Answer:
SnS
Explanation:
Tin(II) sulfide is a chemical compound of tin and sulfur. The chemical formula is SnS. Its natural occurrence concerns herzenbergite, a rare mineral.
Answer:
SnS
Explanation:
Tin, as it shows on the periodic table can have a +2 or +4 charge.
Sulfide is just Sulfur which has a -2 charge.
It tells us the charge of the tin in roman numerals. In this case (II) means two, so it is tin with a charge of two.
In order for these to balance each other, we are going to take one of the tin and one of the sulfur because it the +2 and -2 add to zero.
Fixed place that you use to help you to find position or measurements ?
Answer:
DO YOU PLAY COD OR FORTNIT3
Explanation:
Read excerpt and answer 3 questions I’ll mark brainliest. Pls thank you
Answer:
please also share the excerpt
Explanation:
Thank you
A transition metal in the fourth period from the following list : Cu, O , Pr, Ag
Answer:
Cu
Explanation:
Groups 3 - 12 (or groups IIA - IIB) of the periodic table contain transition elements. Transaction elements start from period four (4) of the periodic table. The phrase alludes to the fact that the d sublevel is filling at a lower main energy level than the s sublevel that came before it.
The transition elements' arrangement is inverted from the fill order, with the 4 s filled prior to the actual 3 d begins. The transition elements are commonly referred to as transition metals since they are all metals. They are less reactive than the metals in Groups 1 and 2 and have normal metallic characteristics.
From the options given Cu is the only transition metal in the fourth period on the periodic table.
The sp of strontium carbonate, SrCO3, is 5.60×10−10 . Calculate the solubility of this compound in g/L.
Answer:
3.50 × 10⁻³ g/L
Explanation:
Step 1: Make an ICE chart for the solution of SrCO₃
"S" represents the molar solubility.
SrCO₃(s) ⇄ Sr²⁺(aq) + CO₃²⁻(aq)
I 0 0
C +S +S
E S S
The solubility product constant (Ksp) is:
Ksp = [Sr²⁺] [CO₃²⁻] = S²
S = √Ksp = √5.60 × 10⁻¹⁰ = 2.37 × 10⁻⁵ M
Step 2: Convert "S" to g/L
The molar mass of SrCO₃ is 147.63 g/mol.
2.37 × 10⁻⁵ mol/L × 147.63 g/mol = 3.50 × 10⁻³ g/L
Cesium-137 is part of the nuclear waste produced by uranium-235 fission. The half-life of cesium-137 is 30.2 years. How much time is required for the activity of a sample of cesium-137 to fall to 9.32 percent of its original value
Answer:
t(9.32% remaining) = 203 yrs (3 sig. figs.)
Explanation:
All radioactive decay follows a 1st order decay profile. This is defined by the expression ...
A =A₀e^-k·t
A = final activity = 9.32%
A₀ = initial activity = 100%
e = base of natural logs
k = rate constant = 0.693/t(1/2) = (0.693/30.2) yrs⁻¹ = 0.023 yrs⁻¹
t = time of decay = ln(A/A₀)/-k = ln(9.32%/100%)/-0.023 yrs⁻¹
= 203.286637 yrs (calc. ans.)
≅ 203 yrs (3 sig. figs.)
A 25.0 mL solution of quinine was titrated with 0.50 M hydrochloric acid, HCl. It was found that the solution contained 0.100 moles of quinine. What was the pH of the solution after 50.00 mL of the HCl solution were added
Answer:
[tex]pH=11.45[/tex]
Explanation:
Hello there!
In this case, since the chemical equation representing the neutralization of the weak base quinine can be written as follows:
[tex]C_{20}H_{24}N_2O_2+HCl\rightarrow C_{20}H_{25}N_2O_2^+Cl^-[/tex]
Whereas we have 0.100 moles of the base and those of acid as shown below
[tex]n_{acid}=0.50molHCl/L*0.05000L=0.025molHCl[/tex]
Which means that the remaining moles of quinine are:
[tex]n_{C_{20}H_{24}N_2O_2}^{final}=0.100mol-0.025mol=0.075mol[/tex]
And the resulting concentration:
[tex][C_{20}H_{24}N_2O_2]=\frac{0.075mol}{(0.025+0.050)L} =1.00M[/tex]
Now, the calculation of the pH requires the pKb of quinine (5.1) as its ionization in water produces OH- ions:
[tex]C_{20}H_{24}N_2O_2+H_2O\rightleftharpoons OH^-++C_{20}H_{25}N_2O_2^+[/tex]
And the equilibrium expression is:
[tex]Kb=\frac{[C_{20}H_{24}N_2O_2][C_{20}H_{25}N_2O_2 ^+]}{[C_{20}H_{24}N_2O_2]} \\\\10^{-5.1}=\frac{x^2}{1.00M}\\\\ 7.94x10^{-6}=\frac{x^2}{1.00M}[/tex]
Which is solved for x as follows:
[tex]x= \sqrt{7.94x10^{-6}*1.00M}\\\\x=0.00282M[/tex]
Which means the pOH is:
[tex]pOH=-log(0.00282)=2.55[/tex]
And the pH:
[tex]pH=14-2.55\\\\pH=11.45[/tex]
Regards!
There are two stereoisomers of 1-tert-butyl-4-chloro-cyclohexane. One of these isomers reacts with sodium ethoxide in an E2 reaction that is 500 times faster than the reaction of the other isomer. Identify the isomer that reacts faster, and explain the difference in rate for these two isomers.
Answer:
Explanation:
Answer:
cis-isomer reacts faster
Explanation:
The missing diagrams in the question are attached in the first image below and the isomers that react faster are shown in the second image attached.
The cis-isomer quickly follows E2 reaction due to the fact that it is locked in a chair conformation whereby chlorine dominates an axial position, as displayed in drawing C as well as the leaving group Cl which is antiperiplanar to a beta proton.
Due to the bulkiness of tert-butyl, the trans-isomer is Basically trapped in a chair configuration, with chlorine occupying an equatorial position as displayed in drawing A below, thus leaving the group isn't antiperiplanar to a beta proton.
Tert butyl favors an equatorial position due to its bulkiness. This makes the Cl to assume an axial position in an isomer
The difference:
From the second image attached below, in the first diagram(1):
Suppose H is antiperiplanar, C-H bond electrons reach antibonding orbitals of C-Cl, assisting in the breakdown of the C-Cl bond and therefore speeding up the process.
From the second diagram(2) in the second image:
Unless Cl is in the axial position would it have β-hydrogen in the antiperiplanar position. Because tert-butyl prefers equatorial location, the Cl occupies equatorial position in the trans isomer.
As a result, the reaction is slower and there is no β-hydrogen antiperiplanar to Cl.
what is the magnitude of the force of gravity acting in a box that has a mass of 100 kg at sea level?
Answer:
force of gravity, F = 980 N
Explanation:
Given that,
The mass of the box, m = 100 kilograms
first we will need to find the magnitude of the force of acting on a box. we can used it with Newton second law.
F = ma
a = acceleration
Here,
F = mg
g = acceleration due to gravity
F=100\ kg\times 9.8\ m/s^2F=100 kg×9.8 m/s2
F = 980 N
Hence, the force acting on the object is 980 N.
Why is iodine always Used in a solution containing excess I2
Answer:
If a standard iodine solution is used as a titrant for an oxidizable analyte, the technique is iodimetry. If an excess of iodide is used to reduce a chemical species while simultaneously forming iodine.
Iodine always used in a solution excess KI is given to aid in the solubilization of free iodine, which would be insoluble in clean water during normal circumstances.
What is Iodine?
Iodine is a kind of element which are mainly used in iodometry titration. It can be represented by I.
What is solution?A solution would be a homogenous mixture of two components, usually a solute as well as a solvent.
Iodimetry would be a technique that uses a standard iodine solution as a titrant for such an oxidizable analyte. When an excessive amount of iodide is used to decrease a chemical while somehow producing iodine.
To know more about iodine and solution
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What is a net ionic equation?
A. An equation showing only what is involved in the reaction
B. An equation that is balanced on both sides
C. An equation that shows all dissolved compounds as ions
O D. An equation that shows all substances as compounds
Answer:
I think A is the correct answer
If the initial concentration of N2O5 was 0.500 M and the concentration of N2O5 was 0.450 M after 0.100 s, what is the average rate of NO2 formation during the first 100 milliseconds
Answer:
The appropriate solution is "1 M/s".
Explanation:
The equation is:
[tex]2N_2O_5 \rightarrow4NO_2+O_2[/tex]
or,
[tex]\frac{1}{2}(-\frac{\Delta(N_2O_5)}{dt} ) =\frac{1}{4}\frac{\Delta (NO_2)}{dt}[/tex]
then,
The rate of [tex]NO_2[/tex] formation:
= [tex]\frac{\Delta NO_2}{dt}[/tex]
= [tex]\frac{4}{2} (-\frac{\Delta(N_2O_5)}{dt})[/tex]
= [tex]2(-\frac{\Delta (N_2O_5)}{dt} )[/tex]
= [tex]2(-\frac{(0.45-0.5)}{0.1} )[/tex]
= [tex]1 \ M/s[/tex]
ose you has aniline as your unknown. What kind of solid derivative would be suitable to synthesize for aniline
Answer:
Amides are suitable to synthesize aniline
Explanation:
Amide are basically used to synthesize aniline.
The chemical formula of Aniline is C6H5NH2 while that of Amide is RCONH2
Amide are solids that can be easily converted to amines.
The drugs Prilosec and Nexium both contain the same active ingredient. Nexium contains a single enantiomer, but Prilosec is a racemic mixture. Which of the following is probably true regarding 20 mg doses of the two different drugs?
a. both drugs will be equally effective
b. both drugs can be prepared using the same synthetic procedure
c. Nexium will be more effective than Prilosec
d. Prilosec will be more effective than Nexium
Answer:
both drugs will be equally effective
Explanation:
A racemic mixture is a substance that contains a 50/50 mixture of the (+) and (-) enantiomers of an optically active compound.
It is important to note that even if a drug occurs as a racemic mixture, only the biologically active enantiomer will interact with the substrate on which the drug acts. The other enantiomer present is just irrelevant. Similarly, its presence does not affect the biological activity of the active enantiomer.
Hence, both Prilosec and Nexium are both equally effective.
The name of an oxyacid has the suffix -ous acid. What is the suffix of the oxyanion?
Answer:
-ate
Explanation:
Use the following information to calculate the concentration, Ka and pka for an unknown monoprotic weak acid. (8 pts.) 20.00 mL
Volume of unknown weak acid used : 20.00 mL Total volume of 0.20 M NaOH required to reach the equivalence point: 18.50 mL Initial pH of the weak acid 2.87
Answer:
Concentration: 0.185M HX
Ka = 9.836x10⁻⁶
pKa = 5.01
Explanation:
A weak acid, HX, reacts with NaOH as follows:
HX + NaOH → NaX + H2O
Where 1 mole of HX reacts with 1 mole of NaOH
To solve this question we need to find the moles of NaOH at equivalence point (Were moles HX = Moles NaOH).
18.50mL = 0.01850L * (0.20mol / L) = 0.00370 moles NaOH = Moles HX
In 20.0mL = 0.0200L =
0.00370 moles HX / 0.0200L = 0.185M HX
The equilibrium of HX is:
HX(aq) ⇄ H⁺(aq) + X⁻(aq)
And Ka is defined as:
Ka = [H⁺] [X⁻] / [HX]
Where [H⁺] = [X⁻] because comes from the same equilibrium
As pH = 2.87, [H+] = 10^-pH = 1.349x10⁻³M
Replacing:
Ka = [H⁺] [H⁺] / [HX]
Ka = [1.349x10⁻³M]² / [0.185M]
Ka = 9.836x10⁻⁶
pKa = -log Ka
pKa = 5.01What causes heat energy when you rub two objects against each other? (2 points)
Group of answer choices
The air around the objects
The flow of heat from one object to the other
The friction between the two objects
The pull of gravity on the two objects
15. Triglycerides, waxes, and steroids are all ___ lipids because they contain only carbon, hydrogen, and oxygen
A. simple
B. methyl esters
C. complex
D. long-chain compounds
Answer:
A. simple
Explanation:
What is the heat of a reaction, in joules, with a total reaction mixture volume of 61.2 mL if the reaction causes a temperature change of 4.6 oC in a calorimeter
Answer:
1178J is the heat of the reaction
Explanation:
Assume that the reaction mixture has a density of 1.00 g/mL and a specific heat of 4.184 J/g-oC. The calorimeter has a heat capacity of 10.0 J/oC
The heat of a reaction follows the equation:
Q = m*S*ΔT
Where Q is the heat of the reaction,
m is the mass:
61.2mL * (1.00g/mL) = 61.2g
S is specific heat = 4.184J/g°C
ΔT = 4.6°C
Replacing:
Q = 61.2g*4.184J/g°C*4.6°C
Q = 1178J is the heat of the reaction
1. Complete the following chart for the following atoms:
Element
Mass
number
Number of
electrons
Number of
neutrons
Atomic
Number
(number of
protons)
Potassium
16
56
26
What is the atomic symbol (the nuclide) for the isotope with 15 protons and 16
neutrons? Your answer must be in the form shown:
AX
You must show the correct numbers for A and Z
and have the correct symbol (Z). (3 points)
Explanation:
If there are 15 protons, 15 nuclear particles of unit positive charge, then
Z
=
15
. Now
Z
≡
the atomic number
, and you look at your copy of the Periodic Table, and you find that for
Z
=
15
, the element phosphorus is specified.
But we are not finished. Along with the 15 defining protons, there are also 16 neutrally charged, massive nuclear particles, 16 neutrons, and the protons and neutrons together determine the atomic mass. The isotope is thus
31
P
, which is almost 100% abundant, and an important nucleus for
NMR spectroscopy.
How many total atoms are in 0.75 moles of CO2
Answer:
4.515 × 10²³ atomsExplanation:
The number of atoms can be found by using the formula
N = n × L
where n is the number of moles
N is the number of entities
L is the Avogadro's constant which is
6.02 × 10²³ entities
From the question we have
N = 0.75 × 6.02 × 10²³
We have the final answer as
4.515 × 10²³ atomsHope this helps you
A 15.0 mL urine from a dehydrated patient has a density of 1.019g/mL. What is the mass of the sample, reported in mg?
Answer:
Mass of sample in mg = 15,285 mg
Explanation:
Given:
Volume of urine sample = 15 ml
Density of sample = 1.019 g/ml
FInd:
Mass of sample in mg
Computation:
Mass = density x volume
Mass of sample in mg = Volume of urine sample x Density of sample
Mass of sample in mg = 1.019 x 15
Mass of sample in mg = 15.285 gram
Mass of sample in mg = 15.285 x 1,000
Mass of sample in mg = 15,285 mg
Express as ordinary numbers.
3 x 10^0 =
Answer:
the answer is 3
Explanation:
hope this works
Name the parts of an electromagnet
Answer:
The iron core, copper wire, and an electricity source.
Explanation: Me
Please help me with this ASAP i I will give you Brainliest
GenAlex Medical, a leading manufacturer of medical laboratory equipment, is designing a new automated system that can detect normal levels of dissolved triiodothyronine ( to ), using a blood sample that is as small as . Calculate the minimum mass in picograms of triiodothyronine that the new system must be able to detect. Be sure your answer has the correct number of significant digits.
Answer:
0.87 pg
Explanation:
GenAlex Medical, a leading manufacturer of medical laboratory equipment, is designing a new automated system that can detect normal levels of dissolved triiodothyronine (230. to 660 pg/dL), using a blood sample that is as small as 380 μL. Calculate the minimum mass in picograms of triiodothyronine that the new system must be able to detect. Be sure your answer has the correct number of significant digits.
Step 1: Convert 380 μL to deciliters
We will use the following conversion factors.
1 L = 10⁶ μL1 L = 10 dL380 μL × 1 L/10⁶ μL × 10 dL/1 L = 3.8 × 10⁻³ L
Step 2: Calculate the minimum mass of triiodothyronine that can be found in a 3.8 × 10⁻³ L blood sample
Since we are looking for the minimum mass, we will use the lower limit of the concentration interval (230. pg/dL).
3.8 × 10⁻³ L × 230. pg/dL = 0.87 pg
25.0 mL of nitrous acid (HNO2) is titrated with a 1.235 M solution of KOH. The equivalence point (stoichiometric point) is observed after 9.26 mL of base is added. What is the original concentration of the acid
Answer:
0.456 M
Explanation:
Step 1: Write the balanced neutralization equation
HNO₂ + KOH ⇒ KNO₂ + H₂O
Step 2: Calculate the reacting moles of KOH
9.26 mL of 1.235 M KOH react.
0.00926 L × 1.235 mol/L = 0.0114 mol
Step 3: Calculate the reacting moles of HNO₂
The molar ratio of HNO₂ to KOH is 1:1. The reacting moles of HNO₂ are 1/1 × 0.0114 mol = 0.0114 mol.
Step 4: Calculate the initial concentration of HNO₂
0.0114 moles of HNO₂ are in 25.0 mL of solution.
[HNO₂] = 0.0114 mol / 0.0250 L = 0.456 M
In a physical change, the _____ does not change.
Physical changes occur when objects or substances undergo a change that does not change their chemical composition. This contrasts with the concept of chemical change in which the composition of a substance changes or one or more substances combine or break up to form new substances.
A 0.288 g sample of an unknown monoprotic acid is dissolved in water and titrated with a 0.115 M NaOH solution. After the addition of 17.84 mL of base, a pH of 4.92 is recorded. The equivalence point is reached when a total of 33.83 mL of NaOH is added. What is the molar mass of the acid
Answer:
74.0 g/mol
Explanation:
Step 1: Write the generic neutralization reaction
HA + NaOH ⇒ NaA + H₂O
Step 2: Calculate the reacting moles of NaOH
At the equivalence point, 33.83 mL of 0.115 M NaOH react.
0.03383 L × 0.115 mol/L = 3.89 × 10⁻³ mol
Step 3: Calculate the moles of HA that completely react with 3.89 × 10⁻³ moles of NaOH
The molar ratio of HA to NaOH is 1:1. The reacting moles of HA is 1/1 × 3.89 × 10⁻³ mol = 3.89 × 10⁻³ mol.
Step 4: Calculate the molar mass of the acid
3.89 × 10⁻³ moles of HA have a mass of 0.288 g.
M = 0.288 g / 3.89 × 10⁻³ mol = 74.0 g/mol
How much energy does an X-ray with an 8 nm (8 x 10-9m) wavelength have?
A. 1.99 x 10-25 J
B. 3.33 x 1016 J
C. 2.48 x 10-17 j
D. 8.28 x 10-26 J
Answer:
it would be option C
Explanation:
Speed of light = 3×10^8m/s
Planck's constant = 6.626×10^-34 Js
Wavelength = 8 x 10^-9 m
Energy = [(3×10^8) * (6.626×10^-34)] / 8 x 10^-9
Energy = [19.878×10^(8-34)] / 8 x 10^-9
Energy = 2.48475 × 10^(-26+9)
Energy = 2.48×10^-17 J
What volume in mL of 0.220 M HBr solution is required to produce 0.0130 moles of HBr?
Answer: A volume of 59 mL of 0.220 M HBr solution is required to produce 0.0130 moles of HBr.
Explanation:
Given: Moles = 0.0130 mol
Molarity = 0.220 M
Molarity is the number of moles of solute present in liter of a solution.
[tex]Molarity = \frac{moles}{volume (in L)}[/tex]
Substitute the values into above formula as follows.
[tex]Molarity = \frac{moles}{volume (in L)}\\0.220 M = \frac{0.0130 mol}{Volume (in L)}\\Volume (in L) = 0.059 L[/tex]
As 1 L = 1000 mL
So, 0.059 L = 59 mL
Thus, we can conclude that a volume of 59 mL of 0.220 M HBr solution is required to produce 0.0130 moles of HBr.
