HELPP! You will get 15 points!

AD is an angle bisector of

Answer:

[tex]y = -4x^2 + 8x + 192[/tex]

Step-by-step explanation:

Hi there!

Standard form: [tex]y=ax^2+bx+c[/tex]

[tex]y = -4(x + 6)(x - 8)[/tex]

Use the distributive property to multiply (x+6) and (x-8)

[tex]y = -4(x(x - 8) + 6(x - 8))\\y = -4(x^2 - 8x + 6x - 48)\\y = -4(x^2 - 2x - 48)[/tex]

Multiply the parentheses by -4

[tex]y = -4x^2 + 8x + 192[/tex]

I hope this helps!

Answer:

the odd graph represented is

y

6

4

1st graph represents the odd function because it  is symmetric about origin

Graph is a mathematical representation of a network and it describes the relationship between lines and points.

For a function f to be odd, it should satisfy the following equation:

f(-x) = -f(x)

For a function f to be even

f(-x)=f(x)

The graph of an odd function will always be symmetric about the origin.

By observing the graphs we can say that:

1st graph is symmetric about origin and hence it is an odd function.

2nd graph is symmetric about y-axis.Hence it is not an odd function.

Hence, 1st graph represents the odd function because it  is symmetric about origin

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Answer:

1144

Step-by-step explanation:

100 + 98 + 96 +.... + 78+76 =

(12-0)/2 (176)  

(6.5) (176) = 1144

The sum of the series will be 1068.

We have the following expression -

[tex]\sum_{i=0}^{12} 100 - 2i[/tex]

We have to rewrite the series as the sum.

A series in mathematics is the sum of a list of numbers that are generated according to some pattern.

We have the following expression -

[tex]\sum_{i=0}^{12} 100 - 2i[/tex]

The terms of this series can be calculated by calculating the value of the function at different values of i.

The series is as follows -

100 + 98 + 96 +.... + 78+76

This is an arithmetic progression with a = 100 and d = - 2 and n = 12. The sum of this series is -

[tex]S = \frac{n}{2} \times {2a + (n-1)d}[/tex]

S = [tex]\frac{12}{2} [{2 \times 100 + (12 -1)(-2)] = 6[200+ 11 \times -2] = 6[200 -22][/tex]

S = 6 x 178 = 1068

The sum of the series will be 1068.

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9514 1404 393

Answer:

  m = 2

  n = 3

Step-by-step explanation:

1125 = 9·125 = 3^2 · 5^3

  m = 2

  n = 3

_____

Additional comment

Using divisibility rules, you can keep dividing by the obvious factors until the quotient is 1.

  1125/5 = 225

  225/5 = 45

  45/5 = 9

  9/3 = 3

  3/3 = 1 . . . . . . 5 is a factor 3 times; 3 is a factor 2 times.

Answer:

2.4

Step-by-step explanation:

Took the assignment

Answer:

2.4 seconds is the correct answer.

Step-by-step explanation:

Just completed it.

Answer:

8 Units, let me know if you didn't understand anything.  

Step-by-step explanation:

Translation is the simple movement of just left, right, up or down.  when dealing with the absolute value function here are the transformations.

A|B(x - C)| + D where A is the vertical stretch that multiplies all y values by A save where y=D.  B is the horizontal shrink, so you divide all x  values by B except for where x=C.  C is the horizontal shift, which is a translation.  C makes ALL points on the graph move to the right by C or if C is negative it moves them to the left.  it could also look like |x + C|.  keep in mind, +C is actually -C because - -C = C.  D shifts up and down, so it is also a translation.  if D is positive it moves up and if D is negative it moves down.

Nowthe only transformation in your problem is -8, which is a horizontal shift to the right.  so the graph moves 8 to the right.  There is your answer, 8 units.

Answer:

P = 64 meters

Step-by-step explanation:

P = 2(l+w)

l = 14 and w = 18

P = 2(14+18)

P = 2( 32)

P = 64 meters

Perimeter of rectangle = 2 ( L + B )

Perimeter of rectangle = 2 ( 14 + 18 )

Perimeter of rectangle = 2 ( 32 )

Perimeter of rectangle = 64 meters.

Answer:12kg

Step-by-step explanation:

8kg+4kg=12kg

the 4kg came from the half block

se um bloco pesa 8 kg meio bloco pesa 4 kg então é só juntar 8+4=12

Answer:

y = -1/4x - 2

Step-by-step explanation:

y = -1/4x - 2

Answer: [tex]14.9^{\circ}[/tex]

Step-by-step explanation:

Given

Applied force is 9 lb to hold of 35 lb crate on a hill

Suppose the hill makes an angle of [tex]\theta[/tex] with horizontal

There will be two component of weights i.e. along and perpendicular to the hill

Only the component along the hill pulls the crate backwards

So,

[tex]\Rightarrow 35\sin \theta=9\\\\\Rightarrow \sin\theta =\dfrac{9}{35}\\\\\Rightarrow \theta =14.89^{\circ}\approx 14.9^{\circ}[/tex]

Answer:

Step-by-step explanation:

Victoria used : 170 g of butter for 250 g of flour.

So, 1 g of flour requires = 170/250 g of butter = 0.68 g of butter.

Victoria's daughter used: 340 g butter for 400 g flour

So, 1 g of flour requires =  340/400 g of butter = 0.85 g of butter

Thus, the cookies are not good made by the daughter as the butter is not in appropriate proportion.

9514 1404 393

Answer:

  26 minutes

Step-by-step explanation:

Let x represent the number of minutes used. The charges will be equal when ...

  18.75 +0.18x = 12.51 +0.42x

  6.24 = 0.24x . . . . . . . . . . . . . . . subtract 0.18x+12.51

  26 = x . . . . . . . . . . . . . . . divide by 0.24

A customer using 26 minutes will receive the same bill from either company.

Answer:

14/19

Step-by-step explanation:

Dividing fractions is the same as multiplying by the reciprocal:

-10/19 ÷ -5/7

-10/19 x -7/5

Multiply the numerators by each other, as well as the denominators:

70/95

Simplify by dividing both the numerator and denominator by 5:

= 14/19

So, the answer is 14/19

Step-by-step explanation:

sec⁴A + tan⁴A = 1 + (2tan²A/cos²A)

LHS = sec⁴A + tan⁴A

= (sec²A)² + (tan²A)² {using formula of a²+b²)

= (sec²A-tan²A) + 2tan²A.sec²A

= 1 + {2tan²A.(1/cos²A)}

= 1 + (2tan²A/cos²A)

Answer: [tex]V=3369.3ft^3[/tex]

Step-by-step explanation:

[tex]V=\frac{4}{3}\pi r^3\\V=\frac{4}{3}\pi (9.3)^3\\V=3369.3ft^3[/tex]

Step-by-step explanation:

We need to find thr range if

[tex] \frac{1}{ (|x| - x)} [/tex]

The absoulte value of something is positive.

So

[tex] \frac{1}{x - x} = \frac{1}{0} [/tex]

This function isn't possible so no range exist.

Answer:

D. linear; y = - 1/2x + 2

Step-by-step explanation:

As the values of x increase by 1, the values of y decrease by 0.5. This means that we have a negative linear relationship of 1/2. In other words, the slope is -1/2. Our y-intercept is 2 since when x = 0, y = 2. So, D is the correct choice.

Answer:

They sold 162 vanilla cones.

Step-by-step explanation:

429-105=324

324/2=162

162+105=267 (chocolate)

267(chocolate)+162(vanilla)=429(total)

Answer:

y = - 2x - 6

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]

with (x₁, y₁ ) = (- 5, 4) and (x₂, y₂ ) = (- 4, 2)

m = [tex]\frac{2-4}{-4-(-5)}[/tex] = [tex]\frac{-2}{-4+5}[/tex] = [tex]\frac{-2}{1}[/tex] = - 2 , then

y = - 2x + c ← is the partial equation

To find c substitute either of the 2 points into the partial equation

Using (- 4, 2 ) , then

2 = 8 + c ⇒ c = 2 - 8 = - 6

y = - 2x - 6 ← equation of line

Step-by-step explanation:

sorry I couldn't draw it properly but that is it...

I hope it helps

Answer:

Step-by-step explanation:

Draw a line and divide it into 13 equal parts.

Mark 0 in the middle of number line.  

Mark negative numbers to the left of zero and mark positive numbers to the right of zero.

The question is incomplete. The complete question is :

A school in Delhi has its own flag, which is rectangular and divided into 4 rows and 6 columns. The word ‘SCHOOL’ is inscribed in the first row, ‘FLAG’ in the fourth row, and a  purple colored rhombus is in the middle, as shown in the given figure.

Based on this picture of the school flag, answer the following questions:  

(a) What fraction of the flag has the purple rhombus?

Solution :

From the figure, the total number of squares in the flag of 4 rows and 6 columns are : 4 x 6 = 24 blocks

The purple colored rhombus is made on the half of the 4 blocks.

i.e. [tex]$\frac{1}{2} \times 4 = 2\ \text{blocks}$[/tex]

Therefore, the fraction of the flag that has the purple rhombus is :

[tex]$=\frac{2}{24}$[/tex]

[tex]$=\frac{1}{12}$[/tex]

Answer:

Hello,

Answer A

Step-by-step explanation:

[tex]a_1=-6\\\\a_2=a_1*(\dfrac{1}{4} )^1\\\\a_3=a_2*(\dfrac{1}{4} )^1=a_1*(\dfrac{1}{4} )^2\\\\\\\\a_n=a_1*(\dfrac{1}{4} )^{n-1}\\\\Answer\ A\\[/tex]

Answer:

The right solution is "0.5545".

Step-by-step explanation:

According to the question,

The probability of having 6 or 7 males will be:

= [tex]P(6 \ males)+ P(7 \ males)[/tex]

= [tex]\frac{15_C_6\times 13_C_6}{28_C_{12}} + \frac{15_C_7\times 13_C_5}{28_C_{12}}[/tex]

= [tex]\frac{5005\times 1716+6435\times 1287}{30421755}[/tex]

= [tex]\frac{16870425}{30421755}[/tex]

= [tex]0.5545[/tex]

Answer:

ratio

Step-by-step explanation:

by using a conversion factor and a fraction, a ratio can be created to convert one unit to another.

Answer:

4’3

Step-by-step explanation:

Took test

Answer:

4’3

Step-by-step explanation:

Answer: Advertisement?

Do I need an explanation? : Y e s  I  d o

Given:

Brown’s time for running a mile in gym class = 9.9 minutes

Ray’s time for running a mile in gym class = 9.47 minutes

Malcolm’s time for running a mile in gym class = 9.76 minutes

To find:

Who ran the mile in less time?

Solution:

It is given that the time taken by Brown, Ray and Malcolm to cover a mile are 9.9 minutes, 9.47 minutes and 9.76 minutes respectively.

9.47 < 9.76 < 9.9

Since, 9.47 minutes is the lowest time, therefore Ray can run a mile in less time.

[tex]3x - 8 = 4x - 17 \\ \\ \sf \longmapsto \: 3x + 4x = - 17 + 8 \\ \\ \sf \longmapsto \: 7x = - 9 \\ \\ \sf \longmapsto \: x = \frac{ - 9}{7} [/tex]

Answer:

D'E' be parallel to the original line

Step-by-step explanation:

Given

[tex]\triangle ABC[/tex]

Line [tex]DE[/tex]

[tex]k = 3[/tex] -- scale factor

Required

The relationship between [tex]DE[/tex] and [tex]D'E'[/tex]

When [tex]\triangle ABC[/tex] is dilated by a scale factor of 3, [tex]\triangle A'B'C'[/tex] will be three times as big as [tex]\triangle ABC[/tex].

Also:

Line [tex]D'E'[/tex] will be three times as long as [tex]DE[/tex]

Since no further transformation is done on [tex]\triangle ABC[/tex] and line [tex]DE[/tex], then [tex]D'E'[/tex] will be parallel to [tex]DE[/tex]