Given that
[tex]\sqrt{2p-7}=3[/tex]
and
[tex]7\sqrt{3q-1}=2[/tex]
Evaluate
[tex]p + {q}^{2} [/tex]​

2x-7y=10 = [tex]\frac{2}{7}[/tex]

5x -6y=2 = [tex]\frac{5}{6}[/tex]

Answer:

10). m∠x = 47°

11). x = 30.96

Step-by-step explanation:

10). By applying Sine rule in the given triangle DEF,

   [tex]\frac{\text{SinF}}{\text{DE}}=\frac{\text{SinD}}{\text{EF}}[/tex]

   [tex]\frac{\text{Sinx}}{7}=\frac{\text{Sin110}}{9}[/tex]

   Sin(x) = [tex]\frac{7\times (\text{Sin110})}{9}[/tex]

   Sin(x) = 0.7309

   m∠x = [tex]\text{Sin}^{-1}(0.7309)[/tex]

   m∠x = 46.96°

   m∠x ≈ 47°

11). By applying Sine rule in ΔRST,

   [tex]\frac{\text{SinR}}{\text{ST}}=\frac{\text{SinT}}{\text{RS}}[/tex]

   [tex]\frac{\text{Sin120}}{35}=\frac{\text{Sin50}}{x}[/tex]

   x = [tex]\frac{35\times (\text{Sin50})}{\text{Sin120}}[/tex]

   x = 30.96   

Answer:

(B) Reflection in the x-axis

Step-by-step explanation:

We can see that these triangles have the exact same x-coordinates, however their y coordinates are opposite each other. This means that if we wanted to get one of the triangles to the other, we’d have to reflect over the x-axis

(by default, if the x values are the same and y are opposite, reflect across x axis. If y values are the same and x is opposite, reflect over y. it’s sort of like opposites.)

Hope this helped!

Answer:

One solution (-1,2)

Step-by-step explanation:

Since these two linear equations have different slopes, different y-intercepts, and are indeed linear, these equations will only have one crossing when graphed, and hence one solution.

To find that solution, we can simply set the equations equal to each other.

y = -x + 1

y = 2x + 4

-x + 1 = 2x + 4

-3 = 3x

-1 = x

Now plug that value back into one of the equations:

y = -x + 1

y = -(-1) + 1

y = 2

So now you know the crossing for these two equations occurs at (-1,2).

Cheers.

You would type in

32^(6/5)

Or you could type in

32^(1.2)

since 6/5 = 1.2

Either way, the final result is 64

1: 8 faces and 9 with the base 9 vertices and 16 edges

2: 3 faces and 5 with the bases 6 vertices and 9 edges

3: 3 faces and 4 with the base 4 vertices and 6 edges

Hope this can help you.

1: 8 faces and 9 with the base 9 vertices and 16 edges

2: 3 faces and 5 with the bases 6 vertices and 9 edges

3: 3 faces and 4 with the base 4 vertices and 6 edges

Answer:

If x is replaced with -x the graph will stay the same because the absolute value makes 2 values so a negative number and a positive one.

Step-by-step explanation:

Go search it up on desmos.

Answer:

[tex]\huge\boxed{a=9 ; b = -8}[/tex]

Step-by-step explanation:

[tex]f(x) = \frac{ax+b}{x}[/tex]

Putting x = 1

=> [tex]f(1) = \frac{a(1)+b}{1}[/tex]

Given that f(1) = 1

=> [tex]1 = a + b[/tex]

=> [tex]a+b = 1[/tex]  -------------------(1)

Now,

Putting x = 2

=> [tex]f(2) = \frac{a(2)+b}{2}[/tex]

Given that f(2) = 5

=> [tex]5 = \frac{2a+b}{2}[/tex]

=> [tex]2a+b = 5*2[/tex]

=> [tex]2a+b = 10[/tex]  ----------------(2)

Subtracting (2) from (1)

[tex]a+b-(2a+b) = 1-10\\a+b-2a-b = -9\\a-2a = -9\\-a = -9\\a = 9[/tex]

For b , Put a = 9 in equation (1)

[tex]9+b = 1\\Subtracting \ both \ sides \ by \ 9\\b = 1-9\\b = -8[/tex]

Answer:

The  95% confidence interval is  [tex]295.9 < \mu< 324.1[/tex]

A   95% level of confidence mean that there is 95%  chance  that the true population mean will be in this interval

Step-by-step explanation:

From the question we are told that

    The sample size is  [tex]n = 25[/tex]

    The mean is  [tex]\= x = 310 \ mg[/tex]

     The standard deviation is  [tex]\sigma = 36 \ mg[/tex]

Given that the confidence level is  95% then the level of significance is mathematically represented as

           [tex]\alpha = 100 - 95[/tex]

=>        [tex]\alpha = 5\%[/tex]

=>        [tex]\alpha = 0.05[/tex]

Next we obtain the critical value of  [tex]\frac{\alpha }{2}[/tex] from the normal distribution table , the value is  

           [tex]Z_{\frac{\alpha }{2} } =Z_{\frac{0.05 }{2} } = 1.96[/tex]

Generally the margin of error is mathematically represented as

        [tex]E = Z_{\frac{\alpha }{2} } * \frac{\sigma }{\sqrt{n} }[/tex]

substituting values

        [tex]E = 1.96 * \frac{36 }{\sqrt{25} }[/tex]

        [tex]E = 14.1[/tex]

The 95% level of confidence interval  is mathematically represented as

      [tex]\= x - E < \mu<\ \= x - E[/tex]

substituting values

     [tex]310- 14.1 < \mu< 310+ 14.1[/tex]

     [tex]295.9 < \mu< 324.1[/tex]

The  95% level of confidence mean that there is 95%  chance  that the true population mean will be in this interval

Answer:

[tex]Probability = 0.35[/tex]

Step-by-step explanation:

Given

Probability of success free throw = 90%

Number of throw = 10

Required

Determine the probability of 10 consecutive free throws

Let p represents the given probability

[tex]p = 90\%[/tex]

Convert to decimal

[tex]p = 0.9[/tex]

Let n represents the number of throw

[tex]n = 10[/tex]

Provided that each throw is independent;

The probability of n consecutive free throw is

[tex]p^n[/tex]

Substitute 0.9 for p and 10 for n

[tex]Probability = 0.9^{10}[/tex]

[tex]Probability = 0.3486784401[/tex]

[tex]Probability = 0.35[/tex] (Approximated)

Answer:

Decision Rule:  To reject the null hypothesis if t > 1.328

t = 3.913

Step-by-step explanation:

The summary of the given statistics include:

sample size n = 21

the correlation between the number of passengers and total fuel cost r = 0.668

(1) We are tasked to state the decision rule for 0.10 significance level

The degree of freedom df = n - 1

degree of freedom df = 21 - 1

degree of freedom df = 19

The  null and the alternative hypothesis can be computed as:

[tex]H_o : \rho < 0\\ \\ Ha : \rho > 0[/tex]

The critical value for [tex]t_{\alpha, df}[/tex]  is  [tex]t_{010, 19}[/tex] = 1.328

Decision Rule:  To reject the null hypothesis if t > 1.328

The test statistics can be computed as follows by using the formula for t-test for Pearson Correlation:

[tex]t = r*\sqrt{ \dfrac{(n-2)}{(1-r^2)}[/tex]

[tex]t = 0.668*\sqrt{ \dfrac{(21-2)}{(1-0.668^2)}[/tex]

[tex]t = 0.668*\sqrt{ \dfrac{(19)}{(1-0.446224)}[/tex]

[tex]t = 0.668*\sqrt{ \dfrac{(19)}{(0.553776)}[/tex]

[tex]t = 0.668*5.858[/tex]

t = 3.913144

t = 3.913    to 3 decimal places

Answer:

[tex]\huge\boxed{f^{-1}(x) = (x-3)^2+2}[/tex]

Step-by-step explanation:

[tex]f(x) = \sqrt{x-2} + 3[/tex]

Replace y = f(x)

[tex]y = \sqrt{x-2} + 3[/tex]

Exchange x and y

[tex]x = \sqrt{y-2}+3[/tex]

Solve for y

[tex]x = \sqrt{y-2}+3[/tex]

Subtracting both sides by 3

[tex]x - 3 = \sqrt{y-2}[/tex]

Taking square on both sides

[tex](x-3)^2 = y -2[/tex]

Adding 2 to both sides

[tex]y = (x-3)^2+2[/tex]

Substitute y = [tex]f^{-1}(x)[/tex]

[tex]f^{-1}(x) = (x-3)^2+2[/tex]

Answer:

Option D is the correct option

Step-by-step explanation:

[tex] \mathsf{f(x) = \sqrt{x - 2} + 3}[/tex]

Replace f(x) with y

[tex] \mathsf{y = \sqrt{x - 2} + 3}[/tex]

Interchange variables

[tex] \mathsf{x = \sqrt{y - 2} + 3}[/tex]

[tex] \mathsf{{(x - 3)}^{2} = {( \sqrt{y - 2)} }^{2} }[/tex]

[tex] \mathsf{ {(x - 3)}^{2} = y - 2}[/tex]

[tex] \mathsf{ y = {(x - 3)}^{2} + 2}[/tex]

Replace y with f ⁻¹( x )

[tex] \mathsf{ {f}^{ - 1} (x) = {(x - 3)}^{2} + 2}[/tex]

Hope I helped!

Best regards!

Answer:

Step-by-step explanation:

Equation of a circle is given by

( x - h)² + ( y - k)² = r²

where r is the radius and

( h , k) is the center of the circle

From the question the radius R = 1/3

the center ( h ,k ) = (4/3 , -8/3)

Substituting the values into the above equation

We have

[tex](x - \frac{4}{3} )^{2} + {(y - - \frac{8}{3}) }^{2} = ({ \frac{1}{3} })^{2} [/tex]

We have the final answer as

[tex](x - \frac{4}{3} )^{2} + {(y + \frac{8}{3}) }^{2} = \frac{1}{9} [/tex]

Hope this helps you

Answer:

the correct options are:

(–1, 3),  (–2, 2) and (–5, –1)

Step-by-step explanation:

Given that a line passes through two points

A(-2, -4) and B(4, 2)

Another point P(0, 4)

To find:

Which points lie on the line that passes through P and is parallel to line AB ?

Solution:

First of all, let us the find the equation of the line which is parallel to AB and passes through point P.

Parallel lines have the same slope.

Slope of a line is given as:

[tex]m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]

[tex]m=\dfrac{2-(-4)}{4-(-2)} = 1[/tex]

Now, using slope intercept form ([tex]y = mx+c[/tex]) of a line, we can write the equation of line parallel to AB:

[tex]y =(1)x+c \Rightarrow y = x+c[/tex]

Now, putting the point P(0,4) to find c:

[tex]4 = 0 +c \Rightarrow c = 4[/tex]

So, the equation is [tex]\bold{y=x+4}[/tex]

So, the coordinates given in the options which have value of y coordinate equal to 4 greater than x coordinate will be true.

So, the correct options are:

(–1, 3),  (–2, 2) and (–5, –1)

Answer:

b,c,e

Step-by-step explanation:

I got it right on edge

Answer:

C. [tex] -\frac{5}{2}} [/tex]

Step-by-step explanation:

If two lines on a graph are perpendicular to each other, their slope is said to be negative reciprocals of each other. This means the slope of one, is the negative reciprocal of the other.

This can be represented as [tex] m_1 = \frac{-1}{m_2} [/tex]

Where, [tex] m_1, m_2 [/tex] are slopes of 2 lines (i.e. the red and green lines given in the question) that are perpendicular to one another.

Thus, the slope of the red line would be:

[tex] m_1 = \frac{-1}{\frac{2}{5}} [/tex]

[tex] m_1 = -1*\frac{5}{2}} [/tex]

[tex] m_1 = -\frac{5}{2}} [/tex]

The slope of the red line = [tex] -\frac{5}{2}} [/tex]

Answer:

see details in graph and below

Step-by-step explanation:

There are many ways to generate the function.

We'll generate a function whose first derivative f'(x) satisfies the required conditions, say, a quadratic.

1. f(x) has a local minimum at x = -3, and

2. a local maximum at x = 3

Therefore f'(x) has to cross the x-axis at x = -3 and x=+3.

Furthermore, f'(x) must be increasing at x=-3 and decreasing at x=+3.

f'(x) = -x^2+9

will satisfy the above conditions.

Finally f(x) must be decreasing at x= -5, which implies that f'(-5) must be negative.

Check: f'(-5) = -(-5)^2+9 = -25+9 = -16 < 0  so ok.

f(x) can then be obtained by integrating f'(x) :

f(x) = integral of -x^2+9 = -x^3/3 + 9x = 9x - x^3/3

A graph of f(x) is attached, and is found to satisfy all three conditions.

A function is differentiable at [tex]x = a[/tex], if the function is continuous at [tex]x = a[/tex]. The function that satisfy the given properties is [tex]f(x) = 9x - \frac{x^3}{3} + 3[/tex]

Given that:

The function decreases at [tex]x = -5[/tex] means that: [tex]f(-5) < 0[/tex]

The local minimum at [tex]x = -3[/tex] and local maximum at [tex]x = 3[/tex] means that:

[tex]x = -3[/tex] or [tex]x = 3[/tex]

Equate both equations to 0

[tex]x + 3 = 0[/tex] or [tex]3 - x = 0[/tex]

Multiply both equations to give y'

[tex]y' = (3 - x) \times (x + 3)[/tex]

Open bracket

[tex]y' = 3x + 9 - x^2 - 3x[/tex]

Collect like terms

[tex]y' = 3x - 3x+ 9 - x^2[/tex]

[tex]y' = 9 - x^2[/tex]

Integrate y'

[tex]y = \frac{9x^{0+1}}{0+1} - \frac{x^{2+1}}{2+1} + c[/tex]

[tex]y = \frac{9x^1}{1} - \frac{x^3}{3} + c[/tex]

[tex]y = 9x - \frac{x^3}{3} + c[/tex]

Express as a function

[tex]f(x) = 9x - \frac{x^3}{3} + c[/tex]

[tex]f(-5) < 0[/tex] implies that:

[tex]9\times -5 - \frac{(-5)^3}{3} + c < 0[/tex]

[tex]-45 - \frac{-125}{3} + c < 0[/tex]

[tex]-45 + \frac{125}{3} + c < 0[/tex]

Take LCM

[tex]\frac{-135 + 125}{3} + c < 0[/tex]

[tex]-\frac{10}{3} + c < 0[/tex]

Collect like terms

[tex]c < \frac{10}{3}[/tex]

[tex]c <3.33[/tex]

We can then assume the value of c to be

[tex]c=3[/tex] or any other value less than 3.33

Substitute [tex]c=3[/tex] in [tex]f(x) = 9x - \frac{x^3}{3} + c[/tex]

[tex]f(x) = 9x - \frac{x^3}{3} + 3[/tex]

See attachment for the function of f(x)

Read more about continuous and differentiable function at:

https://brainly.com/question/19590547

Answer:

Step-by-step explanation:

G = { 3 , 7 , 8 , 9 }

H = { 2 , 5 , 7 , 8 }

The intersection of any two or more sets are the members that occur in both sets.

To find the intersection of G and H look for the members that occur in both sets

From the question , the members that occur in both G and H are 7 and 8

So the intersection of the sets is

Hope this helps you

Answer:

7w

Step-by-step explanation:

Answer:

we see it in our left side of the road

Answer:

x^3-10x^2+1/9

Step-by-step explanation:

For standard form you need to put the exponents in order. So x^3 is first, followed by -10x^2, and finally 1/9. Hope this helps!

Answer:

claire has to leave at 3:50 from her house.

Answer:

She needs to leave by 3:50 to get there on time.

Step-by-step explanation:

4:15 - 0:25 = 3:50.

Answer:

0.1587

Step-by-step explanation:

Given the following :

Mean (m) of distribution = 64 inches

Standard deviation (sd) of distribution = 2 inches

Probability that a randomly selected woman is taller than 66 inches

For a normal distribution :

Z - score = (x - mean) / standard deviation

Where x = 66

P(X > 66) = P( Z > (66 - 64) / 2)

P(X > 66) = P(Z > (2 /2)

P(X > 66) = P(Z > 1)

P(Z > 1) = 1 - P(Z ≤ 1)

P(Z ≤ 1) = 0.8413 ( from z distribution table)

1 - P(Z ≤ 1) = 1 - 0.8413

= 0.1587

1: 8 faces and 9 with the base 9 vertices and 16 edges

2: 3 faces and 5 with the bases 6 vertices and 9 edges

3: 3 faces and 4 with the base 4 vertices and 6 edges

Hope this can help you.

1: 8 faces and 9 with the base 9 vertices and 16 edges

2: 3 faces and 5 with the bases 6 vertices and 9 edges

3: 3 faces and 4 with the base 4 vertices and 6 edges

Answer:

Quotient = 18

Remainder = 10

Step-by-step explanation:

1234/68

=> 68 x 1 = 68

=> 123 - 68 = 55

=> Take the 4 down

=> 554/68

=> 68 x 8 = 544

=> 554 - 544  = 10

So, the quotient = 18.

Remainder = 10

Answer:

[tex]\Huge \boxed{x=44}[/tex]

Step-by-step explanation:

The circumscribed angle and the central angle are supplementary.

∠ACB and ∠AOB add up to 180 degrees.

Create an equation to solve for x.

[tex]3x+10+38=180[/tex]

Add the numbers on the left side of the equation.

[tex]3x+48=180[/tex]

Subtract 48 from both sides of the equation.

[tex]3x=132[/tex]

Divide both sides of the equation by 3.

[tex]x=44[/tex]

Answer:

4)44

Step-by-step explanation:

Answer:

Final population after 10 years

= 288911718

Step-by-step explanation:

Present population p = 258,316,051

Rate of growth R%= 1.12%

Number of years t= 10 years

Number of times calculated n = 10

Final population A

= P(1+r/n)^(nt)

A= 258,316,051(1+0.0112/10)^(10*10)

A= 258,316,051(1+0.00112)^(100)

A= 258,316,051(1.00112)^100

A= 258,316,051(1.118442762)

A= 288911717.6

Approximately A= 288911718

Final population after 10 years

= 288911718

Answer:

Attachment 1 : Option C

Attachment 2 : Option A

Step-by-step explanation:

( 1 ) Expressing the product of z1 and z2 would be as follows,

[tex]14\left[\cos \left(\frac{\pi \:}{5}\right)+i\sin \left(\frac{\pi \:\:}{5}\right)\right]\cdot \:2\sqrt{2}\left[\cos \left(\frac{3\pi \:}{2}\right)+i\sin \left(\frac{3\pi \:\:}{2}\right)\right][/tex]

Now to solve such problems, you will need to know what cos(π / 5) is, sin(π / 5) etc. If you don't know their exact value, I would recommend you use a calculator,

cos(π / 5) = [tex]\frac{\sqrt{5}+1}{4}[/tex],

sin(π / 5) = [tex]\frac{\sqrt{2}\sqrt{5-\sqrt{5}}}{4}[/tex]

cos(3π / 2) = 0,

sin(3π / 2) = - 1

Let's substitute those values in our expression,

[tex]14\left[\frac{\sqrt{5}+1}{4}+i\frac{\sqrt{2}\sqrt{5-\sqrt{5}}}{4}\right]\cdot \:2\sqrt{2}\left[0-i\right][/tex]

And now simplify the expression,

[tex]14\sqrt{5-\sqrt{5}}+i\left(-7\sqrt{10}-7\sqrt{2}\right)[/tex]

The exact value of [tex]14\sqrt{5-\sqrt{5}}[/tex] = [tex]23.27510\dots[/tex] and [tex](-7\sqrt{10}-7\sqrt{2}\right))[/tex] = [tex]-32.03543\dots[/tex] Therefore we have the expression [tex]23.27510 - 32.03543i[/tex], which is close to option c. As you can see they approximated the solution.

( 2 ) Here we will apply the following trivial identities,

cos(π / 3) = [tex]\frac{1}{2}[/tex],

sin(π / 3) = [tex]\frac{\sqrt{3}}{2}[/tex],

cos(- π / 6) = [tex]\frac{\sqrt{3}}{2}[/tex],

sin(- π / 6) = [tex]-\frac{1}{2}[/tex]

Substitute into the following expression, representing the quotient of the given values of z1 and z2,

[tex]15\left[cos\left(\frac{\pi \:}{3}\right)+isin\left(\frac{\pi \:\:}{3}\right)\right] \div \:3\sqrt{2}\left[cos\left(\frac{-\pi \:}{6}\right)+isin\left(\frac{-\pi \:\:}{6}\right)\right][/tex] ⇒

[tex]15\left[\frac{1}{2}+\frac{\sqrt{3}}{2}\right]\div \:3\sqrt{2}\left[\frac{\sqrt{3}}{2}+-\frac{1}{2}\right][/tex]

The simplified expression will be the following,

[tex]i\frac{5\sqrt{2}}{2}[/tex] or in other words [tex]\frac{5\sqrt{2}}{2}i[/tex] or [tex]\frac{5i\sqrt{2}}{2}[/tex]

The solution will be option a, as you can see.

Answer:

The probability of randomly selecting a queen or club from a deck of cards = 17/52

Step-by-step explanation:

Here in this question, we are concerned with computing the probability of randomly selecting a queen or club form a deck of cards

Mathematically, the probability is;

Probability of selecting a queen + Probability of selecting a club

Probability of selecting a queen = number of queens/total card number

The number of queens = 4

Probability of selecting a queen = 4/52

Probability of selecting a club card = number of club cards/ total number of cards

Number of club cards = 13

Probability of selecting a club card = 13/52

The probability of selecting a queen or club from a deck of cards = 4/52 + 13/52 = 17/52

Answer:

[tex]\large \boxed{\sf \bf \ \ k=320 \ \ }[/tex]

Step-by-step explanation:

Hello,

The number of weekly social media posts varies directly with the square root of the poster’s age and inversely with the cube root of the poster’s income.

If a 16-year-old person who earns $8,000 makes 64 posts in a week, what is the value of k?

[tex]64=\dfrac{\sqrt{16}}{\sqrt[3]{8000}}\cdot k=\dfrac{4}{20}\cdot k=\dfrac{1}{5}\cdot k=0.2\cdot k\\\\k=64*5=320[/tex]

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

Answer:

∠POT = 78°

Step-by-step explanation:

If POQ is straight then

x + 18° + 50° + x + 24° = 180° add like terms

2x + 92° = 180°

2x = 180° - 92°

2x = 88° and x = 44 If we say SOT is a straight line then

∠POT + 50° + x + 18° = 180°

∠POT + 102° = 180°

∠POT = 78°