How many moles of electrons must be transferred to plate out 110 g of manganese (MW ~ 55g/mol) from a solution of permanganate (MnO4-)

Answers

Answer 1

Answer:

14 mol e⁻

Explanation:

Step 1: Write the balanced half-reaction for the reduction of permanganate to manganese

8 H⁺(aq) + 7 e⁻ + MnO₄⁻(aq) ⇒ Mn(s) + 4 H₂O(l)

Step 2: Calculate the moles corresponding to 110 g of manganese

The molar mass of Mn is 55 g/mol.

110 g × 1 mol/55 g = 2 mol

Step 3: Calculate the number of moles of electrons needed to produce 2 moles of Mn

According to the half-reaction, 7 moles of electrons are required to produce 1 mole of Mn.

2 mol Mn × 7 mol e⁻/1 mol Mn = 14 mol e⁻


Related Questions

Which metal does not form cations of differing charges?

Answers

Transition metals

Most transition metals differ from the metals of Groups 1, 2, and 13 in that they are capable of forming more than one cation with different ionic charges. As an example, iron commonly forms two different ions

An alkyl groyp has a formula of CxH6, determine the value of x​

Answers

Answer:

i didnt understand

Explanation:

Answer:

x = 2 (C₂H₆)

Explanation:

The general formula for alkanes is CₓH₂ₓ₊₂

2x + 2 = 6

Simply solve for n:

2x = 4

x = 2

HELPPPPPPPPPPPPMEEEEEEEEEE

Answers

Answer:

25%

Explanation:

Cystic fibrosis is a recessive allele, meaning that the child must be aa to suffer the symptoms. Only 1/4 of the paired alleles is aa, so the probability of getting cystic fibrosis would be 25%.

75% is the chance because a capital letter means it’s a dominant allele meaning it’s a possible outcome there’s 3 capital letter for which it’s 75 since each box is worth 25

Identify each of the following as endothermic or exothermic.

a. Water in a pond evaporates.
b. Methane gas burns on a stove top.
c. Water freezes to form ice.
d. Energy flows from the system to the surroundings.
e. Energy flows from the surroundings to the system.

Answers

Answer:

Identify each of the following as endothermic or exothermic.

a. Water in a pond evaporates.

b. Methane gas burns on a stovetop.

c. Water freezes to form ice.

d. Energy flows from the system to the surroundings.

e. Energy flows from the surroundings to the system.

Explanation:

An exothermic reaction is the one in which heat energy is released.

An endothermic reaction is one in which heat energy is absorbed.

a. Water in a pond evaporates.

This process absorbs heat energy.

Hence, this is an example of an endothermic process.

b. Methane gas burns on a stovetop and release heat energy and hence this is an example of an exothermic reaction.

c. Water freezes to form ice.

In this process heat energy is released.So this is an example of exothermic reaction.

d. Energy flows from the system to the surroundings.

That means heat energy is released into the surroundings.

So, this is an example of exothermic process.

e. Energy flows from the surroundings to the system.

That means energy is absorbed by the system.

So, it is an endothermic process.

2. Energy cycles through ecosystems because it returns to the sun.


True or false


Please help I will give 50 points

Answers

Answer:

false

Explanation:

energy does not return to the sun, it returns to the plants or producers. if energy were to return to the sun, it would have to travel though space.

False or doesn’t, Energy does not cycle the way nutrients and atoms do.

Zinc sulfate is a 2-ion electrolyte,
dissociating 40% in a
certain concentration. Calculate its
dissociation (i) factor.
On the basis of 40% dissociation, 100
particles of zinc sulfate
will yield:
40zinc ions
40 sulfate ions
60undissociated particles
Jo 11:03

Answers

Answer: The value of i is 1.4 and 40% dissociation of 100 particles of zinc sulfate will yield 60 undissociated particles.

Explanation:

The equation used to calculate the Vant' Hoff factor in dissociation follows:

[tex]\alpha =\frac{i-1}{n-1}[/tex]

where,

[tex]\alpha [/tex] = degree of dissociation = 40% = 0.40

i = Vant' Hoff factor

n = number of ions dissociated = 2

Putting values in above equation, we get:

[tex]0.40=\frac{i-1}{2-1}\\\\0.40=i-1\\\\i=1.4[/tex]

The equation used to calculate the degee of dissociation follows:

[tex]\alpha =\frac{\text{Number of particles dissociated}}{\text{Total number of particles taken}}[/tex]

Total number of particles taken = 100

Degree of dissociation = 40% = 0.40

Putting values in above equation, we get:

[tex]0.40=\frac{\text{Number of particles dissociated}}{100}\\\\\text{Number of particles dissociated}=(0.40\times 100)=40[/tex]

This means that 40 particles are dissociated and 60 particles remain undissociated in the solution.

Hence, 40% dissociation of 100 particles of zinc sulfate will yield 60 undissociated particles.

True or false? All producers are at the top of the food web

Answers

Answer:

false all producers are at the top of food web

iodide (KI). Identify the correct products of this
reaction. (Note that NO3? is the nitrate ion, a
polyatomic ion.)
AgNO3 + KI – ?
AgK + INO3

Agl + KNO3
Ag + K + I + NO3
COMPLETE
What type of reaction is this?

Answers

Answer:

AgNO3 + KI → Agl + KNO3. Double-replacement reaction

Explanation:

Based on solubility rules, Silver, Ag produce an insoluble salt in presence of halides (Fluorides F-, Chlorides Cl-, Iodides, I-, and bromides Br-). That means the mixture of AgNO3 (Ag⁺ ions) with KI (I- ions) produce AgI as insoluble salt.

The reaction is:

AgNO3 + KI → Agl + KNO3

And this is a double-replacement reaction where the cations exchange of anion to produce 2 new compounds.

Answer:

AgI + KNO3

Explanation:

double replacement

What is the mass of Na2CO3 required to make a
500 mL standard solution of 0.400 mol/L Na2CO3?
a. 212 g
b. 23.4 g
c. 25.8 g
d. 27.39

Answers

Answer:

21.2 g

Explanation:

Step 1: Given data

Molar concentration of the solution (C): 0.400 mol/LVolume of solution (V): 500 mL (0.500 L)

Step 2: Calculate the moles of Na₂CO₃ (solute) in the solution

We will use the definition of molarity.

C = moles of solute / liters of solution

moles of solute = C × liters of solution

moles of solute = 0.400 mol/L × 0.500 L = 0.200 mol

Step 3: Calculate the mass corresponding to 0.200 moles of Na₂CO₃

The molar mass of Na₂CO₃ is 105.99 g/mol.

0.200 mol × 105.99 g/mol = 21.2 g

The chemical equation of the reaction between Hydrogen and Oxygen is given below
H2 + O2 → H2O
(a) Write down the reactants and product of this reaction
(b) This chemical equation is not balanced . Why?
(c) Balance the given equation
9. Consider the given unbalanced reaction
Na + O2 → Na2O
(a) Find out the mono atomic and diatomic molecules in this equation
(b) What is the chemical compound present in this equation
(c) Balance the given equation

Answers

Answer:

1. a. The reactants are H₂ and O₂; The product is H₂O

b. The equation is not balanced because the number of atoms of the elements reacting is not equal to the number of atoms produced. 2 atoms of oxygen reacted but only one atom of oxygen is produced.

c. 2 H₂ + O₂ ---> 2 H₂O

2. a. The monotonic molecule is the sodium molecule, Na, since itnis made up of only one atom in its molecule.

The diatomic molecule is oxygen molecule, O₂, since it is made up of two atoms in its molecule.

b. The chemical compound present is sodium oxide, Na₂O

c. 4 Na + O₂ ---> 2 Na₂O

Explanation:

In a chemical reaction, the reactants are the elements or compounds which are converted to a new substance whichnis known as the product. The products are the new substances formed from the reactants.

In the given equation of reaction below;

H₂ + O₂ ---> H₂O

a. The reactants are H₂ and O₂; The product is H₂O

b. The equation is not balanced because the number of atoms of the elements reacting is not equal to the number of atoms produced. 2 atoms of oxygen reacted but only one atom of oxygen is produced.

c. 2 H₂ + O₂ ---> 2 H₂O

2. Given the reaction equation below:

Na + O₂ ---> Na₂O

a. The monotonic molecule is the sodium molecule, Na, since it is made up of only one atom in its molecule.

The diatomic molecule is oxygen molecule, O₂, since it is made up of two atoms in its molecule.

b. The chemical compound present is sodium oxide, Na₂O since itconsists of two chemically combined elements, sodium and oxygen.

c. 4 Na + O₂ ---> 2 Na₂O

How many moles are in 3.5 x 10^24 molecules of methane gas?

Please show work, will give brainliest

Answers

Answer:

5.81 moles

Explanation:

To find the number of moles (n) in 3.5 x 10²⁴ molecules of methane gas, we divide the number of molecules by Avagadro's number (nA). That is,

n = number of molecules ÷ 6.02 × 10²³

According to this question, 3.5 x 10^24 molecules of methane gas was given, hence,

n = 3.5 × 10²⁴ ÷ 6.02 × 10²³

n = 3.5/6.02 × 10(24 - 23)

n = 0.5814 × 10¹

n = 5.81 moles

Determine the number of significant digits in each number and list the specific significant digits. 1. 306,000 2. 0.0073 3. 39.9999 4. 25.00 5. 40,000,021 6. 45,250.0 7. 0.00011 8. 420.030700

Answers

Answer:

1. 306,000: three significant figures because the last three zeros are not preceded by a decimal point.

2. 0.0073: two significant figures because the the leftmost zeros are not significant.

3. 39.9999: six significant figures because all these numbers are nonzero digits.

4. 25.00: four significant figures because right-handed zeros, after a decimal point, are significant.

5. 40,000,021: eight significant figures because intermediate zeros are significant.

6. 45,250.0: six significant figures because al the zeros are to the right of the nonzero digits.

7. 0.00011: two significant figures as well as #2.

8. 420.030700: nine significant figures because all the zeros are to the right of the first nonzero digits and after the decimal point.

Explanation:

Hello there!

In this case, by considering the given numbers, we can proceed as follows, by keeping in mind the rules for assigning significant figures:

1. 306,000: three significant figures because the last three zeros are not preceded by a decimal point.

2. 0.0073: two significant figures because the the leftmost zeros are not significant.

3. 39.9999: six significant figures because all these numbers are nonzero digits.

4. 25.00: four significant figures because right-handed zeros, after a decimal point, are significant.

5. 40,000,021: eight significant figures because intermediate zeros are significant.

6. 45,250.0: six significant figures because al the zeros are to the right of the nonzero digits.

7. 0.00011: two significant figures as well as #2.

8. 420.030700: nine significant figures because all the zeros are to the right of the first nonzero digits and after the decimal point.

Regards!

Which molecule is pentanoic acid?
ОА.
Н
1
НЕС-ОН
ОВ.
Н
ОН
ор.н.н

Answers

Answer:

PubChem CID 7991

Structure Find Similar Structures

Chemical Safety Laboratory Chemical Safety Summary (LCSS) Datasheet

Molecular Formula C5H10O2 or CH3(CH2)3COOH

Synonyms Valeric acid PENTANOIC ACID n-Valeric acid 109-52-4 n-Pentanoic acid More.

Learning Task 1. Read each item carefully. Choose the letter of your answer.
1. Which type of soil is characterized as having the finest particles holding greater amount of water?
A. Loam
B. Clay
C. Sand
2. Which type of soil is best for planting?
A. Loam
B. Clay
C. Sand
3. How does each soil types differ?
A. Texture
B. Color
C. Both A & B
4. Which type of soil do you usually expect if the community is along the seashore?
A. Loam
B. Clay
C. Sand
5. Why is soil important to living things?
A. Forms part of the earth where animals live
B. Provides the necessary nutrients needed by plants
C. Serves as a place where people live
D. All of the above​

Answers

Answer:

1. B

2. A

3. C

4. C

5. D

Explanation:

Soil is regarded as the solid unconsolidated material of the earth crust. Soil is of three different types namely: Sandy soil, clay soil and loamy soil. These three different soil types possess different properties that distinguish them. Some of them are:

- CLAY soil is characterized as having the finest particles and can hold greater amount of water i.e. have a high water holding capacity.

- LOAMY SOIL is the best soil type for planting agricultural crops because it has the highest concentration of nutrients that suited for plant growth.

- loamy, Sandy and clay differ in how we feel when touched i.e. texture, and colour.

- SANDY soils are the kind of soils that are found in Sea shores and beaches.

- Soil is important to living things as it forms part of the earth where animals live, provides the necessary nutrients needed by plants, serves as a place where people live.

What method is used to removed the unreacted copper (II) carbonate?​

Answers

Answer:

Filtration

Explanation:

Metal carbonate is insoluble, it is possible to filter off the unreacted substances leaving the desired salt solution

For an aqueous solution of sucrose (C12H22O11), determine:

the number of moles of sucrose in 1.50 L of this solution

Answers

Answer:WHAT GRADE WORK IS THIS ?

Explanation:

During the synthesis of 2,4-dinitrophenylhydrazone derivative, you were instructed to triturate the crude product with 10 mL of 2 M hydrochloric acid. What is the purpose of this trituration

Answers

Answer:

to remove any remaining 2,4-dinitrophenylhydrazone

Explanation:

Usually, when an organic compound is synthesised, traces of impurities such as excess reagents or solvent remain in the product.

It is therefore imperative that these contaminants are removed so that the product can attain a very high degree of purity.

Hence, during the synthesis of 2,4-dinitrophenylhydrazone derivative, 10 mL of 2 M hydrochloric acid is titrated against the crude product so that any remaining 2,4-dinitrophenylhydrazone is removed.

Examine the differences between the expanded structure, the condensed structure, and bond-line representation.

Answers

Answer:

One structure shows all the bonds whereas the other shows some of the bonds.

Explanation:

Expanded structure shows all of the bonds connecting all of the atoms in the compound while on the hand, condensed structural shows all atoms, but exclude some or all of the vertical and horizontal bonds. condensed structure makes it easier to write the formula in a line as compared to expanded structure. A bond-line representation is a kind of representation of molecular structure of compounds on a line. In this representation, covalent bonds are represented with one line for each level of bond order.

28) Which of the following is true about the modern model of the atom?
A) Electrons orbit the nucleus in shells at fixed distances
B) Protons, neutrons, and electrons are located in the nucleus.
C)Atoms are hard, indivisible spheres.
D)A positive nucleus is surrounded by negative electrons.

Answers

Answer:

A) Electrons orbit the nucleus in shells at fixed distances

Answer:

the answer is A

Explanation:

Compound X has the formula C8H14.

X reacts with one molar equivalent of hydrogen in the presence of a palladium catalyst to form a mixture of cis- and trans-1,2-dimethylcyclohexane. Treatment of X with ozone follwed by zinc in aqueous acid gives a ketone plus formaldehyde (CH2=O). What is the structure of X?

Answers

Answer:

Compound X has the formula C8H14.

X reacts with one molar equivalent of hydrogen in the presence of a palladium catalyst to form a mixture of cis- and trans-1,2-dimethyl cyclohexane. Treatment of X with ozone followed by zinc in aqueous acid gives a ketone plus formaldehyde (CH2=O). What is the structure of X?

Explanation:

The degree of unsaturation in the given molecule C8H14 is:

DU=(Cn+1)-Hn/2-Xn/2+Nn/2

where,

Cn=number of carbon atoms

Hn=number of hydrogen atoms

Xn=number of halogen atoms

Nn=number of nitrogen atoms

C8H14:

DU=(8+1)-14/2

=>DU=9-7 =2

Hence, the given molecule will have either two double bonds or one double bond and one ring or two rings.

X reacts with one molar equivalent of hydrogen in the presence of a palladium catalyst to form a mixture of cis- and trans-1,2-dimethylcyclohexane.

This indicates that the molecule X has one double bond and one ring that is cyclohexane ring.

Treatment of X with ozone follwed by zinc in aqueous acid gives a ketone plus formaldehyde (CH2=O).

So, the molecule has a ring and double bond CH2.

Based on the given data the structure of compound X is shown below:

The reaction sequence is shown below:

4-chloroaniline, benzoic acid and 1,4-dibromobenzene. Prepare a flow chart to illustrate the process of separation for each component.

Answers

Answer:

The flow chart is found in the attachment

Explanation:

The mixture of 4-chloroaniline, benzoic acid and 1,4-dibromobenzene is separated based on their different solubility properties.

4-nitroaniline is basic and is first extracted using an acid, hydrochloric acid.

Benzoic acid is an acid, hence is extracted using a base, using either sodium hydrogen carbonate or sodium hydroxide.

1,4-dibromobenzene is neutral and is extracted from an organic solvent by evaporation using its property of solubility in an organic solvent.

In the flow chart illustrating the separation process, first the mixture of organic compounds is dissolved in ether, an organic solvent and then placed in a s eparatory funnel.

Then, the basic amine compound,  4-chloroaniline is removed from the organic layer into an aqueous layer by adding an inorganic acid, HCl. The aqueous lower layer is drained into a conical flask. The 4-chloroaniline is then precipitated out of solution by adding concentrated NaOH dropwise.

The organic acidic, benzoic acid is then extracted from the organic layer by adding an inorganic base, sodium hydrogen carbonate. The lower aqueous layer is drained into another flask. Benzoic acid is then precipitated out of solution by adding a concentrated solution of HCL.

The neutral 1,4-dibromobenzene is then obtained by evaporation of the organic solvent

7.A sample of oxygen gas, O2 weighs 28.4 grams. How many molecules of O2 and how
many atoms of O are present in this sample?

Answers

Answer:

5.34275*10²³

Explanation:

Molar mass of O2 is 32g/mol

mass of the sample is 28.4g

number of moles = (mass of the sample) / (molar mass of O2)

=28.5g / 32g/mol

=0.8875mol

number of molecules = number of moles * Avogadro's Constant

= 0.8875 * (6.02*10²³)

= 5.34275 molecules

A student carries out a flame test on an unknown solid. a red flame is seen. the student concludes that the solid is lithium carbonate. explain why this conclusion is not justified​

Answers

I think this is the answer you was looking for hope this helps !!!

Hexane, C6H14, is a(n)
hydrocarbon.
Saturated or Unsaturated

Answers

Answer:

Like any compound ending in '-ane', hexane is an alkane. It is commonly referred to as n-hexane and classified as a saturated hydrocarbon

Answer:

its saturated

cus its like

CnH2n+2

what is the molality of a solution that has 4 mol of KCI in 0.800 kg of water?
help me pleaseeee​

Answers

The molality of a solution that has 4 mol of KCI in 0.800 kg of water is  4 mol/ 0.800 kg.

Therefore option B is correct.

What is  molality?

b is  described as a measure of the number of moles of solute in a solution corresponding to 1 kg or 1000 g of solvent.

In order to  calculate molality, we  need to divide the number of moles of solute by the mass of the solvent in kilograms.

Molality = Number of moles of solute / Mass of solvent in kilograms

Molality = 4 mol / 0.800 kg

In conclusion, the molality is  described as a measure of the concentration of a solution expressed in terms of the number of moles of solute per kilogram of solvent.

Learn more about Molality at:

https://brainly.com/question/1370684

#SPJ1

Cual es la nomenclatura stock/tradicional/sistematica del oxigeno????

Answers

Answer:

english pls so i can answer

what is the colour of alkali

Answers

Answer: blue

Explanation:

The colours from yellow to red indicate an acidic solution, colours blue to violet indicate alkali and green colour indicates that a solution is neutral.

g Suppose you are titrating an acid of unknown concentration with a standardized base. At the beginning of the titration, you read the base titrant volume as 1.84 mL. After running the titration and reaching the endpoint, you read the base titrant volume as 27.30 mL. What volume, in mL, of base was required for the titration?

Answers

Answer:

25.46 mL

Explanation:

In a titration we use the volume and concentration of a solution to determine the previously unknown concentration of other solution. Let's consider the titration of an acid of unknown concentration with a standardized base (a base whose concentration we know). The generic neutralization reaction is:

HA + BOH ⇒ BA + H₂O

The base is in the buret and we will add it to the acid until the equivalence point is reached. The volume of base used is equal to the difference between the final reading of the buret and the initial reading of the buret.

V = 27.30 mL - 1.84 mL = 25.46 mL

Name the subatomic parts of the atom, their charges and where they are located.

Answers

Answer:

protons: positively charged, located in the nucleus

electrons: negatively charged, located outside the nucleus

neutrons: no charge, located in the nucleus

Plutonium-238 is a radioactive element that decays over time into a less harmful element at a rate of 0.8 % per year. A power plant has 50 pounds of plutonium-238 to dispose of. How much plutonium-238 will be left after 10 years

Answers

Answer:

46 pounds

Explanation:

Let the amount of Plutonium-238 left after 10 years be P

Let the initial mass of Plutonium-238 be Po

Let the rate of decay be r

Let the time taken be t

Hence;

P = Poe^-rt

P= 50e^-0.008×10

P= 46 pounds

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