how many h+ ions can the acid h3po4 donate per molecule?

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Answer 1

The acid H3PO4 can donate three hydrogen ions (H+) per molecule.

Thus, the number of H+ ions that the acid H3PO4 can donate per molecule is 3.Explanation:H3PO4 is also known as phosphoric acid. Phosphoric acid is an inorganic mineral acid that is commonly used in fertilizers, detergents, and food additives.

The chemical formula of H3PO4 is H3PO4 which implies that it has three hydrogen ions that are attached to the phosphate anion.Each hydrogen ion, which is donated by H3PO4, has the ability to donate a single positive hydrogen ion or proton (H+).

Therefore, since H3PO4 has three hydrogen ions, it has the ability to donate three H+ ions per molecule (per H3PO4 molecule).

In other words, one molecule of H3PO4 can donate three hydrogen ions.

Therefore, the number of H+ ions that the acid H3PO4 can donate per molecule is 3.

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Related Questions

what is the mass of 12.82 moles of lithium (li) atoms?

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The mass of 12.82 moles of lithium (Li) atoms is 88.89 g.

The molar mass of Lithium (Li) is 6.94 g/mol. Therefore, the mass of 12.82 moles of lithium (Li) atoms can be calculated as follows:

The number of moles of lithium (Li) = 12.82 mol

Molar mass of Lithium (Li) = 6.94 g/mol

We know that the mass of one mole of an element is equal to its atomic or molecular mass in grams.Therefore, the mass of 1 mole of Li atoms is equal to its molar mass which is 6.94 g/mol.

Then the mass of 12.82 moles of Li atoms can be found using mole to mass conversion as follows:

Mass = Number of moles × Molar mass

= 12.82 mol × 6.94 g/mol

= 88.89 g.

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earning current is applied to an aqueous solution of lithium sulfide. What is produced at the anode? What is produced at the cathode? O o2(g) O s(s) o Lis O Li(s) Hz(g) O O2(g) O s(s) O H2(g) Map

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When an electrical current is applied to an aqueous solution of lithium sulfide, hydrogen gas will be produced at the cathode and sulfur will be produced at the anode.

At the cathode, positively charged hydrogen ions (H+) gain electrons and are reduced to hydrogen gas (H2).2H+ + 2e- → H2

At the anode, negatively charged sulfide ions (S2-) lose electrons and are oxidized to form elemental sulfur (S).

S2- → S + 2e-

It's worth noting that lithium ions (Li+) will also be present in the solution but they will not be produced at either the anode or cathode.

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