Therefore, 20,500 Joules of energy can heat 1,104.3 grams of water from 10 degrees Celsius to 45 degrees Celsius.
Specific heat capacity
Calculate the energy (in Joules) required to heat 1 gram of water from 10 degrees Celsius to 45 degrees Celsius:
Q = m * c * ΔT
Q = 1 gram * 4.184 Joules/gram-degree Celsius * (45 - 10) degrees Celsius
Q = 18.47 Joules
Calculate the amount of water (in grams) that can be heated with 20,500 Joules of energy:
20,500 Joules / 18.47 Joules = 1,104.3 grams
Learn more about Specific heat capacity here:
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