Given the following 30-60-90 triangle , find the value of x and y Round to the nearest tenth x = 5.2 X = 6 Y = 6 Y = 5.2​

Given The Following 30-60-90 Triangle , Find The Value Of X And Y Round To The Nearest Tenth X = 5.2

Answers

Answer 1

Step-by-step explanation:

tan30° = Opposite/Adjacent = 3/x.

=> 3/x = √3/3, x = 3√3 = 5.2.

sin30° = Opposite/Hypotenuse = 3/y.

=> 3/y = 1/2, y = 6.

The correct answer is the 1st and 3rd options.

Answer 2

Answer:

[tex] \huge \boxed{ \boxed{ \sf \: x = 5.2 \atop\sf y = 6}}[/tex]

Step-by-step explanation:

to understand thisyou need to know about:trigonometryPEMDASgiven:[tex] \theta = {30}^{o} [/tex]opp:3to find:adjacent (x)hypotenuse (y)tips and formulas:[tex] \tan( {30}^{o} ) = \frac{ \sqrt{3} }{3} [/tex]tan(a)=opp/adjsin(a)=opp/hypo[tex] \sin( {30}^{o} ) = \frac{1}{2} [/tex]let's solve:

according to the question

[tex] \tan( {30}^{o} ) = \frac{3}{x} [/tex]

[tex] \frac{ \sqrt{3} }{3} = \frac{3}{x} \\ x\sqrt{3} = 9 \\ x = \frac{9}{ \sqrt{3} } \\ x = 3\sqrt{3} \\ x = 5.2[/tex]

according to the question

[tex] \sin( {30}^{o} ) = \frac{3}{y} [/tex]

[tex] \frac{1}{2} = \frac{3}{y} [/tex]

[tex]y = 6[/tex]


Related Questions

You have 40 minutes to exercise at the gym, and you want to burn 300 calories total using both
machines. The amount of calories burned on each machine is shown in the picture below. How
much time should you spend on each machine?


Machine a burns 8 calories per minute machine b burns 6 calories per minute.

Answers

a and b are the minutes spent on machine A and machine B, respectively.

a+b = 40
b = 40-a

8a + 6b = 300
8a + 6(40-a) = 300
8a + 240 - 6a = 300
2a = 60
a = 30
b = 40-a = 10

30 minutes on machine A and 10 minutes on machine B

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Two angles are complementary, can they also be supplementary? Explain.

Answers

Answer:

Yes

Step-by-step explanation:

They can because the sum of two Angles is 180, and if they are both 90, they add up to 180, making them congruent.  Hope this helps

Supplementary angles are two angles whose sum is 180 degrees while complementary angles are two angles whose sum is 90 degrees. 

Saying this you should probably infer that if 2 Angles are complementary, then they are 90°.

Meaning you would need 2 pairs of complementary angles to have a supplementary angle (180°).

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Answers

angles in triangle add to 180 degrees
20x=180
x=9
Angle ABC is the top one
8x9=72

Answer:

[tex]x = 9[/tex]

[tex]angle \: abc = 8x + 6x + 6x \\ 20x = 180 \\ x = \frac{180}{20} \\ x= 9[/tex]

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Answer and Step-by-step explanation:

Distribute the 1p to the y and -6 and distribute the 2 to the 3y and 6.

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16y - 38

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Answers

The answer is 9 3/4, 9.75
Explanation: 13/6 x 9/2
(reduce) 13/2 x 3/2
(Multiply 13/2 x 3/2)
39/4
(Reduce again) 9 3/4 or 9.75
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Answers

Answer:

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Step-by-step explanation:

digital shall will also sorry soap sorry s goo form enough wish all so do all kelan kaso kaka kalakalorry root sorry for

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Answers

Answer:

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Step-by-step explanation:

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Answers

2x+y=25
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Answers

Answer: the scale factor would be 2

Step-by-step explanation:

If you add all lengths for triangle ABC you can see that triangle ADE x 2 will give you the lengths for ABC

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Answer:

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Step-by-step explanation:

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Answer:18

Step-by-step explanation:

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milk truck delivers 376 dozen gallons of milk to stores in 1 day. Write and solve an equation to find n​, the number of gallons of milk the milk truck delivers in 1 day. pls help!

Answers

Answer:

376*12=n

My logic:

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Answers

Your answer is 2x^2y^4 (the third option)

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(8x^6y^12)^1/3
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Answers

Answer:

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After a 60% reduction, you purchase a new sofa drink machine on sale for $312.
What was the original price of the sofa drink machne?

Answers

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Mark is making jackets. Mark took 2 hours to make a jacket. The jacket was made up of 50 kilograms of wool. How long do you think it will take Mark to use 500 kilograms of wool for the jackets?

Answers

Given:

Mark took 2 hours to make a jacket.

The jacket was made up of 50 kilograms of wool.

To find:

The time in which Mark use 500 kilograms of wool for the jackets.

Solution:

We have,

1 jacket take 2 hours.

Number of jackets in 50 kg of wool = 1

Number of jackets in 1 kg of wool = [tex]\dfrac{1}{50}[/tex]

Number of jackets in 500 kg of wool = [tex]\dfrac{1}{50}\times 500[/tex]

                                                              = [tex]10[/tex] Jackets

Time taken by 1 jacket = 2 hours

Time taken by 10 jacket = 20 hours

Therefore, it will take 20 hours to use 500 kilograms of wool for the jackets.

Answer:

20 hours

Step-by-step explanation:

1 jacket=50kg wool

1 jacket= 2hrs

500kg available/50kg per jacket= 10 jackets

10 jackets x 2hrs per jacket=20hrs

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Answers

Answer:

Step-by-step explanation:

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denada

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Step-by-step explanation:

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60

Step-by-step explanation:

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Neither side are the hypotenuse.

What property must be used when solving each step of a one variable linear equation?

Answers

add, subtract, multiply, or divide an equation by a number or an expression as long as we do the same thing to both sides of the equal sign. ...

Apply the distributive property as needed:

Isolate the variable on one side of the equation.

Step-by-step explanation:

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How can you describe the graph of the equation y= mx + b? Explain

Answers

Answer:

mx is the slope. b is the y-intercept

Step-by-step explanation:

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Answers

Answer:

Step-by-step explanation:

The conversion factor is 454 grams / pound. That makes the answer D.

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Answer:

450 grams is the closest metric weight of 1 pound which in actuality is 453.592 gram.

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2×2×2×2× 5

Step-by-step explanation:

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Answers

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Step-by-step explanation:

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the half-life of chromium-51 is 38 days. If the sample contained 510 grams. How much would remain after 1 year?​

Answers

Answer:

About 0.6548 grams will be remaining.  

Step-by-step explanation:

We can write an exponential function to model the situation. The standard exponential function is:

[tex]f(t)=a(r)^t[/tex]

The original sample contained 510 grams. So, a = 510.

Each half-life, the amount decreases by half. So, r = 1/2.

For t, since one half-life occurs every 38 days, we can substitute t/38 for t, where t is the time in days.

Therefore, our function is:

[tex]\displaystyle f(t)=510\Big(\frac{1}{2}\Big)^{t/38}[/tex]

One year has 365 days.

Therefore, the amount remaining after one year will be:

[tex]\displaystyle f(365)=510\Big(\frac{1}{2}\Big)^{365/38}\approx0.6548[/tex]

About 0.6548 grams will be remaining.  

Alternatively, we can use the standard exponential growth/decay function modeled by:

[tex]f(t)=Ce^{kt}[/tex]

The starting sample is 510. So, C = 510.

After one half-life (38 days), the remaining amount will be 255. Therefore:

[tex]255=510e^{38k}[/tex]

Solving for k:

[tex]\displaystyle \frac{1}{2}=e^{38k}\Rightarrow k=\frac{1}{38}\ln\Big(\frac{1}{2}\Big)[/tex]

Thus, our function is:

[tex]f(t)=510e^{t\ln(.5)/38}[/tex]

Then after one year or 365 days, the amount remaining will be about:

[tex]f(365)=510e^{365\ln(.5)/38}\approx 0.6548[/tex]

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Three identical cell phones weigh 18.7 ounces. What is the combined weight of two cell phones that are also identical to the three cell phones mentioned in the first sentence?

Answers

Answer:

Two of them, actually.) ... It weighs 4.87 ounces — less than a third of a pound. ... In the photo shown above, Philip Shenon, a Times reporter, sits with ... Phil and I carried the satphone from Frankfurt — it was housed in two 65-pound suitcases. ... Modern mobile satellite data units weigh a total of about three

Step-by-step explanation:

thats all i know

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