Answer:
$1.33
Step-by-step explanation:
Determine the cost per ounce of the larger bottle
cost per ounce = cost of larger bottle / total ounces
$12.99 / 150 = $0.0866
Multiply cost per ounce by 100
$0.0866 x 100 = $8.66
Subtract the above figure from 9.99
9.99 - $8.66 = $1.33
Donte simplified the expression below.
4(1+3i)-(8-5i)
4+3i-8+5i
-4+8i
What mistake did he make?
Answer:
A. He did not apply the distributive property correctly for 4(1+3i)
Step-by-step explanation:
Instructions: Find the value of x
Please help I’ll mark brainilest.
all the lenses inside the circle ar equal and the two chords are also equal distance from the center point so arc x would equal arc CD
X = 50 degrees
Zahara frosted eleven cupcakes today. Dania frosted seven times as many. How many cupcakes did Dania frost?
Solve x^2 -6x=-5 by completing the square. Show all work for the steps below. (a) For x^2 -6x+c+-5+c, what value of c is used to complete the square? (b) Substitute the value for c in Part 2(a). Then complete the square to rewrite the equation as the square of a binomial. (c) Solve for x
The screen at Dallas’ AT&T Stadium is 175 feet wide. A movie theatre screen with similar dimensions is 40 feet wide with a screen area of 896 ft². What is the area of the screen at AT&T Stadium? Round to the nearest square foot.
Answer: The area of the screen at AT&T Stadium = 17150 square foot.
Step-by-step explanation:
When two shapes are similar then,
[tex]\dfrac{(\text{Side of first shape})^2}{(\text{Side of second shape})^2}=\dfrac{\text{area of first shape}}{\text{area of second shape}}[/tex]
As per given , we have
[tex]\dfrac{(175)^2}{(40)^2}=\dfrac{\text{Area of AT}\ \&\text{T Stadium }}{896}\\\\\Rightarrow\ \text{Area of AT}\ \&\text{T Stadium }=\dfrac{30625}{1600}\times896\\\\\Rightarrow\ \text{Area of AT}\ \&\text{T Stadium }=17150[/tex]
Hence, the area of the screen at AT&T Stadium = 17150 square foot.
The following frequency distribution presents the five most frequent reasons for hospital admissions in U.S. community hospitals in a recent year.
Reason Frequency (in thousands)
Congestive heart failure 990
Coronary atherosclerosis 1400
Heart attack 744
Infant birth 3800
Required:
a. Construct a frequency bar graph.
b. Construct a relative frequency distribution.
c. Construct a relative frequency bar graph.
d. Construct a relative frequency Pareto chart.
Answer:
See Explanation
Step-by-step explanation:
Given
[tex]Reason \to Frequency[/tex]
[tex]Congestive\ heart\ failure \to 990[/tex]
[tex]Coronary\ atherosclerosis\to 1400[/tex]
[tex]Heart\ attack \to 744[/tex]
[tex]Infant\ birth\to 3800[/tex]
Solving (a): Frequency bar graph
To do this, we simply plot the reasons (on the x-axis) against the frequency (on the y-axis).
See attachment
Solving (b): Relative frequency distribution
The relative frequency is calculated as:
[tex]RF = \frac{F}{Total}[/tex]
Where
[tex]Total = 990+1400+744+3800[/tex]
[tex]Total = 6934[/tex]
So, we have:
[tex]Congestive\ heart\ failure \to \frac{990}{6934} = 0.1427[/tex]
[tex]Coronary\ atherosclerosis\to \frac{1400}{6934} = 0.2019[/tex]
[tex]Heart\ attack \to \frac{744}{6934} = 0.1073[/tex]
[tex]Infant\ birth\to \frac{3800}{6934} = 0.5481[/tex]
So, the relative distribution is:
[tex]Reason \to Frequency \to Relative\ Frequency[/tex]
[tex]Congestive\ heart\ failure \to 990 \to 0.1427[/tex]
[tex]Coronary\ atherosclerosis\to 1400 \to 0.2019[/tex]
[tex]Heart\ attack \to 744 \to 0.1073[/tex]
[tex]Infant\ birth\to 3800 \to 0.5481[/tex]
Solving (c): Relative frequency bar graph
To do this, we simply plot the reasons (on the x-axis) against the relative frequency (on the y-axis).
See attachment
Solving (d): Relative frequency Pareto chart
First, calculate the cumulative relative frequency
This is done by adding up the previous relative frequency,
So, we have:
[tex]Reason \to Relative\ Frequency \to Cumulative[/tex]
[tex]Congestive\ heart\ failure \to 0.1427 \to 0.1427[/tex]
[tex]Coronary\ atherosclerosis \to 0.2019 \to 0.2019+0.1427=0.3446[/tex]
[tex]Heart\ attack \to 0.1073\to 0.3446+0.1073 = 0.4519[/tex]
[tex]Infant\ birth \to 0.5481 \to 0.5481+4519 =1[/tex]
So, we have:
[tex]Reason \to Relative\ Frequency \to Cumulative[/tex]
[tex]Congestive\ heart\ failure \to 0.1427 \to 0.1427[/tex]
[tex]Coronary\ atherosclerosis \to 0.2019 \to 0.3446[/tex]
[tex]Heart\ attack \to 0.1073\to 0.4519[/tex]
[tex]Infant\ birth \to 0.5481 \to 1[/tex]
Next, we simply plot the reasons (on the x-axis) against the cumulative relative frequency (on the right) and the left of the Pareto chart.
See attachment
A study was conducted to determine whether there were significant differences between medical students admitted through special programs (such as retention incentive and guaranteed placement programs) and medical students admitted through the regular admissions criteria. It was found that the graduation rate was 92.4% for the medical students admitted through special programs. Be sure to enter at least 4 digits of accuracy for this problem!
If 12 of the students from the special programs are randomly selected, find the probability that at least 11 of them graduated.
prob =
At least 4 digits!
If 12 of the students from the special programs are randomly selected, find the probability that exactly 9 of them graduated.
prob =
At least 4 digits!
Would it be unusual to randomly select 12 students from the special programs and get exactly 9 that graduate?
no, it is not unusual
yes, it is unusual
If 12 of the students from the special programs are randomly selected, find the probability that at most 9 of them graduated.
prob =
At least 4 digits!
Would it be unusual to randomly select 12 students from the special programs and get at most 9 that graduate?
yes, it is unusual
no, it is not unusual
Would it be unusual to randomly select 12 students from the special programs and get only 9 that graduate?
no, it is not unusual
yes, it is unusual
Answer:
A) 0.7696
B) 0.0474
C) Yes it's unusual
D) 0.05746
E) No, it is not unusual
F) No, it is not unusual
Step-by-step explanation:
This is a binomial probability distribution question.
We are told that 92.4% of those admitted graduated.
Thus; p = 92.4% = 0.924
From binomial probability distribution, q = 1 - p
Thus;
q = 1 - 0.924
q = 0.076
Formula for binomial probability distribution is;
P(x) = nCx × p^(x) × q^(n - x)
A) At least 11 graduated out of 12.
P(x ≥ 11) = P(11) + P(12)
P(11) = 12C11 × 0.924^(11) × 0.076^(12 - 11)
P(11) = 0.3823
P(12) = 12C12 × 0.924^(12) × 0.076^(12 - 12)
P(12) = 0.3873
P(x ≥ 11) = 0.3823 + 0.3873
P(x ≥ 11) = 0.7696
B) that exactly 9 of them graduated out of 12. This is;
P(9) = 12C9 × 0.924^(9) × 0.076^(12 - 9)
P(9) = 0.0474
C) We are not given significance level here but generally when not given we adopt a significance level of α = 0.05.
Now, exactly 9 out of 12 that graduated which is P(9) = 0.0474.
We see that 0.0474 is less than the significance level of 0.05. Thus, we can say that it is unusual to randomly select 12 students from the special programs and get exactly 9 that graduate
D) that at most 9 of them out of 12 graduated.
P(x ≤ 9) = P(0) + P(1) + P(2) + P(3) + P(4) + P(5) + P(6) + P(7) + P(8) + P(9)
This is going to be very long so I will make use of an online probability calculator to get the values of P(0) to P(8) since I already have P(9) as 0.0474.
Thus, we have;
P(0) = 0
P(1) = 0
P(2) = 0
P(3) = 0.00000001468
P(4) = 0.00000040161
P(5) = 0.00000781232
P(6) = 0.00011081163
P(7) = 0.00115477385
P(8) = 0.00877476184
Thus;
P(x ≤ 9) = 0 + 0 + 0 + 0.00000001468 + 0.00000040161 + 0.00000781232 + 0.00011081163 + 0.00115477385 + 0.00877476184 + 0.04741450256
P(x ≤ 9) = 0.05746
E) P(x ≤ 9) = 0.05746 is more than the significance level of 0.05, thus we will say it is not unusual.
F) from online binomial probability calculator, probability of getting only 9 out of 12 is more than the significance value of 0.05. Thus, we will say it is not unusual
Part A: If (72)x = 1, what is the value of x? Explain your answer. (5 points)
Part B: If (70)x = 1, what are the possible values of x? Explain your answer. (5 points)
Can you Help Me I NEED ANSWER ASAP!!!
Answer:
see below
Step-by-step explanation:
Part A: (72)^x = 1
Take the log base 72 of each side
log72(72^x) = log 72(1)
We know log a^b = b log a
x log72(72) = log72(1)
x = log72(1)
x = 0
Part A: (70)^x = 1
Take the log base 70 of each side
log70(70^x) = log70(1)
We know log a^b = b log a
x log70(70) = log70(1)
x = log70(1)
x = 0
Solve the system of equations
4x + 2y + 1 = 1
2x − y = 1
x + 3y + z = 1
Answer:
x = 1/4
y = -1/2
z = 9/4
Step-by-step explanation:
Here we have a system of 3 equations with 3 variables:
4*x + 2*y + 1 = 1
2*x - y = 1
x + 3*y + z = 1
The first step to solve this, is to isolate one of the variables in one of the equations, let's isolate "y" in the second equation:
2*x - y = 1
2*x - 1 = y
Now that we have an expression equivalent to "y", we can replace this in the other two equations:
4*x + 2*(2*x - 1) + 1 = 1
x + 3*(2*x - 1) + z = 1
Now let's simplify these two equations:
8*x - 1 = 1
7*x - 3 + z = 1
Now, in the first equation we have only the variable x, so we can solve that equation to find the value of x:
8*x - 1 = 1
8*x = 1 + 1 = 2
x = 2/8 = 1/4
Now that we know the value of x, we can replace this in the other equation to find the value of z.
7*(1/4) -3 + z = 1
7/4 - 3 + z = 1
z = 1 + 3 - 7/4
z = 4 - 7/4
z = 16/4 - 7/4 = 9/4
z = 9/4
Now we can use the equation y = 2*x - 1 and the value of x to find the value of y:
y = 2*(1/4) - 1
y = 2/4 - 1
y = 1/2 - 1
y = -1/2
Then the solution is:
x = 1/4
y = -1/2
z = 9/4
Find the area of a triangle ABC when measure B = 56 degrees, a = 10 inches, and c = 7 inches.
To make it more easier for everyone, it's on Khan Academy and this problem is in Algebra 1 to be specific. Solve for x.
3x−8≤23 AND −4x+26≥6
Choose 1 answer:
A: x ≤ 31/3
B: x ≤ 5
C: 5 ≤ x ≤ 31/3
D: There are no solutions
E: All values of x are solutions
Answer:
B: x≤5
Step-by-step explanation:
Hi there!
We're given two inequalities; 3x−8≤23 and −4x+26≥6
We need to find the values of x that make BOTH of the inequalities true (which is the intersection of the two inequality graphs)
First, let's solve for x in both of them
taking the first inequality:
3x−8≤23
add 8 to both sides
3x≤31
divide by 3
x≤31/3
now solve for x in −4x+26≥6
subtract 26 from both sides
-4x≥-20
divide both sides by -4 and remember to FLIP the inequality sign since we have a negative number
x≤5
now let's graph these two inequalities to find the intersection, and that is below with the answer
Hope this helps! :)
Helpp please… due at 12:00
Answer:alternate exterior angles
Step-by-step explanation:
Since they’re on the outside of the parallel lines that makes them exterior
Evan invested $800 in an account that pays 3.25% interest compounded annually.
Assuming no deposits or withdrawals are made, find how much money Evan would
have in the account 12 years after his initial investment. Round to the nearest tenth
(if necessary).
Answer:
Evans would have $852.8
Step-by-step explanation:
Given
[tex]PV = \$800[/tex]
[tex]r = 3.25\%[/tex]
[tex]t = 2[/tex]
[tex]n = 1[/tex] --- annually'
Required
The future value
This is calculated using:
[tex]FV = PV*(1 + \frac{r}{n})^{nt[/tex]
So, we have:
[tex]FV = 800 * (1 + 3.25\%/1)^{2*1}[/tex]
[tex]FV = 800 * (1 + 3.25\%)^{2}[/tex]
[tex]FV = 800 * (1 + 0.0325)^{2}[/tex]
[tex]FV = 800 * (1 .0325)^2[/tex]
[tex]FV = 852.845[/tex]
[tex]FV = 852.8[/tex]
FV =
On a particular game show, there are 8 covered buckets and 2 of them contain a ball.
To win the game, a contestant must select both buckets that contain a ball. Find the
probability that a contestant wins the game if he/she gets to select 4 of the buckets.
Answer:
0.2143 = 21.43% probability that a contestant wins the game if he/she gets to select 4 of the buckets.
Step-by-step explanation:
The buckets are chosen without replacement, which means that the hypergeometric distribution is used to solve this question.
Hypergeometric distribution:
The probability of x sucesses is given by the following formula:
[tex]P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}[/tex]
In which:
x is the number of sucesses.
N is the size of the population.
n is the size of the sample.
k is the total number of desired outcomes.
Combinations formula:
[tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
In this question:
8 covered buckets, so N = 8.
4 buckets are selected, so n = 4.
2 contain a ball, which means that k = 2.
Find the probability that a contestant wins the game if he/she gets to select 4 of the buckets.
This is P(X = 2). So
[tex]P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}[/tex]
[tex]P(X = 2) = h(2,8,4,2) = \frac{C_{2,2}*C_{6,2}}{C_{8,2}} = 0.2143[/tex]
0.2143 = 21.43% probability that a contestant wins the game if he/she gets to select 4 of the buckets.
A computer store buys a computer system at a cost of $450.20. The selling price was first at $710, but then the store
advertised a 30% markdown on the system. What is the current sale price? What is the percent mark up on the current sale
price?
Answer:
i believe it is 497 after the 30% mark down
Step-by-step explanation:
i subtracted 30% from 710
A factory that makes granola bars uses 1/6 of a barrel of raisins in each batch.
Yesterday, the factory used 5/6 of a barrel of raisins. How many batches did the
factory make yesterday?
Answer:
5
Step-by-step explanation:
(5/6) / (1/6) = 5
Answer:
5 batches
Step-by-step explanation:
Divide yesterday's batches by the usual.
(5/6)/(1/6) = 5
Since it only takes 1/6 to make a batch and they used 5x that we know they made 5 batches.
A tortoise and hare are competing in a 1000 meter race. The function f and g are such that f(t) represents the tortoise's distance from the finish line (in meters) t seconds after the start of the race and g(t) represents the hare's distance from the finish line (in meters) t seconds after the start of the race. If we want to compute the number of seconds needed for the hare to finish the race, which procedures should be used?
Answer:
[tex]g(t) = 0[/tex]
Step-by-step explanation:
Given
[tex]d = 1000m[/tex]
[tex]f(t) \to[/tex] Tortoise
[tex]g(t) \to[/tex] Hare
Required
Time needed by the Hare to complete the race
The function [tex]g(t)[/tex] implies that the Hare is t seconds from completing the race.
When g(t) = 0, it means that the Hare has completed the race
So, to calculate the time needed by the Hare;
We simply equate g(t) to 0, then solve for t
simplify 16 + 15 - 5
What are the coordinates of the point that is 1/5
of the way from A(-7,-4) to
B(3,6)?
A. (-5,0)
B. (-5,-2)
C. (0,3)
O D. (1,4)
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Answer:
B. (-5, -2)
Step-by-step explanation:
That point is ...
A + 1/5(B - A)
= (-7, -4) + 1/5(3 -(-7), 6 -(-4)) = (-7, -4) +1/5(10, 10)
= (-7, -4) +(2, 2) = (-5, -2)
The point (-5, -2) is 1/5 of the way from A to B.
A cheetah can run at a speed of 70 miles per hour. Which representation shows the distance a cheetah can travel
at this rate?
I’ll give brainliest
Answer:
Sorry if this is wrong, but seeing the question I think the best answer following the question would be answer B, because for A it shows that 1 hour is 35 miles when it says 70 miles in 1 hour, not C because as the time rises so does the distance, and I checked D and it's wrong.
Step-by-step explanation:
I don't get it please Help me
Step-by-step explanation:
A. 2(x+4)=2x+8
=G
B. 3(2x-1)=6x-3
=I
C. 4(x+2)=4x+8
=J
D. 2(x+3)=2x+6
=K
E. 3(4x+1)=12x+3
=H
A - G
B - I
C - J
D - K
E - H
HOPE IT HELP
Mrs Lefatshe bought 15 metres of cloth.the cost of 1 metre is P69.95. how much did she have to pay?
Answer:
1042.5
Step-by-step explanation:
Given :-
Mrs Lefatshe bought 15 metres of cloth.the cost of 1 metre is P69.95 .Using Unitary Method :-
→ Cost of 1 m is P 69.95
→ Cost of 15m is P ( 69.5 * 15 ) = P 1042.5
NEED HELP ON THIS ASAP PLZ!!
Answer:
cos0 = 6.8556546i/23 or sqrt-47/23
Step-by-step explanation:
hypotenuse is 23, opposite is 24
we have to find the adjacent using the pythagorean theorem
24^2 + b^2 = 23^2
576+b^2=529
subtract
b^2=-47
b=sqrt-47
sqrt of -47 is 6.8556546i, there is an i since it is the square root of a negative
cos = adjacent/hypotenuse
Simplify − { − ( + ) − ÷ }
Answer:
- (- (+) - ÷ )
+) (-) (+) (-)
= (+) (-)
(2104ft)(1 yd/3 ft)(1 football field/100 yds
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Answer:
7 1/75 football fields
Step-by-step explanation:
Multiply it out. The units of feet and yards cancel, leaving football fields.
= (2104·1·1)/(3·100) football fields ≈ 7.0133... football fields
= 7 1/75 football fields
The Isosceles Trapezoid is part of an Isosceles triange with a 32° vertex angle. What is the measure of an acute base angle of the trapezoid?
Answer:
[tex]b = 74^o[/tex] --- acute base
Step-by-step explanation:
Given
See attachment for the figure
Required
The acute base angle of the trapezoid
From the question, the isosceles triangle and the trapezoid share the same base.
Represent the base angle with b.
So:
[tex]b + b + 32^o = 180^o[/tex] --- angles in a triangle
[tex]2b = 180^o-32^o[/tex]
[tex]2b = 148^o[/tex]
Divide by 2
[tex]b = 74^o[/tex]
how many liters of a 40% alcohol solution must be mixed with a 65% solution to obtain 50 L of a 50% alcohol solution
Step-by-step explanation:
Question 264138: How many liters of a 40% alcohol solution must be mixed with a 65% solution to obtain 20 liters of a 50% solution? x=8 gallons of 65% solution is used. 20-8=12 gallons of 40% solution is used.
please mark as brainliest
Find the 66th term of the arithmetic sequence -28,-45,-62
Answer:
Using the formula
an = a of 1 + (n-1)(d)
an = -28 + (n-1)(-17)
simplify
an = -17n - 11
Now that we have the formula, we just plug in 66 for n
a66 = -17(66) - 11
a66 = -1133
what is the prime factorization of 225 in exponent form
Answer:
prime factorization of 225 = 32•52.
Step-by-step explanation:
The number 225 is a composite number so, it is possible to factorize it. 225 can be divided by 1, by itself and at least by 3 and 5.
A composite number is a positive integer that has at least one positive divisor other than one or the number itself. In other words, a composite number is any integer greater than one that is not a prime number.
What is the proof the outcome (not A)?
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Answer:
B
Step-by-step explanation:
If the probability of event "A" is 'p', then the probability of the event "not A" is
P(not A) = 1 - P(A) = 1 - p
For p=0.5, this is ...
P(not A) = 1 -0.5 = 0.5 . . . . . matches choice B
Answer:
○B. 0.5 is the proof the outcome (not A).
