2265 g Fe₃O₄
General Formulas and Concepts:Math
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightChemistry
Atomic Structure
Reading a Periodic TableStoichiometry
Using Dimensional AnalysisExplanation:Step 1: Define
[RxN - Balanced] Fe₃O₄ + 4H₂ → 3Fe + 4H₂O
[Given] 705.0 g H₂O
Step 2: Identify Conversions
[RxN] 4 mol H₂O → 1 mol Fe₃O₄
Molar Mass of H - 1.01 g/mol
Molar Mass of O - 16.00 g/mol
Molar Mass of Fe - 55.85 g/mol
Molar Mass of H₂O - 2(1.01) + 16.00 = 18.02 g/mol
Molar Mass of Fe₃O₄ - 3(55.85) + 4(16.00) = 231.55 g/mol
Step 3: Convert
Set up stoich: [tex]\displaystyle 705.0 \ g \ H_2O(\frac{1 \ mol \ H_2O}{18.02 \ g \ H_2O})(\frac{1 \ mol \ Fe_3O_4}{4 \ mol \ H_2O})(\frac{231.55 \ g \ Fe_3O_4}{1 \ mol \ Fe_3O_4})[/tex]Multiply/Divide/Cancel units: [tex]\displaystyle 2264.74 \ g \ Fe_3O_4[/tex]Step 4: Check
Follow sig fig rules and round. We are given 4 sig figs.
2264.74 g Fe₃O₄ ≈ 2265 g Fe₃O₄
How many moles are in 4.3 x 10 ^22 molecules of Na3PO4
Answer:
0.071 moles of Na₃PO₄ .
Explanation:
Given data:
Number of molecules of Na₃PO₄ = 4.3× 10²² molecules
Number of moles = ?
Solution:
1 mole contain 6.022 × 10²³ molecules
4.3× 10²² molecules × 1 mol / 6.022 × 10²³ molecules
0.71× 10⁻¹ mol
0.071 mol
The number 6.022 × 10²³ is called Avogadro number.
"It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance"
A nucleus with four protons has total positive charge
If the symbol X represents a central atom, Y represents outer atoms, and Z represents lone pairs on the central atom, the structure Y---:X:------Y could be abbreviated as XY2Z2.Classify these structures by the hybridization of the central atom. XY4Z2, XY4Z, XY5Z, XY2Z3, XY2Z, XY3Z, XY2Z2, XY3Z2,XY2,XY3,XY4,XY5,XY6
Answer:
XY4Z2- dsp2
XY4Z- sp3d
XY5Z- sp3d2
XY2Z3- sp3d
XY2Z- sp2
XY3Z- sp3
XY2Z2- sp3
XY3Z2- sp3d
XY2 - sp
,XY3- sp2
XY4- sp3
,XY5- sp3d
XY6- sp3d2
Explanation:
In the answer box I have shown the hybridization patterns of the various arrangement of bond pairs and lone pairs.
Hybridization was put forward to explain the shapes of molecules under the valence bond theory. All molecules having the same hybridization pattern are based on the same geometry. Deviations from the expected geometry may arise due to the presence of lone pairs.
Assuming a 25% efficiency, how many Calories would a horse need to consume to work at 1.0 hp for 2.0 hh ?
Answer:
E = 7.11 × [tex]10^{-7}[/tex] Cal
Explanation:
given data
efficiency = 25 %
solution
first we get here E by the power that is express as
p = [tex]\frac{E}{t}[/tex] ...........1
E = p × t
E = 1 × 2 × [tex]\frac{1hp}{746w} \times \frac{1hr}{3600 s}[/tex]
E = 7.447 × [tex]10^{-7}[/tex] J
and
Ein is get by efficiency
Ein = [tex]\frac{Eout}{\eta }[/tex] ..................2
Ein = [tex]\frac{7.447 \times 10^{-7}}{.25 }[/tex]
Ein = 29.788 × [tex]10^{-7}[/tex] J
so required energy is
E = 29.788 × [tex]10^{-7}[/tex] × [tex]\frac{1Cal}{4.184J}[/tex]
E = 7.11 × [tex]10^{-7}[/tex] Cal
[2071]State and explain Kohlrusch's law.
(2071]Why does the specific conductance decreases and equivalent conductance increase
with dilution of a solution of electrolyte?
ito unit How does it Vary with dilution?
1101
A compound is found to contain 7.962 % silicon , 20.10 % chlorine , and 71.94 % iodine by mass.
a. The empirical formula for this compound is_______ .
b. The molar mass for this compound is 352.8 g/mol. The molecular formula for this compound is:_____
Answer:
A. Empirical formula => SiCl₂I₂
B. Molecular formula = SiCl₂I₂
Explanation:
From the question given above, the following data were:
Silicone (Si) = 7.962 %
Chlorine (Cl) = 20.10 %
Iodine (I) = 71.94 %
Molar mass of compound = 352.8 g/mol
Empirical formula =?
Molecular formula =?
A. Determination of the empirical formula of the compound.
Si = 7.962 %
Cl = 20.10 %
I = 71.94 %
Divide by their molar mass
Si = 7.962 / 28 = 0.284
Cl = 20.10 / 35.5 = 0.566
I = 71.94 / 127 = 0.566
Divide by the smallest
Si = 0.284 / 0.284 = 1
Cl = 0.566 / 0.284 = 2
I = 0.566 / 0.284 = 2
Empirical formula => SiCl₂I₂
B. Determination of the molecular formula of the compound.
Empirical formula => SiCl₂I₂
Molar mass of compound = 352.8 g/mol
Molecular formula =?
Molecular formula = [SiCl₂I₂]ₙ
[SiCl₂I₂]ₙ = 352.8
[28 + (2×35.5) + (2×127)]n = 352.8
[28 + 71 + 254]n = 352.8
353n = 352.8
Divide both side by 353
n = 352.8 / 353
n = 1
Molecular formula = [SiCl₂I₂]ₙ
Molecular formula = [SiCl₂I₂]₁
Molecular formula = SiCl₂I₂
Increasing the force on an object _________ its acceleration, if the mass of the object stays the same
which of the following is NOT a function of the skeletal system?
A. supports the body
B. gives shape to the body
C. enables the body to move
D. yransports nlood throughout the body
Answer:
A yan hehehehe
salamat puso ma ah
PLEASE HELP ASAP I NEED IT
the answer is true the first one
Which atom is most likely to partake in chemical bonding given the number of valence electrons?
A. Krypton
B. Argon
C. Xenon
D. Boron
Need help****
Answer:
D
Explanation:
I hope this helps and have a great day
A sample of iron is put into a calorimeter (see sketch at right) that contains of water. The iron sample starts off at and the temperature of the water starts off at . When the temperature of the water stops changing it's . The pressure remains constant at . Calculate the specific heat capacity of iron according to this experiment. Be sure your answer is rounded to the correct number of significant digits.
Answer:
Therefore, the specific heat capacity of the iron is 0.567J/g.°C.
Note: The question is incomplete. The complete question is given as follows:
A 59.1 g sample of iron is put into a calorimeter (see sketch attached) that contains 100.0 g of water. The iron sample starts off at 85.0 °C and the temperature of the water starts off at 23.0 °C. When the temperature of the water stops changing it's 27.6 °C. The pressure remains constant at 1 atm.
Calculate the specific heat capacity of iron according to this experiment. Be sure your answer is rounded to the correct number of significant digits
Explanation:
Using the formula of heat, Q = mc∆T
where Q = heat energy (Joules, J), m = mass of a substance (g)
c = specific heat capacity (J/g∙°C), ∆T = change in temperature (°C)
When the hot iron is placed in the water, the temperature of the iron and water attains equilibrium when the temperature stops changing at 27.6 °C. Since it is assumed that heat exchange occurs only between the iron metal and water; Heat lost by Iron = Heat gained by water
mass of iron = 59.1 g, c = ?, Tinitial = 85.0 °C, Tfinal = 27.6 °C
∆T = 85.0 °C - 27.6 °C = 57.4 °C
mass of water = 100.0 g, c = 4.184 J/g∙°C, Tinitial = 23.0 °C, Tfinal = 27.6 °C
∆T = 27.6°C - 23.0°C = 4.6 °C
Substituting the values above in the equation; Heat lost by Iron = Heat gained by water
59.1 g * c * 57.4 °C = 100.0 g * 4.184 J/g.°C * 4.6 °C
c = 0.567 J/g.°C
Therefore, the specific heat capacity of the iron is 0.567 J/g.°C.
If the density of a certain oil is 0.8gcm3. What is the mass of 10 cm3 sample of this oil?
report your answer with one significant figure.
Taking into account the definition of density, the mass of the sample of oil with a volume of 10 cm³ and a density of 0.8 [tex]\frac{g}{cm^{3} }[/tex] is 8 grams.
Definition of densityDensity is defined as the property that matter, whether solid, liquid or gas, has to compress into a given space.
In other words, density is a quantity that allows us to measure the amount of mass in a certain volume of a substance.
Then, the expression for the calculation of density is the quotient between the mass of a body and the volume it occupies:
[tex]density=\frac{mass}{volume}[/tex]
From this expression it can be deduced that density is inversely proportional to volume: the smaller the volume occupied by a given mass, the higher the density.
Mass of the sample of oilIn this case, you know that:
Density= 0.8 [tex]\frac{g}{cm^{3} }[/tex]Volume= 10 cm³Replacing in the definition of density:
[tex]0.8 \frac{g}{cm^{3} } =\frac{mass}{10 cm^{3} }[/tex]
Solving:
mass= 0.8 [tex]\frac{g}{cm^{3} }[/tex] × 10 cm³
mass= 8 g
In summary, the mass of the sample of oil with a volume of 10 cm³ and a density of 0.8 [tex]\frac{g}{cm^{3} }[/tex] is 8 grams.
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What is CaF2(aq) + Rb
Answer:
RbF2 + Ca
Explanation:
Since Rb is located in IIA as well as Ca, Rb has ion form Rb2+
Hence CaF2 + Rb → RbF2 +Ca
Please be reminded, this answer may not be 100% correct
Arrange the compounds below in decreasing order of the ionic character of the bonds in them.
a. CsF
b. OF2
c. SrF2
d. F2
Answer: [tex]CsF[/tex] > [tex]SrF_2[/tex] > [tex]OF_2[/tex] > [tex]F_2[/tex]
Explanation:
The percent ionic character is used to determine if a bond is more ionic or covalent. More is the percent ionic character, the more ionic the molecule is. If the electronegativity difference between two elements is higher than 1.7 it will be considered as ionic.
The electronegativity difference for CsF is (3.98-0.79) = 3.19
The electronegativity difference for [tex]OF_2[/tex] is = (3.98-3.44) = 0.54
The electronegativity difference for [tex]SrF_2[/tex] is (3.98-0.95) = 3.0
The electronegativity difference for [tex]F_2[/tex] is 0.
Thus decreasing order of ionic character of the bonds is CsF > [tex]SrF_2[/tex] > [tex]OF_2[/tex] > [tex]F_2[/tex]
Marine chemist exam in the mass percent composition of manganese sulfide compound from ocean floor he determined that 60.2% of this compound is sulfur determine the mole ratio between manganese and sulfur
Explanation:
Let the mass of the compound be 100g.
There are 60.2g of sulfur.
Moles of sulfur
= 60.2g / (32.07g/mol) = 1.877mol
There are 100g - 60.2g
= 39.8g of manganese.
Moles of manganese
= 39.8g / (54.94g/mol) = 0.724mol
Mole ratio of manganese to sulfur
= 0.724mol : 1.877mol = 1 : 2.5.
2 NaOH (s) + CO2(g) → Na2CO3 (s) + H20 (I)
How many grams of water can be produced with 1.85 moles of NaOH
16.7 g H₂O
General Formulas and Concepts:Math
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightChemistry
Stoichiometry
Reading a Periodic TableUsing Dimensional AnalysisExplanation:Step 1: Define
[RxN - Balanced] 2NaOH (s) + CO₂ (g) → Na₂CO₃ (s) + H₂O (l)
[Given] 1.85 mol NaOH
Step 2: Identify Conversions
[RxN] 2 mol NaOH → 1 mol H₂O
Molar Mass of H - 1.01 g/mol
Molar Mass of O - 16.00 g/mol
Molar Mass of H₂O - 2(1.01) + 16.00 = 18.02 g/mol
Step 3: Stoichiometry
Set up: [tex]\displaystyle 1.85 \ mol \ NaOH(\frac{1 \ mol \ H_2O}{2 \ mol \ NaOH})(\frac{18.02 \ g \ H_2O}{1 \ mol \ H_2O})[/tex]Multiply/Divide: [tex]\displaystyle 16.6685 \ g \ H_2O[/tex]Step 4: Check
Follow sig fig rules and round. We are given 3 sig figs.
16.6685 g H₂O ≈ 16.7 g H₂O
How do I round 74,000 to have only one significant figure?
Answer:
7x10⁴.
Explanation:
Hello!
In this case, when rounding big number to a representation with less significant figures than it, we need to make sure we remove the spare figures and round up whether the next digit is five or more.
In such a way, for 74,000, we notice that 4 is not enough to round up the 7, that is why the number would contain a 7 only; moreover, to get rid of the thousand places, we need to introduce an exponent in 4 places, which means that the result would be:
7x10⁴.
Best regards!
50POINTS!
Using the ideal gas law (PV=nRT) solve for the missing. Variable. R= 0.08206atm*L/mol*k
If 22.9L of an ideal gas was collected at STP. How many moles of the gas were present?
A. 1.02 moles
B. 5.99 moles
C. 3.05 moles
D. 2.74 moles
Answer:
A. 1.02 moles .
Explanation:
Hello!
In this case, given the ideal gas equation, as we need to solve for moles, we divide both sides by RT to get:
[tex]n=\frac{PV}{RT}[/tex]
Thus, by plugging in the pressure and temperature at STP (1.00 atm and 273.15 K respectively) we obtain:
[tex]n=\frac{1.00atm*22.9L}{0.08206\frac{atm*L}{mol*K}*273.15K}\\\\n=1.02mol[/tex]
Therefore, the correct answer is A. 1.02 moles
Best regards!
The data below shows the change in concentration of dinitrogen pentoxide over time, at 330 K, according to the following process.
2N2O5(g) = 4NO2(g) + O2
[N2O5] Time (s)
0.100 0.00
0.066 200.00
0.044 400.00
a) Find the rate of disappearance of N2O5 from t=0 s to t=200s
b) Find the rate of appearance of NO2 from t=0 s to t =200s
Answer: a) [tex]1.7\times 10^{-4}[/tex]
b) [tex]3.4\times 10^{-4}[/tex]
Explanation:
The reaction is :
[tex]2N_2O_5(g)\rightarrow 4NO_2(g)+O_2(g)[/tex]
Rate = Rate of disappearance of [tex]N_2O_5[/tex] = Rate of appearance of [tex]NO_2[/tex]
Rate = [tex]-\frac{d[N_2O_5]}{2dt}[/tex] = [tex]\frac{d[NO_2]}{4dt}[/tex]
Rate of disappearance of [tex]N_2O_5[/tex] = [tex]\frac{\text {change in concentration}}{time}[/tex] = [tex]\frac{0.100-0.066}{200-0}=1.7\times 10^{-4}[/tex]
a) Rate of disappearance of [tex]N_2O_5[/tex] = [tex]-\frac{d[N_2O_5]}{2dt}[/tex]
Rate of appearance of [tex]NO_2[/tex] = [tex]\frac{d[NO_2]}{4dt}[/tex]
b) Rate of appearance of [tex]NO_2[/tex] = [tex]\frac{d[NO_2]}{dt}=2\times 1.7\times 10^{-4}}=3.4\times 10^{-4}[/tex]
A) Find the rate of disappearance of [tex]N_2O_5[/tex] from t = 0 s to t = 200s
[tex]Rate = \frac{1}{2}(\frac{-\delta N_2O_5}{\delta t})\\\\Rate = -\frac{1}{2}(\frac{0.066 - 0.100}{200 - 0})\\\\Rate = 8.5*10^{-5}[/tex]
B) Find the rate of appearance of [tex]NO_2[/tex] from t = 0 s to t = 200s
According to rate law,
[tex]\frac{1}{2}(\frac{-\delta N_2O_5}{\delta t}) = \frac{1}{4}(\frac{\delta NO_2}{\delta t})\\\\8.5*10^{-5} = \frac{1}{4}(\frac{\delta NO_2}{\delta t})\\\\\frac{\delta NO_2}{\delta t} = 4 * 8.5*10^{-5}\\\\Rate = 3.4*10^{-4}[/tex]
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(9) How many moles of oleum in 1780. g of oleum? - Write an equation to summarize the process.
Answer:
1. 10moles
2. Find the summarized equation below
Explanation:
Mole = mass ÷ molar mass
Molar mass of oleum (H2S2O7) = 1(2) + 32(2) + 16(7)
= 2 + 64 + 112
= 178g/mol
According to the information provided, the mass of oleum is 1780g, hence, the number of moles in it is:
Mole = 1780/178
Mole = 10moles
2. The summarized equation of the contact process is:
1) S + O2 → SO2
2) 2SO2 + O2 → 2SO3
3) SO3 + H2SO4 (conc. sulfuric acid) → H2S2O7
4) H2S2O7 + H2O → 2H2SO4 (dilute sulfuric acid)
what can scientists learn from index fossils?
Answer:
dating and correlating the strata in which it is found
Explanation:
Answer:
The correct answer is A:The age of an unfamiliar layer of rock
Explanation:
I promise that I got it correct on A P E X <3
Which of the statements about liquids and gases are true?
Both liquids and gases have a definite volume.
O The particles in liquids and gases can move past one another
freely
Both liquids and gases have a definite shape.
Neither liquids nor gases have a definite shape.
Which of the statements about liquids and gases are true?
Answer:The particles in liquids and gases can move past one another freely.
#CARRYONLEARNING #STUDYWELLWhich of the statements about liquids and gases are true?
Choosing:Both liquids and gases have a definite volume.
The particles in liquids and gases can move past one another freely
Both liquids and gases have a definite shape.
Neither liquids nor gases have a definite shape.
Answer:The particles in liquids and gases can move past one another freely.
#READINGHELPSWITHLEARNING #CARRYONLEARNING #STUDYWELLAccording to Image 2, which tectonic plate is composed of the largest percentage of oceanic lithosphere?
A. African Plate
B. Eurasian Plate
C. Indian Plate
D. Nazca Plate
Answer:
I think the answer is A the Afracan plate
Explanation:
hope this helps:)
94.9 grams of Br is equivalent to how many moles of Br?
Answer:
The answer is 79.904.
Explanation:
We assume you are converting between grams Br and mole.
You can view more details on each measurement unit:
molecular weight of Br or mol
The SI base unit for amount of substance is the mole.
1 grams Br is equal to 0.012515018021626 mole.
Note that rounding errors may occur, so always check the results.
Use this page to learn how to convert between grams Br and mole.
Type in your own numbers in the form to convert the units!
give 5 stars rn
The element in Period 4 and Group 14 of the Periodic Table would be classified as a
Answer:
Chalcogen
Explanation:
carbon dioxide is in a steel tank at 20 degrees celsius and 10 liters. what is the volume on the gas when the tank is heated to 100 degrees celsius?
Answer:
12.73 L
Explanation:
Given that,
Initial temperature, [tex]T_i=20^{\circ}=20+273=293\ K[/tex]
Initial volume, [tex]V_i=10\ L[/tex]
We need to find the volume on the gas when the tank is heated to 100 degrees celsius or 373 K.
We know that volume is directly proportional to the temperature of the gas. Using above relation,
[tex]\dfrac{V_i}{T_i}=\dfrac{V_f}{T_f}\\\\V_f=\dfrac{V_iT_f}{T_i}[/tex]
Putting all the values,
[tex]V_f=\dfrac{10\times 373}{293}\\\\V_f=12.73\ L[/tex]
So, the final volume of the gas is 12.73 L.
A student collected a 1.28 g sample of Magnesium. How many atoms of Mg are in his sample?
A student did an experiment that called for 1.24 x 1024 molecules of CaO. What is the mass of her reactant?
A student reacted 0.0405 g of glucose (C6H12O6). How many molecules of glucose did he react?
How can your knowledge of acids and bases
help you approach this problem to keep your soil
viable?
HELP NOW
Answer:
How can we make use of acids or bases to remove heavy metals from soils? We can remove heavy metals from soil by adding acid and catching the solution that drains through. Acids can react with metals turning metalic compounds which can be dissolved by water and washed away. Improve crop yields?
Explanation:
What is the coefficient, subscript for V, and subscript for O in V2O5
Answer: Coefficient 0
subscript for V 2
subscript for O 5
Explanation: yes
There is no coefficient in V₂O₅ and the subscript of vanadium V is 2 and the subscript of oxygen is 5.
What is vanadium pentoxide ?Vanadium pentoxide is an ionic compound formed by donating electrons from the vanadium metal to oxygen. The chemical formula of vanadium pentoxide is V₂O₅.
The chemical formula of a compound is written in terms of the chemical symbol of each constituent elements and the number of their atoms. The number of atoms is written as subscript for the chemical symbols.
In V₂O₅, there are are 2 vanadium atoms and 5 oxygen atoms. Coefficients are numbers prior to the formula in reaction. Here there is no coefficient and the subscript for V is 2 and that of O is 5.
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PLS HELP GIVING 100 PTS EASY SCIENCE HELP PLS
Answer:
B hope it helps
Explanation:
