How can you use what you know about 5(2) to find 5(-2)?
Please help

Answer:

Step-by-step explanation:

We know

[tex] \\ \sf \longmapsto \: new \: length = length + increased \: length \\ \\ \sf \longmapsto \: new \: length = 11.4 + 2.25 \\ \\ \sf \longmapsto \: new \: length = 13.65in[/tex]

Answer:

(-3,-6) and (-3,2)

Step-by-step explanation:

A line with an undefined slope is vertical. In this case it must have x coordinates equal to -3

Answer:

B.

Step-by-step explanation:

Other equations don't have any value of x.

Answer:

Because if you see.. The component of x will get canceled in each of the other 3 options.. ( 2x - 2x) which means no solution.. In option B.. 2x + 2x will give 4x..= 31-31 = 0..

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Hope it helps...

Have a great day!!

Answer:

( - 7 + √17 ) / 2, ( - 7 - √17 ) / 2

Step-by-step explanation:

x^2 = - 7x - 8

x^2 + 7x + 8 = 0

Here,

a = 1

b = 7

c = 8

D = b^2 - 4ac

= 7^2 - 4 ( 1 ) ( 8 )

= 49 - 32

D = 17

x = - b ± √D / 2a

= - 7 ± √17 / 2 ( 1 )

x = ( - 7 + √17 ) / 2, ( - 7 - √17 ) / 2

Given:

Diameter of the tennis ball = 14 inches.

Three tennis balls are fit in a cylindrical tennis ball cane.

To find:

The volume of air left between the balls and the cane​.

Solution:

Diameter of the tennis ball = 14 inches.

Radius of the tennis ball = 7 inches

Radius of tennis ball is equal to radius of cane. So,

Radius of the cane = 7 inches

Height of cane is:

[tex]3\times 14=42[/tex] inches

Volume of a ball is:

[tex]V_1=\dfrac{4}{3}\pi r^3[/tex]

Where, r is the radius of the ball.

So, the volume of 3 ball is:

[tex]V_2=3\times V_1[/tex]

[tex]V_2=3\times \dfrac{4}{3}\times \dfrac{22}{7}\times (7)^3[/tex]

[tex]V_2=4312[/tex]

Volume of the cane is:

[tex]V_3=\pi r^2h[/tex]

Where, r is the radius of the cane and h is the height of the cane.

[tex]V_3=\dfrac{22}{7}\times (7)^2\times 42[/tex]

[tex]V_3=6468[/tex]

Now, the volume of air left between the balls and the cane​ is:

[tex]V=V_3-V_2[/tex]

[tex]V=6468-4312[/tex]

[tex]V=2156[/tex]

Therefore, the volume of air left between the balls and the cane​ is 2156 cubic inches.

Answer:

bka bla bla bla sorry I newbie

tienees que fijartelos extrreemos

Answer:

Step-by-step explanation:

If we are looking for how long it will take the level to be less than or equal to 64 cups, we are solving an inequality as opposed to an equation. It would look like this:

-.414t + 129.549 ≤ 64  We subtract 129.549 from both sides to get

-.414t ≤ -65.549 and then divide by -.414. But because we are dividing by a negative number we need to change the way the inequality is pointing:

t ≥ 158.3 minutes which is about 2.6 hours

Answer:

t ≥ 158.33, or rounded, t ≥ 160.

Explanation:

The equation we're given is

W = -0.414t + 129.549, which an be written as

-0.414t + 129.549 = W.

We are asked to find the amount of time it would take for the water level to be less than or equal to 64 cups.  Plugging this information in, we have:

-0.414t + 129.549 ≤ 64

To solve this, we first cancel 129.549 by subtracting from both sides:

-0.414t + 129.549 - 129.549 ≤ 64 - 129.549

-0.414t ≤ -65.549

Now divide both sides by -0.414:

-0.414t/-0.414 ≤ -65.549/-0.414

t ≥ 158.33

(When we multiply or divide both sides of an inequality by a negative number, we must flip the inequality symbol)

Answer:

60

Step-by-step explanation:

To get the value of x;

3x:90

(90/3) = 30

x = 30

To get the value of 2x;

(2×X);

2 × 30

=60

Answer:

I don't know how to do please let me I will try solve the question

Answer:

A & D

First and last

Step-by-step explanation:

Answer:

19:1

Step-by-step explanation:

There are 10000 headlights. If 5% are defective, then 500 are defective. Since we took that 500 out, we get 9500 good headlights. The ratio is 9500:500 or 19:1

The ratio of defective headlights to non-defective headlights will be 19:1.

The Percentage is defined as representing any number with respect to 100. It is denoted by the sign %. The percentage stands for "out of 100." Imagine any measurement or object being divided into 100 equal bits.

In mathematics, ratios are used to determine the relationship between two numbers it indicates how many times is one number to another number.

There are 10000 headlights. If 5% are defective, then 500 are defective. Since we took that 500 out, we get 9500 good headlights.

The ratio will be calculated as below:-

Ratio = 9500:500

Ratio = 19:1

Therefore, the ratio of defective headlights to non-defective headlights will be 19:1.

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Answer:

The last answer

Step-by-step explanation:

We can check

For example,

a5=-6×a4

a5=-6×(-216)

a5=1296

Answer:

1. Multiply by 3

2. Multiply by 1/3

Step-by-step explanation:

6x - 3y = 3

-2x + y = -14

1. In order to eliminate the x-terms, they would both have to equal the same number with opposite signs (positive and negative). Since we are only touching the second equation, how can we get from 2 to 6? We can multiply 2 by 3 to get to 6 (negative 6 in the end.) This would result as follows:

6x - 3y = 3

-6x + 3y = 42

2. In order to eliminate the y-terns through multiplying with the first equation, we have to figure out how to make 3y into 1y. We can do this by adding its reciprocal, 1/3. 1/3 × 3 = 1. This would result as follows:

2x - y = 1

x + y = 32 (1)

3x + 4y = 120 (2)

x = 8; y = 24

Step-by-step explanation:

Total students = 120

Number of groups = 32

If the number of three person groups = x

Number of four person groups = y

write a system of equations that models this situation

x + y = 32 (1)

3x + 4y = 120 (2)

From (1)

x = 32 - y

Substitute x = 32 - y into (2)

3(32 - y) + 4y = 120

96 - 3y + 4y = 120

- 3y + 4y = 120 - 96

y = 24

Substitute y = 24 into (1)

x + y = 32

x + 24 = 32

x = 32 - 24

x = 8

x = 8; y = 24

Answer:

[tex]y = \boxed0[/tex]

Step-by-step explanation:

we are given a sin function

[tex] \displaystyle h(x) = - 4 \sin(x -\pi /4) [/tex]

we want to figure out the midline of the function graphically The midline of a sinusoidal function is the horizontal line that passes exactly in the midline of its extreme value however since we a function recall that,

[tex] \displaystyle f(x) = a \sin(bx -c) + d[/tex]

where the midline is

to figure out the midline rewrite the function

[tex] \displaystyle h(x) = - 4 \sin(x -\pi /4) + 0[/tex]

therefore the midline is

[tex]y = \boxed0[/tex]

Answer:

I think it's a

Step-by-step explanation:

hsjshbwibs hshhsvsu hshsbsbus

(x-h)²+(y-k)²=r²

(3-h)²+(3-0)²=5²

h²-6h+9+9=25

h²-6h-7=0 —> (h-7)(h+1)=0

h=7 , h=-1

h=7 —> (x-h)²+y²=r² —> (x-7)²+y²=25 —>

x²-14x+49+y²=25 —> x²+y²-14x+24=0

h=–1 —> (x-h)²+y²=r² —> (x+1)²+y²=25 —>

x²+2x+1+y²=25 —> x²+y²+2x–24=0

I hope it helped you ^_^

b) ( 7, 21)

Step-by-step explanation:

5(7)=2(21)-7

35=42-7

35=35

Answer:

None of them

Step-by-step explanation:

a: 5*0=2*6-7 False

b: 5*21=2*7-7 False

c: 5*18=2*8-7 False

d: 5*4=2*-3-7 False

Answer:

sin θ = (√119)/12

tan θ = (√119)/5

csc θ = 12/(√119)

cot θ = 5/(√119)

Five trigonometric functions of θ are

sinθ = [tex]\frac{\sqrt{119} }{12}[/tex]cosθ = [tex]\frac{5}{12}[/tex]tanθ = [tex]\frac{\sqrt{119} }{5}[/tex]cosecθ = [tex]\frac{12}{\sqrt{119} }[/tex]secθ = [tex]\frac{12}{5}[/tex]cotθ = [tex]\frac{5}{\sqrt{119} }[/tex]

"The trigonometric functions of θ are functions of an angle. sine, cosine, and tangent are familiar trigonometric functions. The trigonometric functions relates the angles of a triangle to the length of its side."

Let θ be an acute angle of a right angle triangle

"An acute angle ("acute" meaning "small") is an angle smaller than a right angle. The range of an acute angle is between 0 and 90 degrees."

"A right angled triangle is a triangle in which one angle is a right angle (that is, a 90-degree angle).

"The side opposite the right angle is called the 'hypotenuse'. The hypotenuse is always the longest side. The sum of the other two interior angles is equal to 90°."

"An 'opposite' side is the one across from a given angle."

"An 'adjacent' side is next to a given angle. We use special words to describe the sides of right triangles."

we have,

cosθ = [tex]\frac{5}{12}[/tex]

secθ = [tex]\frac{12}{5}[/tex]

Hypotenuse side = 12

Adjacent side = 5

∴ Opposite side = [tex]\sqrt{hyp^{2}-adj^{2} }[/tex]= [tex]\sqrt{12^{2}-5^{2} }[/tex] = [tex]\sqrt{119}[/tex]

sinθ = [tex]\frac{opp}{hyp}[/tex] = [tex]\frac{\sqrt{119} }{12}[/tex]

tanθ = [tex]\frac{opp}{adj}[/tex] = [tex]\frac{\sqrt{119} }{5}[/tex]

cosecθ = [tex]\frac{hyp}{opp}[/tex] = [tex]\frac{12}{\sqrt{119} }[/tex]

cotθ  = [tex]\frac{adj}{opp}[/tex] = [tex]\frac{5}{\sqrt{119} }[/tex]

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Answer:

x=6

pqs=82

sqr=59

Step-by-step explanation:

13x + 4 + 10x - 1 = 141

23x + 3= 141

23x = 136

x = 136/23 = 6

~~~~~~~~~~~~~~~

pqs = 13x + 4  = 13(6) + 4 = 78+4 = 82

sqr =  10x - 1 = 10(6)-1 = 60 - 1 = 59

Answer:

x = 6

Angle PQS is 82

Angle SQR is 59

Step-by-step explanation:

13x + 4 + 10x - 1 = 141

Group like terms : 23x + 3 = 141

Subtract 3 from both sides to get 23x = 138

Divide both sides by 23 to get x = 6

Angle PQS: Plug 6 into x  for 13x + 4 = 13 (6) + 4 = 82

Angle SQR: Plug 6 into x for 10x - 1 = 10 (6) -1 = 59

Answer:

please send the pic again clearly

Answer:

I hope it will help you

Step-by-step explanation:

thank u

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