help me pleaseeeeeeeeeeeee

1.) The answers:

A) BME

B) MER

C) Mm

D) xBy

E) Straight

F) REB

G) MEB and BER

H) xBy

Answer:

z is greater than 27/14

z € ( 37/14 ∞)

Answer:

12 and 12.5

Step-by-step explanation:

Answer:

True

Step-by-step explanation:

Answer:

Your answer is B

Step-by-step explanation:

Answer:

Domain: [tex][3,\infty)[/tex]

Range: [tex][6,\infty)[/tex]

Step-by-step explanation:

I assume you mean [tex]y=\sqrt{x-3} +6[/tex]?

Take note of how x cannot be less than 3 because it would result in a negative number under the radical, which isn't real. However, x CAN be 3 because [tex]\sqrt{3-3}+6=\sqrt{0}+6=0+6=6[/tex] which is real.

Therefore, the domain of the function is [tex][3,\infty)[/tex]

As for the range of the function, we saw previously that the minimum of the domain resulted in the minimum of the range, which was 6.

Therefore, the range of the function is [tex][6,\infty)[/tex]

See attached graph below for a visual.

Answer:

2/3

Step-by-step explanation:

to the the slope of the perpendicular line we must first find the slope of line given in the problem. To do this we must transform this equation into the slope intercept format

The slope intercept form of a liner equation is:

Y = mx + b

Where m is slope and b is the y - intercept value.

solving the equation in the problem for y produces :

3x - 3x + 2y = -3x - 5

0 + 2y = 3x - 5

2y = - 3x - 5

2y = -3x - 5

2 2

y = - 3 x - 5

2. 2

Therefore the slope of this line is m = - 3

2

the slope of perpendicular line is the negative inverse of the slope of the line we are given,or

- 1

m

so for our problem the slope of a perpendicular line is - - 2 = 2

3. 3

Answer:

150

Step-by-step explanation:

The sum of the angles of a quadrilateral are 360.  Let x be the unknown angle

30+70+110+x = 360

Combine like terms

210 +x = 360

Subtract 210 from each side

210+x-210 = 360-210

x = 150

Answer:

The measures of the fourth angle is 150 .

Step-by-step explanation:

The measures of three angles of quadrilateral are 30 , 70 and 110.

Find the measures of fourth angle.

Let, the measures of fourth angle be x.

We know that sum angles of quadrilateral are 360 .

30 + 70 + 110 + x = 360

combine like terms

210 + x = 360

subtract 210 from 360.

x = 360 - 210

x = 150

Therefore, the fourth angle of quadrilateral is 150.

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Explanation:

Each square has a side length of 5 inches, so each square has area 5*5 = 25 square inches. We have 6 such squares to give a total surface area of 6*25 = 150 square inches.

Effectively, this is the same as using the formula below

S = 6x^2

S = 6*5^2

S = 6*5*5

S = 150

x = 5 refers to the side length and S is the surface area. It might help to cut the figure from the paper, and fold it up and you should find that a 3D box will form. There are 6 faces with area of 5*5 each, hence the 6*5*5

Answer:

Yes of course I would like to help u.

Answer:

slope = 6

y-intercept is (0,-1)

Step-by-step explanation:

the equation y = 6x-1 is written in slope-intercept form so it's easy to find the slope and the y-intercept

Answer: it is a linear line

Step-by-step explanation:

They both together make 0

Answer:

Options (1), (2), (3) and (7)

Step-by-step explanation:

Given expression is [tex]\frac{\sqrt[3]{8^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}[/tex].

Now we will solve this expression with the help of law of exponents.

[tex]\frac{\sqrt[3]{8^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}=\frac{\sqrt[3]{(2^3)^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}[/tex]

           [tex]=\frac{\sqrt[3]{2\times 3} }{3\times2^{\frac{1}{9}}}[/tex]

           [tex]=\frac{2^{\frac{1}{3}}\times 3^{\frac{1}{3}}}{3\times 2^{\frac{1}{9}}}[/tex]

           [tex]=2^{\frac{1}{3}}\times 3^{\frac{1}{3}}\times 2^{-\frac{1}{9}}\times 3^{-1}[/tex]

           [tex]=2^{\frac{1}{3}-\frac{1}{9}}\times 3^{\frac{1}{3}-1}[/tex]

           [tex]=2^{\frac{3-1}{9}}\times 3^{\frac{1-3}{3}}[/tex]

           [tex]=2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }[/tex] [Option 2]

[tex]2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(\sqrt[9]{2})^2\times (\sqrt[3]{\frac{1}{3} } )^2[/tex] [Option 1]

[tex]2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(\sqrt[9]{2})^2\times (\sqrt[3]{\frac{1}{3} } )^2[/tex]

                [tex]=(2^2)^{\frac{1}{9}}\times (3^2)^{-\frac{1}{3} }[/tex]

                [tex]=\sqrt[9]{4}\times \sqrt[3]{\frac{1}{9} }[/tex] [Option 3]

[tex]2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(2^2)^{\frac{1}{9}}\times (3^{-2})^{\frac{1}{3} }[/tex]

               [tex]=\sqrt[9]{2^2}\times \sqrt[3]{3^{-2}}[/tex] [Option 7]

Therefore, Options (1), (2), (3) and (7) are the correct options.

Answer:-244

Step-by-step explanation:

I think you subtract -290 from -46.

Sorry If I am wrong.

========================================================

Explanation:

Imagine reflecting everything so that location A is above location B. Effectively all you're doing is erasing the negative signs.

That would place A at 290 feet and B would be at 46 feet. The difference in elevation is 290-46 = 244 feet

Instead of reflecting, you can turn the page upside down and just ignore the negative signs, and then subtract like normal.

This trick only works if both elevations A and B are below sea level.

--------

Or you could subtract like so:

|A-B| = |-290-(-46)| = |-290+46| = |-244| = 244

The absolute value is used to ensure the result is not negative. A negative difference makes no sense. In this case, "difference" and "distance" mean the same thing more or less.

Answer:

d. employed individuals aged 25-29

Step-by-step explanation:

"Population" in a research study is the comprehensive group that the experimenter or the researcher is interested in.

It is given that US Census Bureau, showed that percentage of the employed individual who are of age group 25 years to 29 years are college educated and is at all time high.

The research study focuses on the specific age group of individuals those who graduated form college or at least have a bachelor degree.

Thus the population of the research study those who studied in each of the four years are the employed individuals aged from 25-29.

Answer:

Please find the complete question in the attached file.

Step-by-step explanation:

For point a:

[tex]\to fx_1(x_1)=\int^{x_{1}}_{0} f(x_1,x_2)\ dx\\\\[/tex]

[tex]=\int^{x_{1}}_{0} e^{-x_1}\ dx_2\\\\= e^{-x_1} \ [x_2]^{x_1}_0 \\\\\therefore f x_1(x_1)=x_1e^{-x_1}; \ \ x_1>0\\\\[/tex]

For point b:

[tex]\to f(x_2|x_1)=\frac{f(x_1,x_2)}{f(x_1)}\ =\frac{e^{-x_1}}{x_1\ e^{-x_1}}=\frac{1}{x_1} ; \\\\ \ \ 0\leq x_2 \leq x_1 \\\\[/tex]

For point c:

[tex]P(x_1>2|x_2=7)= 1.00 \\\\\because x_2=7\to x_1>7\to x_1>2\\\\[/tex]

Answer:

the equation has no solution

Answer: d

Step-by-step explanation:

Answer:

acute triangle

if i m wrong please dont mind and

correct me

Answer:Ping Pong Balls

Step-by-step explanation:

Answer:

F(x) = -1/3 x^2 - 7x + C

Answer:

11.

Step-by-step explanation:

The scores 60-69 has two people. The scores 70-79 have 9 people. Both are lower or below 80.

Answer:

11

Step-by-step explanation:

Add the number of people in the 60-69 range ( 2) and the number of people in the 70-79 range (9) to get the number of people below 80

2+9 = 11

Answer:

-60

hope it helps

Answer:

The colder it is, the more cups of hot chocolate will be sold.

Step-by-step explanation:

When it was 15 degrees Fahrenheit, 80 cups of hot chocolate were sold. When it was a 90 degree summer day, only 4 cups of hot chocolate were sold.

Answer: The answer is C.

Step-by-step explanation:

It is definitely not B because the average of the numbers compared to what that shows don't make sense.

The biggest number that you gave us is 34 but on option A, it looks like its 30 or 31. So that's not correct.

Finally, it can't be D because the biggest number shown there is 35 when it actually is 34.

I hope I was able to help!

Good luck and have a great day :)

Answer:

C

Step-by-step explanation:

Your welcome! :) Good luck!