Answers
Answer:
The answer is A.
Step-by-step explanation:
A supplementary angles are angles that when adding both sides will sum up to 180 Degrees.
<JKH and <LKH will be the correct answer because they add up tp 180 degrees.
Star Me!!!
Related Questions
How many odd numbers are between 10 and 50?
Answers
Answer:
There are 20 odd numbers between 10 and 50
Step-by-step explanation:
Here are all the odd numbers! Hope this helps!
11, 13, 15, 17, 19, 21, 23, 25, 27, 29, 31, 33, 35, 37, 39, 41, 43, 45, 47, 49
PLSS HELP ASAP!!
13 points when answered:) Thank you!!
Answers
Answer:
The wright answer is A
Step-by-step explanation:
[tex] \sqrt{20} = 4.47 \\ \frac{14}{3} = 4.67 \\ 4.47 < 4.5 < 4.67[/tex]
What are some of the applications for exponential functions?
Designing identification tags
Conversion of measurements
Assigning phone numbers
Finding perimeter
Determining the number of subsets in a given set
Answers
Answer:
Option B and D are correct
Step-by-step explanation:
Exponential functions are really useful in the real world situation. They can be used to solve following
a) Population Models
b) Determination of area and perimeters
c) Determine time related things such as half life, time of happening of an event etc.
d) Useful for solving financial problems such as computing investments etc.
Hence, option B and D
A bicycle is originally priced at $60. The online retailer gives a discount and the bicycle is now priced at $42. Enter the percentage discount for the cost of the bicycle.
Answers
Answer:
30% ywww
Step-by-step explanation:
!NO LINKS, NO FILES!
please :)
Answers
12 x 6 = 72
the area is 72 in^2
Answer:
the area is 72
Step-by-step explanation:
what is the midpoint of a segment with endpoints at (-4,-8) and (8,10)
Answers
Answer: Midpoint: (2, 1)
Step-by-step explanation:
Midpoint formula: ((x1 + x2)/2 , (y1 + y2)/2)
(-4 + 8)/2 = 2
(-8 + 10)/2 = 1
Answer: (2, 1)
Pls help i'll give brainlest
Answers
Answer: B. 183 cm^3
V = pi r^2 h/3
V = pi (5^2) (7/3)
V = pi (25) (2.33)
V = 183
Answer:
B.183 [tex]cm^{3}[/tex]
Step-by-step explanation:
Volume of cone is [tex]V=\pi r^{2} \frac{h}{3}[/tex]
where h=7 and r=5 (because r=d/2, where d=10)
V=[tex]5^{2}\frac{7}{3}\pi[/tex]
V=25·[tex]\frac{7}{3} \pi[/tex]
V=175/3[tex]\pi[/tex]
V=183.2595715 or 183 [tex]cm^{3}[/tex]
Which of the following equations is equivalent to S= xi?n?
On-S-xr2
S
Golf
S
On-$+$12
Answers
Answer:
umm to me its 2--%456
Step-by-step explanation:
The most expensive type of life insurance is
O limited-payment life insurance
O term insurance
O endowment life insurance
O whole-life insurance
Answers
An agricultural scientist collected data to study the relationship between the amount of nitrogen added to a cornfield and the number of
bushels of corn produced. This is the regression line of the data, where y is measured in bushels of corn and x is measured in pounds of
nitrogen.
y = 0.43x + 28.5
What is the meaning of the slope of the regression line?
O A. For every 0.43 pounds of nitrogen added to the field, the amount of corn yielded increases by 28.5 bushels.
OB. For every 1 pound of nitrogen added to the field, the amount of corn yielded increases by 0.43 bushels.
-
OC. For every 1 pound of nitrogen added to the field, the amount of corn yielded increases by 28.5 bushels.
OD. For every 28.5 pounds of nitrogen added to the field, the amount of corn yielded increases by 0.43 bushels.
Answers
Answer:
D.
Step-by-step explanation:
just done the assignment
Linear regression line is a algebraic model to show the relationship between the two models by putting the value of the one variable to get the value of other.. For every 1 pound of nitrogen added to the field, the amount of corn yielded increases by 0.43 bushels. Therefore the option B is the correct option.
Given information-The equation of the experiment to know the relationship between the amount of nitrogen added to a cornfield and the number of bushels of corn produced is,
[tex]y=0.43x+28.5[/tex]
Linear regression lineLinear regression line is a algebraic model to show the relationship between the two models by putting the value of the one variable to get the value of other.
Linear regression line can be represent as,
[tex]y=Ax+B[/tex]
Here x is the explanatory variable and y is the dependent variable. A is the slope of the line and B is the intercept.
In the given equation there are two variable given.
Variable x represent the amount of nitrogen added, and the variable y, represents the number of bushels of corn produced.
As putting the value of x the y increases with value of number 0.43. Thus as we are increasing the value of the nitrogen with unit 1 the number of bushels of corn produced is increased by unit 0.43.
Hence for every 1 pound of nitrogen added to the field, the amount of corn yielded increases by 0.43 bushels. Therefore the option B is the correct option.
Learn more about the linear regression here;
https://brainly.com/question/25311696
Pre-Test
Active
1
2
3
4
10
The quotient of (x4 + 5x - 3x – 15) and a polynomial is (x3 - 3). What is the polynomial?
x? + 5x6 - 6x4 - 30x3 + 9x + 45
x-5
x + 5
x7 + 5x + 6x4 + 30x3 + 9x + 45
Answers
Answer:
x5
Step-by-step explanation:
Answer: C.
Step-by-step explanation:
EDGE 2023
Helpppppppppppppppppppp
Answers
Answer:
95°
Step-by-step explanation:
95°
They are vertical angles.
Answer:
95 degree write it fast jakakkaoaoa
Can someone help? I hate math so much lol I don’t understand
Answers
Answer:
±6
Step-by-step explanation:
Given the mathematical expression;
√36 < √42 < √49
But, √36 = 6 * 6 = 6²
√49 = 7 * 7 = 7²
Simplifying further, we would substitute the new values respectively;
±[6] < √42 < ±[7]
Therefore, evaluating √36 is equal to ±6.
Find the area of the composite figure.
9 ft
4 ft
6 ft
Answers
A worldwide organization of academics claims that the mean IQ score of its members is 118, with a standard deviation of 17. A randomly selected group of 35 members of this organization is tested, and the results reveal that the mean IQ score in this sample is 116.8. If the organization's claim is correct, what is the probability of having a sample mean of 116.8 or less for a random sample of this size
Answers
Answer:
0.3372 = 33.72% probability of having a sample mean of 116.8 or less for a random sample of this size
Step-by-step explanation:
To solve this question, we need to understand the normal probability distribution and the central limit theorem.
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Central Limit Theorem
The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
The mean IQ score of its members is 118, with a standard deviation of 17.
This means that [tex]\mu = 118, \sigma = 17[/tex]
Sample of 35:
This means that [tex]n = 35, s = \frac{17}{\sqrt{35}}[/tex]
What is the probability of having a sample mean of 116.8 or less for a random sample of this size?
This is the pvalue of Z when X = 116.8. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
By the Central Limit Theorem
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]Z = \frac{116.8 - 118}{\frac{17}{\sqrt{35}}}[/tex]
[tex]Z = -0.42[/tex]
[tex]Z = -0.42[/tex] has a pvalue of 0.3372
0.3372 = 33.72% probability of having a sample mean of 116.8 or less for a random sample of this size
Which fraction is the product of 5/4 x 6?
Answers
Answer:
15 x /2
Step-by-step explanation:
You have been given the task of designing a study concerning the lifetimes of five different types of electric motor. The initial question to be addressed is whether there are differences in mean lifetime among the five types. There are 20 motors, four of each type, available for testing. A maximum of five motors can be tested in a day. The ambient temperature differs from day to day, and this can affect motor lifetime.
a. Describe how you would choose the five motors to test each day. Would you use a completely randomized design? Would you use any randomization at all?
b. If X;j represents the measured lifetime of a motor of type i tested on day j, express the test statistic for testing the null hypothesis of equal lifetimes in terms of the Xir
Answers
Answer:
a-As the only factor of interest is type of electric motor, thus instead of using 1-factor randomization, a randomized block design is used where at maximum one motor of each type is tested every day.
b- The test statistic is given as
[tex]F_{I-1,(I-1)(J-1)}=\dfrac{12\left(\Sigma^{5}_{i=1}\bar{X}^{2}_{i.}-IJ\bar{X}^2_{..}\right) }{\Sigma^5_{i=1}\Sigma^4_{j=1}\left(X_{ij}-\bar{X}_{i.}-\bar{X}_{.j}+\bar{X}_{..}\right)^2}[/tex]
Step-by-step explanation:
a-
This is done such that the days are considered as blocks and the randomization is only occuring within the block. The order of testing is random. However the condition is implemented such that one motor of each type is tested each day.
b-
The F-Value is given as
[tex]F-Value=\dfrac{MSA}{MSAB}[/tex]
Here MSA is given as
[tex]MSA=\dfrac{J\Sigma^I_{i=1}(\bar{X}_{i.}-\bar{X}_{..})^2}{I-1}[/tex]
Here
I is the number of types which is 5J is the number of motors of each type which is 4[tex]\bar{X}_{i.}[/tex] is the row-wise mean which is given as [tex]\bar{X}_{i.}=\dfrac{1}{J}\Sigma^J_{j=1}X_{ij}[/tex][tex]\bar{X}_{..}[/tex] is the sample grand mean which is given as [tex]\bar{X}_{..}=\dfrac{1}{IJ}\Sigma^I_{i=1}\Sigma^J_{j=1}X_{ij}[/tex]Similarly MSAB is given as
[tex]MSAB=\dfrac{\Sigma^I_{i=1}\Sigma^J_{j=1}\left(X_{ij}-\bar{X}_{i.}-\bar{X}_{.j}+\bar{X}_{..}\right)^2}{(I-1)(J-1)}[/tex]
Here
I is the number of types which is 5J is the number of motors of each type which is 4[tex]\bar{X}_{i.}[/tex] is the row-wise mean which is given as [tex]\bar{X}_{i.}=\dfrac{1}{J}\Sigma^J_{j=1}X_{ij}[/tex][tex]\bar{X}_{..}[/tex] is the sample grand mean which is given as [tex]\bar{X}_{..}=\dfrac{1}{IJ}\Sigma^I_{i=1}\Sigma^J_{j=1}X_{ij}[/tex][tex]\bar{X}_{.j}[/tex] is the column-wise mean which is given as [tex]\bar{X}_{.j}=\dfrac{1}{I}\Sigma^I_{i=1}X_{ij}[/tex][tex]X_{ij}[/tex] is the any motor j of type iBy putting these values and simplifying, equation becomes:
[tex]F-Value=\dfrac{MSA}{MSAB}\\\\F-Value=\dfrac{\dfrac{J\Sigma^I_{i=1}(\bar{X}_{i.}-\bar{X}_{..})^2}{I-1}}{\dfrac{\Sigma^I_{i=1}\Sigma^J_{j=1}\left(X_{ij}-\bar{X}_{i.}-\bar{X}_{.j}+\bar{X}_{..}\right)^2}{(I-1)(J-1)}}\\\\F-Value=\dfrac{\dfrac{4\Sigma^5_{i=1}(\bar{X}_{i.}-\bar{X}_{..})^2}{5-1}}{\dfrac{\Sigma^5_{i=1}\Sigma^4_{j=1}\left(X_{ij}-\bar{X}_{i.}-\bar{X}_{.j}+\bar{X}_{..}\right)^2}{(5-1)(4-1)}}\\\\[/tex]
This is further simplified as
[tex]F-Value=\dfrac{\dfrac{4\Sigma^5_{i=1}(\bar{X}_{i.}-\bar{X}_{..})^2}{4}}{\dfrac{\Sigma^5_{i=1}\Sigma^4_{j=1}\left(X_{ij}-\bar{X}_{i.}-\bar{X}_{.j}+\bar{X}_{..}\right)^2}{12}}\\\\F-Value=\dfrac{\Sigma^5_{i=1}(\bar{X}_{i.}-\bar{X}_{..})^2}{\dfrac{\Sigma^5_{i=1}\Sigma^4_{j=1}\left(X_{ij}-\bar{X}_{i.}-\bar{X}_{.j}+\bar{X}_{..}\right)^2}{12}}\\\\[/tex]
The numerator can be written as
[tex]F-Value=\dfrac{\Sigma^{5}_{i=1}\bar{X}^{2}_{i.}-IJ\bar{X}^2_{..}}{\dfrac{\Sigma^5_{i=1}\Sigma^4_{j=1}\left(X_{ij}-\bar{X}_{i.}-\bar{X}_{.j}+\bar{X}_{..}\right)^2}{12}}\\\\F-Value=\dfrac{12(\Sigma^{5}_{i=1}\bar{X}^{2}_{i.}-IJ\bar{X}^2_{..})}{{\Sigma^5_{i=1}\Sigma^4_{j=1}\left(X_{ij}-\bar{X}_{i.}-\bar{X}_{.j}+\bar{X}_{..}\right)^2}}\\[/tex]
4^?=1024? i know the answer is 5 but is there an easier way to find that out instead of guessing?
Answers
Answer:
here you go............
Step-by-step explanation:
I hope it helped
Select the correct answer.
In a sequence described by a function, what does the notation f(3) = 1 mean?
OA.
The third term in the sequence has a value of 1.
OB.
The common difference I of the sequence is 3.
O C.
The first term in the sequence has a value of 3.
OD
The common ratio of the sequence is 3.
Answers
Answer:
c is correct
Step-by-step explanation:
Answer:
c is right answer
Step-by-step explanation:
HOPE IT HELPS U
FOLLOW MY ACCOUNT PLS PLS
Challenge:
Put these in order (least to greatest)
Answers
Answer:
1 1/4, -1, -1/4, 0, 1/4, 1
Step-by-step explanation:
Answer:
-1 1/4, -1, -1/4, 0, 1/4, 1,
Step-by-step explanation:
1. Find (f(g(2)) for f(x)= 3x² and g(x)= 5 - x.
Answers
Answer: 27
Step-by-step explanation:
The standard gasoline engine for the 2017 Toyota Corolla includes the following data: Configuration: In-line four-stroke, four-cylinder engine Bore: 3.17 in Stroke: 3.48 in Compression ratio: 10.6:1 Assuming an ideal Otto cycle to describe this engine. Consider the working fluid to be air, modeled as an ideal gas with variable specific heat. Determine: (a) The total engine volume VBDC for all cylinders (cu.in). (b) The mass of air (lbm) contained in the engine assuming ambient conditions of 540 R and 14.7 psia. (c) The efficiency of the engine (%). The maximum temperature that occurs during the cycle is 3600 R.
Answers
Answer:
a) The total engine volume is 30.3265 in³
b) the mass of air contained in the engine is 0.00129 lbm
c) The efficiency of the engine is 55.6%
Step-by-step explanation:
Given the data in the question;
The configuration is in line with four-stroke, four-cylinder engine.
Bore ( d ) = 3.17 in
Stroke ( L ) = 3.48 in
compression ratio ( r ) = 10.6 : 1
First, we calculate the swept Volume V₁ = π/4 × d²L
we substitute
V₁ = π/4 × (3.17 )² × (3.48) = 27.4655 in³
Now, Compression Ration; r = Vs + Vc / Vc
r = (V₁ + V₂) / V₂
we substitute
10.6 = (27.4655 + V₂) / V₂
10.6V₂ = 27.4655 + V₂
10.6V₂ - V₂ = 27.4655
9.6V₂ = 27.4655
V₂ = 2.861 in³
So
a) total engine volume
[tex]V_{BDC[/tex] = V₁ + V₂
we substitute
[tex]V_{BDC[/tex] = 27.4655 in³ + 2.861 in³
[tex]V_{BDC[/tex] = 27.4655 in³ + 2.861 in³
[tex]V_{BDC[/tex] = 30.3265 in³
Therefore, The total engine volume is 30.3265 in³
b) The mass of air
given that; T = 540°R, P = 14.7 psia
we know that; PV = mRT { R is constant }
we solve for m
m = PV / RT
we substitute
m = (14.7 × 30.3265) / ( 0.3704 × 1728 )540
m = 445.79955 / 345627.648
m = 0.00129 lbm
Therefore, the mass of air contained in the engine is 0.00129 lbm
c) The efficiency
from table { properties of air}
At 540°R; u₁ = 92.04 BTu/lbm, u[tex]_r[/tex]₁ = 144.32
Now process 1 - 2 ( Isentropic ) u[tex]_r[/tex]₁ / u[tex]_r[/tex]₂ = V₁/V₁ = r
so, u[tex]_r[/tex]₁ / u[tex]_r[/tex]₂ = r
144.32 / u[tex]_r[/tex]₂ = 10.6
u[tex]_r[/tex]₂ = 144.32/10.6
u[tex]_r[/tex]₂ = 13.61
Thus, at u[tex]_r[/tex]₂ = 13.61, u₂ = 235 BTU/lbm, T₂ = 1340°R
Now, we know that;
P₁V₁/T₁ = P₂V₂/T₂ ⇒ (P₁/V₁)r = P₂/T₂
⇒ ( 14.7 / 540 )10.6 = P₂/1340
P₂ = 386.664 psia
process 2 - 3; constant volume heat addition;
Now, At T₃ = 3600°R, u₃ = 721.44 BTU/lbm, u[tex]_r[/tex]₃ = 0.6449
so, [tex]q_{in[/tex] = u₃ - u₂
we substitute
so, [tex]q_{in[/tex] = 721.44 - 235 = 486.44 BTU/lbm
Next, process 3 - 4; Isentropic
u[tex]_r[/tex]₄/u[tex]_r[/tex]₃ = V₄/V₃ = r
u[tex]_r[/tex]₄ / 0.6449 = 10.6
u[tex]_r[/tex]₄ = 6.8359
At u[tex]_r[/tex]₄ = 6.8359; u₄ = 308 BTU/lbm
∴
Heat Rejection [tex]q_{out[/tex] = u₄ - u₁ = 308 - 92.04 = 215.96 BTU/lbm
so, [tex]W_{net[/tex] = [tex]q_{in[/tex] - [tex]q_{out[/tex]
[tex]W_{net[/tex] = 486.44 - 215.96
[tex]W_{net[/tex] = 270.48 BTU/lbm
so the efficiency; η[tex]_{thermal[/tex] = ([tex]W_{net[/tex] / [tex]q_{in[/tex] ) × 100%
η[tex]_{thermal[/tex] = ( 270.48 / 486.44 ) × 100%
η[tex]_{thermal[/tex] = ( 0.55604 ) × 100%
η[tex]_{thermal[/tex] = 55.6%
Therefore, The efficiency of the engine is 55.6%
Define the following terms using your own words. (2-3 sentences only)
1. Frequency
2 Class size
3. Ogive
4. Variance
5. Range
Answers
Answer:
Frequency: the rate at which something occurs over a particular period of time or in a given sample.Class size :Class size is the average number of students per class, calculated by dividing the number of students enrolled by the number of classes..O give :Ogive is the curve which is constructed by plotting cumulative frequency data on the graph paper, in the form of a smooth curve.Variance: The term variance refers to a statistical measurement of the spread between numbers in a data set. Range: The range, the difference between the largest value and the smallest value.The base and height of a triangle are 9 yards and 10 yards respectively. Find the area of the triangle.
Answers
Answer:
45
Step-by-step explanation:
1/2×9×10
since the formula says half base times height, so therefore
Area =45
How many faces does a triangular pyramid have?
A. 3
B. 6
C. 4
D. 5
Answers
[tex]\huge{\textbf{\textsf{{\color{navy}{An}}{\purple{sw}}{\pink{er}} {\color{pink}{:}}}}}[/tex]
C. 4.
thanks hope it helpsThe management of KSmall Industries is considering a new method of assembling a computer. The current assembling method requires a mean time of 66 minutes with a standard deviation of 3.0 minutes. Using the new method, the mean assembly time for a random sample of 24 computers was 61 minutes.
a. Using the 0.10 level of significance, can we conclude that the assembly time using the new method is faster?
b. What is the probability of a Type II error? (Round "Critical values" to 2 decimal places and round your final answer to 4 decimal places.)
Answers
Answer:
Part a:
Since the calculated z= 8.1649 falls in the critical region z < ± 1.28 we reject H0 and conclude that the assembly time using the new method is faster.
Part b:
P (Type II Error)= 0.6628
Step-by-step explanation:
The null and alternate hypothesis are
H0: μ1 ≥ μ2 against the claim Ha: μ1 < μ2
This is left tailed test
The critical region for this test at 0.10 ∝ is z < ± 1.28
The test statistic
z= x1-x2/ s/√n
z= 66-61/ 3/√24
z= 5/0.61238
z= 8.16486
Since the calculated z= 8.1649 falls in the critical region z < ± 1.28 we reject H0 and conclude that the assembly time using the new method is faster.
Part b:
P (Type II Error) = P ( accept H0/ H0 is false)
z ( ∝)= X-u/s/√n
1.28= X-61/0.61238
X= 61.7838
So I will incorrectly fail to reject the null as long as a draw a sample mean that greater than 61.7838
The probability of a Type II error is given by
P (z> 61.7838-66/24)
P (z>- 0.42161)
From the tables
P (z>- 0.42161)= 0.6628
Please help with this question it is due today I will give 20 points. Thank you and may God bless you! :)
Answers
I would say A but please wait for someone else to answer to make sure it's not wrong I would hate for you to get this wrong
Suppose that there is a black urn containing nine black balls and three yellow balls and there is a yellow urn containing six black balls and six yellow balls. An experiment consists of selecting at random a ball from the black urn and then (without replacing the first ball) selecting at random a ball from the urn having the color of the first ball.
1. Construct a tree diagram showing the probabilities associated with this problem. Write a probability on each branch (6 branches). Multiply the the probabilities along each path and write that number at the end of the path (4 answers).
2. Find the probability that the second ball is yellow.
Answers
Answer:
See Annex ( Tree diagram )
Step-by-step explanation:
1) Attached
2) Probability of the second ball is yellow is
P(2nd ball is yellow ) = Probability 2nd ball s yellow (if the first one was black) + Probability 2nd ball s yellow (if the first one was Yellow)
P(2nd ball is yellow ) = 0,204 + 0,045
P(2nd ball is yellow ) = 0,249
what is the formula of finding square rood
Answers
Answer:
[tex] \huge\blue{ \mid{ \underline{ \overline{ \tt ♡ ANSWER ♡ }} \mid}}[/tex]
There's no specific formula to find the square root of a number, however we can find the square root of a number by the following methods:
i) By Prime Factorisation
ii) By Long Division
iii) By Repeated subtraction method
✏ By Prime Factorisation:Step I: Obtain the given number.
Step II: Reduce the given number into prime factors by successive division.
Step III: Now make pairs of prime factors in such a way that both the factors in each pair are equal.
Step IV: Take one factor from each pair and find the product of these factors.
Step V: The product obtained by multiplying the factors is the required square root.
✏ Long Division:Step 1: Firstly, we place a bar on every pair of digits starting from the unit digit. If the number of digits in it is odd, we put a bar on the single-digit too.
Step 2: Now we find the largest number whose square is less than or equal to the 1st number.
Step 3: Now we bring down the next bar number.
Step 4: For new divisor, we add the divisor & quotient.
Step 5: Number taken is the product of a new divisor and this digit is equal to or less than the new dividend.
✏ Repeated subtraction method:In this method, the given number is subtracted by 1, 3, 5, 7,… at every step till you get zero at the end. The number of steps in the solution is the required square root.
ʰᵒᵖᵉ ⁱᵗ ʰᵉˡᵖˢ
A sweater costs $25. The store marks up the price by 85%. What is the selling price of the sweater?
