how many feet is in one centimeter and how many inches is in 1 feet?​

Answer:

1) D - 30 cm 2) 12 percents

Step-by-step explanation:

The first question was If two perpendicular sides of a right-angled triangle are 5 cm and 12 cm, its perimeter is: (A) 13 cm (B) 17 cm (C) 27 cm (D) 30 cm

two perpendicular sides are legs, find the hipotenuse of the triangle

It is equal to sqrt(5^2+12^2)= sqrt169=13

5+12+13=30 - D - the perimeter

The second question

7500 -100 percents

8400- x

7500/8400=100/x

75/84=100/x

(25/28)*x=100

(1/28)*x=4

x=4/(1/28)= 4*28= 112 percents

The profit is 12 percents

2) Option D is correct. If two perpendicular sides of a right-angled triangle are 5 cm and 12 cm, its perimeter will be 30cm.

3) None of the given options are correct. If an article is purchased for 7,500 and sold for 8,400, the profit percentage will be 12%

2) A right-angled triangle is a triangle with three sides and one of its angles is 90degrees. Find the image of a right-angled triangle attached below.

The triangle consists of 3 sides which are:

Before we can get the perimeter of the right triangle, we need to get the third side first (the hypotenuse side) using the Pythagoras theorem. According to the theorem:

[tex]c^2=a^2+b^2[/tex]

Given

a = 5 cm

b =12 cm

[tex]c^2=5^2+12^2\\c^2=25+144\\c^2=169\\c=\sqrt{169}\\c=13 cm[/tex]

Perimeter of the right triangle = a + b + c

Perimeter of the right triangle = 5 cm + 12 cm + 13 cm

Perimeter of the right triangle = 30 cm

Hence the perimeter of the right triangle is 30 cm.

3) If an article is purchased for 7,500, then;

If the same article is sold for 8,400, then:

[tex]\% profit=\frac{SP-CP}{CP} \times 100[/tex]

Substitute the given parameters

[tex]\% profit=\frac{8400-7500}{7500} \times 100\\\%profit=\frac{900}{7500} \times 100 \\\%profit=\frac{900}{75}\\\% profit = 12 \%[/tex]

This shows that the profit percent is 12%

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Answer:

B. The largest exponent value of the a terms is equal to the value of the exponent on the binomial. The exponent values then decrease from left to right.

Step-by-step explanation:

The exponent values of the a terms increase from one side of the binomial to the other. The value of the largest exponent is equal to part of the binomial expression.

Answer:

Hence the required probability is, 3/4

Step-by-step explanation:  

At the shelter, he likes :  

a male coolie, a female coolie, a male boxer, a female boxer, a male beagle, a female beagle, a male Labrador, and a female Labrador.  

Let, A denote the event of selecting a male coolie and B denote the event of selecting a male Labrador.  

P(A) = 1/8 = P(B)  

Here the probability of selecting a puppy except A & B is,  

P(AUB)c = 1 - P(AUB) = 1 - { P(A) + P(B) } = 1 - 1/8 - 1/8 = 3/4

Hey there!

A right pyramid with a square base just means that it isn't slanted all funny. If you create a triangle with a point on one of the edges of the base, the center of the base, and the top of the pyramid, it would be a right triangle.

To find the volume of a right pyramid, you just take the base area, multiply it by the height, and then divide by three.

However, we are looking for the height. We have been given, so we will just go backwards.

252×3=756 (multiply instead of divide)

6×6=36 (base is a square, so you just square 6. This is our base area)

756/36=21

So, the vertical height of the pyramid is 21 cubic centimeters.

Have a wonderful day! :D

Answer:

6000 hope this helps

if the question is 5,422 then the round figure is 5000

but the question is 5,821 its above 5500 will be 6000

The logarithmic model is:

[tex]g(x) = \frac{\ln{x}}{0.4}[/tex]

-------------

-------------

The original function is:

[tex]y = f(x) = e^{0.4x}[/tex]

To find the inverse function, first, we exchange y and x, so:

[tex]e^{0.4y} = x[/tex]

Now, we have to isolate y, and we start applying the natural logarithm to both sides of the equality. So

[tex]\ln{e^{0.4y}} = \ln{x}[/tex]

[tex]0.4y = \ln{x}[/tex]

[tex]y = \frac{\ln{x}}{0.4}[/tex]

Thus, the logarithmic model is:

[tex]g(x) = \frac{\ln{x}}{0.4}[/tex]

A similar question is given at https://brainly.com/question/24290183

Answer:

q=6

Step-by-step explanation:

3+9+5+7+Q=5Q

5Q-Q=24

Q=6

Answer:

The answer is 82.2  

Step-by-step explanation

hope this helps

Answer:

C.

Step-by-step explanation:

A P E X

Answer:

(b) 829 seconds

(c) 13.8 minutes

Step-by-step explanation:

(b) 2.48×10⁸/2.99×10⁵ = 829 seconds

(c) 829/60 = 13.8 minutes

Answer:

To find critical points, take the first derivative and set it equal to zero:

f(x) = -2x^2 + 4x + 5

f'(x) = -4x + 4

-4x+4 = 0

-4x = -4

x = 1

Critical point at x = 1

Alternatively, if you mean zeros, or where the x intersects, you can use the quadratic equation.

Answer:

1/10

Step-by-step explanation:

1/5*1/2

1/10

Answer:

8. SU = 24

9. TU = 16√3

Step-by-step explanation:

Recall: SOH CAH TOA

8. Reference angle (θ) = 30°

Opposite = 8√3

Adjacent = SU

Apply TOA,

Tan θ = Opp/Adj

Substitute

Tan 30° = 8√3/SU

Tan 30° × SU = 8√3

SU = 8√3/Tan 30°

SU = 8√3/(1/√3) (tan 30° = 1/√3)

SU = 8√3*√3/1

SU = 8*3

SU = 24

9. Reference angle (θ) = 30°

Opposite = 8√3

Hypotenuse = TU

Apply SOH,

Sin θ = Opp/Hyp

Substitute

Sin 30° = 8√3/TU

Sin 30° × TU = 8√3

TU = 8√3/sin 30°

TU = 8√3/(½) (sin 30° = ½)

TU = 8√3 × 2/1

TU = 16√3

Answer:

Not a subspace

Step-by-step explanation:

(4,0,0) and (0,4,0) are vectors in R3 with zero or one entries being nonzero, but their sum, (4,4,0) has two nonzero entries.

Using the hypothesis test for one sample mean, There is NO SIGNIFICANT EVIDENCE to support the typist's claim

[tex]H_{0} = 45\\H_{1} < 45\\\\[/tex]

The test statistic :

T = (x - μ) ÷ (s/√(n))

T = (43 - 45) ÷ (15/√70)

T = - 2 ÷ 1.7928429

T = -1.12

At α = 0.05

Pvalue :

Degree of freedom, df = 70 - 1 = 69

Pvalue = 0.1333

Decision region :

Reject [tex]H_{0}[/tex] if Pvalue < α

0.1333 > 0.05

Since Pvalue > α We fail to reject the Null

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9514 1404 393

Answer:

Step-by-step explanation:

Let n represent the number of non-cardholder tickets sold. Then total revenue is ...

  2.00n +1.25(578 -n) = 880.00

  0.75n + 722.50 = 880.00

  0.75n = 157.50 . . . . . . . . . . . subtract 722.50

  n = 210 . . . . . . . . . . . . . . . divide by 0.75. Number of non-cardholder tickets

  578 -n = 368 . . . . . number of cardholder tickets

368 cardholder and 210 non-cardholder tickets were sold.

Answer:

Not sure but I think it's 3.75

9514 1404 393

Answer:

  a) 2.038 seconds

  b) 5.918 meters

  c) 1.076 seconds

Step-by-step explanation:

For the purpose of answering these questions, it is convenient to put the given equation into vertex form.

  h = -4.9t² +9.2t +1.6

  = -4.9(t² -(9.2/4.9)t) +1.6

  = -4.9(t² -(9.2/4.9)t +(4.6/4.9)²) +1.6 +4.9(4.6/4.9)²

  = -4.9(t -46/49)² +290/49

__

a) To find h = 0, we solve ...

  0 = -4.9(t -46/49)² +290/49

  290/240.1 = (t -46/49)² . . . . subtract 290/49 and divide by -4.9

  √(2900/2401) +46/49 = t ≈ 2.0378 . . . . seconds

The ball takes about 2.038 seconds to fall to the ground.

__

b) The maximum height is the h value at the vertex of the function. It is the value of h when the squared term is zero:

  290/49 m ≈ 5.918 m

The maximum height of the ball is about 5.918 m.

__

c) We want to find t for h ≥ 4.5.

  h ≥ 4.5

  -4.9(t -46/49)² +290/49 ≥ 4.5

Subtracting 290/49 and dividing by -4.9, we have ...

  (t -46/49)² ≥ 695/2401

Taking the square root, and adding 46/49, we find the time interval to be ...

  -√(695/2401) +46/49 ≤ t ≤ √(695/2401) +46/49

The difference between the interval end points is the time above 4.5 meters. That difference is ...

  2√(695/2401) ≈ 1.076 . . . . seconds

The ball is at or above 4.5 meters for about 1.076 seconds.

__

I like a graphing calculator for its ability to answer these questions quickly and easily. The essentials for answering this question involve typing a couple of equations and highlighting a few points on the graph.

_____

Additional comment

I have a preference for "exact" answers where possible, so have used fractions, rather than their rounded decimal equivalents. The calculator I use deals with these fairly nicely. Unfortunately, the mess of numbers can tend to obscure the working.

"Vertex form" for a quadratic is ...

  y = a(x -h)² +k . . . .  where the vertex is (h, k) and 'a' is a vertical scale factor.

In the above, we have 'a' = -4.9, and (h, k) = (46/49, 290/49) ≈ (0.939, 5.918)

Answer:

(x - 3) inches

Step-by-step explanation:

the ratio of -15 (of the area term) and +5 (of the length term) suggests a term for the width ending in -3. and we need an x in there to get x² for the area.

so, immediate assumption is (x-3) for the width.

let's check

(x+5)(x-3) = x² + 5x - 3x - 15 = x² + 2x - 15

correct.

Answer:

28

Step-by-step explanation:

Find the gcf

Answer:

D

Step-by-step explanation:

Graph it

The 8 will end up in the "ones place".

When 'a' is divided by 'b', then the result we get from the division is the part of 'a' that each one of 'b' items will get. Division can be interpreted as equally dividing the number that is being divided into total x parts, where x is the number of parts the given number is divided.

We need to find the 8 will end up in which place

A negative divided by a negative is positive, then;

2380/ 10 = 238

Therefore, The 8 will end up in the _ ones_ place.

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Answer:

x=145°

Step-by-step explanation:

180 = 35 + x

x = 180-35

x= 145°

Answer:

Step-by-step explanation:

Answer:

Table C

Step-by-step explanation:

For x and y to be proportional , then the values of

[tex]\frac{y}{x}[/tex] = constant k

Table B

[tex]\frac{y}{x}[/tex] = [tex]\frac{6}{3}[/tex] = 2

[tex]\frac{y}{x}[/tex] = [tex]\frac{24}{6}[/tex] = 4

[tex]\frac{y}{x}[/tex] = [tex]\frac{36}{9}[/tex] = 4

The values are not constant

Table C

[tex]\frac{y}{x}[/tex] = [tex]\frac{2}{3}[/tex]

[tex]\frac{y}{x}[/tex] = [tex]\frac{4}{6}[/tex] = [tex]\frac{2}{3}[/tex]

[tex]\frac{y}{x}[/tex] = [tex]\frac{6}{9}[/tex] = [tex]\frac{2}{3}[/tex]

These values are constant

Then Table C shows a proportional relationship between x and y

It looks like you want to find

[tex]\displaystyle \int t^{11} e^{-t^6}\,\mathrm dt[/tex]

Substitute u = -t ⁶ and du = -6t ⁵ dt. Then

[tex]\displaystyle \int t^{11} e^{-t^6}\,\mathrm dt = \frac16 \int (-6t^5) \times (-t^6) e^{-t^6}\,\mathrm dt = \frac16 \int ue^u \,\mathrm du[/tex]

Integrate by parts, taking

f = u   ==>   df = du

dg = eᵘ du   ==>   g = eᵘ

Then

[tex]\displaystyle \frac16 \int ue^u \,\mathrm du = \frac16\left(fg-\int g\,\mathrm df\right) \\\\ =\frac16 ue^u - \frac16\int e^u\,\mathrm du \\\\ =\frac16 ue^u - \frac16 e^u + C \\\\ =-\frac16 t^6 e^{-t^6} - \frac16 e^{-t^6} + C \\\\ =\boxed{-\frac16 e^{-t^6} \left(t^6+1\right) + C}[/tex]

Answer:

%17.80

Step-by-step explanation:

17.8% is the probability that more than 4 are wearing their seat belts.

It is a branch of mathematics that deals with the occurrence of a random event.

Given that Police estimate that 25% of drivers drive without their seat belts.

If they stop 6 drivers at random we need to find the probability that more than 4 are wearing their seat belts.

For each driver stopped, there are only two possible outcomes. Either they are wearing their seatbelts, or they are not.

he drivers are chosen at random, which mean that the probability of a driver wearing their seatbelts is independent from other drivers.

Police estimate that​ 25% of drivers drive without their seat belts.

This means that 75% wear their seatbelts, so P=0.75

If they stop 6 drivers at​ random, find the probability that all of them are wearing their seat belts.

[tex]P(X=x)=C_{n,x} p^{x} (1-p)^{n-x}[/tex]

[tex]P(X=6)=C_{6,6} 0.75^{6} (1-0.75)^{0} =0.1780[/tex]

Hence, 17.8% is the probability that more than 4 are wearing their seat belts.

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Answer: infinitely many