help can you please help question a b and c
(with the working out)​

Answer:

the function is the solution is done using the operation

Answer:2x^2 + 7x - 30

Step-by-step explanation:

1. x(2x-3)(x+3)^2

2. x(2x-3)(x+10)

3. 2x^2+10x-3x-30

4. 2x^2+7x-30

Answer:

[tex]\displaystyle \frac{\tan\theta}{\sec\theta - \cos\theta} = \frac{1}{\sin\theta} = \csc\theta[/tex]

Step-by-step explanation:

We have the expression:

[tex]\displaystyle \frac{\tan\theta}{\sec\theta - \cos\theta}[/tex]

And we want to write the expression in terms of sine and cosine and simplify.

Thus, let tanθ = sinθ / cosθ and secθ = 1 / cosθ. Substitute:

[tex]=\displaystyle \frac{\dfrac{\sin\theta}{\cos\theta}}{\dfrac{1}{\cos\theta}-\cos\theta}[/tex]

Multiply both layers by cosθ:

[tex]=\displaystyle \frac{\left(\dfrac{\sin\theta}{\cos\theta}\right)\cdot \cos\theta}{\left(\dfrac{1}{\cos\theta}-\cos\theta\right)\cdot \cos\theta}[/tex]

Distribute:

[tex]\displaystyle =\frac{\sin\theta}{1-\cos^2\theta}[/tex]

Recall from the Pythagorean Theorem that sin²θ + cos²θ = 1. Hence, 1 - cos²θ = sin²θ. Substitute and simplify:

[tex]\displaystyle =\frac{\sin\theta}{\sin^2\theta} \\ \\ =\frac{1}{\sin\theta}[/tex]

We can convert this to cosecant if we wish.

Answer:

1/4 of a yard of material

Step-by-step explanation:

First, we must convert both 12 1/4 yards and 8 1/2 yards to quarters. Since 1/2 of a yard is equal to 2/4 of a yard, 8 1/2 yards will be equal to 8 2/4 yards. 8 yards + 12 yards = 20 yards, and 2/4 of a yard + 1/4 of a yard = 3/4 of a yard, so you get 20 3/4 of a yard to finish the draperies. To find the leftover material, do 21 yards - 20 3/4 yards = 1/4 of a yard of material. Hope this helps!

Answer:

No

Step-by-step explanation:

x⁵ + 2x³ + x - 1  -> degree of  the polynomial is 5

So, when x⁵ is divided by x³, the quotient should be x⁵⁻³ = x².

So, x³ - 3x + 1 cannot be a quotient

Answer:

3b

Step-by-step explanation:

[tex]\dfrac{24a^2b^4c^3}{8a^2b^3\sqrt[3]{c^9}} =[/tex]

[tex] = 3a^{2 - 2}b^{4 - 3} \times \dfrac{c^3}{c^\frac{9}{3}} [/tex]

[tex] = 3a^{0}b^{1} \times \dfrac{c^3}{c^3} [/tex]

[tex] = 3bc^{3-3} [/tex]

[tex] = 3bc^{0} [/tex]

[tex] = 3b [/tex]

Answer:

188 m

Step-by-step explanation:

[tex] \tan(12) = \frac{40}{x} \\ x = \frac{40}{ \tan(12) } \\ x = 188[/tex]

Answer:

I think that the other answer is WRONG

tan(12) = [tex]\frac{x}{40}[/tex]

x = tan(12)*40 = 8.5

Step-by-step explanation:

[tex]\frac{sin\left(78\right)}{40}=\frac{sin\left(12\right)}{x}[/tex] = 8.5

Answer:

b must be because the therom is aas so

Answer:

B is answer

Step-by-step explanation:

just did it

Answer:

50

Step-by-step explanation:

Given:

140, 166, 132, 165, 152, 168, 181, 158, 173, 171, 180, 182, 163, 177, 180, 142, 147, 149, 178

Arranging in ascending order (from the lowest to the highest)

= 132, 140, 142, 147, 149, 152, 158, 163, 165, 166, 168, 171, 173, 177, 178, 180, 180 181, 182

Range = highest number - lowest number

= 182 - 132

= 50

Answer:

50

Step-by-step explanation:

              None

Answer:

1

Step-by-step explanation:

Let the number be n.

We are given:

n/12=q1+(7/12) where q1 is the quotient

n/6=q2+(?/6) where q2 is the quotient and ? is the remainder value we are trying to find.

? must be a integer between 0 and 5, inclusive. A remainder cannot be bigger than or equal to the divisor.

Let's rewrite the first equations

Multiply equation 1 on both sides by 2:

n/6=2q1+7/6

Remainder cannot be 7.

Rewrite again.

6 goes into 7 1 time with remainder 1.

n/6=2q1+(1+1/6)

n/6=(2q1+1)+1/6

So q2=2q1+1 and the remainder is 1 when dividing n by 6.

For fun. What is a number n with such conditions on it?

So what number has remainder 7 when divided by 12 and a remainder 1 when divided by 6.

n=12q1+7

n=6q2+1

If q1=1, we find a number right away that works.

19/12=1+7/12

19/6=3+1/6

Answer:

vanilla small= 14

lemon large= 25

Step-by-step explanation:

total= 120

120÷3= 40

each of flavoured cake have 40

lemon= 40 - 26= 14

vanilla= 40- 15= 25

Answer:

x = 12

Step-by-step explanation:

The sum of angles in a triangle is 180°

Thus,

(x + 20) + (10x) + (x + 16) = 180°

Collect like terms

x + 10x + x + 20 + 16 = 180°

12x + 36 = 180°

12x = 180 - 36

12x = 144

Divide both sides by 12

x = 144 ÷ 12

x = 12

Substitute the value of x into the question

Therefore,

x + 20 = 12 + 20

= 32°

10x = 10(12)

= 120°

x + 16 = 12 + 16

= 28°

Answer:

Below.

Step-by-step explanation:

Ok so, Since its 510 - x = 410. Speeds equals the wind.

SO?

100=2x

x=50

410+50 = 460!

Answer:

40 and 136

Step-by-step explanation:

The ratio of the 2 numbers = 5 : 17 = 5x : 17x ( x is a multiplier )

One number is 96 more than the other then

17x = 5x + 96 ( subtract 5x from both sides )

12x = 96 ( divide both sides by 12 )

x = 8 , then

5x = 5 × 8 = 40

17x = 17 × 8 = 136

The 2 numbers are 40 and 136

Step-by-step explanation:

ratio =4:1

total= 4+1 =5

1/5 × 52= 10.4 years

Answer:

Step-by-step explanation:

let age of Shyam=x

age of Ram=x+4

x+x+4=52

2x=52-4=48

2x=48

x=48/2=24

age of Shyam=24 years

age of Ram=24+4=28 years.

=============================================================

Explanation:

Choice B has the GCF x we can factor out like so

10x^4-5x^3+70x^2+3x = x(10x^3-5x^2+70x+3)

Showing that choice B is not prime. If a polynomial can be factored, then we consider it not prime. It's analogous to saying a number like 15 isn't prime because 15 = 3*5, ie 15 can be factored into something that doesn't involve 1 as a factor.

In contrast, we consider 7 prime because even though 7 = 1*7, there aren't any other ways to write this integer as a factorization if we don't involve 1.

-----------------------------------

Choice C is a similar story. This time we can factor out 3

3x^2 + 18y = 3(x^2 + 6y)

So we can rule this out as well.

-----------------------------------

Choice D is a bit tricky, but we can use the difference of cubes factoring rule

a^3 - b^3 = (a-b)(a^2+ab+b^2)

where in this case a = x and b = 3y^2

Note how b^3 = (3y^2)^3 = 3^3*(y^2)^3 = 27y^(2*3) = 27y^6

All of this means choice D can be factored and it's not prime either.

------------------------------------

We've ruled out choices B through D. The answer must be choice A.

If you let w = x^2, then w^2 = x^4

The polynomial w^2+20w-100 is prime because setting it equal to zero and solving for w leads to irrational solutions. I'm assuming your teacher wants you to factor over the rational numbers.

Because w^2+20w-100 can't be factored over the rational numbers, neither can x^4+20x^2-100. This confirms that choice A is prime.

Answer:

Can u explain more pls?

Step-by-step explanation:

Answer:

Square

Step-by-step explanation:

Answer:

x ≈ 60.6°

Step-by-step explanation:

Using the tangent ratio in the right triangle

tan x = [tex]\frac{opposite}{adjacent}[/tex] = [tex]\frac{IJ}{HI}[/tex] = [tex]\frac{3.9}{2.2}[/tex] , then

x = [tex]tan^{-1}[/tex] ([tex]\frac{3.9}{2.2}[/tex] ) ≈ 60.6° ( to the nearest tenth )

Answer:

Radical (20)

Step-by-step explanation:

Radical ( (4-6)² + (2-6)²)) =radical ( 4+16) = radical (20)

Answer:

b

Step-by-step explanation:

i belive the answer is c

Answer:

it is what it is

Step-by-step explanation:

Answer:

The actual price of the article was Rs. 1200.

Step-by-step explanation:

mp (marked price)

ap (actual price)

[tex]mp = 1380[/tex]

[tex]mp = ap + 15\%(ap)[/tex]

[tex]1 380 = ap + \frac{15}{100} ap[/tex]

[tex]1380 = \frac{100}{100} ap + \frac{15}{100} ap[/tex]

[tex]1380 = \frac{115}{100} ap[/tex]

[tex]1380 \div \frac{115}{100} = ap[/tex]

[tex]1380 \times \frac{100}{115} = ap[/tex]

[tex] \frac{138000}{115} = ap[/tex]

[tex]1200 = ap[/tex]

The actual price of the article is given by the equation A = $ 1,200

What is an Equation?

Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.

It demonstrates the equality of the relationship between the expressions printed on the left and right sides.

Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.

Given data ,

Let the actual price of the article be A

Now , the equation will be

The marked price of the article be = $ 1380

The percentage of increase from the actual price = 15 %

So , the equation is

The actual price + percentage of increase from the actual price = 1380

Substituting the values in the equation , we get

A + ( 15/100 )A = 1380   be equation (1)

( 115/100 ) A = 1380

Multiply by 100 on both sides of the equation , we get

115A = 138000

Divide by 115 on both sides of the equation , we get

A = $ 1200

Therefore , the value of A is $ 1200

Hence , the actual price of the article is $ 1200

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Answer:

height of the tree ≈ 8.42 m

Step-by-step explanation:

The diagram given represents that of two similar triangles. Therefore, the corresponding lengths of the similar triangles are proportional to each other.

height of tree = h

Therefore:

1.45/h = (31.65 - 26.2)/31.65

1.45/h = 5.45/31.65

Cross multiply

h*5.45 = 1.45*31.65

h*5.45 = 45.8925

h = 45.8925/5.45

h ≈ 8.42 m (nearest hundredth)

Answer:

{(-4, - 2),(-1, - 1), (- 1,1),(3,5), (7, 10)} is not a function.

Step-by-step explanation:

For a function to be a function, there is only ever one y value per x value. In this set, -1 has two outputs, or y values. It has -1 and 1. As a result, this is not a function.

Answer:

[tex]y=|x-(-2)|+2[/tex]

Step-by-step explanation:

Hope this is helpful.

The required absolute function is given as y = |x - 2| + 2.

Given that,
From the graph, y = |x - h| + k, values of h and k is to be determined,

Functions are the relationship between sets of values. e g y=f(x), for every value of x there is its exists in a set of y. x is the independent variable while Y is the dependent variable.

Here,
In the graph and function, h represents the shift on the x-axis, which 2 units left so the value of h is 2, while k is given the shift of the function over the y-axis which 2 units up means that k = 2

Thus, The required absolute function is given as y = |x - 2| + 2.

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Answer:

hope this will help you more

Step-by-step explanation:

hope it is helpful to you

stay safe healthy and happy

Step-by-step explanation:

Given that,

The positions of the first particle,[tex]s_1=4t-t^2[/tex]

Velocity,

[tex]v_1=\dfrac{ds_1}{dt}\\\\v_1=\dfrac{d(4t-t^2)}{dt}\\\\v_1=4-2t[/tex]

Position,

[tex]s_2=5t^2-t^3[/tex]

[tex]v_2=\dfrac{ds_2}{dt}\\\\v_2=\dfrac{d(5t^2-t^3)}{dt}\\\\v_2=10t-3t^2[/tex]

Hence, this is the required solution.

Answer:

Step-by-step explanation:

I'm assuming you need the age of the bowl. Start with the fact that you have remaining 28% of the original amount before any of it decayed. You always start with 100% of something unless you're told differently. That means that the equation looks like this:

[tex]28=100e^{-.0001t}[/tex] and begin by dividing both sides by 100 to get

[tex].28=e^{-.0001t}[/tex] . To solve for t we have to be able to bring it down from its current position of exponential. To do this we would either take the log or the natural log since the rules for both are the same. However, the natural log is the inverse of e, so they undo each other. We take the natural log of both sides which allows us to pull down the -.0001t. At the same time remember that the natural log and e are inverses of each other so they are both eliminated when we do this.

ln(.28) = -.0001t Now it's easy to solve for t.

[tex]\frac{ln(.28)}{-.0001}=t[/tex] and

[tex]\frac{-1.272965676}{-.0001}=t[/tex] so

t = 12729.65676 years or rounded, 12730 years.