Chemistry College

how does soil erosion affect living things​

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Answer 1

The effects of soil erosion go beyond the loss of fertile land. It has led to increased pollution and sedimentation in streams and rivers, clogging these waterways and causing declines in fish and other species. And degraded lands are also often less able to hold onto water, which can worsen flooding.

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Water has t. = 647.1 k and p = 220.6 bar. what do these values imply about the state of waterunder ordinary conditions?​

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The Tc and Pc values of water are very high compared to the room temperature and common atmospheric pressure. As a result, water exists in liquid state under ordinary condition of temperature and pressure.

Why does water exist in the liquid state under ordinary conditions?

Water exists in the liquid state under ordinary conditions because its critical temperature (Tc = 647.1 K) and critical pressure (Pc = 220.6 bar) are significantly higher than room temperature and common atmospheric pressure.

The critical temperature is the temperature above which a substance cannot exist in the liquid state regardless of the pressure applied and the critical pressure is the pressure required to convert a substance into a liquid at its critical temperature.

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1. Thinley filled a ballon with 14L of hydrogen gas, the the reduced the pressure to 4 atmosphere and found out that the ballon expanded to occupy double the initial volume. What was the initial pressure exerted on the ballon?​

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The initial pressure exerted on the balloon was 8 atmospheres.

To find the initial pressure exerted on the balloon, we can use Boyle's Law, which states that the pressure of a gas is inversely proportional to its volume when temperature is constant. The formula for Boyle's Law is P1V1 = P2V2, where P1 and V1 represent the initial pressure and volume, and P2 and V2 represent the final pressure and volume.

In this case, we are given that the initial volume (V1) is 14 L and the final volume (V2) is double the initial volume (2 x V1). We are also given that the final pressure (P2) is 4 atmospheres. We need to find the initial pressure (P1).

Using the formula P1V1 = P2V2 and plugging in the given values, we have:

P1 * 14 = 4 * (2 * 14)

P1 * 14 = 4 * 28

P1 * 14 = 112

To isolate P1, we divide both sides of the equation by 14:

P1 = 112 / 14

P1 = 8

It's important to note that the unit of pressure in this case is atmospheres, as stated in the question. If the pressure unit had been different, appropriate unit conversions would have been necessary.

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