How much water should be added to 90ml of 45 percent acid solution to dilute it to 25 percent acid solution

Answers

Answer 1

Answer:

72 ml

Step-by-step explanation:

Let

x = amount of water that should be added

45% acid solution = 45/100 = 0.45

25% acid solution = 25/100 = 0.25

The equation is

90(0.45) = 0.25(x + 90)

40.5 = 0.25x + 22.5

40.5 - 22.5 = 0.25x

18 = 0.25x

Divide both sides by 0.25

x = 18/0.25

= 72

x = 72 ml


Related Questions

Solve inequality problem (urgent help please)

Answers

Answer:

B

Step-by-step explanation:

|3m-2|=>1

1 <= 3m-2 or 3m-2 <= -1

3 <= 3m or 3m <= 1

1 <= m or m <= (1/3)

Can someone help me with this please !!

Answers

Step-by-step explanation:

I need help to...

I keep putting it in and no one has ever answered it and I'm struggling and getting stressed.

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