. How many moles of BaSO4 could be obtained from 0.75moles of BaCl2 via the precipitation reaction:
BaCl2(aq) + Na2S04(aq) --> 2NaCl(aq) + BaSO4(s) ?​

Answers

Answer 1

Answer:

0.75 moles of BaSO4

Explanation:

Based on the balanced equation:

BaCl2(aq) + Na2S04(aq) --> 2NaCl(aq) + BaSO4(s)

1 mole of BaSO4 is obtained from 1 mole of BaCl2 when Na2SO4 is in excess.

That means if you add 0.75 moles of BaCl2, the moles of BaSO4 that could be obtained are the same:

0.75 moles of BaSO4


Related Questions

1. Describe the general procedure on how to wash glassware used for organic lab experiments. Also, include what the common solvent used to wash organic glassware

Answers

Explanation:

As a number of glassware are used in lab experiments so it is necessary that they should be cleaned properly after and before the experiment.

This can be done as follows.

1). At first acetone is used to rinse the glassware. If water soluble contents present in the glassware then use deionized water after rinsing it with acetone and if ethanol soluble components are present there then rinse with ethanol followed by rinses with deionized water.

2). When glassware are dirty in such a manner that they cannot be washed immediately then soak them in water for a certain period of time. This can help in removing the dirt or chemicals easily from the glassware.

3). The laboratory glassware can be easily washed with detergents or products like lab wash, alconox etc. Once these glassware are thoroughly cleaned then rinse them 3 times with deionized water.

The name of an oxyacid has the suffix -ous acid. What is the suffix of the oxyanion?

Answers

Answer:

-ate

Explanation:

Match the alkane names and structures.
-butane
-methane
-ethane
-propane

Answers

Answer:

Explanation:

Here is the names and matches of butane methane ethane propane

Butane goes to the second one

Methane goes to the third one

Ethane is the first one

Propane is the last one

How much energy does an X-ray with an 8 nm (8 x 10-9m) wavelength have?
A. 1.99 x 10-25 J
B. 3.33 x 1016 J
C. 2.48 x 10-17 j
D. 8.28 x 10-26 J

Answers

Answer:

it would be option C

Explanation:

Speed of light = 3×10^8m/s

Planck's constant = 6.626×10^-34 Js

Wavelength = 8 x 10^-9 m

Energy = [(3×10^8) * (6.626×10^-34)] / 8 x 10^-9

Energy = [19.878×10^(8-34)] / 8 x 10^-9

Energy = 2.48475 × 10^(-26+9)

Energy = 2.48×10^-17 J

Analyze the reasons why a dropping mercury electrode is better as
compared to a conventional electrode.

Answers

yes doğru yapmissin aferin

What is the mass (g) of 1.00 L water if the density is 1.000 g/mL.

Answers

Answer:

1000g

Explanation:

1 * 1000 = 1000

In a physical change, the _____ does not change.

Answers

Physical changes occur when objects or substances undergo a change that does not change their chemical composition. This contrasts with the concept of chemical change in which the composition of a substance changes or one or more substances combine or break up to form new substances.

What is a net ionic equation?
A. An equation showing only what is involved in the reaction
B. An equation that is balanced on both sides
C. An equation that shows all dissolved compounds as ions
O D. An equation that shows all substances as compounds

Answers

Answer:

I think A is the correct answer

A 25.0 mL solution of quinine was titrated with 0.50 M hydrochloric acid, HCl. It was found that the solution contained 0.100 moles of quinine. What was the pH of the solution after 50.00 mL of the HCl solution were added

Answers

Answer:

[tex]pH=11.45[/tex]

Explanation:

Hello there!

In this case, since the chemical equation representing the neutralization of the weak base quinine can be written as follows:

[tex]C_{20}H_{24}N_2O_2+HCl\rightarrow C_{20}H_{25}N_2O_2^+Cl^-[/tex]

Whereas we have 0.100 moles of the base and those of acid as shown below

[tex]n_{acid}=0.50molHCl/L*0.05000L=0.025molHCl[/tex]

Which means that the remaining moles of quinine are:

[tex]n_{C_{20}H_{24}N_2O_2}^{final}=0.100mol-0.025mol=0.075mol[/tex]

And the resulting concentration:

[tex][C_{20}H_{24}N_2O_2]=\frac{0.075mol}{(0.025+0.050)L} =1.00M[/tex]

Now, the calculation of the pH requires the pKb of quinine (5.1) as its ionization in water produces OH- ions:

[tex]C_{20}H_{24}N_2O_2+H_2O\rightleftharpoons OH^-++C_{20}H_{25}N_2O_2^+[/tex]

And the equilibrium expression is:

[tex]Kb=\frac{[C_{20}H_{24}N_2O_2][C_{20}H_{25}N_2O_2 ^+]}{[C_{20}H_{24}N_2O_2]} \\\\10^{-5.1}=\frac{x^2}{1.00M}\\\\ 7.94x10^{-6}=\frac{x^2}{1.00M}[/tex]

Which is solved for x as follows:

[tex]x= \sqrt{7.94x10^{-6}*1.00M}\\\\x=0.00282M[/tex]

Which means the pOH is:

[tex]pOH=-log(0.00282)=2.55[/tex]

And the pH:

[tex]pH=14-2.55\\\\pH=11.45[/tex]

Regards!

Fixed place that you use to help you to find position or measurements ?

Answers

Answer:

DO YOU PLAY COD OR FORTNIT3

Explanation:

What must happen for ice to melt at a given pressure?
A. The average kinetic energy of the water molecules must decrease.
B. Thermal energy must be transferred to the ice from its
surroundings.
C. The orderliness of the water molecules must decrease.
D. Thermal energy must be transferred from the ice to its
surroundings.

Answers

Answer:

D

Explanation:

thermal energy must be transferred from the ice to it's surroundings

Thermal energy is the heat and energy present in the system. The thermal energy must be dissipated from ice to the surroundings to melt and produce liquid. Thus, option D is correct.

What is thermal energy?

Thermal energy is present in any substance in the form of energy and heat that depends on kinetic energy, orderliness, randomness, temperature, etc. It is passed from a substance to the surrounding at a lesser temperature.

The ice can melt into a liquid when it loses its thermal energy and heat to the surrounding with increased kinetic energy and releases the temperature to the area with a temperature less than the ice.

Therefore, the heat from ice will get dissipated to the outer environment to melt.

Learn more about thermal energy here:

https://brainly.com/question/11278589

#SPJ5

What is the molar mass of Na2SO4?
O A. 142.04 g/mol
O B. 71.05 g/mol
O c. 238.22 g/mol
O D. 94.04 g/mol

Answers

I believe its D due to my thinking

Answer: A. 142.04 g/mol

Explanation:

what is the magnitude of the force of gravity acting in a box that has a mass of 100 kg at sea level?

Answers

Answer:

force of gravity, F = 980 N

Explanation:

Given that,

The mass of the box, m = 100 kilograms

first we will need to find the magnitude of the force of acting on a box. we can used it with Newton second law.

F = ma

a = acceleration

Here,

F = mg

g = acceleration due to gravity

F=100\ kg\times 9.8\ m/s^2F=100 kg×9.8 m/s2

F = 980 N

Hence, the force acting on the object is 980 N.

980 N Fs I’m sure I’m sorry if it’s incorrect

Over time, rocks break down into sediment by wind, water, ice, and/or gravity. This process is commonly referred to as
chemical change

Answers

Answer:

Explanation:

Chemical change

Molecule contains carbon, hydrogen and sulfur atoms. When a sample of 0.535g of this compound is burnt in oxygen, 1.119 g of CO2and 0.229 gof H2O and 0.407g of SO2are obtained.
Calculate its empirical formula.

Answers

Answer:

The empirical formula is, C4H4S

Explanation:

Number of moles of carbon = 1.119 g/ 44g/mol = 0.025 moles

Mass of Carbon= 0.025 moles × 12 g/ mole = 0.3 g

Number of moles of hydrogen = 0.229/18g/mol × 2 = 0.025 moles

Mass of hydrogen = 0.025 moles × 1 = 0.025 g

Number of moles of sulphur = 0.407g/ 64 g/mol = 0.0064 moles

Mass of sulphur= 0.0064 moles ×32 = 0.2 g

Now we obtain the mole ratios by dividing through by the lowest ratio.

C- 0.025 moles/ 0.0064 moles, H- 0.025 moles/ 0.0064 moles, S- 0.0064 moles/0.0064 moles

C4H4S

Use the following information to calculate the concentration, Ka and pka for an unknown monoprotic weak acid. (8 pts.) 20.00 mL
Volume of unknown weak acid used : 20.00 mL Total volume of 0.20 M NaOH required to reach the equivalence point: 18.50 mL Initial pH of the weak acid 2.87

Answers

Answer:

Concentration: 0.185M HX

Ka = 9.836x10⁻⁶

pKa = 5.01

Explanation:

A weak acid, HX, reacts with NaOH as follows:

HX + NaOH → NaX + H2O

Where 1 mole of HX reacts with 1 mole of NaOH

To solve this question we need to find the moles of NaOH at equivalence point (Were moles HX = Moles NaOH).

18.50mL = 0.01850L * (0.20mol / L) = 0.00370 moles NaOH = Moles HX

In 20.0mL = 0.0200L =

0.00370 moles HX / 0.0200L = 0.185M HX

The equilibrium of HX is:

HX(aq) ⇄ H⁺(aq) + X⁻(aq)

And Ka is defined as:

Ka = [H⁺] [X⁻] / [HX]

Where [H⁺] = [X⁻] because comes from the same equilibrium

As pH = 2.87, [H+] = 10^-pH = 1.349x10⁻³M

Replacing:

Ka = [H⁺] [H⁺] / [HX]

Ka = [1.349x10⁻³M]² / [0.185M]

Ka = 9.836x10⁻⁶

pKa = -log Ka

pKa = 5.01

As: [Ar]4s23d104p3 [Ar]4s23d104p2 [Kr]4s24d104p3 [Kr]4s23d104p3

Answers

Answer:

[Ar]4s23d104p3

Explanation:

Answer:

[Ar]4s23d104p3 (Option A)

Explanation:

on edge2021 :D

Explain how a scanning electron microscope (SEM) can be used in combination with an energy dispersive X-ray spectrometer (EDS) to perform elemental analysis on extremely small particles by placing the statements in the order that they occur.

Answers

Answer:

SEM provides detailed high resolution images of the sample by rastering a focussed electron beam across the surface and detecting secondary or backscattered electron signal. An Energy Dispersive X-Ray Analyzer (EDX or EDA) is also used to provide elemental identification and quantitative compositional information.

Energy Dispersive X-Ray Spectroscopy (EDS) is a chemical microanalysis technique used in conjunction with scanning electron microscopy (SEM).

The EDS technique detects x-rays emitted from the sample during bombardment by an electron beam to characterize the elemental composition of the analyzed volume.The SEM is an instrument that produces a largely magnified image by using electrons instead of light to form an image. A beam of electrons is produced at the top of the microscope by an electron gun. Once the beam hits the sample, electrons and X-rays are ejected from the sample. The electrons in the beam interact with the sample, producing various signals that can be used to obtain information about the surface topography and composition.

Learn more:

brainly.com/question/15899795

Alcohols undergo an oxidation when treated with Dess-Martin periodinane in dichloromethane.

a. True
b. False

Answers

Answer:

True

Explanation:

the answer to your question is true

There are two stereoisomers of 1-tert-butyl-4-chloro-cyclohexane. One of these isomers reacts with sodium ethoxide in an E2 reaction that is 500 times faster than the reaction of the other isomer. Identify the isomer that reacts faster, and explain the difference in rate for these two isomers.

Answers

Answer:

Explanation:

Answer:

cis-isomer reacts faster

Explanation:

The missing diagrams in the question are attached in the first image below and the isomers that react faster are shown in the second image attached.

The cis-isomer quickly follows E2 reaction due to the fact that it is locked in a chair conformation whereby chlorine dominates an axial position, as displayed in drawing C as well as the leaving group Cl which is antiperiplanar to a beta proton.

Due to the bulkiness of tert-butyl, the trans-isomer is Basically trapped in a chair configuration, with chlorine occupying an equatorial position as displayed in drawing A below, thus leaving the group isn't antiperiplanar to a beta proton.

Tert butyl favors an equatorial position due to its bulkiness. This makes the Cl to assume an axial position in an isomer

The difference:

From the second image attached below, in the first diagram(1):

Suppose H is antiperiplanar, C-H bond electrons reach antibonding orbitals of C-Cl, assisting in the breakdown of the C-Cl bond and therefore speeding up the process.

From the second diagram(2) in the second image:

Unless Cl is in the axial position would it have β-hydrogen in the antiperiplanar position. Because tert-butyl prefers equatorial location, the Cl occupies equatorial position in the trans isomer.

As a result, the reaction is slower and there is no β-hydrogen antiperiplanar to Cl.

Please write the right question. I’ll mark as brainliest if it’s right

Answers

Answer:

The correct answer is - A. alkane and E. Branched.

Explanation:

Alkane is saturated hydrocarbons that are combined with a single bond they can be either linear, branched, or cyclic hydrocarbons. A branched-chain or branched compound is a compound that has alkyl groups bonded to its central carbon chain.

Branched alkanes contain only carbon atoms and hydrogen atoms bonded with these carbon atoms in different branches, with carbons connected to other carbons by single bonds only, but the molecules contain branches.

GenAlex Medical, a leading manufacturer of medical laboratory equipment, is designing a new automated system that can detect normal levels of dissolved triiodothyronine ( to ), using a blood sample that is as small as . Calculate the minimum mass in picograms of triiodothyronine that the new system must be able to detect. Be sure your answer has the correct number of significant digits.

Answers

Answer:

0.87 pg

Explanation:

GenAlex Medical, a leading manufacturer of medical laboratory equipment, is designing a new automated system that can detect normal levels of dissolved triiodothyronine (230. to 660 pg/dL), using a blood sample that is as small as 380 μL. Calculate the minimum mass in picograms of triiodothyronine that the new system must be able to detect. Be sure your answer has the correct number of significant digits.

Step 1: Convert 380 μL to deciliters

We will use the following conversion factors.

1 L = 10⁶ μL1 L = 10 dL

380 μL × 1 L/10⁶ μL × 10 dL/1 L = 3.8 × 10⁻³ L

Step 2: Calculate the minimum mass of triiodothyronine that can be found in a 3.8 × 10⁻³ L blood sample

Since we are looking for the minimum mass, we will use the lower limit of the concentration interval (230. pg/dL).

3.8 × 10⁻³ L × 230. pg/dL = 0.87 pg

A sample of flammable liquid is placed into an enclosed cylinder which is then fitted with a movable piston. Initially the cylinder contains a volume of 8.20 L. The sample is ignited producing gas and releasing 427.8 J of energy. To what volume will the cylinder expand to if it must expand against a pressure of 826.1 mmHg. Assume all the energy released is converted to work used to push the piston?


760 mmHg = 1 atm
101.3 J = 1 L atm

Answers

Answer:

12.09 L

Explanation:

Step 1: Convert 826.1 mmHg to atm

We will use the conversion factor 760 mmHg = 1 atm.

826.1 mmHg × 1 atm/760 mmHg = 1.087 atm

Step 2: Convert 427.8 J to L.atm

We will use the conversion factor 101.3 J = 1 L.atm.

427.8 J × 1 L.atm/101.3 J = 4.223 L.atm

Step 3: Calculate the change in the volume

Assuming the work done (w) is 4.223 L.atm against a pressure (P) of 1.087 atm, the change in the volume is:

w = P × ΔV

ΔV = w/P

ΔV = 4.223 L.atm/1.087 atm = 3.885 L

Step 4: Calculate the final volume

V₂ = V₁ + ΔV

V₂ = 8.20 L + 3.885 L = 12.09 L

A substance contains just copper and oxygen analysis shows that a 12.5g sample contains 11.1 of cooper and 1.4 of oxygen what is the formula of this red powder

Answers

Answer:

The formula of the compound is Cu₂O.

Explanation:

From the question given above, the following data were obtained:

Mass of compound = 12.5 g

Mass of copper (Cu) = 11.1 g

Mass of oxygen (O) = 1.4 g

Formula of compound =?

The formula of the compound can be obtained as follow:

Cu = 11.1 g

O = 1.4 g

Divide by their molar mass

Cu = 11.1 / 63.5 = 0.175

O = 1.4 / 16 = 0.0875

Divide by the smallest

Cu = 0.175 / 0.0875 = 2

O = 0.0875 / 0.0875 = 1

Therefore, the formula of the compound is Cu₂O.

Convert speed of 581 miles an hour to units of feet per minute Also so the unit analysis by dragging components into the unit factor factor's

Answers

Explanation:

answer is in photo above

If the initial concentration of N2O5 was 0.500 M and the concentration of N2O5 was 0.450 M after 0.100 s, what is the average rate of NO2 formation during the first 100 milliseconds

Answers

Answer:

The appropriate solution is "1 M/s".

Explanation:

The equation is:

[tex]2N_2O_5 \rightarrow4NO_2+O_2[/tex]

or,

[tex]\frac{1}{2}(-\frac{\Delta(N_2O_5)}{dt} ) =\frac{1}{4}\frac{\Delta (NO_2)}{dt}[/tex]

then,

The rate of [tex]NO_2[/tex] formation:

= [tex]\frac{\Delta NO_2}{dt}[/tex]

= [tex]\frac{4}{2} (-\frac{\Delta(N_2O_5)}{dt})[/tex]

= [tex]2(-\frac{\Delta (N_2O_5)}{dt} )[/tex]

= [tex]2(-\frac{(0.45-0.5)}{0.1} )[/tex]

= [tex]1 \ M/s[/tex]

Why do field researchers work with tribal healers in their search for new rainforest drugs

Answers

Answer:

See explanation

Explanation:

Drugs are obtained from plants. The rainforest zone has abundance of a variety of plant species due to the plentitude of rainfall all year round.

Many of these plants have known medicinal properties and have been used by tribal healers to cure diverse ailments.

Field researchers need to work closely with these tribal healers to identify plant species with observed medicinal properties. These plant species are now studied scientifically and the active ingredients in them are extracted and used to produce new potent drugs.

Read excerpt and answer 3 questions I’ll mark brainliest. Pls thank you

Answers

Answer:

please also share the excerpt

Explanation:

Thank you

What volume in mL of 0.220 M HBr solution is required to produce 0.0130 moles of HBr?

Answers

Answer: A volume of 59 mL of 0.220 M HBr solution is required to produce 0.0130 moles of HBr.

Explanation:

Given: Moles = 0.0130 mol

Molarity = 0.220 M

Molarity is the number of moles of solute present in liter of a solution.

[tex]Molarity = \frac{moles}{volume (in L)}[/tex]

Substitute the values into above formula as follows.

[tex]Molarity = \frac{moles}{volume (in L)}\\0.220 M = \frac{0.0130 mol}{Volume (in L)}\\Volume (in L) = 0.059 L[/tex]

As 1 L = 1000 mL

So, 0.059 L = 59 mL

Thus, we can conclude that a volume of 59 mL of 0.220 M HBr solution is required to produce 0.0130 moles of HBr.

1 What direction do
molecules move in?

Answers

Answer:

The majority of the molecules move from higher to lower concentration, although there will be some that move from low to high. The overall (or net) movement is thus from high to low concentration.

hope this helps!<3

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