Mathematics College

Help meeeeeeeeeeeeeeeeeeeeee

Answers

Answer 1

Step-by-step explanation:

the answer is in the above image

use the app

WOLFRAM ALPHA it helps a lot

Answer 2

Answer:

[tex] \frac{1}{ 2^{1} } + \frac{1}{ {3}^{2} } + \frac{1}{ {4}^{3} } + \frac{1}{ {5}^{4} } + ... \\ \frac{1}{2} + \frac{1}{9} + \frac{1}{64} + \frac{1}{625} + ... \\ = \frac{226201}{360000} \\ = 0.6283..[/tex]

Related Questions

Pythagorean triples are super important to know. If the hypotenuse of a triangle is 15, what are its legs ( hint - use the three, four, five triple)

Answers

Answer:

9, 12

Step-by-step explanation:

Just multiply the 3,4,5 triple by 3 and u get 9, 12, 15

which ones do i press ?

Answers

Answer:

Step-by-step explanation:

b,e

I need help with this problem for my homework pls help

Answers

Answer:

x = 6.93

y = 13.86

Step-by-step explanation:

We can solve x by;

Tan(60) = 12/x

Tan(60) * x = 12

x = 12 / Tan(60)

x = 6.93

We can solve y by;

A² + B² = C²

12² + 6.93² = y²

144 + 48.02 = y²

192.02 = y²

[tex]\sqrt{192.02}[/tex] = y²

13.86 = y

Hope this helps!

2.02b + 4.30 = 2.00b + 6.30

Answers

Answer: b = 100

Step-by-step explanation:

simplifying

2.02b + 4.30 = 2.00b + 6.30

reorder the terms:

4.30 + 2.02b = 2.00b + 6.30

reorder the terms:

4.30 + 2.02b = 6.30 + 2.00b

solving

4.30 + 2.02b = 6.30 + 2.00b

solving for variable 'b'.

move all terms containing b to the left, all other terms to the right.

add '-2.00b' to each side of the equation.

4.30 + 2.02b + -2.00b = 6.30 + 2.00b + -2.00b

combine like terms: 2.02b + -2.00b = 0.02b

4.30 + 0.02b = 6.30 + 2.00b + -2.00b

combine like terms: 2.00b + -2.00b = 0.00

4.30 + 0.02b = 6.30 + 0.00

4.30 + 0.02b = 6.30

add '-4.30' to each side of the equation.

4.30 + -4.30 + 0.02b = 6.30 + -4.30

combine like terms: 4.30 + -4.30 = 0.00

0.00 + 0.02b = 6.30 + -4.30

0.02b = 6.30 + -4.30

combine like terms: 6.30 + -4.30 = 2

0.02b = 2

divide each side by '0.02'.

getting: b = 100

Please help me solve this

Answers

Answer:

m1 = 107°

m2 = 73°

m3 = 107°

m1+m2+m3+m4 = 360°

107+73+107+73=360°

I need help with this

Answers

Base: 3 units

Height: 5 units

Area: 15 square units

([tex]A=b*h=3*5=15[/tex])

hope this helps :)

There are two packs of hyenas that live just outside of a small town in Harar, Ethiopia. Each night, the
packs fight to determine which pack can go through the city gate. The city provides unlimited food and
water to any hyenas that enter.
Is there competition taking place in the scenario? *
2 points
Yes
No

Answers

Answer:

yes

Step-by-step explanation:

the packs are fighting for a common goal against each other

so they are competing

3. Two dice are rolled. What’s the conditional probability that both dice are 5’s if it’s known that the sum of points is divisible by 5?

Answers

Answer:

[tex]Pr =\frac{1}{3}[/tex]

Step-by-step explanation:

Given

[tex]S = \{(1, 1) (1, 2) (1, 3) (1, 4) (1, 5) (1, 6)(2, 1) (2, 2) (2, 3) (2, 4) (2, 5) (2, 6)[/tex]

[tex](3, 1) (3, 2) (3, 3) (3, 4) (3, 5) (3, 6)(4, 1) (4, 2) (4, 3) (4, 4) (4, 5) (4, 6)[/tex]

[tex](5, 1) (5, 2) (5, 3) (5, 4) (5, 5) (5, 6)(6, 1) (6, 2) (6, 3) (6, 4) (6, 5) (6, 6)\}[/tex] --- sample space

First, list out all outcomes whose sum is divisible by 5

[tex]A = \{(4,6), (5,5),(6,4)\}[/tex]

So, we have:

[tex]n(A) = 3[/tex]

Next, list out all outcomes that has an outcome of 5 in both rolls

[tex]B = \{(5,5)\}[/tex]

[tex]n(B) =1[/tex]

The required conditional probability is:

[tex]Pr =\frac{n(B)}{n(A)}[/tex]

[tex]Pr =\frac{1}{3}[/tex]

please help me find the area

Answers

Answer:

320 square feet.

Step-by-step explanation:

For the moment, let's put the square back in place. That would make the length 16 + 8 = 24 and the width 16.

L = 24

W = 16

Area = L * W

Area = 24 * 16

Area = 384

Now the next step is to take out the square. It is 8 * 8 = 64

The area of the figure = 384 - 64 = 320 square feet, and that's the answer.

Answer:

320 in^2

Step-by-step explanation:

we need to find the area of this figure

Firstly divide above picture in two parts

1st figure = (16*16)in.

2nd figure = (8*8)in.

Area of 1st figure = 16*16 = 256 in^2

Area of 2nd figure = 8*8 = 64 in^2

Area of whole figure = ( 256 + 64 )in^2

= 320 in^2

Alex wants to arrange chairs in such a way that the number of chairs in a row is equal to the number of columns. He has ordered 5100 tables.
a)How many more tables needed to arrange in such a way that he planned? Justify your answer
2)How many chairs can he remove to arrange in a way that he wants? Justify your answer.

Answers

Answer:

Step-by-step explanation:

In other to have the same number of chayes in both rows and columns ;

If the Number of chairs per row = x ; then number of chairs per column = x

Then the total number of chairs needed = x * x = x²

Hence, if there are 5100 chairs ;

Number of chairs needed more ;

Take the square root of 5100 ;the round to the next whole number :

B.) For number of chairs to be removed ;

Take the square root of 5100 and round down to the whole number.

Hence,

A.) = √5100 = 71.414 = 72

72² - 5100 = 84

B.) 5100 = 71.414 = 71

5100 - 71² =

Order the side lengths

Answers

Answer:

Step-by-step explanation:

First fill in the missing angles of each triangle:

angle IJK = 180-47-51 = 82°

angle KJL = 180 - 63 - 57 = 60°

Within EACH triangle, the side length is proportional to the opposite angle.

Therefore for triangle IJK,

JK < JL < IK

and for triangle JKL

JL < KL <JK

so combining (chaining) the two inequalities,

JL < LK <JK < JL < IK

Answer:

Step-by-step explanation:

first lets find angle J in triangle IJK

for angle J

47 + 51 + angle J =180 degree (sum of interior angle of a triangle )

98 + angle J =180

angle J =180 - 98

angle J =82 degree

Now lets find angle J in triangle JKL

for angle J

57 + 63 + angle J =180 degree (being sum of interior angle of the triangle)

120 + angle J =180

angle J = 180 - 120

angle J =60 degree

now lets place the angle from samllest to largest

angle I = 41 degree

angle K = 51 degree

angle K of JKL triangle = 57 degree

angle J of JKL triangle = 60 degree

angle L =63 degree

angle J of IJK triangle = 80 degree

Side opposite to the smallest angle is smallest in sides and side opposite to the longest angle is largest in side.So,

side opposite to angle I is JK

side opposite to angle K is IJ

side opposite to angle K of JKL triangle is JL.

solve for this square.

Answers

Answer:

c16 brainliest plzz

Answer:

a) SV = 2

The line that is SV actually is not the full slash. It is halfway, and we know that half of four would be two.

b) RT = 4

This time RT is a full line going all the way down. So it would be 4.

c) p = a + b + c

The lengths are all the same because we calculated in the first question that two is half of four. So the base, height, and hypotenuse are the same, 2.

2 + 2 + 2 = 6

So the perimeter of the triangle RVS is 6.

When g(x) = 3x, what is g(5)?

Answers

Answer:

g(5) = 15

Explanation:

If the x in g(x) is 5 then the x beside 3 would also be 5.

g(5) = 3(5)

g(5) = 15

Hope this helps, good luck!

Answer:

g(5)= 15

Step-by-step explanation:

g(x) = 3x and in this situation x =5 ( g(5) )

so substitute x for 5 in the original equation:

g(x) = 3x --> g(5) = 3(5)

which gives you 15. Hope this helps!

in the number 32.8 which digit is in the ones place
help pls

Answers

Answer:

Step-by-step explanation:

the number 2 is in the ones place

its a pretty easy answer

Consider the following hypothesis test. : : The following results are for two independent samples taken from two populations. Excel File: data10-03.xlsx Enter negative values as negative numbers. a. What is the value of the test statistic? (to 2 decimals) b. What is the -value? (to 4 decimals) c. With , what is your hypothesis testing conclusion? - Select your answer -

Answers

Answer:

[tex]z = -1.53[/tex] --- test statistic

[tex]p = 0.1260[/tex] --- p value

Conclusion: Fail to reject the null hypothesis.

Step-by-step explanation:

Given

[tex]n_1 = 80[/tex] [tex]\bar x_1= 104[/tex] [tex]\sigma_1 = 8.4[/tex]

[tex]n_2 = 70[/tex] [tex]\bar x_2 = 106[/tex] [tex]\sigma_2 = 7.6[/tex]

[tex]H_o: \mu_1 - \mu_2 = 0[/tex] --- Null hypothesis

[tex]H_a: \mu_1 - \mu_2 \ne 0[/tex] ---- Alternate hypothesis

[tex]\alpha = 0.05[/tex]

Solving (a): The test statistic

This is calculated as:

[tex]z = \frac{\bar x_1 - \bar x_2}{\sqrt{\frac{\sigma_1^2}{n_1} + \frac{\sigma_2^2}{n_2} }}[/tex]

So, we have:

[tex]z = \frac{104 - 106}{\sqrt{\frac{8.4^2}{80} + \frac{7.6^2}{70} }}[/tex]

[tex]z = \frac{104 - 106}{\sqrt{\frac{70.56}{80} + \frac{57.76}{70}}}[/tex]

[tex]z = \frac{-2}{\sqrt{0.8820 + 0.8251}}[/tex]

[tex]z = \frac{-2}{\sqrt{1.7071}}[/tex]

[tex]z = \frac{-2}{1.3066}[/tex]

[tex]z = -1.53[/tex]

Solving (b): The p value

This is calculated as:

[tex]p = 2 * P(Z < z)[/tex]

So, we have:

[tex]p = 2 * P(Z < -1.53)[/tex]

Look up the z probability in the z score table. So, the expression becomes

[tex]p = 2 * 0.0630[/tex]

[tex]p = 0.1260[/tex]

Solving (c): With [tex]\alpha = 0.05[/tex], what is the conclusion based on the p value

We have:

[tex]\alpha = 0.05[/tex]

In (b), we have:

[tex]p = 0.1260[/tex]

By comparison:

[tex]p > \alpha[/tex]

i.e.

[tex]0.1260 > 0.05[/tex]

So, we fail to reject the null hypothesis.

Suppose, as a rough estimate, we say that there are 20 distinct geons used for object recognition; and each geon can come in 5 classifiable qualitative sizes (tiny, small, moderate, large, huge); and a pair of geons can be placed in 10 distinct qualitative relations (geon A on top of geon B; geon A to upper left of geon B; geon A to the left of geon B; and so forth).How many distinct two-geon objects do we have in the space described above?

Answers

Answer:

49500

Step-by-step explanation:

According to the Question,

Given That, Suppose, as a rough estimate, we say that there are 20 distinct geons used for object recognition, and each geon can come in 5 classifiable qualitative sizes (tiny, small, moderate, large, huge). and a pair of geons can be placed in 10 distinct qualitative relations.

We have, District geons = 20 , District Size = 5

So, The Number Of Ways A geon can be selected 20 x 5 = 100

Now, We choose 2 geons From 100 Geons and arrange them in 10 district relations.

So, The number of district two-geon object

= [tex]\left[\begin{array}{ccc}100\\2\end{array}\right] * 10[/tex]

= (100 × 99)/2 × 10

= 49.5×100×10 ⇒ 49500

Kayla wants to fence in a rectangular dog pen that is 30 ft by 40 ft How would you use wha
you know about geometry to help her ensure that she has truly built a rectangular pen?

Answers

Answer:

Kindly check explanation

Step-by-step explanation:

Given the dimension of the dog pen = 30 ft by 40 ft.

Using the knowledge of geometry, that know that a rectangle has been built, the area of the pen should be :

Area of rectangle = Length * width

Area = 40 * 30

Area = 1200 ft²

Perimeter of rectangle = 2(Length + width)

Perimeter = 2(40 + 30)

Perimeter = 2(70)

Perimeter = 140 feets

Hence, area of the pen should be 1200 ft² and its perimeter or fencing should measure 140 feets

A manufacturer knows that their items have a lengths that are skewed right, with a mean of 10 inches, and standard deviation of 1.6 inches. If 39 items are chosen at random, what is the probability that their mean length is greater than 10.5 inches

Answers

Solution :

Given :

Mean, μ = 10 inches

Standard deviation, σ = 1.6 inches

Sample size is n = 39

Therefore,

[tex]$\mu_{\overline x}=\mu = 10$[/tex]

[tex]$\sigma_{\overline x}=\frac{\sigma}{\sqrt n } = \frac{1.6}{\sqrt{39}}$[/tex]

= 0.25

[tex]$P (\overline X > 10.5 ) = P\left( \frac{\overline X - \mu_{\overline x}}{\sigma_{\overline x}} > \frac{10.5 - 10}{0.25} \right)$[/tex]

= P( Z >2)

= 1 - P(Z < 2)

= 1 - 0.97225 (from standard normal table)

= 0.0277

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