given the nth term of geometric expression is (as in the diagram)

a) state the value of k
b) the first term of progression ​

The statement if two noncollinear rays join at a common endpoint, then an angle is created is a DEFINED TERM.

A defined term is a sentence or expression used to define a concept, statement or confusing words.  

From the question shown,  we can see that a statement was created which is defined  as "If two noncollinear rays join at a common endpoint, then an angle is created". This can be said to be a defined term since there are presence of keywords that made the statement meaningful and easily understandable.

Hence we can conclude that the statement is neither postulate, theorem nor an undefined term rather we can say it is a DEFINED term.

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The person above is correct defined term :)

Answer:

In recreational mathematics, a square array of numbers, usually positive integers, is called a magic square if the sums of the numbers in each row, each column, and both main diagonals are the same.[1][2] The order of the magic square is the number of integers along one side (n), and the constant sum is called the magic constant. If the array includes just the positive integers {\displaystyle 1,2,...,n^{2}}{\displaystyle 1,2,...,n^{2}}, the magic square is said to be normal. Some authors take magic square to mean normal magic square.[3]

The smallest (and unique up to rotation and reflection) non-trivial case of a magic square, order 3

Magic squares that include repeated entries do not fall under this definition and are referred to as trivial. Some well-known examples, including the Sagrada Família magic square and the Parker square are trivial in this sense. When all the rows and columns but not both diagonals sum to the magic constant we have semimagic squares (sometimes called orthomagic squares).

The mathematical study of magic squares typically deals with its construction, classification, and enumeration. Although completely general methods for producing all the magic squares of all orders do not exist, historically three general techniques have been discovered: by bordering method, by making composite magic squares, and by adding two preliminary squares. There are also more specific strategies like the continuous enumeration method that reproduces specific patterns. Magic squares are generally classified according to their order n as: odd if n is odd, evenly even (also referred to as "doubly even") if n is a multiple of 4, oddly even (also known as "singly even") if n is any other even number. This classification is based on different techniques required to construct odd, evenly even, and oddly even squares. Beside this, depending on further properties, magic squares are also classified as associative magic squares, pandiagonal magic squares, most-perfect magic squares, and so on. More challengingly, attempts have also been made to classify all the magic squares of a given order as transformations of a smaller set of squares. Except for n ≤ 5, the enumeration of higher order magic squares is still an open challenge. The enumeration of most-perfect magic squares of any order was only accomplished in the late 20th century.

Magic squares have a long history, dating back to at least 190 BCE in China. At various times they have acquired occult or mythical significance, and have appeared as symbols in works of art. In modern times they have been generalized a number of ways, including using extra or different constraints, multiplying instead of adding cells, using alternate shapes or more than two dimensions, and replacing numbers with shapes and addition with geometric operations.

The sum area of shaded region​ is [tex]\frac{1}{3}[/tex].

The formula to find the sum of infinite geometric progression is

[tex]S_{n}=\frac{a_{1}(1-q^{n}) }{1-q} \ \ q \ne 1[/tex]

Given

S = [tex]\frac{1}{4} +\frac{1}{16} +\frac{1}{64} +.........[/tex]

Using geometric progression

S = [tex]\lim_{h \to \infty} [\frac{1}{4} +(\frac{1}{4} )^{2} +(\frac{1}{4} )^{3} +.........+(\frac{1}{4} )^{n}][/tex]

Using summation formula for geometric progression

[tex]S_{n}=\frac{a_{1}(1-q^{n}) }{1-q} \ \ q \ne 1[/tex]

= [tex]\lim_{h \to \infty} \frac{\frac{1}{4} (1-(\frac{1}{4} )^{n} }{1-\frac{1}{4} }[/tex]

= [tex]\lim_{h \to \infty} \frac{\frac{1}{4} (1-\frac{1}{4^{n} }) }{\frac{3}{4} }[/tex]

= [tex]\lim_{h\to \infty} \frac{1}{3}(1-\frac{1}{4^{n} } )[/tex]

[tex]\lim_{h\to \infty} \frac{1}{4^{n} }[/tex] = 0

S  = [tex]\frac{1}{3}(1-0) = \frac{1}{3}[/tex]

The sum area of shaded region​ is [tex]\frac{1}{3}[/tex].

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Given:

[tex]ABDF\sim VXZT[/tex]

To find:

The pairs of congruent angles and the extended proportion that relates the corresponding sides for the similar polygons.

Solution:

We have,

[tex]ABDF\sim VXZT[/tex]

The corresponding angles of similar polygons are congruent. So,

[tex]\angle A\cong \angle V[/tex]

[tex]\angle B\cong \angle X[/tex]

[tex]\angle D\cong \angle Z[/tex]

[tex]\angle F\cong \angle T[/tex]

The corresponding sides of similar polygons are proportional. So,

[tex]\dfrac{AB}{VX}=\dfrac{BD}{XZ}=\dfrac{DF}{ZT}=\dfrac{A F}{VT}[/tex]

Therefore, the required solutions are [tex]\angle A\cong \angle V,\angle B\cong \angle X,\angle D\cong \angle Z,\angle F\cong \angle T[/tex] and [tex]\dfrac{AB}{VX}=\dfrac{BD}{XZ}=\dfrac{DF}{ZT}=\dfrac{A F}{VT}[/tex].

Answer:

y=16x

Step-by-step explanation:

24=1 1/2x=3/2x

x=24*(2/3)=16

y= total money earned; x=number of hours worked

Answer:

[tex]-73[/tex]

Step-by-step explanation:

Note: My explanation is based of the order-of-operations

First, using the order-of-operations, we evaluate the expressions in parentheses. Fully simplifying [tex](5-7)^2[/tex] gives us: [tex](5-7)^2 = -2^2 = 4[/tex].

Next, we do [tex]6\cdot2[/tex] giving us [tex]12[/tex]. So far, our expression is simplified to [tex]\frac{84}{12} + 4 - 72 - 12[/tex].

We also know that [tex]\frac{84}{12}[/tex] is just [tex]7[/tex] so we can replace that value in the expression leaving us with: [tex]7+4-72-12[/tex]. Now, we can solve it in simple steps!

1)  [tex]7+4=11[/tex]

3) [tex]11-72=-61[/tex]

4) [tex]-61-12=-73[/tex]

Our answer is [tex]-73[/tex]

Hopefully this helped you out! Please (please) tell me if their is a mistake in the solution and I will correct it as fast as possible for me.

Answer:

2(2)+7=11

2(3)+7=13

2(4)+7=15

2(5)+7=17

2(9)+7=25

Step-by-step explanation:

2(2)+7

4+7=11

2(3)+7

6+7=13

2(4)+7

8+7=15

2(5)+7

10+7=17

2(9)+7

18+7=25

Answer:

-3/2 >x

Step-by-step explanation:

-5-15>10+20x

Combine like terms

-20 > 10 +20x

Subtract 20 from each side

-20 -10 > 10+20x-10

-30> 20x

Divide by 20

-30/20 >20x/20

-3/2 >x

Answer:

-3/2 > x

Step-by-step explanation:

-5 - 15 > 10 + 20x

 ^    ^

  -20

-20 > 10 + 20x

-10    -10

---------------------

-30 > 20x

-----   -------

20     20

-3/2 > x

Hope this helped.

Answer:

3/4x^2

Step-by-step explanation:

Answer:

[tex] \frac{3}{4} \sqrt{x} [/tex]

where 'X' is the number

Step-by-step explanation:

hope this helps

Answer:

Yes it can be right angle triangle

Step-by-step explanation:

Eueydhhdgdgdbdbddbdbhd

Answer:

Hello,

[tex]R=\dfrac{18}{\pi}\ (cm)[/tex]

Step-by-step explanation:

[tex]Formula: \ L=\theta*R\\[/tex]

[tex]R=\dfrac{6}{\dfrac{\pi}{3} } =\dfrac{6*3}{\pi} =\dfrac{18}{\pi}\ (cm)[/tex]

Answer:

{1/√3+1/2} ÷{1/√3× 1/2}

Answer:

16

Step-by-step explanation:

First use the Pythagorean theorem a^2+b^2=c^2.

12^2+b^2=20^2. Solve the exponents: 144+b^2=400. Then, subtract the 144 from 400. That would be 256. Therefore b^2=256. Then you find the square root of 256=16.

Step-by-step explanation:

using pythogoras theory

hyp^2=opp^2+adj^2

you have been given the hyp and the opp so lets make the unknown x

20^2=12^2+x^2

400 =144+x^2

make x the subject of the formula

400-144=x^2

266=x^2

x=the square root of 266

Answer:

Hence the answer is Letter B.

Step-by-step explanation:

° ° °

Answer:

Step-by-step explanation:

Slope intercept form is y = mx + b where m is the slope and b is the y intercept SO

y = mx + b

3y - 9 = 12x

3y = 12x + 9 (divide by common denominator 3)

y = 4x + 3

Answer: 0.6/0.8

= (0.6*100)/(0.8*100) {multiplying by 100 in both numerator and denominator}

= 60/80 (cut the zero)

= 6/8 (cut by 2)

= 3/4

7n-16

Step-by-step explanation:

Sry can u give me the picture

Answer:

21.758

Step-by-step explanation:

If you draw the triangle out, you find that cos 41 = x/28.83, when x is equal to the side opposite the 49 angle

Simplify this into 28.83 cos 41, and plug it into the calculator and you get

21.75827.

msin²x+cos²x=m-1

since the interval are 0 and π/4

Therefore

msin²(0)+cos²(0)=m-1

m(0)+1=m-1

1=m-1

m=2

use π/4 now

msin²(π/4)+cos²(π/4)=m-1

m(1/2)+(1/2)=m-1

m+1=2(m-1)

m+1=2m-2

-m=-3

m=3

Therefore

m=2 or 3

Answer:

True

Step-by-step explanation:

tan B = sin B / cos B = 3/4 Let sin B =3 and cos B = 4

Cot B = cos B / sin B = 4/3

This is true

Answer:

-57

Step-by-step explanation:

the answer is -57 because if it is below sea level it is a negative but if it is above sea level it will be a positive

Answer: x ≥ 87

Step-by-step explanation:

Set the minimum score on the next test as x & calculate it:

[tex]\frac{75+78+89+71+x}{5} =80\\\\75+78+89+71+x=80(5)\\\\313+x=400\\\\x=400-313=87[/tex]

So they need at least a score of 87 for the average to be 80+.

Answer:

x ≥ 87

Step-by-step explanation:

====================================================

Explanation:

The two smaller triangles are proportional, which lets us set up this equation

5/n = n/15

Cross multiplying leads to

5*15 = n*n

n^2 = 75

----------

Apply the pythagorean theorem on the smaller triangle on top, or on the right.

a^2+b^2 = c^2

5^2+n^2 = m^2

25+75 = m^2

100 = m^2

m^2 = 100

m = sqrt(100)

m = 10

Answer:

41 cm Hg

Step-by-step explanation:

Answer:x²-3 x+4/ 2x-3 units

Step-by-step explanation:

Area = Length * Width sq. units

x^2 - 3x + 4 = Length * 2x - 3

=>Length = x^2- 3 x + 4/ 2 x − 3 units

Answer:

KL = 6

Step-by-step explanation:

IL = 26

IJ = 9

JK = 11

KL = ?

To find KL

Let KL be x

IJ + JK + KL = IL

9 + 11 + x = 26

20 + x = 26

transpose to find KL that is x

x = 26 - 20

x = 6

therefore KL = 6

Answer:

KL = 6

Step-by-step explanation:

First step is to create an equation

Given: IL = 26

This means that the sum of the segments that make up IL also equal 26

In other words, IJ + JK + KL = 26 ( note that this is the equation that we will use to solve for the missing segment )

Given: IJ = 9 , JK = 11 and KL = ?

To find the length of the missing segment we simply plug in the known segment lengths into the equation we created and solve for the unknown one.

Equation created: IJ + JK + KL = 26

Variables: IJ = 9 , JK = 11 and KL = ?

Plug in variables into equation

9 + 11 + KL = 26

Now solve for KL

Step 1 Combine like terms ( 9 + 11 = 20 )

20 + KL = 26

Step 2 Subtract 20 from both sides

20 - 20 + KL = 26 - 20

KL = 6

And we are done!

Answer:

lines 1 and 3

Step-by-step explanation:

y = 2 is a horizontal line parallel to the x- axis

x = - 4 is a vertical line parallel to the y- axis

Then these 2 lines are perpendicular to each other

y = 15x - 3 ( in the form y = mx + c ) with m = 15

y + 1 = - 5(x + 2) ( in the form y - b = m(x - a) with m = - 5

For the lines to be perpendicular the product of their slopes = - 1

However

15 × - 5 = - 75 ≠ - 1

The 2 lines 1 and 3 are perpendicular

Answer:

394

Step-by-step explanation:

11^2+8*11*3+3^2

121+8*11*3+9

121+264+9

385+9

394

Answer:

This question seems to be asking for the work, so I put it below.

Anyhow, Marla had 3.5 candies, and Ron had 10.5.

Step-by-step explanation:

x = 3x - 7  (lets set this as "a")   { a = 3x - 7}

x + 7 = 3x -7 + 7

x + 7 = 3x

( x + 7 ) / 3 = 3/3x

( x + 7 ) / 3 = x     =    *(same as "a") {a}

( x + 7 ) / 3 = 3x - 7

( x + 7 ) / 3 * 3 = ( 3x - 7 ) * 3

x + 7 = 9x - 21

x - x + 7 = 9x - x - 21

7 = 8x - 21

7 + 21 = 8x - 21 + 21

28 = 8x

28 / 8 = 8/8x

3.5 = x

We can plug this back into the original equation and find that it is correct because:

x = 3x - 7

x = 3.5  =====

3.5 = 3( 3.5 ) - 7

3.5 = 10.5 - 7

3.5 = 3.5

Answer:

Marla has 7 and Ron has 21

Step-by-step explanation:

lets take

no. of candies Marla has as "x"

and no. of  candies Ron has will be "3x"

Marla says if Ron gives her seven candies, they will have the same no. of candies

so your equation will be -

x + 7 = 3x - 7 (as Marla gets the candy, Ron loses the candy)

3x - x = 7 + 7

2x = 14

∴x = 7

and 3x = 3 x 7 = 21

YOUR WELCOME

Answer:

y-intercept is 0, x-intercept is 0 and 1

Step-by-step explanation:

For y-intercept, x=0 :

[tex]{ \tt{y = {(0)}^{2} - 2(0) }} \\ { \tt{y = 0}}[/tex]

For x-intercept, y=0 :

[tex]{ \tt{0 = {2x}^{2} - 2x }} \\ { \tt{2x(x - 1) = 0}} \\ { \tt{x = 0 \: \: and \: \: 1}}[/tex]