Calculate the concentration of all species in a 0.140 M solution of H2CO3.
The species are H2CO3,HCO3-, CO3^2-, H30,OH.
Can anyone help show me how to solve this? There are a couple up already, but they are not correct. Please help me out.

Answers

Answer 1

The concentration of the species in a 0.140 M solution of H₂CO₃ is given by:

[H₂CO₃] = 0.140 M, [HCO₃⁻] = 1.45×10^−7 M, [CO₃²⁻] = 1.45×10^−10 M, [H₃O⁺] = 4.5×10^−4 M, [OH⁻] = 2.2×10^−11 M.

Carbonic acid is a diprotic acid, which means that it has two acid dissociation constants. The first step is for the acid to donate a proton to form bicarbonate, and the second step is for the acid to donate another proton to form carbonate. H₂CO₃(aq) + H₂O(l) ⇌ H₃O⁺(aq) + HCO₃⁻(aq) Ka₁ = 4.3×10−7

HCO₃⁻(aq) + H₂O(l) ⇌ H₃O⁺(aq) + CO₃²⁻(aq) Ka₂ = 4.7×10−11

The formula for the concentrations of the species present in the solution is as follows:

[H₂CO₃] = 0.140 M

[HCO₃⁻] = Ka₁

[H₂CO₃]/[H₃O⁺] = 1.45×10^−7 M

[CO₃²⁻] = Ka₂[HCO₃⁻]/[H₃O⁺]

= 1.45×10^−10 M

[H₃O⁺] = Ka₁[H₂CO₃]/[HCO₃⁻]

= 4.5×10^−4 M

[OH⁻] = Kw/[H₃O⁺] = 2.2×10^−11 M, where Kw is the ion product constant for water.

Learn more about diprotic acid here:

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