four terms in the sequence an are a3=15, a4=19, a5=23, and a6=27 which function can be used to find the nth term in the sequence

The percentage reduction can be written as 16.6667% of 300. 83.3333 percent decrease (%↓) or reduction from 300 is 50.

Answer:

83.33%

Step-by-step explanation:

300-50=250

250/300=83.33%

Answer:

Part A

x + y ≤ 460...(1)

2.5·x + 1.25·y ≥ 600...(2)

Part B

The number of bottles of water the student must sell ≥ 192 bottles of water

Step-by-step explanation:

The given parameters are;

The selling price of each can of lemonade = $2.50

The selling price of each bottle of water = $1.25

The amount of money the club needs to raise = $600

The maximum number of cans and bottles the students can accept = 460

Part A

Let 'x' represent the number of cans of lemonade the students accept, and let 'y' represent the number of bottles the student accept, the system of inequalities that can be used to represent the situation can be presented as follows;

x + y ≤ 460...(1)

2.5·x + 1.25·y ≥ 600...(2)

Part B

The number of cans of lemonade the club sells, x = 144

The number of bottles of water the student must sell to cover the cost of costumes, 'y', is given from the second inequality as follows;

2.5 × 144 + 1.25·y ≥ 600

1.25·y ≥ 600 - 2.5 × 144 = 240

1.25·y ≥ 240

y ≥ 240/1.25 = 192

y ≥ 192

The number of bottles of water the student must sell = 192 bottles of water

Step-by-step explanation:

my answer is an image above

Answer:

6x-1

Step-by-step explanation:

m(x)= 2x-9

p(x)= 4x+8

(m+p)(x)  = 2x-9+4x+8

= 6x-1

Answer:8

Step-by-step explanation:

0.5*10=5

3+5=8

a. Montserrat runs 7.5 kilometers in her 10th training week.

b. by her 15th training week, Montserrat will have run a total of 78.75 kilometers.

To find how many kilometers Montserrat runs in her 10th training week, we can use the arithmetic sequence formula to find the nth term:

[tex]a_n = a_1 + (n - 1) * d[/tex]

where:

[tex]a_n[/tex] is the nth term (the number of kilometers in the nth week),

[tex]a_1[/tex] is the first term (the number of kilometers in the first week, which is 3 km),

n is the number of weeks (in this case, 10), and

d is the common difference (the amount by which the distance increases each week, which is 0.5 km).

[tex]a_{10} = 3 + (10 - 1) * 0.5\\a_{10} = 3 + 9 * 0.5\\a_{10} = 3 + 4.5\\a_{10 }= 7.5 km[/tex]

So, Montserrat runs 7.5 kilometers in her 10th training week.

b. Next, to calculate the total number of kilometers Montserrat will have run by her 15th training week, we use the sum of the first n terms formula:

[tex]S_n = (n / 2) * (a_1 + a_n)[/tex]

where:

[tex]S_n[/tex] is the sum of the first n terms (the total number of kilometers run by the nth week),

[tex]a_1[/tex] is the first term (3 km),

[tex]a_n[/tex] is the nth term (which we found to be 7.5 km in her 10th week),

n is the number of weeks (15 in this case).

[tex]S_{15} = (15 / 2) * (3 + 7.5)\\S_{15} = 7.5 * 10.5\\S_{15} = 78.75 km[/tex]

So, by her 15th training week, Montserrat will have run a total of 78.75 kilometers.

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Answer:

can u plz rewrite the question

Answer:

5%

Step-by-step explanation:

Percent error = (actual - estimated) / actual x 100

(240 - 228) / 240 x 100 = 5%

Answer:

x      -2      -1       0      1

y      -1       2        5      8

Step-by-step explanation:

y=3x+5

When x=-2

y=3(-2)+5

y=-6+5

y=-1

when x=-1

y=3(-1)+5

y=-3+5

y=2

whenx=0

y=3(0)+5

y=5

When x=1

y=3(1)+5

y=3+5

y=8

Answer:

29

Step-by-step explanation:

There is a triangle embedded in triangle MNO, which is triangle PQO, and these are similar triangles in that their corresponding sides are always in the same ratio, which in this case is 2:1, as MP = MO due to the midpoint definition, and therefore MO is twice as long as MP. Same for NO and QO.

Now that we know the ratio, we can set 6x-4 = 2(-5x+64)

6x-4 = -10x +108

16x = 112

x = 7

Plug x back in for PQ, -5(7)+64 = 29

The measure of PQ is 22 units.

A triangle's third side is stated to be parallel to the line segment uniting its two midpoints, and it is also half as long as the third side.

Given:

PQ = 5x + 62, and MN = 6x-4

Now, using Mid- Point Theorem

PQ= 1/2 MN

-5x+ 62 = 1/2( 6x - 4)

-5x+ 62 = 3x - 2

-5x- 3x = -2 - 62

-8x = -64

x= 8

and, PQ= 5x+ 62 = -5(8) + 62 = -40 + 62 = 22

Hence, the measure of PQ is 22 units.

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Step-by-step explanation:

When X is - 5 then y is 3

When X is-1 then y is - 2

When X is 3 then y is -4

From the graph we get, when x is - 5 then y is 3, when x is -1 then y is - 2, and when x is 3 then y is -4.

A point is a dot in space used to indicate an exact location in space.

Consider the first line, which has constant y values. its x value ranges from -1 to negative infinity.

The second line is starts from (-1,-2) point and tend towards positive infinity but its y values and x values are varying.

Hence, when x = -5 y is 3 and at x = -1 the y values is -2. Similarly, when x = 3 then y = -4.

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Answer:

B. (7b – 9)(7b + 9)

Step-by-step explanation:

got 100% on my quiz

Answer:

38.92 dollars

Step-by-step explanation:

Answer: $13.90

Step-by-step explanation:

Since Susana has a budget for school stationery of $33, but has already spent $19.10 on books and folders, the inequality that shows how much she can spend on other stationery, will be represented by:

p + $19.10 = $33

p = $33 - $19.10

The inequality is p = $33 - $19.10

Then, the amount that she can spend on other stationery will be:

P = $33 - $19.10

P = $13.90

She can spend $13.90 on other stationary

Answer:

[tex]10 \frac{2}{5}[/tex]

Step-by-step explanation:

Using BODMAS

[tex]6\frac{1}{2} \times (\frac{8}{9} \div\frac{13}{18}) + ( \frac{3}{4} )\ of \ 3\frac{1}{5} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ [ \ solving \ expression \ inside \ bracket \ ]\\\\\frac{13}{2} \times (\frac{8}{9} \times \frac{18}{13}) + (\frac{3}{4}) \ of \ \frac{16}{5} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ [ \ \frac{a}{b} \div \frac{c}{d} = \frac{a}{b} \times \frac{d}{c} \ ]\\\\\frac{13}{2} \times (\frac{16}{13}) + (\frac{3}{4}) \ of \frac{16}{5} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ [ \ solving \ of \ ] \\\\[/tex]

[tex]\frac{13}{2} \times (\frac{16}{13} ) + (\frac{3}{4} \times \frac{16}{5} )\\\\\frac{13}{2} \times (\frac{16}{13} ) + \frac{12}{5} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ [\ solving \ \times \ expressions \ ] \\\\(\frac{13}{2} \times \frac{16}{13}) + \frac{12}{5}\\\\8 + \frac{12}{5}\\\\\frac{40 + 12}{5}\\\\\frac{52}{5}\\\\10\frac{2}{5}[/tex]

Answer:

Step-by-step explanation:

The standard form equation for this type of problem is

[tex]y=a(b)^x[/tex] where a is the initial value, b is the rate of depreciation, and x is the number of years in question. Because the value of the car is going down, b can also be written as (1 - r) where r is the rate of depreciation. For us, then, the equation will look like this:

[tex]y=a(1-r)^x[/tex] and filling in:

[tex]y=21000(1-.14)^3[/tex] which in simplified form is

[tex]y=21000(.86)^3[/tex] which I'm assuming is how choice 4 should look.

Answer:

x=3.5

Step-by-step explanation:

25÷2=12.5

12.5-9=3.5

Answer:

7/5 or 3.5

Step-by-step explanation:

2 (x+9) =25

x+9 = 25/2

x = (25/2) - 9

x = 7/2 in decimal = 3.5

Answer:

0, 0.5, 8/3, root 5, 3.1

Answer:

C. g(x) = 4x²

Step-by-step explanation:

we have one specific point on g(x) : (1,4)

so, for x=1 the functional value (y) has to be 4.

A. (4×1)² = 4² = 16 and not 4. => wrong

B. 1/4 × 1² = 1/4 and not 4. => wrong

C. 4×1² = 4 and that IS 4 => correct

D. 16×1² = 16 and not 4 => wrong

Answer:

Can I get the full question please

Step-by-step explanation:

x + y = 10 - - - 1

x=2y - - - - - 2

Putting the value of x in eqn 1,

2y+y=10

y=10/3

=3.33 yrs

Which i feel is incorrect

Answer:

z = -74

Step-by-step explanation:

12 = (2+z) / -6

Multiply each side by -6

-6 * 12 = (2+z)/ -6 * -6

-72 = 2+z

Subtract 2 from each side

-72-2 = 2+z-2

-74 =z

Answer:

n=8

Step-by-step explanation:

Answer:   7 years

Step-by-step explanation:

let x be the age of Mary

so John's age will be 2x

the equation becomes

2x+x=21

3x=21

x=21/3

x=7

Answer:

Step-by-step explanation:

Let Mary's age = x years

John's age = 2 * x = 2x

The sum of their ages = 21

x + 2x = 21

3x = 21

Divide both sides by 3

x = 21/3

x = 7

Mary's age = 7 years

Answer:

Option C, functions can only have one y-value at any given x-place

[tex]\displaystyle\bf 1200=12*100=3*4*(2*5)^2=3*2^2*2^2*5^2=2^4*3^1*5^2 \\\\Answer: \boxed{ A)\quad a=4 \quad ; \quad b=1 \quad ; \quad c=2}[/tex]

Answer:

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Answer:

I hope it helps u..........

Answer:

30

So the two sectors add to the full length:

JK + IJ = IK

x+6 + 9 = 2x

Rearrange:

x=15

So the numerical length:

2x

2*15

30