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Answer:

[tex]\mathbf{\mu_S = 12 }[/tex]; [tex]\text{Elroy can expect to roller skate and weight train, on average, 12 }[/tex][tex]\text{hours in a typical week.}[/tex]

Step-by-step explanation:

Given that:

The mean [tex]\mu_X = 5[/tex]

The mean [tex]\mu_Y = 7[/tex]

Where;

[tex]S= X+ Y[/tex]

[tex]\mu_S = \mu _X + \mu_Y \\ \\ \mu_S = 5+7 \\ \\ \mu_S = 12[/tex]

Thus;

[tex]\mathbf{\mu_S = 12 }[/tex];[tex]\text{ Elroy can expect to roller skate and weight train, on average, 12 }[/tex][tex]\text{hours in a typical week.}[/tex]

Answer:

C ♡♡

Step-by-step explanation:

jus took the quiz !!!

Answer:

33cm

Step-by-step explanation:

You need to add up all the sides

Answer:

x = 20

Step-by-step explanation:

19 < x < 25

x had to be higher than 19 but lower than 25

18 cant be the answer because it is less than 19

27 cant be the answer because it is higher than 25

that leaves 20, which is the right answer

19 < 20 < 25

Answer:

A

Step-by-step explanation:

(y-5) / (7-5) = (x-1) / (2-1)

(y-5) / 2 = x-1

y-5 = 2x -2

y = 2x +3

Answer:

90$

Step-by-step explanation:

X(40%) = 36$

X(40/100) =36

40X = 3600

X = 90$

(recheck: 90$ x 40%= 36$)

Answer:

Step-by-step explanation:

B = 2×10⁸

A = 3×10⁸

9514 1404 393

Answer:

  10.5

Step-by-step explanation:

Corresponding sides of similar triangles are proportional, so ...

  ZX/ZY = CA/CB

  ZX = Zy(CA/CB) = 14(3/4)

  ZX = 10.5

Answer:

[tex]A' = (0,20)[/tex]

[tex]B' = (16,12)[/tex]

[tex]C' = (8,4)[/tex]

Step-by-step explanation:

Given

[tex]A = (0,10)[/tex]

[tex]B =(8,6)[/tex]

[tex]C=(4,2)[/tex]

[tex]k = 2[/tex] --- scale factor

Required

The coordinates of A'B'C'

This is calculated as thus:

[tex]A'B'C' = ABC * k[/tex]

So, we have:

[tex]A' = (0,10) * 2[/tex]

[tex]A' = (0,20)[/tex]

[tex]B' = (8,6) * 2[/tex]

[tex]B' = (16,12)[/tex]

[tex]C' = (4,2)*2[/tex]

[tex]C' = (8,4)[/tex]

9514 1404 393

Answer:

  282.74 units³

Step-by-step explanation:

Put the given dimensions in the volume formula and do the arithmetic.

  V = πr²h

  V = 3.14159(3²)(10) ≈ 282.74 . . . units³

Answer:

p = 16.8

[tex] r \geqslant 5.5[/tex]

Step-by-step explanation:

12)

p + 2.1 = 18.9

p = 18.9 - 2.1

p = 16.8

13)

[tex]r \geqslant 5.5[/tex]

Answer:

∠x = 117°

Step-by-step explanation:

supplement of ∠101° = 79°

all triangle interior angles add up to 180°

180° - 79° - 38° = 63°

the supplementary angle to 63° is 117°

Answer:

8

Step-by-step explanation:

y = (10x^2 + 3x^4)/ 2x^2

where x is not equal to 0

(20x + 12x)/4x

32x / 4x

= 8

Answer:

b

Step-by-step explanation:

Answer:

3 units to the right of -5

Step-by-step explanation:

Answer:

she would be able to buy 6.6

Answer:

its 6.6

Step-by-step explanation:

cause i did that already

Answer:

h= -21.2

Step-by-step explanation:

Subtract 10.6 from both sides to isolate the h

Now lets check the answer

-21.2 + 10.6 = -10.6

-10.6 = -10.6 ✅

I hope this helps!

Answer:

No a rhombus is not a rectangle

Step-by-step explanation:

Answer:

37

Step-by-step explanation:

Answer:

16

Step-by-step explanation:

Hope you pass good luck to you!

Answer:

this is a wild guess but  10.

Step-by-step explanation:

Not sure if you're allowed to do this but i added the x's

7x+3x= 10x

   10x+20.

I then subtracted 10 by both sides. That leaves me with 10.

  x =10

 this is a guess i apologize if it's wrong

Answer:

BD = 4

Step-by-step explanation:

∆BAD is congruent to ∆CAD based on the AAS Congruence Theorem.

Therefore:

BD = CD

3x + 1 = 5x - 1 (substitution)

Collect like terms

3x - 5x = -1 - 1

-2x = -2

Divide both sides by -2

x = -2/-2

x = 1

✔️BD = 3x + 1

Plug in the value of x

BD = 3(1) + 1

BD = 3 + 1

BD = 4

Answer:

Exercise (a)

The work done in pulling the rope to the top of the building is 750 lb·ft

Exercise (b)

The work done in pulling half the rope to the top of the building is 562.5 lb·ft

Step-by-step explanation:

Exercise (a)

The given parameters of the rope are;

The length of the rope = 50 ft.

The weight of the rope = 0.6 lb/ft.

The height of the building = 120 ft.

We have;

The work done in pulling a piece of the upper portion, ΔW₁ is given as follows;

ΔW₁ = 0.6Δx·x

The work done for the second half, ΔW₂, is given as follows;

ΔW₂ = 0.6Δx·x + 25×0.6 × 25 =  0.6Δx·x + 375

The total work done, W = W₁ + W₂ = 0.6Δx·x + 0.6Δx·x + 375

∴ We have;

W = [tex]2 \times \int\limits^{25}_0 {0.6 \cdot x} \, dx + 375= 2 \times \left[0.6 \cdot \dfrac{x^2}{2} \right]^{25}_0 + 375 = 750[/tex]

The work done in pulling the rope to the top of the building, W = 750 lb·ft

Exercise (b)

The work done in pulling half the rope is given by W₂ as follows;

[tex]W_2 = \int\limits^{25}_0 {0.6 \cdot x} \, dx + 375= \left[0.6 \cdot \dfrac{x^2}{2} \right]^{25}_0 + 375 = 562.5[/tex]

The work done in pulling half the rope, W₂ = 562.5 lb·ft

Answer:

[tex]\huge\boxed{\tt{x = 24, y = 17}}[/tex]

Step-by-step explanation:

Let the greater number be x and the smaller number be y.

So,

Condition # 1:

x - y = 7 --------------(1)

Condition # 2:

3x = 72 --------------(2)

Taking Eq. (2)

3x = 72

Divide both sides by 3

x = 72 / 3

x = 24

Now, Put x = 24 in Eq. (1)

24 - y = 7

Subtract 24 to both sides

-y = 7 - 24

-y = -17

y = 17

[tex]\rule[225]{225}{2}[/tex]

Hope this helped!

Answer:

4

This figure has 4 lines of symmetry.

Answer:

48000

Step-by-step explanation:

multiply the mass value by 32000

Answer:

48000

Step-by-step explanation:

.

Answer:

Step-by-step explanation:

vertex:(h,k)

therefore

vertex:(-1,4)

axis of symmetry:x=h

therefore

axis of symmetry:x=-1

vertex form of quadratic equation:

therefore

it's to notice that we don't know what a is

therefore we have to figure it out

the graph crosses y-asix at (0,3) coordinates

so,

3=a(0+1)²+4

simplify parentheses:

[tex]3 = a(1 {)}^{2} + 4[/tex]

simplify exponent:

[tex]3 = a + 4[/tex]

therefore

[tex]a = - 1[/tex]

our vertex form of quadratic equation is

let's simplify it to standard form

simplify square:

[tex]y = - ( {x}^{2} + 2x + 1) + 4[/tex]

simplify parentheses:

[tex]y = - {x}^{2} - 2x - 1 + 4[/tex]

simplify addition:

[tex]y = - {x}^{2} - 2x + 3[/tex]

therefore our answer is D)y=-x²-2x+3

the domain of the function

[tex]x\in \mathbb{R}[/tex]

and the range of the function is

[tex]y\leqslant 4[/tex]

zeroes of the function:

[tex] - {x}^{2} - 2x + 3 = 0[/tex]

[tex] \sf divide \: both \: sides \: by \: - 1[/tex]

[tex] {x}^{2} + 2x - 3 = 0[/tex]

[tex] \implies \: {x}^{2} + 3x - x + 3 = 0[/tex]

factor out x and -1 respectively:

[tex] \sf \implies \: x(x + 3) - 1(x + 3 )= 0[/tex]

group:

[tex] \implies \: (x - 1)(x + 3) = 0[/tex]

therefore

[tex] \begin{cases} x_{1} = 1 \\ x_{2} = - 3\end{cases}[/tex]

Answer:

x=66

Step-by-step explanation:

Hello There!

∠BAC ≅ ∠CDB because in a parallelogram opposite angles are congruent

So all we have to do is solver for ∠BAC

Remember the sum of the triangles angles is 180 so to find ∠BAC

we subtract the given angles (83 and 31) from  180

180-83-31=66

so ∠BAC = 66

like stated before

∠BAC≅∠BDC so if ∠BAC = 66 then x also equals 66

Answer:

x = 66

Step-by-step explanation:

x = 66 degree