Help Please!!!!!!!!!!

Answer:

Area of cardboard required = 468 cm²

Step-by-step explanation:

Area of the cardboard required = Surface area of the triangular prism

Surface area of the triangular prism = Area of the lateral sides + Area of the triangular sides

Area of the one triangular side = [tex]\frac{1}{2}(\text{Base)}(\text{Height})[/tex]

                                                    = [tex]\frac{1}{2}(12)(9)[/tex]

                                                    = 54 cm²

Area of lateral sides = Perimeter of the triangular base × Height

Perimeter of the triangular base = 9 + 12 + 15

                                                     = 36 cm

Now area of the lateral sides = (36) × 10

                                                = 360 cm²

Surface area of the prism = 360 + 2(54)

                                          = 360 + 108

                                          = 468 cm²

Therefore, area of cardboard required for each box = 468 cm²

Answer:

A right circular cone

Step-by-step explanation:

Step-by-step explanation:

f(g(x))

f(x-1)

(x-1)^2

x^2 -2x + 1

Step-by-step explanation:

120=2/5t

120×5/2=t

t=600/2

t=300

hope it helps u

Answer:

here you go............

Step-by-step explanation:

I hope it helped

Answer:

See Annex ( Tree diagram )

Step-by-step explanation:

1) Attached

2) Probability of the second ball is yellow is

P(2nd ball is yellow ) = Probability 2nd ball s yellow (if the first one was black) + Probability 2nd ball s yellow (if the first one was Yellow)

P(2nd ball is yellow ) = 0,204 + 0,045

P(2nd ball is yellow ) = 0,249

Answer:

The minutes wouldn't it be hours?

Step-by-step explanation:

Answer:

53:240

Step-by-step explanation:

Turn the hours into minutes since the minutes can't change to hours.

Answer: B. 183 cm^3

V = pi r^2 h/3

V = pi (5^2) (7/3)

V = pi (25) (2.33)

V = 183

Answer:

B.183 [tex]cm^{3}[/tex]

Step-by-step explanation:

Volume of cone is [tex]V=\pi r^{2} \frac{h}{3}[/tex]

where h=7 and r=5 (because r=d/2, where d=10)

V=[tex]5^{2}\frac{7}{3}\pi[/tex]

V=25·[tex]\frac{7}{3} \pi[/tex]

V=175/3[tex]\pi[/tex]

V=183.2595715 or 183 [tex]cm^{3}[/tex]

Answer:

a) The total engine volume is 30.3265 in³

b) the mass of air contained in the engine is 0.00129 lbm

c) The efficiency of the engine is 55.6%

Step-by-step explanation:

Given the data in the question;

The configuration is in line with four-stroke, four-cylinder engine.

Bore ( d ) = 3.17 in

Stroke ( L ) = 3.48 in

compression ratio ( r ) = 10.6 : 1

First, we calculate the swept Volume V₁ = π/4 × d²L

we substitute

V₁ = π/4 × (3.17 )² × (3.48) = 27.4655 in³

Now, Compression Ration; r = Vs + Vc / Vc

r = (V₁ + V₂) / V₂

we substitute

10.6 = (27.4655 + V₂) / V₂

10.6V₂ = 27.4655 + V₂

10.6V₂ - V₂ = 27.4655

9.6V₂ = 27.4655

V₂ = 2.861 in³

So

a) total engine volume

[tex]V_{BDC[/tex] = V₁ + V₂

we substitute

[tex]V_{BDC[/tex] = 27.4655 in³ + 2.861 in³

[tex]V_{BDC[/tex] = 27.4655 in³ + 2.861 in³

[tex]V_{BDC[/tex] = 30.3265 in³

Therefore, The total engine volume is 30.3265 in³

b) The mass of air

given that; T = 540°R, P = 14.7 psia

we know that; PV = mRT   { R is constant }

we solve for m

m = PV / RT

we substitute

m = (14.7 × 30.3265)  / ( 0.3704 × 1728 )540

m = 445.79955 / 345627.648

m = 0.00129 lbm

Therefore, the mass of air contained in the engine is 0.00129 lbm

c) The efficiency

from table { properties of air}

At 540°R; u₁ = 92.04 BTu/lbm, u[tex]_r[/tex]₁ = 144.32

Now process 1 - 2 ( Isentropic )   u[tex]_r[/tex]₁ / u[tex]_r[/tex]₂  = V₁/V₁ = r

so,  u[tex]_r[/tex]₁ / u[tex]_r[/tex]₂ = r

144.32  / u[tex]_r[/tex]₂ = 10.6

u[tex]_r[/tex]₂ = 144.32/10.6

u[tex]_r[/tex]₂ = 13.61

Thus, at u[tex]_r[/tex]₂ = 13.61, u₂ = 235 BTU/lbm, T₂ = 1340°R

Now, we know that;

P₁V₁/T₁ = P₂V₂/T₂  ⇒ (P₁/V₁)r = P₂/T₂

⇒ ( 14.7 / 540 )10.6 = P₂/1340

P₂ = 386.664 psia  

process 2 - 3; constant volume heat addition;

Now, At T₃ = 3600°R, u₃ = 721.44 BTU/lbm, u[tex]_r[/tex]₃ = 0.6449

so, [tex]q_{in[/tex] =  u₃ -  u₂

we substitute

so, [tex]q_{in[/tex] =  721.44  -  235  = 486.44 BTU/lbm

Next, process 3 - 4; Isentropic  

u[tex]_r[/tex]₄/u[tex]_r[/tex]₃ = V₄/V₃ = r

u[tex]_r[/tex]₄ / 0.6449  = 10.6

u[tex]_r[/tex]₄ = 6.8359

At u[tex]_r[/tex]₄ = 6.8359; u₄ = 308 BTU/lbm

∴

Heat Rejection [tex]q_{out[/tex] = u₄ - u₁ = 308 - 92.04 = 215.96 BTU/lbm

so, [tex]W_{net[/tex] = [tex]q_{in[/tex] - [tex]q_{out[/tex]

[tex]W_{net[/tex] = 486.44 - 215.96

[tex]W_{net[/tex] = 270.48 BTU/lbm

so the efficiency; η[tex]_{thermal[/tex] = ([tex]W_{net[/tex] / [tex]q_{in[/tex] ) × 100%

η[tex]_{thermal[/tex] = ( 270.48 / 486.44  ) × 100%

η[tex]_{thermal[/tex] = ( 0.55604  ) × 100%    

η[tex]_{thermal[/tex] = 55.6%

Therefore, The efficiency of the engine is 55.6%

Answer:

umm to me its 2--%456

Step-by-step explanation:

Answer:

A. I

Step-by-step explanation:

The other person is wrong and I took the test

1.  C

2.  A

3. B

Hope This Helped!

(Brainliest will be appreciated)

Answer:

1- distributive property

2- Subtraction.

3- -3/2

Step-by-step explanation:

1- When the given equation is given, the 4 outside the parenthesis multiplied with the variable x and number 1. This process of multiplication between a number and all the variables in parenthesis is called known as the distributive property.

2- As it was adding with 2x on the left side when it passed with Inverse Operation to the right side, its sign change to subtraction.

3- The 2 passes to the other side of the equation with Inverse Operation, therefore dividing. The -3, otherwise, as it didn't move to the other side, has no effect and remains the negative.

Answer:

Step-by-step explanation:

Use SOH CAH TOA to recall how the trig functions fit on a triangle

SOH: Sin(Ф)= Opp / Hyp

CAH: Cos(Ф)= Adj / Hyp

TOA: Tan(Ф) = Opp / Adj

Let's use CAH  1st  , on the Lenovo building,  b/c we  have they Hypotenuse (Hyp)  and an angle and we want to know the other side of the Lenovo building

Cos(30) = x/294

294*Cos(30) = x

254.611 = x

Sin(30) = y / 294

294*Sin(30) = y

147 = y

perimeter = 147+254.611+294

perimeter Lenovo = 695.611 feet

For Asus building

hyp = sqrt [ ( 144.5*[tex]\sqrt{2}[/tex])^2 +  144.5*[tex]\sqrt{2}[/tex])^2 )]

hyp = 289

perimeter = 289+144.5*[tex]\sqrt{2}[/tex]+144.5*[tex]\sqrt{2}[/tex]

perimeter Asus = 697.7077

The difference of the two buildings is

697.7077 -  695.611 =2.09671 feet

the difference is 2.10 feet ( rounded to nearest 100th)

Answer:

x5

Step-by-step explanation:

Answer: C.

Step-by-step explanation:

EDGE 2023

Answer: The area of rectangle U is 12.

Step-by-step explanation:

We can solve this by finding the ratio of the two rectangle lengths which are given. We see that the ratio is 2/1. Now, from here you have two options to go. The first option is dividing 48 / 8 which is 6. Now you divide 6 / 2, because 2 is the scale factor. 6 / 2 = 3. 4 * 3 = 12, giving us the area of 12. Another way to do it is since the scale factor is 2, the ratio of the areas are the scale factor squared. 48 / 2 ^ 2 = 48 / 4 = 12.

Answer:

The answer is 7/20 miles.

Step-by-step explanation:

Just multiply 7/6 x 2/5, then you have the answer

Answer:

ima say its a that is my lucky guess im sorry if you get it wrong

Answer:

[tex]13[/tex]

Step-by-step explanation:

let the unknown number be x

[tex]x + ( - 9) = 4 \\ x - 9 = 4 \\ x = 4 + 9 \\ x = 13[/tex]

hope this helps you.

Can I have the brainliest please?

Have a nice day!

Answer:

yhe picture is blur.

Step-by-step explanation:

Answer:

The rectangle is 5 inches long by 19 inches wide.

Step-by-step explanation:

Let's start by listing what we know:

Let's represent the width with "w" and length with "l", and make a system of equations based on what we know.

[tex]\left \{ {{2w + 2l = 48} \atop {w = 3l + 4}} \right.[/tex]

Now, let's solve the system of equations using substitution:

[tex]2w + 2l = 48[/tex]

[tex]2 (3l + 4) + 2l = 48[/tex]

[tex]6l + 8 + 2l = 48[/tex]

[tex]8l + 8 = 48[/tex]

[tex]8l = 40[/tex]

[tex]l = 5[/tex]

The length of the rectangle is 5 inches.

Now, let's use this to solve for the width.

[tex]w = 3l + 4[/tex]

[tex]w = 3(5) + 4[/tex]

[tex]w = 15 + 4[/tex]

[tex]w = 19[/tex]

The width of the rectangle is 19 inches.

Let's check our work:

[tex]2w + 2l = 48[/tex]

[tex]2(19) + 2(5) = 48[/tex]

[tex]38 + 10 = 48[/tex]

[tex]48 = 48[/tex]

The results match, so our answer is correct.

The rectangle is 5 inches long by 19 inches wide.

[tex]\huge{\textbf{\textsf{{\color{navy}{An}}{\purple{sw}}{\pink{er}} {\color{pink}{:}}}}}[/tex]

C. 4.

Answer:

(1,-7)

Step-by-step explanation:

1) (5,-4). 4 units to the left will be (1,-4)

2) (1,-4). 3 units down will be (1,-7)

Answer:

70  cm

Step-by-step explanation:

Answer:

70 cubic feet

Step-by-step explanation:

First step is to multiply the 2 feet deep by th 5 feet wide. which is also written as:

2*5=10

Next multiply 10 by the 7 feet tall. You can write this like:

10*7=70

70 cubic feet is the answer

Answer:

|x-8| = 7

Step-by-step explanation:

The following equation would make x=15 when solved.

|x-8| = 7

This is because if we substitute 15 for x we would have to subtract 8 from 15 which would give us 7 and the absolute value of 7 is 7 which would ultimately make the equation true.

Answer:

D.

Step-by-step explanation:

just done the assignment

Linear regression line is a algebraic model to show the relationship between the two models by putting the value of the one variable to get the value of other.. For every 1 pound of nitrogen added to the field, the amount of corn yielded increases by 0.43 bushels. Therefore the option B is the correct option.

The equation of the experiment to know the relationship between the amount of nitrogen added to a cornfield and the number of bushels of corn produced is,

[tex]y=0.43x+28.5[/tex]

Linear regression line is a algebraic model to show the relationship between the two models by putting the value of the one variable to get the value of other.

Linear regression line can be represent as,

[tex]y=Ax+B[/tex]

Here x is the explanatory variable and y is the dependent variable. A is the slope of the line and B is the intercept.

In the given equation there are two variable given.

Variable x represent the amount of nitrogen added, and the variable y, represents the number of bushels of corn produced.

As putting the value of x the y increases with value of number 0.43. Thus as we are increasing the value of the nitrogen with unit 1 the number of bushels of corn produced is increased by unit 0.43.

Hence for every 1 pound of nitrogen added to the field, the amount of corn yielded increases by 0.43 bushels. Therefore the option B is the correct option.

Learn more about the linear regression here;

https://brainly.com/question/25311696

Answer:

(0.806, 0.839)

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.

[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

In which

z is the zscore that has a pvalue of [tex]1 - \frac{\alpha}{2}[/tex].

Suppose we take a poll (random sample) of 3653 students classified as Juniors and find that 3005 of them believe that they will find a job immediately after graduation.

This means that [tex]n = 3653, \pi = \frac{3005}{3653} = 0.823[/tex]

99% confidence level

So [tex]\alpha = 0.01[/tex], z is the value of Z that has a pvalue of [tex]1 - \frac{0.01}{2} = 0.995[/tex], so [tex]Z = 2.575[/tex].

The lower limit of this interval is:

[tex]\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.823 - 2.575\sqrt{\frac{0.823*0.177}{3653}} = 0.806[/tex]

The upper limit of this interval is:

[tex]\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.823 + 2.575\sqrt{\frac{0.823*0.177}{3653}} = 0.839[/tex]

The answer is (0.806, 0.839)

answer:

2,3

2,2

2,1

1,2

1,1

1,3

Those are the possible choices of selecting apples and pears.

If she randomly selects 1 apple and 1 pear then the possible choices are 6.

It is a branch of mathematics that deals with the occurrence of a random event.

Given that, Mercedes can select from 2 types of apples and 3 types of pears.

Mercedes randomly selects 1 apple and 1 pear.

We need to find the number of possible choices does she have.

(2,3)(2,2)(2,1),(1,2)(1,1)(1,3)

The probability of choosing 1 apple from 2 apples will be 1/2.

The probability of choosing 1 pear from 3 pears will be 1/3.

Now the probability of choosing a apple and a pear will be

1/2×1/3

1/6

Hence, If she randomly selects 1 apple and 1 pear then the possible choices are 6.

To learn more on probability click:

https://brainly.com/question/11234923

#SPJ2

Answer:

Answer:

d

Step-by-step explanation:

Answer:

its d

Step-by-step explanation: