How would I simplify the expressions on the picture?

How Would I Simplify The Expressions On The Picture?

Answers

Answer 1

Answer:

7. [tex]x^{11}[/tex]   8. [tex]y^{2}\\[/tex]  9. [tex]p^{12}[/tex]  10.[tex]a^{3} b^{2}[/tex]  11.[tex]g^{16}[/tex]  12.[tex]r^{9} h^{3}[/tex]  13.[tex]m^{15} p^{6}[/tex]  14.[tex]k^{6} y[/tex]  15.[tex]x^6 z^4[/tex]

Step-by-step explanation:

7. [tex]x^3[/tex] × [tex]x^8[/tex] = [tex]x^{11}[/tex] when multiplying with exponents you add

8. [tex]\frac{y^{6} }{y^{4} }[/tex] = [tex]y^{2}[/tex] when dividing with exponents you subtract

9. [tex](p^{3})^4[/tex] = [tex]p^{12}\\[/tex] when it's power to power, you multiply

10. [tex]\frac{a^{9} b^{4}}{a^{6} b^{2}}[/tex] = [tex]a^{3} b^{2}[/tex]  (subtract exponents)

11. [tex](g^{8})^2[/tex] = [tex]g^{16}[/tex]  (multiply exponents)

12. [tex]r^{4} h^{2} r^{5} h[/tex] = [tex]r^{9} h^{3}[/tex]  (add exponents [tex]r^4 + r^5\\[/tex] and [tex]h^2 +h^1\\[/tex] )

13. [tex](m^{5} p^{2})^3[/tex] = [tex]m^{15} p^{6}[/tex] (multiply exponents)

14. [tex]\frac{k^{7} y^{4}}{y^{3}k}[/tex] =  [tex]k^{6} y[/tex] (subtract exponents [tex]k^7-k^1[/tex] and [tex]y^4-y^3\\[/tex] )

15. [tex]x^3 z^2 x^3 z^2[/tex] = [tex]x^6 z^4[/tex] (add exponents same as #12)


Related Questions

Solve the exponential equation: 6^-2x = 6^2 ^- 3x
A) 3
B) 2
C)4
D)-2

Answers

Answer:

the answer is x = 2 or B, hope this helps

Step-by-step explanation:

Give at least four different symbols that have been used to represent specific statistical measures. Describe what measure each represents.

Answers

can you show a picture of the symbols

Can you answer this an help me with this question an others ??

Answers

Answer:

D. The y-intercept of the new graph would shift down 2 units.

Step-by-step explanation:

y = -9x + 3 has a y-intercept of 3 (0, 3).

y = -9x + 1 has a y-intercept of 1 (0, 1).

3 - 1 = 2

So, down two units.

which equation has the steepest graph ?

Answers

Answer:

Step-by-step explanation:

A.

[tex] \green{\huge{\red{\boxed{\green{\mathfrak{QUESTION}}}}}} [/tex]

which equation has the steepest graph ?

[tex] \red{ \bold{ \textit{STANDARD \: EQUATION}}}[/tex]

[tex]y = mx + c[/tex]

[tex]WHERE \\ m = SLOPE \\ c = Y - INTERCEPT[/tex]

[tex] \huge\green{\boxed{\huge\mathbb{\red A \pink{N}\purple{S} \blue{W} \orange{ER}}}}[/tex]

[tex] \blue{A.T.Q}[/tex]

PART A:-

[tex]y = mx + c \sim y= -14x+1 [/tex]

[tex] \orange{SO}[/tex]

m= (-14)

which is equal to the slope of the equation .

PART B:-

[tex]y = mx + c \sim y= ¾x-9 [/tex]

[tex] \orange{SO}[/tex]

m= (¾)

PART C:-

[tex]y = mx + c \sim y= 10x-5[/tex]

[tex] \orange{SO}[/tex]

m= (10)

PART D:-

[tex]y = mx + c \sim y= 2x+8[/tex]

[tex] \orange{SO}[/tex]

m= (2)

SO MAXIMUM SLOPE IS :-( -14 )

Negative shows Slope is in negative direction.

[tex] \red \star{Thanks \: And \: Brainlist} \blue\star \\ \green\star If \: U \: Liked \: My \: Answer \purple \star[/tex]

someone help and tell me what the correct answer is? got it wrong and want to learn​

Answers

The answer would be 48. Since UW is an angle bisector that would mean the angle was split in half evenly. Since the angles are now even, VUW = WUT. You can put the two equations equal to each other (4x + 6) = (6x - 10) after solving you would find that x = 8. Take that 8 and substitute it in the equation ( 6(8) - 10 ) and solve it.

El prestigioso hotel Los Cisnes, cobra la recepción a las delegaciones extranjeras de acuerdo con la siguiente política: Las delegaciones con menos de 30 personas pagan $10 por persona, mientras que las delegaciones con 30 personas o más pagan una tarifa reducida de $9.50 por persona.
a) Determine el costo que pagaran las delegaciones extranjeras por la recepción en función a la cantidad de personas (1.5 puntos)
b) Trace un bosquejo de la gráfica del inciso a) (1.5 puntos)
c) Cuánto dinero ahorrará la delegación de 29 personas si pudiera incluir un miembro adicional (1 punto)
d) Halle el dominio y rango de la función costo por la recepción (1 punto)

Answers

Answer:

"x" cantidad de personas, que será igual a

f(x) = $10x   Si   x < 30

f(x) = $9.5x si x ≥ 30

Si tenemos que son 29 personas entonces el costo es de:

f(x) = $10*29 = $290

Si incluye un miembro adicional

f(x) = $9.5*30 = $285

Ahorra un total de: $290 - $285 = $5

The mean per capita consumption of milk per year is 131 liters with a variance of 841. If a sample of 132 people is randomly selected, what is the probability that the sample mean would be less than 133.5 liters

Answers

Answer:

0.8389 = 83.89% probability that the sample mean would be less than 133.5 liters.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

The mean per capita consumption of milk per year is 131 liters with a variance of 841.

This means that [tex]\mu = 131, \sigma = \sqrt{841} = 29[/tex]

Sample of 132 people

This means that [tex]n = 132, s = \frac{29}{\sqrt{132}}[/tex]

What is the probability that the sample mean would be less than 133.5 liters?

This is the p-value of Z when X = 133.5. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{133.5 - 131}{\frac{29}{\sqrt{132}}}[/tex]

[tex]Z = 0.99[/tex]

[tex]Z = 0.99[/tex] has a p-value of 0.8389

0.8389 = 83.89% probability that the sample mean would be less than 133.5 liters.

What is the inverse of function f?

Answers

9514 1404 393

Answer:

  D.  f^-1(x) = 3 -7x

Step-by-step explanation:

Solve x = f(y) for y to find the inverse function.

  x = f(y)

  x = (3 -y)/7 . . . . . . use the function definition

  7x = 3 -y . . . . . . . .multiply by 7

  y = 3 -7x . . . . . . . add y-7x to both sides

Then the inverse function is ...

  [tex]\boxed{f^{-1}(x)=3-7x}[/tex]

How many solutions are there for the system of nonlinear equations
represented by this graph?
10
8
0
4
2
-
BE
-10-8
-6
0
-2
-2
2
4
8
10
4
-
-8
-10
O A. Two
O B. None
C. One

Answers

The correct answer is 2 Solutions , see it’s how many times the two lines intersect, so 2

Can someone help me out here please? I do not know how to solve this problem nor where to start?

Answers

Answer:

200 test tubes will fill the container

Step-by-step explanation:

Hi there!

We need to find out how many 5 milliliter tubes will fill a 1 liter container

First, let's convert everything to the same unit, as the tubes and the container are in different units.

Let's do milliliters, as those are smaller than liters and we will avoid having decimals.

there are 1,000 milliliters in a liter (the unit prefix "milli-" means "thousand")

Let's say the number of test tubes needed to fill the container is x

As each tube has 5 milliliters of water, 5x milliliters will equal 1,000 milliliters (1 liter)

as an equation, that's

5x=1,000

divide both sides by 5

x=200

So that means 200 test tubes will fill the container

Hope this helps! :)

Answer:

Here is how to start

Step-by-step explanation:    7  2  13  42

1 milliliter is one one thousands of a liter      1 milliliter  = 0.001 liter

1000 milliliter is equal to 1 liter

How many 5 milliliter test tubes are in 1 liter?

1000 milliliter / 5 milliliter per test tube   =  ________  test tubes

Name the following segment or point.
Given:
L, M, N are midpoints
orthocenter of triangle ABC

Answers

Answer:

P

Step-by-step explanation:

It's where the altitudes meet

Plz help I’ll mark you

Answers

Answer:

option (B) is the answer

You are installing new carpeting in a family room. The room is rectangular with dimensions 2012feet × 1318feet . You intend to install baseboards around the entire perimeter of the room except for a 312 -foot opening into the kitchen. How many linear feet of board must you purchase?

Answers

Answer: 1. When you estimate, it is not an exact measurement. 3ft 8 in gets rounded to 4ft and 12 ft 3 in rounds to 12ft. now find the perimeter. P=2l+2w P= 2*12 +2*4 P=32feet

2. 3ft 8in = 3 8/12 or reduced to 3 2/3  12ft 3in = 12 3/12 or reduced to 12 1/4   The fractional part is referring to a fraction of a foot.

3. The perimeter of the room is P=2l+2w or P=2(12 1/4) + 2(3 2/3) p=24 1/2 + 7 1/3  P= 31 5/6 feet

4. The estimate and the actual are very close. They are 1/6 of a foot apart.

5a. Total baseboard 31 5/6ft - 2 1/4 ft = 29 7/12 feet needed.

5b. Take the total and divide it by 8ft  = 29 7/12 divided by 8= 3.7  You are not buying a fraction of a board so you would need 4 boards.

A card is drawn from a well shuffled pack of 52 cards . find the probability of '2' of spades​

Answers

Answer:

[tex] \frac{1}{52} [/tex]

Step-by-step explanation:

Given,

Total no. of cards = 52

No. of 2 of spades cards = 1

Therefore,

Probability of getting 2 of spades

[tex] = \frac{no. \: of \: required \: outcomes}{total \: outcomes} [/tex]

[tex] = \frac{1}{52} (ans)[/tex]

At the 6th grade school dance, there are 132 boys, 89 girls, and 14 adults. What is the ratio of adults to boys at the school dance?​

Answers

Answer:

14 to 132

Step-by-step explanation:

We are given that there are 132 boys and 14 adults. Since the question is only asking for the ratio of adults to boys, we don't have to worry about the number of girls in this question. From here, we see that the question is asking for the ratio of adults to boys, so we put it in that exact order. Our answer is 14 to 132. I hope this helps and please don't hesitate to reach out with more questions!

Find f(6), f(0), and f(-1)
f(x)=-7X​

Answers

Answer:

f(6)=-42

f(0)=0

f(-1)=7

Step-by-step explanation:

since f(x) =-7x

it implies that f(6),f(0) and f(-1) are all equal to f(x)

which is equal to -7x .

so wherever you find x you out it in the

function

X^2-y^2=k need the answer

Answers

Answer:

Let's solve for k.

x2−y2=k

Step 1: Flip the equation.

k=x2−y2

Answer:

k=x2−y2

Step-by-step explanation:

the focus of a parabola is (-5,-1) and the directrix is y= -3.

what is an equation of the parabola? (one of the answered above)

Answers

Answer:

Step-by-step explanation:

-2

Evaluate the expression below for m=2/3 and n= 1/3

Answers

m=2/3 and ;=1/3
Using formulae,
mn-nm,
2/3*1/3-1/3*2/3.
2/3-1/3,
6-3/3, 3/3=0.

Answer:

Evaluación de expresiones y polinomios

Purplemath

"Evaluación" significa principalmente "simplificar una expresión a un solo valor numérico". A veces se le dará una expresión numérica, donde todo lo que tiene que hacer es simplificar; esa es más una cuestión de orden de operaciones. En esta lección, me concentraré en el aspecto de la evaluación de "conectar y tragar": introducir valores para las variables y "avanzar" hasta llegar a la respuesta simplificada.

(Por cierto, sí, "plug-n-chug" es una terminología bastante estándar. No es un término "técnico", por lo que probablemente no lo verá en su libro de texto, pero seguramente lo escuchará de otros estudiantes. , y quizás también su instructor.)

MathHelp.com

Evaluar expresiones en MathHelp.com

Evaluar expresiones

Por lo general, la única parte difícil de la evaluación es hacer un seguimiento de los signos "menos". Le recomiendo encarecidamente que utilice los paréntesis libremente, especialmente cuando recién está comenzando.

Evalúe a2b para a = –2, b = 3, c = –4 y d = 4.

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Para encontrar mi respuesta, simplemente conecto los valores dados, teniendo cuidado de usar paréntesis, particularmente alrededor de los signos "menos". Especialmente cuando recién estoy comenzando, dibujar los paréntesis primero puede ser útil:

a2 b

() 2 ()

(–2) 2 (3)

(4) (3)

12

Observe cómo el uso de paréntesis me ayudó a realizar un seguimiento del signo "menos" en el valor de a. Esto era importante, porque de otro modo podría haber elevado al cuadrado solo el 2, terminando con –4, lo que habría estado mal.

Por cierto, resultó que no necesitábamos los valores de las variables c y d. Cuando se le da un gran conjunto de expresiones para evaluar, debe esperar que a menudo haya una u otra de las variables que no se incluirán en ningún ejercicio en particular del conjunto.

Evalúe a - cd para a = –2, b = 3, c = –4 y d = 4.

En este ejercicio, me dieron información adicional. No hay una b en la expresión que quieren que evalúe, por lo que puedo ignorar este valor en mi trabajo:

(–2) - (–4) (4)

–2 - (–16)

–2 + 16

16 - 2

14

Step-by-step explanation:

hola

Identify the level of measurement of the data, and explain what is wrong with the given calculation. Ina set of data, alert levels are represented as 1 for low, 2 for medium, and 3 for high. The average mean of the 522 alert levels is 1.3. The data are at the ________ level of measurement. a. Nominalb. Ordinalc. Ratiod. IntervalWhat is wrong with the given calculation?a. Such data should not be used for calculations such as an average.b. One must use a different method to take the average of such datac. The true average is 2.5d. There is nothing wrong with the given calculation.

Answers

Answer:

(1) Ordinal

(2) Such data should not be used for calculations such as an average.

Step-by-step explanation:

Given

[tex]1 \to Low[/tex]

[tex]2 \to Medium[/tex]

[tex]3 \to High[/tex]

[tex]Average = 1.3[/tex]

Solving (a): The level of measurement

When observations are presented in ranks such as:

[tex]1 \to Low[/tex]

[tex]2 \to Medium[/tex]

[tex]3 \to High[/tex]

The level of measurement of such observation is ordinal

Solving (b): What is wrong with the computation?

Ordinal level of measurement are not numerical values whose average can be calculated because they are used as ranks.

Hence, (a) is correct

ANSWER QUICKLY!!! What is the median of Restaurant B's cleanliness ratings?

4
3
1
5
2

Answers

2 is the answer Hope it helped

Simultaneous equations 5x-4y=19
X+2y=8

Answers

Answer:

x=5

y=3/2

Step-by-step explanation:

Take it or leave it, that's what the computer said.

Which one is the correct answer? help pls!!

Answers

Answer:

(2k, k)

Step-by-step explanation:

x + y = 3k

x - y = k

Add the equations.

2x = 4k

x = 2k

2k + y = 3k

y = k

Answer: (2k, k)

What is the standard form equation of the quadratic function shown in this graph?

Answers

Answer:

A is the equation in standard form

Step-by-step explanation:

If f(x) = 3X + 10x and g(x) = 4x - 2, find (f+g)(x).
O A. 17x - 2
O B. 3* + 6x + 2
O C. 3* - 6x + 2
D. 3X + 14x-2



help!!!

Answers

17x-2 just add the two functions

Find the approximate circumstance of a circle with a diameter of 80 yards

Answers

Answer:

251.33

Step-by-step explanation:

C=3.14(d)

C=3.14(80)

The mean points obtained in an aptitude examination is 167 points with a standard deviation of 20 points. What is the probability that the mean of the sample would differ from the population mean by less than 3.8 points if 76 exams are sampled

Answers

Answer:

0.9029 = 90.29% probability that the mean of the sample would differ from the population mean by less than 3.8 points if 76 exams are sampled

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean [tex]\mu = p[/tex] and standard deviation [tex]s = \sqrt{\frac{p(1-p)}{n}}[/tex]

The mean points obtained in an aptitude examination is 167 points with a standard deviation of 20 points

This means that [tex]\mu = 167, \sigma = 20[/tex]

Sample of 76:

This means that [tex]n = 76, s = \frac{20}{\sqrt{76}}[/tex]

What is the probability that the mean of the sample would differ from the population mean by less than 3.8 points?

P-value of Z when X = 167 + 3.8 = 170.8 subtracted by the p-value of Z when X = 167 - 3.8 = 163.2. So

X = 170.8

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{170.8 - 167}{\frac{20}{\sqrt{76}}}[/tex]

[tex]Z = 1.66[/tex]

[tex]Z = 1.66[/tex] has a p-value of 0.9515

X = 163.2

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{163.2 - 167}{\frac{20}{\sqrt{76}}}[/tex]

[tex]Z = -1.66[/tex]

[tex]Z = -1.66[/tex] has a p-value of 0.0485

0.9514 - 0.0485 = 0.9029

0.9029 = 90.29% probability that the mean of the sample would differ from the population mean by less than 3.8 points if 76 exams are sampled

A seller of the property listed at $200,000 excepted a 90% offer the home appraised at $185,000 and the buyers obtained a loan for 85% for 30 years at 5% interest what is the first months interest

Answers

Answer:

$637.50

Step-by-step explanation:

According to the Question,

Given That, A seller of the property listed at $200,000 excepted a 90% offer the home appraised at $185,000 and the buyers obtained a loan for 85% for 30 years at 5% interest

Thus, the first months interest is

$200,000 list price x 0.90 = $180,000 contract sales price.

Since lender always uses the less of the appraised value or the contract sales price, use $180,00 for the remainder of the calculations.

$180,000 contract sales price x 0.85 LTV = $153,000 loan. $153,000 loan x 0.05 interest rate = $7,650 annual interest. $7,650 ÷ 12 = $637.50 monthly interest payment for the first month.

Answer:

$637.50

Step-by-step explanation:

The appraised value is irrelevant. The lender will consider the lower of the appraised value or the agreed purchase price.

The term of the loan is also irrelevant. It is not an amortization problem.

The first month’s interest is $637.50.

A confided aquifer has a piezometric height of 30 feet before being pumped. The well is then pumped at 250 gallons/day for a very long time and results in a drawdown of 10 feet at the well. If the transmissivity in the aquifer is 10.0 ft2/day and the radius of the well is 0.5 feet, estimate the drawdown in feet for a well 50 feet away

Answers

Answer:

[tex]d_2=-8.32ft[/tex]

Step-by-step explanation:

From the question we are told that:

Height of first draw down [tex]h=30[/tex]

Pump Discharge [tex]Q=250gallons/day[/tex]

Well 1 depth [tex]d_1=10ft[/tex]

Transmissivity[tex]\=T 10.0 ft2/day[/tex]

Radius[tex]r=0.5[/tex]

Well 2 depth [tex]d_2=50ft[/tex]

Generally the Thiem's equation for Discharge is mathematically given by

 [tex]Q=\frac{2\piT(h_2-h_1)}{ln(\frac{r_2}{r_1})}[/tex]

 [tex]250=\frac{2*\pi 10 (10-d_2)}{ln(\frac{50}{0.5})}[/tex]

 [tex]1151.293=2*\pi 10 (10-d_2)[/tex]

 [tex]d_2=-8.32ft[/tex]

Tiham is the only striker of his team. He can catch one of the four passes delivered to him and when he get a pass he takes the shot. One of his four shots go towards the net but the goal keeper of the opposite team stop one of every two shots. What is the minimum number of passes have to be delivered to Tiham to score minimum one goal?

Answers

Answer:

1/4 *1/4*1/2 =0.03125

which as a fraction is 1/32

so the minimuim number of passes that will get him a goal is 1 since he could get it on the first try

Hope This Helps!!!

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