalent resistor can be calculated using Ohm's law as follows;

V = I R              ------------------(ii)

Where;

V = Voltage supplied to the circuit = 9.0V

I = Current through the circuit

R = Resistance of the equivalent resistor = 35.0Ω

Substitute these values into equation (ii)

9.0 = I x 35.0

I = [tex]\frac{9.0}{35.0}[/tex]

I = 0.26A

This is also the current flowing through each of the resistors separately.

iii. Calculate the voltage drop across

1. 5.0 Ω resistor

Applying Ohm's law from equation (ii)

V = I x R

Where;

V = voltage drop across the 5.0Ω resistor

I = current through the 5.0Ω resistor = 0.26A

R = resistance of the 5.0Ω resistor = 5.0Ω

=> V = 0.26 x 5.0

=> V = 1.3V

2. 10.0 Ω resistor

Applying Ohm's law from equation (ii)

V = I x R

Where;

V = voltage drop across the 10.0Ω resistor

I = current through the 10.0Ω resistor = 0.26A

R = resistance of the 10.0Ω resistor = 10.0Ω

=> V = 0.26 x 10.0

=> V = 2.6V

3. 20.0 Ω resistor

Applying Ohm's law from equation (ii)

V = I x R

Where;

V = voltage drop across the 20.0Ω resistor

I = current through the 20.0Ω resistor = 0.26A

R = resistance of the 20.0Ω resistor = 10.0Ω

=> V = 0.26 x 20.0

=> V = 5.2V

Accuracy of measurement is the degree of how close the measurement is, to the actual measurement.

For a measurement of 2.00 m, 1.99 m is more accurate because it is closer to 2.00 m than 1.95 m.

The set of data is not given. So, I will give a general explanation.

For a measurement to be the accurate, the measurement must be close to the actual measurement, and in some cases, the measurement should be approximated to the actual measurement.

Given that:

[tex]Length =2.00m[/tex]

An example of an accurate measurement is:

[tex]Length =1.95m[/tex]

Why? The reasons are

Another example is:

[tex]Length = 1.99m[/tex]

1.99 m is also an accurate measurement because of the reasons above.

However, 1.99 m is more accurate because it is closer to 2.00 m than 1.95 m

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Answer:

I HOPE THIS IS CORRECT

Explanation:

Power of water =2 kw=2000w

Mass of water =200kg

difference in temperature ΔT=70−10=60oC

Concept

energy required to heat the water = energy given by water in time t=pt

energy required to increase tempeature of water by 60oC,Q=msΔT

S= specific heat =4200J/kgoC

              pt=msΔT

   2000×t=200×4200×60

      t=25200  

or   t=25.2×103sec.

The quantity of heat generated is 720,000 Joules or 720 kiloJoules.

Given the following data:

To find the quantity of heat generated when the electrical coil is used:

Note: the quantity of heat generated is energy.

First of all, we would convert the time in hour to seconds.

Conversion:

1 hour = 3600 seconds

Mathematically, the energy of a device is given by the formula;

[tex]Energy = power[/tex] × [tex]time[/tex]

Substituting the values into the formula, we have;

[tex]Energy = 200[/tex] × [tex]3600[/tex]

Energy = 720,000 Joules or 720 kiloJoules.

Therefore, the quantity of heat generated is 720,000 Joules or 720 kiloJoules.

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Answer:

a. The disk

b. Because it has the smallest rotational inertia

Explanation:

a. Which object do you expect to reach the bottom of the inclined plan first?

I would expect the disk to reach the bottom first.

b. Why?

This is because the disk has the smallest rotational inertia.

The rotational inertial of the hollow sphere, disk and ring are 2/3MR², 1/2MR² and MR² respectively.

Since the three objects are rolling from the same height, they have the same mechanical energy.

But, since the disk has the smallest rotational inertia, it would have the smallest rotational kinetic energy and largest translational kinetic energy.  The disk's smaller rotational kinetic energy will cause  to rotate less but translate more than the other objects and thus reach the bottom first.

The object which is expected to reach the bottom of the inclined plan first is the disk, as it has the lowest rotational inertia.

Moment of inertia is the force which acts in the opposite direction of the force of angular acceleration acting on the body.

There are three objects, hollow sphere, disk and ring.

       [tex]I=\dfrac{2}{3}mr^2[/tex]

        [tex]I=mr^2[/tex]

Here, (m) is the mass and (r) is the radius of the object.

These three objects are going to race by releasing from rest at the top of an inclined plane to the bottom of the plane.

As moment of inertia is the force which acts in the opposite direction of the force of angular acceleration acting on the body.

Thus the less the value of inertia will result in less the time required to reach at the bottom of the inclined plane.

Hence, the object which is expected to reach the bottom of the inclined plan first is the disk, as it has the lowest rotational inertia.

Learn more about the force of inertia here;

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Answer:

LOL PUEDO HABLAR CON

Explanation:

Answer:

Whats the anwser/????

Explanation:

Answer:

B

Explanation:

Explanation:

Friction is the force resisting the relative motion of solid surfaces, fluid layers, and material elements sliding against each other. There are several types of friction: Dry friction is a force that opposes the relative lateral motion of two solid surfaces in

Answer:

Dragging a Chair, Climbing, Rubbing Hands

Answer:

276 your welcome give me brainliest

Answer:

C) Turn off the magnetic field by switching off the electric current.

PLEASE MARK THIS BRAINLIEST ❤️

Answer:

8.5 feet.

Explanation:

A sketch of the position of the three people gives a right angled triangle. The hypotenuse of the triangle gives the resultant displacement, while the two other sides are 6 feet each.

The resultant displacement, R, is the overall displacement covered by the doctor. This can be determined by;

R = [tex]\sqrt{d_{1} ^{2} + d_{2} ^{2} }[/tex]

where: [tex]d_{1}[/tex] = 6 feet and [tex]d_{2}[/tex] = 6 feet.

Thus,

R = [tex]\sqrt{6^{2} + 6^{2} }[/tex]

  = [tex]\sqrt{72}[/tex]

R = 8.49

The resultant displacement covered by the doctor is 8.5 feet.

Answer:

English please!!!!!!!!!!!!!!!!!!!!!!!

Answer:

The interpersonal environment is considered to be a subset of the organizational environment – defined as the employee’s perception of the practices, policies, and processes of an organization

Explanation:

Answer:

The power is 465.44 W.

Explanation:

mass, m = 70 kg

number of steps,  n = 1576

height of each step, h = 0.241 m

time taken, t = 9.33 min= 9.33 x 60 s

The power is given by the rate of doing work.

W = n m g h

W = 1576 x 70 x 9.8 x 0.241

W = 260553.776 J

The power is given by

[tex]P = \frac{W}{t}\\\\P = \frac{260553.776}{9.33\times 60}\\\\P = 465.44 W[/tex]  

Answer:

Sultan Kösen

here is a pic

Answer:

O The environment did work on an object

Explanation:

Answer:

(a) t = 1.14 s

(b) h = 0.82 m

(c) vf = 7.17 m/s

Explanation:

(b)

Considering the upward motion, we apply the third equation of motion:

[tex]2gh = v_f^2 - v_i^2[/tex]

where,

g = - 9.8 m/s² (-ve sign for upward motion)

h = max height reached = ?

vf = final speed = 0 m/s

vi = initial speed = 4 m/s

Therefore,

[tex](2)(9.8\ m/s^2)h = (0\ m/s)^2-(4\ m/s)^2\\[/tex]

h = 0.82 m

Now, for the time in air during upward motion we use first equation of motion:

[tex]v_f = v_i + gt_1\\0\ m/s = 4\ m/s + (-9.8\ m/s^2)t_1\\t_1 = 0.41\ s[/tex]

(c)

Now we will consider the downward motion and use the third equation of motion:

[tex]2gh = v_f^2-v_i^2[/tex]

where,

h = total height = 0.82 m + 1.8 m = 2.62 m

vi = initial speed = 0 m/s

g = 9.8 m/s²

vf = final speed = ?

Therefore,

[tex]2(9.8\ m/s^2)(2.62\ m) = v_f^2 - (0\ m/s)^2\\[/tex]

vf = 7.17 m/s

Now, for the time in air during downward motion we use the first equation of motion:

[tex]v_f = v_i + gt_1\\7.17\ m/s = 0\ m/s + (9.8\ m/s^2)t_2\\t_2 = 0.73\ s[/tex]

(a)

Total Time of Flight = t = t₁ + t₂

t = 0.41 s + 0.73 s

t = 1.14 s

Answer:

C.

Explanation:

The x axis is the origin and the degrees move counter clockwise from there so a 90° flip would be answer C.

Answer:

O 75 kilometers/hour

Explanation:

v = distance/time

v = 30km/0.4h

v = 75km/h

Answer:

b. 1600 watts

Explanation:

Modulation is the process of impressing a low frequency signal unto a high frequency signal so a to transmit over long distance.

If the modulation index (m) for an AM wave is less than 1, modulation would occur with no distortion, if m = 1, modulation occurs but if m > 1, it leads to over modulation and loss in AM envelope.

The total output power of an AM is the sum of the carrier power, upper side band power and lower side band power.

Total output power of an AM [tex](P_{AM})=(\frac{2+m^2}{2} )P_c\\[/tex]

Pc is the carrier power. Given that modulation (m) = 50% = 0.5:

[tex]P_{AM}=\frac{2+m^2}{2} P_c\\\\1800=\frac{2+0.5^2}{2} P_c\\\\1800=1.125P_c\\\\P_c=1600\ watts[/tex]

Answer:

a) B = 3.11 km.  θ= 54.7º E of S

b) B = 3.11 km  θ= 54.7º W of S

Explanation:

a)

        [tex]C=\sqrt{(2.2km)^{2} + B^{2} } = 3.81 Km (1)[/tex]

       [tex]B=\sqrt{(3.81km)^{2} -(2.2km)^{2} } = 3.11 Km (2)[/tex]

        [tex]\theta = arc tg (\frac{B}{A} )= arc tg ( \frac{3.11}{2.2} )= arctg (1.414) = 54.7 deg (3)[/tex]

b)

      [tex]\theta = arc tg (\frac{-B}{A} )= arc tg ( \frac{-3.11}{2.2} )= arctg (-1.414) = -54.7 deg (4)[/tex]