Given
Δ
Q
R
S

Δ
T
U
V
,
Q
S
=
3
v
+
2
and
T
V
=
7
v

6
, find the length of QS and TV.

Answers

Answer 1

The length of the segment QS is 8 units and the length of the segment TV is 8 units and this can be determined by using similar triangle properties.

Given :

Triangle QRS is congruent to triangle TUV.The length of the segment QS is (3v + 2).The length of the segment TV is (7v - 6).

The following steps can be used in order to determine the length of QS and TV:

Step 1 - According to the given data, the triangle QRS is congruent to triangle TUV.

Step 2 - So, the length of the segment QS is equal to the length of the segment TV.

QS = TV

Step 3 - Substitute the values of QS and TV in the above expression.

3v + 2 = 7v - 6

7v - 3v = 6 + 2

4v = 8

v = 2

Step 4 - The length of the segment QS and TV is:

QS = 3(2) + 2 = 6 + 2

QS = 8

TV = 7(2) - 6 = 14 - 6

TV = 8

For more information, refer to the link given below:

https://brainly.com/question/25882965


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Step-by-step explanation:

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I think the answer is 2.

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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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Answers

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Step-by-step explanation:

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Answers

Answer:

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Answers

Answer:

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Step-by-step explanation:

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Answers

Given:

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Answers

Answer:

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Step-by-step explanation:

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Answer:

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Answers

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Answers

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Answers

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Step-by-step explanation:

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Answers

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Answer:

[tex]Section \: A. \\before \: the \: donation \ : jane \: had \: \boxed{18 \: (stuffed \: animals)} \\

Section B.\\

\boxed{the\: percentage\: of\: female\: student\: is\: \boxed{48 \%}}

[/tex]

Step-by-step explanation:

[tex]Section A.\\let \: the \: total \: animals \: be \to \: t_{a} \\ let \: the \: donated\: animals \: be \to \: d_{a} \\ then \to \\ if \: d_{a} = \frac{2}{3} (t_{a} ) : we \: can \: find \: t_{a} \: by \to \\ 12 = \frac{2}{3} (t_{a} ) \\ 2(t_{a} )= 12 \times 3 \\ t_{a} = \frac{36}{2} \\ \boxed{ t_{a} = 18.}

\\ \\

Section B.\\

let \: the \: total \: number\: of \: students\: be \: be \to \: t_{s} \\ let \: the \: number\: of \: male\: student\: be \: be \to \: m_{s} \\ then \to \\ if \: t_{s} = m_{s} +1 3 \: then \\

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m_{s} =12 \\

hence \: percentage \: of \: girls \: is = \frac{12}{25} \times 100 \\

the \: percentage\: is \to \boxed{m_{s} = 48\%}

[/tex]

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