How do I solve problems like this? I did it last year, but I don't remember how to do it.


Solve for x:


1/2x + 3 = 7


2x + 3 - 4x - 7 = 11


thanks!!

9514 1404 393

Answer:

  D.) a+2b

Step-by-step explanation:

The integers 'a' and 'b' can be any, so you can choose a couple and evaluate these expressions to see what you get. For example, we can let a=1 and b=0. For these values, the offered expressions evaluate to ...

  A) 3(0) = 0 . . . even

  B) 1 +3 = 4 . . . even

  C) 2(1+0) = 2 . . . even

  D) 1 +2(0) = 1 . . . odd

_____

Additional comment

These rules apply to even/odd:

Then A is (odd)(even) = even; B is (odd)+(odd) = even; C is (even)(whatever) = even; D = (odd)+(even) = odd.

Answer:

8 hours 10 minutes

I hope this answers your question

Answer: paul has been away from home for 7 hours and 50 minutes.

Step-by-step explanation:

Answer:

the answer is -299.808 well that's what I think it's

Answer:

-299.808

Step-by-step explanation:

= 10700/100 + 5192/100 - 412

= 107 + 5.192 - 412

= -299.808

Answer:

she baked 3 times as many cranberry than blueberry muffins

Step-by-step explanation:

i think that because 9×3=27

the amount of the cranberry muffins are 9

Answer:

Step-by-step explanation:

Let the amount of gas in the tank before filling was x.

We have:

let the amount of gas be x

[tex]\\ \sf\longmapsto x+2\dfrac{4}{7}=4[/tex]

[tex]\\ \sf\longmapsto x+\dfrac{18}{7}=4[/tex]

[tex]\\ \sf\longmapsto x=4-\dfrac{18}{7}[/tex]

[tex]\\ \sf\longmapsto x=\dfrac{28-18}{7}[/tex]

[tex]\\ \sf\longmapsto x=\dfrac{10}{7}[/tex]

[tex]\\ \sf\longmapsto x=1\dfrac{3}{7}[/tex]

Answer:

1.9

Step-by-step explanation:

You round when the numbers behind the decimal are 5 or greater. This being said, you need to round from the number furthest away from the decimal. In this case it would be 9. 9 is greater than 5 so we round 8 up to 9 and get rid of the number behind it. We are left with 1.9

Answer:[tex]\huge \boxed{x=180-26-90=64}[/tex]

Step-by-step explanation:

Answer:

Step-by-step explanation:

You have the angels 180, 26, 90(right angle) and x. So when you add them all up you should get 360 because there aren’t two straight lines. Only line makes a 180 angle. So...

180 + 26 + 90 + x = 360

296 + x = 360

x = 360 - 296

x = 64

Answer:

D

Step-by-step explanation:

I took the quiz

Answer:

B

Step-by-step explanation:

here we use trigonometric ratio involving soh,cah,toa

Answer:

The answer is 2.)

Step-by-step explanation:

Given initial velocity=135 ft/s

& cliff=76 foot

Given quadratic equation

⇒                      (let h=0 it is given)

⇒  

⇒  

⇒    t=8.96≈9 s (the other root is negative)

Hence, rocket will take 9 s to hit the ground after launched.

Answer:  Choice D

0 = 16t^2 + 135t + 76;  9 s

==============================================

Explanation:

The equation we start with is

[tex]h = -16t^2 + vt + c\\\\[/tex]

where v is the starting or initial velocity, and c is the starting height.

We're told that v = 135 and c = 76

We let h = 0 to indicate when the object hits the ground, aka the height is 0 ft.

That means the equation updates to [tex]0 = -16t^2 + 135t + 76\\\\[/tex]

Based on that alone, the answer is between A or D

-------------------

We'll use the quadratic formula to solve for t

We have

So,

[tex]t = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\\\\t = \frac{-135 \pm \sqrt{135^2 - 4(-16)(76)}}{2(-16)}\\\\t = \frac{-135 \pm \sqrt{23,089}}{-32}\\\\t \approx \frac{-135 \pm 151.9506}{-32}\\\\t \approx \frac{-135 + 151.9506}{-32} \ \text{ or } \ t \approx \frac{-135 - 151.9506}{-32}\\\\t \approx \frac{16.9506}{-32} \ \text{ or } \ t \approx \frac{-286.9506}{-32}\\\\t \approx -0.52971 \ \text{ or } \ t \approx 8.96721\\\\[/tex]

We ignore the negative t value because a negative time duration makes no sense.

The only practical solution here is roughly 8.96721 which rounds to 9.0 or simply 9 when we round to the nearest tenth (one decimal place).

In short, the object will hit the ground at the 9 second mark roughly. Or put another way: the object is in the air for about 9 seconds.

From this, we can see that the final answer is choice D.

Keep in mind that we aren't accounting for any wind resistance. Considering this variable greatly complicates the problem and requires much higher level mathematics. So we just assume that there is no wind at this moment.

Answer: the answer to your question is 7

Step-by-step explanation:

Answer:

(a+b)³=a³+3a²b+3ab²+b³

Answer:

Step-by-step explanation:

Hello!

(a+b)(a+b)(a+b)

(a+b)(a+b) = a²+2ab + b²

(a²+2ab + b²) (a+b)=

a³ + a²b +  2a²b + 2ab² + ab² + b³ =

a³ + b³ +  2a²b + 2ab² + ab²  + a²b

Answer:

Does the answer help you?

Answer:

x^2 +2x -6

Step-by-step explanation:

f(x)=2x+1

g(x)=x^2-7,

(f+g)(x) = 2x+1 + x^2 -7

Combine like terms

           = x^2 +2x -6

f (x) = 2x + 1

g (x) = x² - 7

(f+g) (x) = 2x+1 + x² - 7

Adding like terms

⇛ x² + 2x - 6

Answer:

wyatt

Step-by-step explanation:

4:30 mins is 270 seconds

Step-by-step explanation:

(f*g) (x)=f(x) * g(x)

=(x+3)(2x^2-4)

=2x^3-4x+6x^2-12

Answer:

c) 21

Step-by-step explanation:

[tex] \sqrt{169} + \sqrt{64} [/tex]

13+8

answer is 21

Answer:

B. 4/5

Step-by-step explanation:

Sin = Opposite/Hypotenuse

Sin∠A = 8/10 = 4/5

Answer:

9x^2 + 2x - 5

Step-by-step explanation:

7x^2 - 5x + 3

2x^2 + 7x - 8

__________

9x^2 + 2x - 5

Option B is the correct answer.

Answer:

2nd option

Step-by-step explanation:

Given f(x) then f(x + a) is a horizontal translation of f(x)

• If a > 0 then a shift left of a units

• If a < 0 then a shift right of a units

Here g(x) = (x - 6)²

The base graph has been shifted right 6 units

Answer:

The values of [tex]a[/tex] and [tex]b[/tex] are [tex]5[/tex] and [tex]-\frac{15}{7}[/tex], respectively.

Step-by-step explanation:

There are mistakes in the statement, correct form is presented below:

[tex]5+\frac{\sqrt{3}}{7} + 2\sqrt{3} = a - b\cdot \sqrt{3}[/tex].

By direct comparison we have the following system of equations:

[tex]a = 5[/tex] (1)

[tex]\frac{\sqrt{3}}{7}+2\sqrt{3} = -b\cdot \sqrt{3}[/tex] (2)

In (2) we solve for [tex]b[/tex]:

[tex]\left(\frac{1}{7}+2 \right)\cdot \sqrt{3} = -b\cdot \sqrt{3}[/tex]

[tex]b = -\frac{15}{7}[/tex]

The values of [tex]a[/tex] and [tex]b[/tex] are [tex]5[/tex] and [tex]-\frac{15}{7}[/tex], respectively.

Answer:

y = -x + 1

Step-by-step explanation:

eqn of line: y=mx+c

perpendicular, m1 x m2 = -1

m × 1 = -1

m = -1

y=-x+c

sub x=-5, y=6

6 = -(-5) +c

6 = 5 + c

c = 1

y = -x + 1

Answer:

c on edge

Step-by-step explanation:

Answer:  Choice A

y=2x+3; y=-1/3x+3

==================================================

Explanation:

The left portion of the blue curve is y = 2x+3 but it is only graphed when x < 0 (we could argue that [tex]x \le 0[/tex] but I'll set that aside for the other portion).

The right portion is the line y = -1/3x + 3 and it's only graphed when [tex]x \ge 0[/tex]

So we could have this piecewise function

[tex]f(x) = \begin{cases}2x+3 \ \text{ if } x < 0\\-\frac{1}{3}x+3 \ \text{ if } x \ge 0\\\end{cases}[/tex]

Or we could easily swap the "or equal to" portion to move to the first part instead like this

[tex]f(x) = \begin{cases}2x+3 \ \text{ if } x \le 0\\-\frac{1}{3}x+3 \ \text{ if } x > 0\\\end{cases}[/tex]

Either way, we're involving the equations mentioned in choice A

Answer:

The cost price of Dakshes was $ 5,500, while the cost price of Sayad was $ 5,000.

Step-by-step explanation:

Given that Sayad bought a watch and sold to Dakshes at 10% profit, and Dakshes again sold it to Sahayata for $ 6,050 at 10% profit, to find the cost price of Dakshes and the cost price of Sayad the following calculations must be performed:

6,050 / 1.1 = X

5,500 = X

5,500 / 1.1 = X

5,000 = X

Therefore, the cost price of Dakshes was $ 5,500, while the cost price of Sayad was $ 5,000.

Answer:

it will take 5days to reach a total of 180meters

Step-by-step explanation:

80m+20+20+20+20+20

=180meters

=5days

Answer:

B

Step-by-step explanation:

x -> x and y -> y+5

-1 -> - 1 and - 3 -> 2, so b is the correct answer.

Answer:

try 14n

Step-by-step explanation:

Answer:

[tex]r \: = 2sin2 \theta \\ = > r = 2.2sin\theta.cos\theta \\ = > r = 4sin\theta.cos\theta \: \\ \\ \sf \: we \: know \: that \: \\ x = r \: cos\theta \: \therefore \: cos\theta = \frac{x}{r} \\ \\ y = r \: sin\theta \: \therefore \: sin\theta = \frac{y}{r} \\ \\ \sf \: now \\ \\ r = 4 \times \frac{y}{r} \times \frac{x}{r} \\ = > {r}^{3 } = 4xy \\ \\ \sf \: again \: \: r = \sqrt{ {x}^{2} + {y}^{2} } \\ \\ = > {( \sqrt{ {x}^{2} + {y}^{2} } })^{3} = 4xy \\ = > {( {x}^{2} + {y}^{2} })^{ \frac{3}{2} } = 4xy \\ = > {( {x}^{2} + {y}^{2} })^{3} = 16 {x}^{2} {y}^{2} [/tex]

Please mark me as Brainliest

Refer the attached image for the answer

HOPE SO IT HELPS YOU