Answers
Hope it helps
Related Questions
Question 9 of 10
Which functional group does the molecule below have?
Answers
Answer:
Hydroxyl
Explanation:
A P E X
calculate the oxidation number of the central atom of FeSO4 7H2O
Answers
Answer:
[tex]{ \tt{let \: the \: oxidation \: state \: be \: x}} \\ { \bf{x + sulphate \: ion+ water = overall \: charge}} \\ \\ \\ { \tt{x + ( - 2) + 0 = 0}} \\ \\ { \tt{x = + 2}} \\ { \tt{oxidation \: state = + 2}}[/tex]
What mass of sulfuric acid, H2SO4, is required to react with 3.27 g of potassium hydroxide, KOH? The products of this reaction are potassium sulfate and water.
Have both the unbalanced and balanced chemical equations.
Explain how to find the molar mass of the compounds.
Explain how the balanced chemical equation is used to find the ratio of moles
Explain how many significant figures your answer needs to have.
The numerical answer
Answers
Answer:
pa help din ako jan pleaseAnswer:
Don't plagiarize here.
Explanation:
Your online teacher knows that you are looking here for the answer!!!!
CHEM FINAL PLEASE HELP
This is?
alkene
aromatic hydrocarbon
alkyne
alkane
Answers
Answer:
It is alkyne
Explanation:
What mass of Na2SO4is needed to make 2.5 L of 2.0 Msolution? (Na = 23 g; S = 32 g; O = 16 g)
a.356 g
b.284 g
c.710 g
d.178 g
Answers
Answer:
mass (g) needed = 710.2 grams Na₂SO₄(s)
Explanation:
Needed is 2.5 Liters of 2.0M Na₂SO₄; formula wt Na₂SO₄ = 142.04g/mol.
mass (grams) of Na₂SO₄(s) = Molarity needed x Volume needed in Liters x Formula Wt of solute
mass (grams) of Na₂SO₄(s) = (2.5L)(2.0M)(142.04g/mol) = 710.2 grams Na₂SO₄(s)
Mixing: Transfer 710.4 grams Na₂SO₄ into mixing vessel and add water-solvent up to but not to exceed 2.5 Liters total volume. Mix until dissolved.
Gives 2.5 Liters of 2.0M Na₂SO₄(aq) solution.
The number of molecules in 17.9 g of CO is
Answers
Answer:
3.85 × 10²³ molecules CO
General Formulas and Concepts:
Atomic Structure
Reading a Periodic TableCompoundsMolesAvogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.Stoichiometry
Using Dimensional AnalysisExplanation:
Step 1: Define
Identify
[Given] 17.9 g CO
[Solve] molecules CO
Step 2: Identify Conversions
Avogadro's Number
[PT] Molar Mass of C: 12.01 g/mol
[PT] Molar Mass of O: 16.00 g/mol
Molar Mass of CO: 12.01 + 16.00 = 28.01 g/mol
Step 3: Convert
[DA] Set up: [tex]\displaystyle 17.9 \ g \ CO(\frac{1 \ mol \ CO}{28.01 \ g \ CO})(\frac{6.022 \cdot 10^{23} \ molecules \ CO}{1 \ mol \ CO})[/tex][DA] Divide/Multiply [Cancel out units]: [tex]\displaystyle 3.8484 \cdot 10^{23} \ molecules \ CO[/tex]Step 4: Check
Follow sig fig rules and round. We are given 3 sig figs.
3.8484 × 10²³ molecules CO ≈ 3.85 × 10²³ molecules CO
Figure 1 (Use this figure to answer questions 6,7, and 8. Assume that the height at point
A and point C are the same)
С
B
As the car moves from point A, to point B, and finally to point C, the total energy of the car
decreases from point A to point B, then increases from point B to point
increases from point A to point B, then decreases from point B to point
O is lost between points B and C
stays the same, but is converted between potential and kinetic energy
Answers
Answer:
JWBVH
Explanation:
NWSBWHSBHS
3 Cu + 8HNO3 → 3 Cu(NO3)2 + 2 NO + 4 H2O
In the above equation, how many grams of water can be made when 15.9 moles of HNO3 are consumed?
Answers
Answer:
45673
Explanation:
PLEASEE HELLLPPP mE WITH THE QUESTIONS I POSTE DIL MARK U THE BRAINLIEST I SWEAAARr
Answers
Answer:
PIEASE E first write question
(1) The solubility of Salt AB2(s) is 5mol/dm^3. (a) Obtain an expression for the solubility product of Salt AB2,in terms of s.
Answers
Answer:
See explanation
Explanation:
Let the equation of dissolution be;
AB2(s) ⇄A(aq) + 2S
Hence;
Ksp = [A] [2s]^2
Let the concentration of the species be s
Ksp= s × (2s)^2
Ksp= 4s^3
Since s= 5mol/dm^3
Ksp = 4(5mol/dm^3)^3
Ksp = 500 mol^2dm^-6
Give an example of each of the following chemical changes.
(a) A photochemical reaction involving
(i) silver salt
(ii) water
(b) A reaction involving
(i) blue solution
(ii) formation of dirty green precipitate
(c) Two gases combine to form white solid.
(d) A reaction where colour change is noticed.
Answers
Answer:
Give an example of each of the following chemical changes.
(a) A photochemical reaction involving
(i) silver salt
(ii) water
(b) A reaction involving
(i) blue solution
(ii) formation of dirty green precipitate
(c) Two gases combine to form white solid.
(d) A reaction where colour change is noticed.
Explanation:
a) A photochemical reaction involving silver salt is used in black and white photography.
AgCl breaks down and converts into Ag during this photochemical reaction.
(ii) Photochemicalreaction involving water takes place in plants during the photosynthesis process.
Plants prepare food(carbohydrate) by using sunlight water and CO2 gas.
(b) A reaction involving
(i) blue solution:
For example reaction of copper sulfate solution with an iron nail.
When an iron nail is placed in CuSO4 blue color solution, then it changes to green color and reddish-brown solid deposits at the bottom of the container.
(ii) Reaction of ferrous sulfate with NaOH forms a dirty green precipitate of ferrous hydroxide.
(C) Two gases combine and form a white solid:
For example when HCl gas reacts with ammonia gas, then a white solid of ammonium chloride will be formed.
(d) A reaction where the color change is noticed.:
When an iron nail is placed in CuSO4 blue color solution, then it changes to green color and reddish-brown solid deposits at the bottom of the container.
Which is TRUE about 'acidified' water acting on rocks?
Please give 1 answer.
A.
Peaty soil water does not cause weathering
B.
Limestone is eroded faster than basalt rock by this type of weathering
c.
It is an example of physical weathering
D.
Nearly neutral water will not weather rocks
Answers
Subtract to find the temperature changes
for the water and the metal.
Answers
Answer:
???what metal????????????
Será lançado na próxima quarta-feira, 1º de julho, em São Bernardo do Campo (SP), o primeiro ônibus brasileiro a hidrogênio. [...] O projeto Ônibus Brasileiro à Célula Combustível a Hidrogênio é o ponto de partida para o desenvolvimento de uma solução mais limpa para o transporte público urbano no Brasil. (Disponível em: Acesso em: 19 out. 2009.) Quanto aos processos químicos envolvidos na produção de energia elétrica em células de combustíveis a partir do oxigênio e do hidrogênio, é correto afirmar:
Answers
A 30. g sample of Aluminum was heated to 40. 0C and placed in a calorimeter containing 50. g of water at 21 0C. What is the final temperature of the aluminum-water system if the cAl = 0.21 cal/g0C and cwater = 1.0 cal/ g 0C.
Write the complete equation you will use. 1 point
Substitute the values in the equation in step 1 . 1 point
Report the math answer with 2 sig figs and the correct unit. 1 point
Answers
Answer: The final temperature will be [tex]23^oC[/tex]
Explanation:
Calculating the heat released or absorbed for the process:
[tex]q=m\times C\times (T_2-T_1)[/tex]
In a system, the total amount of heat released is equal to the total amount of heat absorbed.
[tex]q_1=-q_2[/tex]
OR
[tex]m_1\times C_1\times (T_f-T_1)=-m_2\times C_2\times (T_f-T_2)[/tex] ......(1)
where,
[tex]C_1[/tex] = specific heat of aluminium = [tex]0.21 Cal/g^oC[/tex]
[tex]C_2[/tex] = heat capacity of water = [tex]1Cal/g^oC[/tex]
[tex]m_1[/tex] = mass of aluminium = 30. g
[tex]m_2[/tex] = mass of water = 50. g
[tex]T_f[/tex] = final temperature of the system = ?
[tex]T_1[/tex] = initial temperature of aluminium = [tex]40.^oC[/tex]
[tex]T_2[/tex] = initial temperature of the water = [tex]21.^oC[/tex]
Putting values in equation 1, we get:
[tex]30\times 0.21\times (T_f-40)=-50\times 1\times (T_f-21)\\\\56.3T_f=1302\\\\T_f=\frac{1302}{56.3}=23.13^oC=23^oC[/tex]
Hence, the final temperature will be [tex]23^oC[/tex]
A gas has a volume of 1000.0 mL at a temperature of 20.OK and a pressure
of 1.0 atm. What will be the new volume when the temperature is changed
to 40.0K and the pressure is changed to
0.5 atm?
Answers
Answer:
4000mL
Explanation:
Using the combined gas law equation;
P1V1/T1 = P2V2/T2
Where;
P1 = initial pressure (atm)
P2 = final pressure (atm)
V1 = initial volume (mL)
V2 = final volume (mL)
T1 = initial temperature (K)
T2 = final temperature (K)
According to the information given in this question:
V1 = 1000mL
T1 = 20K
P1 = 1.0atm
V2 = ?
P2 = 0.5atm
T2 = 40K
Using P1V1/T1 = P2V2/T2
1 × 1000/20 = 0.5 × V2/40
1000/20 = 0.5V2/40
50 = 0.5V2/40
50 × 40 = 0.5V2
2000 = 0.5V2
V2 = 2000/0.5
V2 = 4000mL
How do the Carnivorous plants survive without soil?
Answers
Carnivorous plants are easy to grow, if you follow a few, simple rules.
Wet all of the time.
Mineral-free water.
Mineral-free soil.
Lots of light.
Wet all of the time.
Carnivorous plants are native to bogs and similar nutrient-poor habitats. As a consequence, the plants live in conditions that are constantly damp. To grow healthy carnivorous plants, it is important to duplicate their habitat as closely as possible. Keep the soil wet or at least damp all of the time. The easiest way to do this is use the tray method. Set the pots in a tray or saucer, and keep water in it at all times. Pitcher plants can grow in soggy soil with the water level in the saucer as deep as 1/2 the pot, but most carnivorous plants prefer damp to wet soil, so keep the water at about 1/4 inch and refill as soon as it is nearly gone. Water from below, by adding water to the tray, rather than watering the plant. This will avoid washing away the sticky muscilage of the sundews and butterworts and keep from closing the flytraps with a false alarm.
Mineral-free water.
Always use mineral-free water with your carnivorous plants, such as rainwater or distilled water. Try keeping a bucket near the downspout to collect rainwater. Distilled water can be purchased at the grocery store, but avoid bottled drinking water. There are simply too many minerals in it. The condensation line from an air conditioner or heat pump is another source of mineral-free water. Reverse-osmosis water is fine to use. Carnivorous plants grow in nutrient poor soils. The minerals from tap water can “over-fertilize” and “burn out” the plants. In a pinch, tap water will work for a short while, but flush out the minerals with generous portions of rainwater, when it is available.
Mineral-free soil.
The nutrient poor soils to which the carnivorous plants have adapted are often rich in peat and sand. This can be duplicated with a soil mixture of sphagnum peat moss and horticultural sand. Be sure to check the peat label for sphagnum moss. Other types will not work well. The sand should be clean and washed. Play box sand is great, and so is horticultural sand. Avoid “contractor’s sand” which will contain fine dust, silt, clay and other minerals. Never use beach sand or limestone based sand. The salt content will harm the plants. The ratio of the mix is not critical, 1 part peat with 1 part sand works well for most carnivorous plants. Flytraps prefer a bit more sand, and nepenthes prefer much more peat. Use plastic pots, as terra cotta pots will leach out minerals over time and stress your plants.
Explanation:
Kayo na Po bahala magpaigsi
Answer:
A simple answer: Carnivores don't eat plants only flesh. So they would not need soil. But it would be hard for Carnivores to get energy because they get energy indirectly from the animals (herbivores) that they eat. How do they get the energy from a herbivore you might ask. Herbivores eat only plants and that gives the herbivore the plant's energy; but if the herbivore gets eaten, it is indirectly transferred into the Carnivore. Hope this helped!!
Carnivore = only feeds on flesh
Herbivore = eats only plants
Omnivore = eats plants and animals/flesh
pls answer the following question for me
Answers
1. and C.
Terrycot is a fiber that is made by mixing two fibers. Terrycot is a blended fabric made of terylene and cotton. It has better absorbing power as compared to Terylene. Nylon and terylene are produced through condensation polymeriztation.
Hope it helps...
Answer:
Explanation:
1-B
2-A
3-D
4-C
What is the phase of water at 1.0 atm and 50°C?
A. Liquid and gas
B. Solid
C. Liquid
D. Gas
Answers
Arrange the compounds in order of increasing entropy (S).
CH3OH(s)
CH3OH(l),
CH3OH(g),
CH3CH2OH(g)
CH3OH(s) > CH3OH (l) > CH3OH(g) > CH3CH2OH(g)
CH3OH(s) < CH3OH (l) < CH3OH(g) < CH3CH2OH(g)
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Answer: The given compounds are arranged in order of increasing entropy (S) as [tex]CH_{3}OH(s) < CH_{3}OH(l) < CH_{3}CH_{2}OH < CH_{3}OH(g)[/tex]
Explanation:
The degree of randomness present in a substance is called entropy.
This means that more is the number of molecules weakly held together and rapidly moving from one place to another more will be its entropy.
In solids, the molecules are held together strongly with each other. So, they will have least entropy.
In liquids, the molecules are a little loosely held together. So, they have more entropy than a solid substance.
In gases, the molecules are held by weak forces due to which they move rapidly from one place to another. Hence, gases have high entropy as compared to solids and liquids.
Also, more is the molecular mass of a gas less will be its rate of effusion. Hence, less will be its entropy.
[tex]Rate of effusion \propto \frac{1}{\sqrt{M}}[/tex]
where,
M = molecular mass
Thus, we can conclude that given compounds are arranged in order of increasing entropy (S) as [tex]CH_{3}OH(s) < CH_{3}OH(l) < CH_{3}CH_{2}OH < CH_{3}OH(g)[/tex]
ayudenme porfa doy corona xd
Answers
Answer:
e) 5
Explanation:
Because it's H
What is the value of Keq for the reaction expressed in scientific notation? 1.6 ´ 10–5 6.2 ´ 10–4 6.2 ´ 104 1.6 ´ 105
Answers
The question is incomplete, the complete question is:
Consider the reaction:
[tex]2NOCl\rightleftharpoons 2NO+Cl_2[/tex]
At equilibrium, the concentrations are as follows. [NOCl] = 1.4 × 10–2 M [NO] = 1.2 × 10–3 M [Cl2] = 2.2 × 10–3 M What is the value of Keq for the reaction expressed in scientific notation?
A) 1.6 × 10–5
B) 6.2 × 10–4
C) 6.2 × 10+4
D) 1.6 × 10+5
Answer: The correct option is A) [tex]1.6\times 10^{-5}[/tex]
Explanation:
The equilibrium constant is defined as the ratio of the concentration of products to the concentration of reactants raised to the power of the stoichiometric coefficient of each. It is represented by the term [tex]K_{eq}[/tex]
For the given chemical equation:
[tex]2NOCl\rightleftharpoons 2NO+Cl_2[/tex]
The expression for equilibrium constant will be:
[tex]K_{eq}=\frac{[NO]^2}{[Cl_2][NOCl]^2}[/tex]
Given values:
[tex][NO]=1.2\times 10^{-3}M[/tex]
[tex][Cl_2]=2.2\times 10^{-3}M[/tex]
[tex][NOCl]=1.4\times 10^{-2}M[/tex]
Putting values in above expression, we get:
[tex]K_{eq}=\frac{(1.2\times 10^{-3})^2\times (2.2\times 10^{-3})}{(1.4\times 10^{-2})^2}\\\\K_{eq}=1.6\times 10^{-5}[/tex]
Hence, the correct option is A) [tex]1.6\times 10^{-5}[/tex]
State the name(s) of the sub-atomic particle(s) that have/has a positive charge. Answer with the name of the particle(s) only.
A. Neurons
B. Protons
C. Electrons
Answers
Answer:
protons because they have the most positive charge
Can someone pls help I need this quick
Zinc has been added to dilute sulphuric acid. The two react together and a gas bubble forms. The gas that forms is hydrogen. Prove why the gas is hydrogen.
Answers
Answer:
Here's your answer
Explanation:
When we insert a burning matchstick near the mouth of gas jar the matchstick burns with a pop sound and produces a blue flame. This proves that the gas collected is hydrogen.
hope it helps
Which two of the following changes of state involve solids?
Select two (2) answers
A. melting
B. boiling
C. freezing
D. evaporating
Answers
Answer:
Answer is A... Melting and freezing
un estudiante introduce un corcho cuya densidad es 0.95 g/cm en cada uno de los liquidos que figura representa mejor la situacion
Answers
Answer:
La respuesta correcta es la opción A.
Explicación:
La densidad del corcho es 0.95g / cm3 por lo que se hundirá en la solución de acetona porque el corcho es más denso que la solución de acetona mientras que por otro lado, el corcho flotará en otros dos líquidos porque la densidad del corcho es menor que en otros dos líquidos o, en otras palabras, los dos líquidos son más densos que el corcho, por eso el corcho flotará en estos dos líquidos.
What would happen to the entropy in the reaction 203(9) ► 302(g)?
Answers
Answer:
Enthalpy and entropy. ... What would happen to the entropy in the reaction 2O3(g) 3O2(g)? It increases
What would happen to the entropy in the reaction 2O3(g) --> 3O2(g)?
It increases.
Edward is gathering physical evidence at the scene of a crime. He finds a fingerprint pressed into the wax of a candle. What type of fingerprint is this?
Answers
The type of fingerprint found at the crime scene in this scenario is referred to as plastic.
What is Plastic fingerprint?This is the of fingerprint which is three dimensional and can be easily seen with the human eye.
Plastic fingerprint can be made by pressing the finger on substances such as wax, paint etc.
Read more about Fingerprint here https://brainly.com/question/11165604
#SPJ1
Answer:
the answer would be molded I believe.
choices are Latent,patent, inadmissible molded,trace.
why is dilute tetraoxosulphate(VI) acid not suitable for preparing carbon monooxide
Answers
Answer: Because this does not dissolve in water - it forms a barrier on the surface of the unreacted CaCO3 which prevents any further reaction. A small volume of CO2 is produced , but this stops after a short time . Conclusion: H2SO4 cannot be used with CaCO3 to produce CO2 gas .
Explanation:
A boulder rests on a ledge 31.2 m above a lake. If it has 2.65 x 10 J of gravitational
potential energy relative to the lake surface, what is the mass of the boulder?
Answers
Answer:
This question is incomplete, the gravitational potential energy is 2.65 x 10^5 J
mass of the boulder = 866.7g
Explanation:
Potential energy (P.E) refers to the energy due to the position of a body. It can be calculated as follows:
P.E = m × g × h
Where;
m = mass of substance (g)
g = acceleration due to gravity (m/s²)
h = height (m)
According to the information provided in this question,
h = 31.2 m
g = 9.8m/s²
m = ?
P.E = 2.65 x 10^5 J
Using P.E = m × g × h
2.65 x 10^5 = m × 9.8 × 31.2
2.65 x 10^5 = 305.76m
265000 = 305.76m
m = 265000 ÷ 305.76
m = 866.69
mass of the boulder = 866.7g
