how do I find angle 1?

Answer:

73.0m

Step-by-step explanation:

see the attachment. Hope it helps.

Answer:

(a):

Dannette                   Alphonso

[tex]\bar x_D = 4.33[/tex]                    [tex]\bar x_A = 5.17[/tex]

[tex]M_D = 2.5[/tex]                    [tex]M_A = 5[/tex]

[tex]\sigma_D = 3.350[/tex]                  [tex]\sigma_A = 1.951[/tex]

[tex]IQR_D = 7[/tex]                  [tex]IQR_A = 1.5[/tex]

(b):

Measure of center: Median

Measure of spread: Interquartile range

(c):

There are no outliers in Dannette's dataset

There are outliers in Alphonso's dataset

Step-by-step explanation:

Given

See attachment for the appropriate data presentation

Solving (a): Mean, Median, Standard deviation and IQR of each

From the attached plots, we have:

IQR_A = 1.5 ---- Dannette

[tex]A = \{3,4,4,4,4,5,5,5,5,6,6,11\}[/tex] ---- Alphonso

n = 12 --- number of dataset

Mean

The mean is calculated

[tex]\bar x = \frac{\sum x}{n}[/tex]

So, we have:

[tex]\bar x_D = \frac{1+1+1+1+2+2+3+7+8+8+9+9}{12}[/tex]

[tex]\bar x_D = \frac{52}{12}[/tex]

[tex]\bar x_D = 4.33[/tex] --- Dannette

[tex]\bar x_A = \frac{3+4+4+4+4+5+5+5+5+6+6+11}{12}[/tex]

[tex]\bar x_A = \frac{62}{12}[/tex]

[tex]\bar x_A = 5.17[/tex]  --- Alphonso

Median

The median is calculated as:

[tex]M = \frac{n + 1}{2}th[/tex]

[tex]M = \frac{12 + 1}{2}th[/tex]

[tex]M = \frac{13}{2}th[/tex]

[tex]M = 6.5th[/tex]

This implies that the median is the mean of the 6th and the 7th item.

So, we have:

[tex]M_D = \frac{2+3}{2}[/tex]

[tex]M_D = \frac{5}{2}[/tex]

[tex]M_D = 2.5[/tex] ---- Dannette

[tex]M_A = \frac{5+5}{2}[/tex]

[tex]M_A = \frac{10}{2}[/tex]

[tex]M_A = 5[/tex]  ---- Alphonso

Standard Deviation

This is calculated as:

[tex]\sigma = \sqrt{\frac{\sum(x - \bar x)^2}{n}}[/tex]

So, we have:

[tex]\sigma_D = \sqrt{\frac{(1 - 4.33)^2 +.............+(9- 4.33)^2}{12}}[/tex]

[tex]\sigma_D = \sqrt{\frac{134.6668}{12}}[/tex]

[tex]\sigma_D = 3.350[/tex] ---- Dannette

[tex]\sigma_A = \sqrt{\frac{(3-5.17)^2+............+(11-5.17)^2}{12}}[/tex]

[tex]\sigma_A = \sqrt{\frac{45.6668}{12}}[/tex]

[tex]\sigma_A = 1.951[/tex] --- Alphonso

The Interquartile Range (IQR)

This is calculated as:

[tex]IQR =Q_3 - Q_1[/tex]

Where

[tex]Q_3 \to[/tex] Upper Quartile       and        [tex]Q_1 \to[/tex] Lower Quartile

[tex]Q_3[/tex] is calculated as:

[tex]Q_3 = \frac{3}{4}*({n + 1})th[/tex]

[tex]Q_3 = \frac{3}{4}*(12 + 1})th[/tex]

[tex]Q_3 = \frac{3}{4}*13th[/tex]

[tex]Q_3 = 9.75th[/tex]

This means that [tex]Q_3[/tex] is the mean of the 9th and 7th item. So, we have:

[tex]Q_3 = \frac{1}{2} * (8+8) = \frac{1}{2} * 16[/tex]           [tex]Q_3 = \frac{1}{2} * (5+6) = \frac{1}{2} * 11[/tex]

[tex]Q_3 = 8[/tex] ---- Dannette                 [tex]Q_3 = 5.5[/tex] --- Alphonso

[tex]Q_1[/tex] is calculated as:

[tex]Q_1 = \frac{1}{4}*({n + 1})th[/tex]

[tex]Q_1 = \frac{1}{4}*({12 + 1})th[/tex]

[tex]Q_1 = \frac{1}{4}*13th[/tex]

[tex]Q_1 = 3.25th[/tex]

This means that [tex]Q_1[/tex] is the mean of the 3rd and 4th item. So, we have:

[tex]Q_1 = \frac{1}{2}(1+1) = \frac{1}{2} * 2[/tex]                  [tex]Q_1 = \frac{1}{2}(4+4) = \frac{1}{2} * 8[/tex]

[tex]Q_1 = 1[/tex] --- Dannette                   [tex]Q_1 = 4[/tex] ---- Alphonso

So, the IQR is:

[tex]IQR = Q_3 - Q_1[/tex]

[tex]IQR_D = 8 - 1[/tex]                                     [tex]IQR_A = 5.5 - 4[/tex]

[tex]IQR_D = 7[/tex] --- Dannette                      [tex]IQR_A = 1.5[/tex] --- Alphonso

Solving (b): The measures to compare

Measure of  center

By observation, we can see that there are outliers is the plot of Alphonso (because 11 is far from the other dataset) while there are no outliers in Dannette plot (as all data are close).

Since, the above is the case; we simply compare the median of both because it is not affected by outliers

Measure of  spread

Compare the interquartile range of both, as it is arguably the best measure of spread, because it is also not affected by outliers.

Solving (c): Check for outlier

To check for outlier, we make use of the following formulas:

[tex]Lower =Q_1 - 1.5 * IQR[/tex]

[tex]Upper =Q_3 + 1.5 * IQR[/tex]

For Dannette:

[tex]Lower = 1 - 1.5 * 7 = -9.5[/tex]

[tex]Upper = 8 + 1.5 * 7 = 18.5[/tex]

Since, the dataset are all positive, we change the lower outlier to 0.

So, the valid data range are:

[tex]Valid = 0 \to 18.5[/tex]

From the question, the range of Dannette's dataset is: 1 to 9. Hence, there are no outliers in Dannette's dataset

For Alphonso:

[tex]Lower = 4 - 1.5 * 1.5 =1.75[/tex]

[tex]Upper = 5.5 + 1.5 * 1.5 =7.75[/tex]  

So, the valid data range are:

[tex]Valid = 1.75\to 7.75[/tex]

From the question, the range of Alphonso's dataset is: 3 to 11. Hence, there are outliers in Alphonso's dataset

Step-by-step explanation:

-3,4 Is the answer Is it right or wrong if it is true plz mark me as brainliest

Answer:

Ano is correct

Step-by-step explanation:

-3,4is theoretically correct answer

Answer: 45 pencils were in the box originally

Step-by-step explanation:

Suppose there were x pencils in the box originally. Since 18 pencils is equal to 2/5 of the total number of pencils in the box originally, set 18 equal to 2/5x or

18=2/5x

Now solve

x = 18x5/2 = 45

Answer and Step-by-step explanation:

The answer is the second answer choice. y = 2x + 1

By looking at the graph, we see that there is a y-intercept at (0, 1), and it has a positive slope of 2.

#teamtrees #PAW (Plant and Water)

Answer:

43.5 % decrease

Step-by-step explanation:

Take the original price and subtract the new price

850-480

370

Divide by the original price

370/850

.435294118

Change to percent form by multiplying by 100

43.5294118 % decrease

43.5 % decrease

Answer:

May the ans will help you.

Answer:

33.51 cubic inches

Step-by-step explanation:

Formula for volume of a sphere is V= 4 /3 · π · r3

We know the diameter is 4, and the radius is half the diameter, so the radius is 2.

V = 4 /3 · π · [tex]2^{3}[/tex]

≈ 33. 51032

Rounded to the nearest hundreth is 33.51.

9514 1404 393

Answer:

  d, b, c, a, e

Step-by-step explanation:

The order of the letters in the congruence statement tells you ...

  ΔQOP ≅ ΔABC

  ∠Q ≅ ∠A

  ∠O ≅ ∠B ≅ 115°

  ∠P ≅ ∠C

  QO ≅ AB = 5 m

  OP ≅ BC = 8 m

  PQ ≅ CA

Answer:

[tex] {x}^{2} + 26x = 11 \\ x = 0.4 \: and \: - 26.4[/tex]

Answer:

1.tenisha

2.1\5+1\3=1\×

3.n-12=1\3(n+2)

4.500×=120

ok check image file in the image is answers with color code

Answer:

3:7

Step-by-step explanation:

We know that there are 4 girls and 3 boys and 4+3=7.

Answer:

See below

Step-by-step explanation:

Congruent means having the same size and shape.

If triangle A'B'C' is the image of triangle ABC after a dilation with a scale factor of 1/2 then the two triangles will not acquire the same size

This is because when a shape undergoes a dilation the dilated image is either larger or smaller and can therefore not maintain the same size as the pre image. Hence the triangles are not congruent.

Triangle ABC is not congruent to triangle A'B'C'

The triangles are given as:

Triangle ABC and A'B'C'

The other parameters are:

Scale factor, k = 1/2

Center = Point A

Since the scale factor is not 1, then the triangles would not be congruent; but they would be similar

Hence, triangle ABC is not congruent to triangle A'B'C'

Read more about dilation at:

https://brainly.com/question/9791066

12z - 21 = 92

12z - 21 + 21 = 92 + 21

12z = 113

z = 113/12

Answer:

CLAE

Step-by-step explanation:

1=43

2=28

3=24

4=83

Answer:

1/8 Of the animals are rabbits.

Step-by-step explanation:

3/8 Cats + 4/8 Dogs = 7/8

1/8 Is all you have room left for so 1/8 would be rabbits.

Answer:

1/8.

Step-by-step explanation:

Fraction of rabbits = 1 - (3/7 + 4/8)

= 1 - 7/8

= 8/8 - 7/8

= 1/8.

Answer:

2.45.250- 94.750

= 92. 2975. this is the learners who got the admission

Answer:

1,50,500 students

Step-by-step explanation:

Hope this helps... vote as brainliest

Answer:

[tex]x = 97[/tex]

Step-by-step explanation:

Given

[tex]t = 20[/tex] --- time (years)

[tex]A =1000[/tex] --- amount

[tex]r = 10\%[/tex] --- rate of interest

Required

The last 10 payments (x)

First, calculate the end of year 1 payment

[tex]y_1(end) = 10\% * 1000 * 150\%[/tex]

[tex]y_1(end) = 150[/tex]

Amount at end of year 1

[tex]A_1=A - y_1(end) - r * A[/tex]

[tex]A_1=1000 - (150 - 10\% * 1000)[/tex]

[tex]A_1 =1000 - (150- 100)[/tex]

[tex]A_1 =950[/tex]

Rewrite as:

[tex]A_1 = 0.95 * 1000^1[/tex]

Next, calculate the end of year 1 payment

[tex]y_2(end) = 10\% * 950 * 150\%[/tex]

[tex]y_2(end) = 142.5[/tex]

Amount at end of year 2

[tex]A_2=A_1 - (y_2(end) - r * A_1)[/tex]

[tex]A_2=950 - (142.5 - 10\%*950)[/tex]

[tex]A_2 = 902.5[/tex]

Rewrite as:

[tex]A_2 = 0.95 * 1000^2[/tex]

We have been able to create a pattern:

[tex]A_1 = 1000 * 0.95^1 = 950[/tex]

[tex]A_2 = 1000 * 0.95^2 = 902.5[/tex]

So, the payment till the end of the 10th year is:

[tex]A_{10} = 1000*0.95^{10}[/tex]

[tex]A_{10} = 598.74[/tex]

To calculate X (the last 10 payments), we make use of the following geometric series:

[tex]Amount = \sum\limits^{9}_{n=0} x * (1 + r)^n[/tex]

[tex]Amount = \sum\limits^{9}_{n=0} x * (1 + 10\%)^n[/tex]

[tex]Amount = \sum\limits^{9}_{n=0} x * (1 + 0.10)^n[/tex]

[tex]Amount = \sum\limits^{9}_{n=0} x * (1.10)^n[/tex]

The amount to be paid is:

[tex]Amount = A_{10}*(1 + r)^{10}[/tex] --- i.e. amount at the end of the 10th year * rate of 10 years

[tex]Amount = 1000 * 0.95^{10} * (1+r)^{10}[/tex]

So, we have:

[tex]Amount = \sum\limits^{9}_{n=0} x * (1.10)^n[/tex]

[tex]\sum\limits^{9}_{n=0} x * (1.10)^n = 1000 * 0.95^{10} * (1+r)^{10}[/tex]

[tex]\sum\limits^{9}_{n=0} x * (1.10)^n = 1000 * 0.95^{10} * (1+10\%)^{10}[/tex]

[tex]\sum\limits^{9}_{n=0} x * (1.10)^n = 1000 * 0.95^{10} * (1+0.10)^{10}[/tex]

[tex]\sum\limits^{9}_{n=0} x * (1.10)^n = 1000 * 0.95^{10} * (1.10)^{10}[/tex]

The geometric sum can be rewritten using the following formula:

[tex]S_n = \sum\limits^{9}_{n=0} x * (1.10)^n[/tex]

[tex]S_n =\frac{a(r^n - 1)}{r -1}[/tex]

In this case:

[tex]a = x[/tex]

[tex]r = 1.10[/tex]

[tex]n =10[/tex]

So, we have:

[tex]\frac{x(r^{10} - 1)}{r -1} = \sum\limits^{9}_{n=0} x * (1.10)^n[/tex]

[tex]\frac{x((1.10)^{10} - 1)}{1.10 -1} = \sum\limits^{9}_{n=0} x * (1.10)^n[/tex]

[tex]\frac{x((1.10)^{10} - 1)}{0.10} = \sum\limits^{9}_{n=0} x * (1.10)^n[/tex]

[tex]x * \frac{1.10^{10} - 1}{0.10} = \sum\limits^{9}_{n=0} x * (1.10)^n[/tex]

So, the equation becomes:

[tex]x * \frac{1.10^{10} - 1}{0.10} = 1000 * 0.95^{10} * (1.10)^{10}[/tex]

Solve for x

[tex]x = \frac{1000 * 0.95^{10} * 1.10^{10} * 0.10}{1.10^{10} - 1}[/tex]

[tex]x = 97.44[/tex]

Approximate

[tex]x = 97[/tex]

Answer:

The modulus of z is [tex]\sqrt{10}[/tex]

Step-by-step explanation:

Complex number:

A complex number, given by:

[tex]z = x + iy[/tex]

Can be represented also as a point (x,y).

The modulus is given by:

[tex]|z| = \sqrt{x^2 + y^2}[/tex]

Point z is at (negative 3, 1). What is the modulus of z?

[tex]x = -3, y = 1[/tex]. So

[tex]|z| = \sqrt{x^2 + y^2} = \sqrt{(-3)^2+1^2} = \sqrt{10}[/tex]

The modulus of z is [tex]\sqrt{10}[/tex]

Answer:

-2

Step-by-step explanation:

if this is the right problem it is -2

Answer

19.013.153,42629466 giây

Step-by-step explanati

van toc ánh sán  =299.792.458 m/s

s= v*t

t=s/v

t= 5.699.999.999.999.999/299.792.458= 19.013.153,42629466 giây

Answer:

A U B={1,2,3,4,5,6,7,8,9,10} represents A union B

(includes all the members of set Sand the members of set Bout together, do not repeat anyone that comes twice)

A n B={1,4} represents A interception B( this refers to the members that sets A and B have in common)

Answer:

A ∪ B = { 1 , 2 , 3 , 4 , 5 , 6 , 7 , 8 , 9 , 10 }

Step-by-step explanation:

A = { 1 , 3 , 4 , 5 , 7 , 9 }

B = { 1 , 2 , 4 , 6 , 8 , 10 }

A ∪ B = { 1 , 2 , 3 , 4 , 5 , 6 , 7 , 8 , 9 , 10 }

           It represents the whole numbers between 0 and 11

          [ A ∪ B is the elements of both A and B , without any repetition ]    

A ∩ B = { 1 , 4 }

            It represents the common numbers in both A and B

Answer:

B'(4, 0)

Step-by-step explanation:

B (1, 5)

it translated right 3 units => x'=x+3

down 5 units => y'= y-5

Answer:

39 feet

Step-by-step explanation:

p = 15 + 8 + 10 + 6

p = 39

39 feet

Answer:

1. The first set of number is

1,2,3,4,5

Mean= 1+2+3+4+5/5

= 15/5

= 3

Median= 3

Mode= N/A

The next set of numbers is

2,3,4,5,6,6

Mean= 2+3+4+5+6+6/6

= 26/6

= 4.3

Median=4+5/2

= 9/2

= 4.5

Mode= 6

The next set of number is

6,7,5,4,5,6,2,5

Mean= 2+4+5+5+5+6+6+7/8

= 40/8

= 5

Median= 5+5/2

= 10/2

= 5

Mode= 5

Answer:

C. she is not beautiful and not clever.

Step-by-step explanation:

A. she is beautiful but not clever. B. she is beautiful and clever

C. she is not beautiful and not clever.

D. she is beautiful or not clever.

p: she is beautiful

q :she is clever

~p^ (~q) in verbal form

~p = she is not beautiful

~q = she is not clever

~p^ (~q) = she is not beautiful and not clever.

C. she is not beautiful and not clever.

Answer:

The lorry travels by 6 mph more than the expected speed.

Step-by-step explanation:

Velocity formula:

Velocity is distance divided by time, that is:

[tex]v = \frac{d}{t}[/tex]

Shortest route:

400 miles in 10 hours, which means that [tex]d = 400, v = 10[/tex]. So

[tex]v = \frac{d}{t} = \frac{400}{10} = 40[/tex]

In mph.

The lorry actually travels by a different route which increases the distance by 15%, but it still arrives in 10 hours.

Distance is multiplied by 100% + 15% = 115% = 1.15, so:

[tex]d = 1.15*400 = 460[/tex]

Then

[tex]v = \frac{d}{t} = \frac{460}{10} = 46[/tex]

46 mph

By how many more mph than the expected speed does the lorry travel?

46 - 40 = 6 mph

The lorry travels by 6 mph more than the expected speed.

Answer:

Mary's friend Larry is taller by 15cm.

Step-by-step explanation:

First look for the bigger number.

Then subtract the smaller number from the bigger number.