How many four-digit numbers are divisible by 15 and have 15 as the two middle digits?

Answers

Answer 1

Answer: There are 600 four-digit numbers divisible by 15.

Step-by-step explanation:

1005, 1020, 1035, 1050, 1065, 1080, 1095, 1110, 1125, 1140, 1155, 1170, 1185, 1200, 1215, 1230, 1245, 1260, 1275, 1290, 1305, 1320, 1335, 1350, 1365, 1380, 1395, 1410, 1425, 1440, 1455, 1470, 1485, 1500, 1515, 1530, 1545, 1560, 1575, 1590, 1605, 1620, 1635, 1650, 1665, 1680, 1695, 1710, 1725, 1740, 1755, 1770, 1785, 1800, 1815, 1830, 1845, 1860, 1875, 1890, 1905, 1920, 1935, 1950, 1965, 1980, 1995, 2010, 2025, 2040, 2055, 2070, 2085, 2100, 2115, 2130, 2145, 2160, 2175, 2190, 2205, 2220, 2235, 2250, 2265, 2280, 2295, 2310, 2325, 2340, 2355, 2370, 2385, 2400, 2415, 2430, 2445, 2460, 2475, 2490, 2505, 2520, 2535, 2550, 2565, 2580, 2595, 2610, 2625, 2640, 2655, 2670, 2685, 2700, 2715, 2730, 2745, 2760, 2775, 2790, 2805, 2820, 2835, 2850, 2865, 2880, 2895, 2910, 2925, 2940, 2955, 2970, 2985, 3000, 3015, 3030, 3045, 3060, 3075, 3090, 3105, 3120, 3135, 3150, 3165, 3180, 3195, 3210, 3225, 3240, 3255, 3270, 3285, 3300, 3315, 3330, 3345, 3360, 3375, 3390, 3405, 3420, 3435, 3450, 3465, 3480, 3495, 3510, 3525, 3540, 3555, 3570, 3585, 3600, 3615, 3630, 3645, 3660, 3675, 3690, 3705, 3720, 3735, 3750, 3765, 3780, 3795, 3810, 3825, 3840, 3855, 3870, 3885, 3900, 3915, 3930, 3945, 3960, 3975, 3990, 4005, 4020, 4035, 4050, 4065, 4080, 4095, 4110, 4125, 4140, 4155, 4170, 4185, 4200, 4215, 4230, 4245, 4260, 4275, 4290, 4305, 4320, 4335, 4350, 4365, 4380, 4395, 4410, 4425, 4440, 4455, 4470, 4485, 4500, 4515, 4530, 4545, 4560, 4575, 4590, 4605, 4620, 4635, 4650, 4665, 4680, 4695, 4710, 4725, 4740, 4755, 4770, 4785, 4800, 4815, 4830, 4845, 4860, 4875, 4890, 4905, 4920, 4935, 4950, 4965, 4980, 4995, 5010, 5025, 5040, 5055, 5070, 5085, 5100, 5115, 5130, 5145, 5160, 5175, 5190, 5205, 5220, 5235, 5250, 5265, 5280, 5295, 5310, 5325, 5340, 5355, 5370, 5385, 5400, 5415, 5430, 5445, 5460, 5475, 5490, 5505, 5520, 5535, 5550, 5565, 5580, 5595, 5610, 5625, 5640, 5655, 5670, 5685, 5700, 5715, 5730, 5745, 5760, 5775, 5790, 5805, 5820, 5835, 5850, 5865, 5880, 5895, 5910, 5925, 5940, 5955, 5970, 5985, 6000, 6015, 6030, 6045, 6060, 6075, 6090, 6105, 6120, 6135, 6150, 6165, 6180, 6195, 6210, 6225, 6240, 6255, 6270, 6285, 6300, 6315, 6330, 6345, 6360, 6375, 6390, 6405, 6420, 6435, 6450, 6465, 6480, 6495, 6510, 6525, 6540, 6555, 6570, 6585, 6600, 6615, 6630, 6645, 6660, 6675, 6690, 6705, 6720, 6735, 6750, 6765, 6780, 6795, 6810, 6825, 6840, 6855, 6870, 6885, 6900, 6915, 6930, 6945, 6960, 6975, 6990, 7005, 7020, 7035, 7050, 7065, 7080, 7095, 7110, 7125, 7140, 7155, 7170, 7185, 7200, 7215, 7230, 7245, 7260, 7275, 7290, 7305, 7320, 7335, 7350, 7365, 7380, 7395, 7410, 7425, 7440, 7455, 7470, 7485, 7500, 7515, 7530, 7545, 7560, 7575, 7590, 7605, 7620, 7635, 7650, 7665, 7680, 7695, 7710, 7725, 7740, 7755, 7770, 7785, 7800, 7815, 7830, 7845, 7860, 7875, 7890, 7905, 7920, 7935, 7950, 7965, 7980, 7995, 8010, 8025, 8040, 8055, 8070, 8085, 8100, 8115, 8130, 8145, 8160, 8175, 8190, 8205, 8220, 8235, 8250, 8265, 8280, 8295, 8310, 8325, 8340, 8355, 8370, 8385, 8400, 8415, 8430, 8445, 8460, 8475, 8490, 8505, 8520, 8535, 8550, 8565, 8580, 8595, 8610, 8625, 8640, 8655, 8670, 8685, 8700, 8715, 8730, 8745, 8760, 8775, 8790, 8805, 8820, 8835, 8850, 8865, 8880, 8895, 8910, 8925, 8940, 8955, 8970, 8985, 9000, 9015, 9030, 9045, 9060, 9075, 9090, 9105, 9120, 9135, 9150, 9165, 9180, 9195, 9210, 9225, 9240, 9255, 9270, 9285, 9300, 9315, 9330, 9345, 9360, 9375, 9390, 9405, 9420, 9435, 9450, 9465, 9480, 9495, 9510, 9525, 9540, 9555, 9570, 9585, 9600, 9615, 9630, 9645, 9660, 9675, 9690, 9705, 9720, 9735, 9750, 9765, 9780, 9795, 9810, 9825, 9840, 9855, 9870, 9885, 9900, 9915, 9930, 9945, 9960, 9975, 9990

Answer 2

There is a total of 600 four-digit numbers which are divisible by 15 and this can be determined by using the arithmetic progression.

Given :

Four-digit numbers are divisible by 15 and have 15 as the two middle digits.

Arithmetic progression can be used to determine the total number of four-digit numbers which are divisible by 15.

So by simply calculating in mind, it can be easily found out that the first four-digit number which is divisible by 15 is 1005 and similarly the last four-digit number divisible by 15 is 9990.

The [tex]\rm T_{n}[/tex] term formula in the arithmetic progression is given by:

[tex]\rm T_n = a + (n-1)d[/tex]    ----- (1)

where 'a' is the first term, 'd' is the difference between two consecutive numbers, [tex]\rm T_{n}[/tex] is the last term in the progression, and 'n' is the total number of terms.

According to the given data the value of 'a' is 1005, the value of the last term [tex]\rm T_{n}[/tex] is 9990 and the difference 'd' is 15.

Put the values of a, d, and [tex]\rm T_{n}[/tex] in the equation (1).

[tex]9990=1005+(n-1)15[/tex]

8985 = (n - 1)15

599 = n - 1

n = 600

Therefore, there is a total of 600 four-digit numbers which are divisible by 15.

For more information, refer to the link given below:

https://brainly.com/question/13773036


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Step-by-step explanation:


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Answers

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Answers

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Answers

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Answers

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Answers

Answer:

The answer is D

Step-by-step explanation:

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Answers

m=4/1
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A.

B.

C.

D.

Answers

Answer:

B. 7 1/2

Step-by-step explanation:

1. To solve this problem, we have to multiply 2 1/2 by the reciprocal of 1/3.

In other words, multiply 2 1/2 by the inverse of 1/3, which is 3.

2. (Solving)

[tex]2\frac{1}{2} *3[/tex] [tex]\frac{5}{2} *3[/tex] [tex]\frac{15}{2}[/tex] [tex]7\frac{1}{2}[/tex]

Therefore, the answer is B. 7 1/2.

Answer:

its B mark branli.est pls

Step-by-step explanation:

Look at attached link

Answers

The answer is -29/16
Have a great day/night !

Answer:

[tex]-1\frac{13}{16}[/tex]

Step-by-step explanation:

Hello There!

First let's put our equation to get started

[tex]-3\frac{5}{8}\cdot\frac{1}{2}[/tex]

We can make this an improper fraction by multiplying the integer with the denominator.

Then you would add the total you got with multiplying the total that you got from the whole number and the denominator

DefinitionAn integer is colloquially defined as a number that can be written without a fractional component

[tex]-\frac{29}{8} \cdot\frac{1}{2}[/tex]

Now we can solve it

[tex]-29\cdot1=-29[/tex]

[tex]8\cdot2=16[/tex]

Now our equation is

[tex]-\frac{29}{16}[/tex]

Reduce

Definition - reduction refers to the rewriting of an expression into a simpler form. For example, the process of rewriting a fraction into one with the smallest whole-number denominator possible

Once we've reduced we will have our equation being

[tex]-1\frac{13}{16}[/tex]

Have a good day :) !

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Answers

Answer: 4

Step-by-step explanation:

(4,-2) will be point 1, (7,10) will be point 2. The order doesn't matter.

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slope = 10 - (-2) / 7 - 4

slope = 12 / 3

slope = 4

The slope of the line that passing through (4, -2) and (7, 10) is 11/3.

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The equation of a line is given by:

y = mx + c

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Example:

The slope of the line y = 2x + 3 is 2.

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We have,

(4, -1) = (a, b) and (7, 10) = (c, d)

Slope:

= (d - b) / (c - a)

= (10 + 1) / (7 - 4)

= 11 / 3

Thus,

The slope is 11/3.

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Answers

if f(x) = -x^2 - 4

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If f(x) = (-x)^2 - 4

Then

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f(1) = 1 - 4

f(1) = -3
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