Grayson is 1.25 meters tall. At 12 noon, he measures the length of a tree's shadow to be 22.75 meters. He stands 17.6 meters away from the tree, so that the tip of his shadow meets the tip of the tree's shadow . Find the height of the tree to the nearest hundredth of a meter.

Answer:

Step-by-step explanation:

Answer:

The total amount of celery and onion needed for the soup is 7/10 cup.

Step-by-step explanation:

2/4 + 1/5 = 7/10 cup.

hope it helped :)

mark me brainliest!

Answer:

C

Step-by-step explanation:

use Pythagorean theorem

[tex]a^{2}[/tex] + [tex]b^{2}[/tex] = [tex]c^{2}[/tex]

c is the longest side

if [tex]a^{2}[/tex] + [tex]b^{2}[/tex] > [tex]c^{2}[/tex] then it's acute (greater than)

if [tex]a^{2}[/tex] + [tex]b^{2}[/tex] < [tex]c^{2}[/tex] then it's obtuse   (less than)

if they are equal, then its a right triangle

[tex]6^{2}[/tex] + [tex]10^{2}[/tex] = [tex]12^{2}[/tex]

36 + 100 = 144

136 = 144

136 < 144   obtuse

The correct classification for this triangle is:

obtuse, because 6² + 10² < 12²

Option C is the correct answer.

A triangle is a 2-D figure with three sides and three angles.

The sum of the angles is 180 degrees.

We can have an obtuse triangle, an acute triangle, or a right triangle.

We have,

To determine the classification of a triangle based on its side lengths, we can use the triangle inequality theorem, which states that the sum of the lengths of any two sides of a triangle must be greater than the length of the third side.

In this case, we have a triangle with side lengths of 6 cm, 10 cm, and 12 cm. Checking the sum of the lengths of each pair of sides, we have:

6 + 10 = 16 > 12

6 + 12 = 18 > 10

10 + 12 = 22 > 6

Since all three pairs satisfy the triangle inequality theorem, the given side lengths do form a valid triangle.

Next, we can use the law of cosines to determine the measure of the largest angle in the triangle, which will allow us to classify it.

The law of cosines states that, for a triangle with side lengths a, b, and c, and the angle opposite c denoted as C, we have:

[tex]c^2 = a^2 + b^2 - 2ab cos(C)[/tex]

In this case, the side lengths are a = 6 cm, b = 10 cm, and c = 12 cm. Substituting these values into the formula and solving for cos(C), we get:

cos(C) = (6² + 10² - 12²) / (2 x 6 x 10)

cos(C) = -1/5

Since the cosine function is negative for angles between 90 and 180 degrees, we know that angle C is obtuse.

Therefore,

The correct classification for this triangle is:

obtuse, because 6² + 10² < 12²

Learn more about triangles here:

https://brainly.com/question/25950519

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Answer:

-60x

Step-by-step explanation:

Answer:

x = 50.6

Step-by-step explanation:

through my working i got to 41² is the hypotenuse.

21²+20²=c²

factor out the square

(21+20)²=c²

41²=c²

and 41² is 1681

Answer:

29 units

Step-by-step explanation:

i just took the quiz

Answer:

[tex]\implies \dfrac{ -4x+7}{2(x-2) }[/tex]

Step-by-step explanation:

The given expression to us is ,

[tex]\implies \dfrac{\frac{ 3}{x-1} -4 }{ 2 -\frac{2}{x-1}}[/tex]

Now take the LCM as ( x - 1 ) and Simplify , we have ,

[tex]\implies \dfrac{\frac{ 3 -4(x-1) }{x-1} }{ \frac{2-2(2x-1)}{x-1}}[/tex]

Simplifying further , we get ,

[tex]\implies \dfrac{ -4x+7}{2(x-2) }[/tex]

Hence the second option is correct .

Step-by-step explanation:

[tex] \frac{ \frac{3}{x - 1} - 4}{2 - \frac{2}{x - 1} } \\ = \frac{ \frac{3 - 4(x - 1)}{x - 1} }{ \frac{2(x - 1) - 2}{x - 1} } \\ = \frac{3 - 4x + 4}{2x - 2 - 2} \\ = \frac{7 - 4x}{2x - 4} = \frac{ - 4x - 7}{2(x - 2)} \\ thank \: you[/tex]

[tex]option \: b \\ thank \: you[/tex]

Answer:

2.5 years

Step-by-step explanation:

The given amount invested, which is the principal, P = $16,800

The simple interest rate, R = 5% per annum

The intended total value of the investment, A = $18,900

The simple interest on the principal, I = A - P

∴ I = $18,900 - $16,800 = $2,100

The formula for the simple interest, I, is given as follows;

[tex]I = \dfrac{P \times R \times T}{100}[/tex]

Therefore, we have;

[tex]T = \dfrac{I \times 100}{P \times R}[/tex]

Plugging in the values, gives;

[tex]T = \dfrac{2,100 \times 100}{16,800 \times 5} =2.5[/tex]

The time it will take the investment to grow to $18,900 is T = 2.5 years

environment is not natural uniform all from

Answer:

5÷35 = 1/7× 100

Step-by-step explanation:

P(E)= n(E)÷ n(s)

Answer:

17%

Step-by-step explanation:

Add all of the students up and then form a ratio:

30 students in total; 5 seniors/30 students

5/30 = 1/6 = 16.67%

(I think that's the answer, hope it helps)

Answer: read below

Step-by-step explanation:

A circle graph is a graph showing proportions of thing that label the person by using different colours

Answer:

B

Step-by-step explanation:

B was missed. You have to convert this from hours into minutes before you can deal with seconds.

Observe that

5/12 = 1/4 + 1/6

so that

tan(5π/12) = tan(π/4 + π/6)

Then

tan(5π/12) = sin(π/4 + π/6) / cos(π/4 + π/6)

… = (sin(π/4) cos(π/6) + cos(π/4) sin(π/6)) / (cos(π/4) cos(π/6) - sin(π/4) sin(π/6))

… = (cos(π/6) + sin(π/6)) / (cos(π/6) - sin(π/6))

(since sin(π/4) = cos(π/4) = 1/√2)

… = (√3/2 + 1/2) / (√3/2 - 1/2)

… = (√3 + 1) / (√3 - 1)

… = (√3 + 1) / (√3 - 1) × (√3 + 1) / (√3 + 1)

… = (√3 + 1)² / ((√3)² - 1²)

… = ((√3)² + 2√3 + 1²) / (3 - 1)

… = (3 + 2√3 + 1) / 2

… = (4 + 2√3) / 2

… = 2 + √3 … … … (C)

If you insist on using the half-angle identity, recall that

sin²(x) = (1 - cos(2x))/2

cos²(x) = (1 + cos(2x))/2

==>   tan²(x) = (1 - cos(2x)) / (1 + cos(2x))

Let x = 5π/12. The angle x lies in the first quadrant, so we know tan(x) is positive.

==>   tan(x) = +√[(1 - cos(2x)) / (1 + cos(2x))]

We also know

cos(2x) = cos(5π/6) = -√3/2

which means

tan(x) = tan(5π/12) = √[(1 - (-√3/2)) / (1 + (-√3/2))]

… = √[(1 + √3/2) / (1 - √3/2)]

… = √[(2 + √3) / (2 - √3)]

… = √[(2 + √3) / (2 - √3) × (2 + √3) / (2 + √3)]

… = √[(2 + √3)² / (2² - (√3)²)]

… = √[(2 + √3)² / (4 - 3)]

… = √[(2 + √3)²]

… = 2 + √3

Answer:

2√10 km

Step-by-step explanation:

By Pythagoras theorem,

x^2 + 9^2 = 11^2

x^2 + 81 = 121

x^2 = 121 - 81

x^2 = 40

= 4 x 10

x^2 = 2^2 x 10

x = 2√10 km

Answer:

ok so on the left ill put minutes and on the right ill put dollars

150=7.50

220=11.00

250=12.50

275=13.75

so now lets break this down by dividing the smallest numbers by 2 a couple times

75=3.75(2)

25=1.25(3)

1=0.05(25)

so for every minute on the phone you pay 5 cents

Hope This Helps!!!

Answer:

for every minute on the phone you pay 5 cents, add brainly plz.

Step-by-step explanation:

Answer:

See below

Step-by-step explanation:

Let side AB equal x. Since triangle ABC is equilateral, sides AB, BC, and Ac are all the same length, x. In any isosceles triangle(equilateral is a type of isosceles triangle) the median is the same as the altitude and angle bisector. This means we can say that AD is also a median. A median splits a side into two equal sections, so we can say BD = DC = x / 2. We are given that DC = CE, so we can also say CE = DC = x / 2. Now, we can use the pythagorean theorem to find the length of AD. So we get the equation:

AB^2 - BD^2 = AD^2

We have the values of AB and BD, so we can substitute them and solve for AD:

x^2 - (x/2)^2 = AD^2

x^2 - x^2 / 4 = AD^2

AD^2 = 3x^2 / 4

AD = x√3 / 2

DE is equal to the sum of DC and CE because of segment addition postulate, so we can say DE = DC + CE = x / 2 + x/ 2 = x. We can again use the pythagorean theorem to find the length of AE:

AD^2 + DE^2 = AE^2

(x√3 / 2)^2 + x^2 = AE^2

3x^2 / 4 + x^2 = AE^2

AE^2 = 7x^2 / 4

AE = x√7 / 2

Now, we know(from before) that AE squared is 7x^2 / 4. We can say EC squared is x^2 / 4 because EC is x / 2 and x / 2 squared is x^2 / 4. We can also notice that AE squared is 7 times EC squared because 7x^2 / 4 = 7 * x^2 / 4

Therefore, we can come to the conclusion AE^2 = 7 EC^2

Answer:

the answer is rotation hope it helps ahhaha

Answer:

£8520

43000-11000=32000

20/100×32000

£6400

48300-43000=5300

40/100×5300=2120

£8520

Answer:

∆a = 1/2

Step-by-step explanation:

parabolas cross the x-axis at (-4, 0) and (6, 0)

y = a(x + 4)(x - 6)

At the y-intercept x = 0

y =  a(0 + 4)(0 - 6)

y = -24a

-----------------------

y-intercept of the first parabola is (0,–12)

-12 = -24a

a = 1/2

-----------------------

y-intercept of the second parabola is (0, -24)

-24 = -24a

a = 1

----------------------

What is the positive difference between the a values

∆a = 1 - 1/2

∆a = 1/2

Answer:

36π mm²

Step-by-step explanation:

Formula: πr²

r=radius

r=6

π6²=36π

Answer:

160=130+x

x=160-130

x=30

Answer:

a). y = 7x - 46      b). y = -1/7x - 22/7

Step-by-step explanation:

a). y = 7x + b

-4 = 7(6) + b

-4 = 42 + b

-46 = b

y = 7x - 46

b). y = -1/7x + b

-4 = -1/7(6) + b

-4 = -6/7 + b

-22/7 = b

y = -1/7x - 22/7

Answer:

(A)

Step-by-step explanation:

The bottom arrow goes to 5 1/2, and then because adding -3 is the same as subtracting 3, the top arrow correctly goes back 3, resulting in an answer of 2 1/2.

Hope it helps (●'◡'●)

Answer:

B.

Step-by-step explanation:

Since the numbers in the root is all the same, lets say [tex]\sqrt{2}[/tex] is a variable.

7x[tex]\sqrt{2}[/tex] - 4[tex]\sqrt{2}[/tex] + x[tex]\sqrt{2}[/tex]

Group with like terms:

7x[tex]\sqrt{2}[/tex] + x[tex]\sqrt{2}[/tex] - 4[tex]\sqrt{2}[/tex]

Combine like terms:

8x[tex]\sqrt{2}[/tex] - 4[tex]\sqrt{2}[/tex]

There you have it! Since all the square roots are the same thing, we can treat them like variables.

the answer is B..................

Answer:

2nd option

Step-by-step explanation:

[tex]\frac{7\pi }{12}[/tex] is an angle in the second quadrant

Thus to find the reference angle, subtract from π , that is

r = π - θ

Answer:

(fg)(x) = (4x^2 + x^4)(x^2 + 4)^(1/2)

Step-by-step explanation:

Mathematically;

(fg)(x) = f(x) * g(x)

so we have;

4x^2 +x^4 * √(x^2 + 4)

But √(x^2 + 4) = (x^2 + 4)^(1/2)

So we have;

(fg)(x) = (4x^2 + x^4)(x^2 + 4)^(1/2)

Answer:

D.

Step-by-step explanation:

She cannot buy a negative number of notebooks. She can buy 0 notebooks, or 1 notebook, or 2, or 3, etc. The number of notebooks she buys must be a non-negative integer.

Answer: D.

Answer:

p = 2/3

q = 1/2

Step-by-step explanation:

The given equation is ,

[tex]\sf\to px^2 + px + 3q = 1 + 2x [/tex]

We can write it as ,

[tex]\sf\to px^2 + px + 3q - 1 -2x=0 [/tex]

Rearrange the terms ,

[tex]\sf\to px^2 - 2x + px + (3q -1)=0 [/tex]

This can be written as ,

[tex]\sf\to px^2 + x ( p - 2) + (3q -1) =0[/tex]

Now wrt Standard form of a quadratic equation ,

[tex]\bf \implies ax^2+bx + c = 0 [/tex]

we have ,

We know that product of zeroes :-

[tex]\to \sf q \times \dfrac{1}{p} = \dfrac{3q-1}{p } \\\\\sf\to 3q - 1 = q \\\\\sf\to 2q = 1 \\\\\sf\to \boxed{ q =\dfrac{1}{2}}[/tex]

Sum of roots :-

[tex]\to \sf q + \dfrac{1}{p} = \dfrac{2-p}{p} \\\\\sf\to \dfrac{ qp + 1}{p}= \dfrac{2-p}{p} \\\\\sf\to qp + 1 = 2 - p \\\\\sf\to p/2 + p = 1 \\\\\sf\to 3p/2 = 1 \\\\\sf\to \boxed{ p =\dfrac{2}{3}}[/tex]