The answer is 3 to the 3/4 power.
Mrs. Nygaard needs 12 hours to grade all of her students’ projects. She made a chart to show how much time she could spend grading the projects during the week. Project Grading Day Hours Grading Monday 1 and three-fourths Tuesday 1 and one-half Wednesday 1 and one-fifth Thursday 2 Friday 1 and one-fourth How many hours will Mrs. Nygaard need to work over the weekend to finish grading the projects? 1 and three-fifths hours 4 and StartFraction 3 over 10 EndFraction hours 6 and one-half hours 19 and StartFraction 7 over 10 EndFraction hours
Answer:
B
Step-by-step explanation:
Option B is correct, 4 and 3/10 hours will Mrs. Nygaard need to work over the weekend to finish grading the projects.
What is Fraction?A fraction represents a part of a whole.
To find the total amount of time Mrs. Nygaard has available during the week to grade projects, we need to add up the hours for each day:
1 and three-fourths + 1 and one-half + 1 and one-fifth + 2 + 1 and one-fourth = 7 and five-tenths hours
This means that Mrs. Nygaard has 7.5 hours during the week to grade projects.
If she needs 12 hours to grade all the projects, then she will need to work for an additional:
12 - 7.5 = 4.5 hours over the weekend to finish grading the projects.
Therefore, 4 and 3/10 hours required to Mrs. Nygaard need to work over the weekend to finish grading the projects.
To learn more on Fractions click:
https://brainly.com/question/10354322
#SPJ7
A 4 metre ladder is placed against a vertical wall.
The base of the ladder is 1.5 metres from the base of the wall.
Answer:
Original position: base is 1.5 meters away from the wall and the vertical distance from the top end to the ground let it be y and length of the ladder be L.
Step-by-step explanation:
By pythagorean theorem, L^2=y^2+(1.5)^2=y^2+2.25 Eq1.
Final position: base is 2 meters away, and the vertical distance from top end to the ground is y - 0.25 because it falls down the wall 0.25 meters and length of the ladder is also L.
By pythagorean theorem, L^2=(y -0.25)^2+(2)^2=y^2–0.5y+ 0.0625+4=y^2–0.5y+4.0625 Eq 2.
Equating both Eq 1 and Eq 2: y^2+2.25=y^2–0.5y+4.0625
y^2-y^2+0.5y+2.25–4.0625=0
0.5y- 1.8125=0
0.5y=1.8125
y=1.8125/0.5= 3.625
Using Eq 1: L^2=(3.625)^2+2.25=15.390625, L=(15.390625)^1/2= 3.92 meters length of ladder
Using Eq 2: L^2=(3.625)^2–0.5(3.625)+4.0625
L^2=13.140625–0.90625+4.0615=15.390625
L= (15.390625)^1/2= 3.92 meters length of ladder
hope it helps...
correct me if I'm wrong...
Tom and 29 friends (30 total) are to sit in three rows of 10 at a movie theatre. They madea rule that Within each row, they must sit in order of tallest to shortest with the tallestperson on the left. Given that there are no two people with the same height and there areno restrictions on where a person must sit, how many different seating arrangements arepossible
Answer:
The answer is "6000".
Step-by-step explanation:
It seems to be a total of 30 buddies there. Every column has 10 seats so that the 10 pals are now in a row. Of all the other 20 buddies, 10 are on the following row. And we have ten friends remaining and that they are sitting in the next row.
Therefore the possibility of sitting is:
[tex]30 \times 20 \times 10 = 6000[/tex]
[tex]\text{Solve for 'x'.}\\\\x^2-25=0\\\\\text{Thank you.}[/tex]
Hi there!
»»————- ★ ————-««
I believe your answer is:
[tex]x = \pm 5[/tex]
»»————- ★ ————-««
Here’s why:
⸻⸻⸻⸻
[tex]\boxed{\text{Solving for 'x'...}}\\\\x^2-25 = 0\\-------------\\\rightarrow x^2 -25 + 25 = 0 + 25\\\\\rightarrow x^2 = 25\\\\\rightarrow \sqrt{x^2}=\sqrt{25}\\\\\rightarrow \boxed{x = \pm 5}[/tex]
⸻⸻⸻⸻
»»————- ★ ————-««
Hope this helps you. I apologize if it’s incorrect.
Answer:
[tex]x = 5 \: \: \: or \: \: \: x = - 5[/tex]
Step-by-step explanation:
[tex] {x}^{2} - 25 = 0 \\ {x}^{2} - {5}^{2} \\ ( x - 5)(x + 5) = 0 \\ \\ x - 5 = 0 \\ x = 5 \\ or \\ x + 5 = 0 \\ x = - 5[/tex]
Function A and Function B are linear functions. Function A x y – 10 – 14 – 1 – 5 9 5 Function B y=2x+4 Which statement is true?
Answer:
See explanation
Step-by-step explanation:
Function A is not clear; I will use the following in place of function A
Function A:
[tex]x \to\ 1 |\ 3 |\ 4 |\ 6[/tex]
[tex]y \to -1|\ 3|\ 5|\ 9[/tex]
Function B:
[tex]y = 2x + 4[/tex]
Required
Compare both functions
For linear functions, we often compare the slope and the y intercepts only.
Calculating the slope of function A, we have:
[tex]m = \frac{y_2 - y_1}{x_2 - x_1}[/tex]
Where:
[tex](x_1,y_1) = (1,-1)[/tex]
[tex](x_2,y_2) = (3,3)[/tex]
So, we have:
[tex]m = \frac{3 - -1}{3 - 1}[/tex]
[tex]m = \frac{4}{2}[/tex]
[tex]m = 2[/tex]
To calculate the y intercept, we set [tex]x = 0[/tex], then solve for y
i.e.[tex](x,y) = (0,y)[/tex]
Using the slope formula, we have:
[tex]m = \frac{y_2 - y_1}{x_2 - x_1}[/tex]
Where:
[tex]m = 2[/tex]
[tex](x_1,y_1) = (0,y)[/tex]
[tex](x_2,y_2) = (3,3)[/tex]
So, we have:
[tex]2 = \frac{3 - y}{3 - 0}[/tex]
[tex]2 = \frac{3 - y}{3}[/tex]
Multiply by 3
[tex]6 = 3 - y[/tex]
Collect like terms
[tex]y = 3 - 6[/tex]
[tex]y = -3[/tex]
So, for function A:
[tex]m = 2[/tex] -- slope
[tex]y = -3[/tex] --- y intercept
For function B
[tex]y = 2x + 4[/tex]
A linear function is represented as:
[tex]y = mx + b[/tex]
By comparison
[tex]m = 2[/tex] --- slope
[tex]b = 4[/tex] --- y intercept
By comparing the results of both functions, we have the following conclusion:
Functions A and B have the same slope (i.e. 2)
Function B has a greater y intercept (i.e. 4)
Word problem One of the citizens has 97 silver coins. How many bronze coins would it take to equal this amount
Given: Given that a citizen have 97 silver coins.
To find : Here we need to find that how many bronze coins would it take to equal this amount.
Solution: We know, 1 silver coin=10 bronze coin
So, 97 silver coin=10×97 bronze coin
=970 bronze coin
Therefore, 970 bronze coins would it take to equal this amount.
please help me! im having trouble
Answers:
3 chocolate cones
1 strawberry cones
===========================================================
Explanation:
Let's isolate the variable c in the first equation
c+s = 4
c = 4-s
we subtract s from both sides to get c all by itself. This will then be plugged into the second equation. I'm using the substitution property.
1.75c + 1.3s = 6.55
1.75(4-s) + 1.3s = 6.55 ..... replace c with 4-s
1.75*4 + 1.75*(-s) + 1.3s = 6.55
7 - 1.75s + 1.3s = 6.55
-0.45s + 7 = 6.55
-0.45s = 6.55 - 7
-0.45s = -0.45
s = -0.45/(-0.45)
s = 1
So he bought 1 strawberry cone. Use this value of s to find c
c = 4-s
c = 4-1
c = 3
This says he also bought 3 chocolate cones.
-------------------
As a check, we see that c+s = 3+1 = 4, showing that he bought 4 cones total.
Also,
1.75c + 1.3s = 1.75*3 + 1.3*1 = 6.55
indicating he spent $6.55 total for the four cones. This matches with what the instructions tell us, so the answer is confirmed.
Answer:
Step-by-step explanation:
[tex]\left \{ {{c+s=4} \atop {1.75c+1.3s=6.55}} \right.[/tex]
1.75c + 1.75s = 1.75 × 4 ........ (1)
1.75c + 1.3s = 6.55 ........ (2)
(1) - (2)
0.45s = 0.45 ⇒ s = 1
c + 1 = 4 ⇒ c = 3
[ 3 ] chocolate [ 1 ] strawberry
which of the following statements must be true, given that ΔABC≅ΔXYZ, and the measure of ∠C is 32°
[tex]\huge\boxed{\boxed{\underline{\textsf{\textbf{Answer}}}}}[/tex]
Given,
ΔABC ≅ ΔXYZ
If these 2 triangles are congruent with each other then,
∠ A = ∠ X [tex]\boxed{\bf{Corresponding \ parts \ of \ congruent \ triangles}}[/tex]
∠ B = ∠ Y [tex]\boxed{\bf{Corresponding \ parts \ of \ congruent \ triangles}}[/tex]
∠ C = ∠ Z [tex]\boxed{\bf{Corresponding \ parts \ of \ congruent \ triangles}}[/tex]
Now,
We saw that ∠ C = ∠ Z.
⟹ So, if ∠ C = 32°, then even ∠ Z will be equal to 32°. [tex]\boxed{\sf{Equal \ angles \ have \ equal \ measurements}}[/tex]
ᶛɲƧཡэʀ ↦ C. m ∠X = 32°
ʰᵒᵖᵉ ⁱᵗ ʰᵉˡᵖˢ
꧁❣ ʀᴀɪɴʙᴏᴡˢᵃˡᵗ2²2² ࿐
Work out the area of the shaded shape.
Answer:
65 m²
Step-by-step explanation:
Area 1 :-
A = 3m * 9m A = 27 m²Area 2 :-
A = (12-3-2) m * (9 - 5) m A = 7m * 4 mA = 28 m²Area 3 :-
Area = 2m * 5 m A = 10 m²Total Area :-
A = ( 27 + 28 + 10 ) m²A = 65 m²What is another name for CD?
Answer:
I think album is another name of CD.
Is (0,0) a solution of the graphed inequality?
Choose 1 answer:
Yes
No
Answer:
no..........................
14.8 = n minus 0.3
n = negative 15.1
n = negative 14.5
n = 14.5
n = 15.1
Hello!
14.8 = n - 0.3
n - 0.3 = 14.8
n = 14.8 + 0.3
n = 15.1 → value of n
Good luck! :)
Answer:
D: n = 15.1
Step-by-step explanation:
14.8 = n minus 0.3
14.8= n - 0.3
14.8 - is +
+
0.3
=
15.1
:D if u need help with more just ask!
I love this kind of math.
( t^15/27x^9 ) ^-2/3
Please solve this
it is fraction with a negative fraction exponent
Answer:
Step-by-step explanation:
Exponent laws:
[tex](a^{m})^{n}=a^{m*n}\\\\a^{-m}=\frac{1}{a^{m}}[/tex]
[tex](t^{\frac{15}{27}}x^{9}})^{\frac{-2}{3}}= \ t^{\frac{15}{27}*\frac{-2}{3}}*x^{9*\frac{-2}{3}}\\\\\\= t^{\frac{5}{9}*\frac{-2}{3}}*x^{3*-2}\\\\=t^{\frac{-10}{27}}x^{-6}\\\\=\frac{1}{t^{\frac{10}{27}}x^{6}}[/tex]
simplify the following.(2x-y)(x+2y)
Answer:
[tex]=2x^2+3xy-2y^2[/tex]
Step-by-step explanation:
When given the following problem;
[tex](2x-y)(x+2y)[/tex]
Distribute, multiply every number in one of the parenthesis by every number in the other;
[tex](2x-y)(x+2y)\\=(2x)(x)+(2x)(2y)+(-y)(x)+(2y)(-y)[/tex]
Simplify,
[tex]=(2x)(x)+(2x)(2y)+(-y)(x)+(2y)(-y)\\=2x^2+4xy-xy-2y^2\\=2x^2+3xy-2y^2[/tex]
Therefore, the final answer is;
[tex]=2x^2+3xy-2y^2[/tex]
Help please-- Given circle O below, if arc GH and arc HJ are congruent, what is the measure of chord line HJ?
Answer:
the answer is D
Step-by-step explanation:
Find the x in the kite below
Answer:
x = 5
Step-by-step explanation:
comment if you need explanation
Answer:
Step-by-step explanation:
It just so happens that x is the hypotenuse in the right triangle with sides 3 and 4. To find x we use Pythagorean's Theorem:
[tex]x^2=3^2+4^2[/tex] and
[tex]x^2=9+16[/tex] and
[tex]x^2=25[/tex] so
x = 5
what is the length of segment LM?
Here we are provided with a diagram of a triangle. We need to find out the length of the segment LM . As we can see that ,
∆ KNL ≈ MNL , [ By AAS ]
Therefore ,
KN = MN ( by cpct )⇒ KN = MN
⇒ 14x - 3 = 25
⇒ 14x = 25 + 3
⇒ 14x = 28
⇒ x = 2
Put this x = 2 in LM :-
⇒ LM = 9x + 5
⇒ LM = 9*2 + 5
⇒ LM = 18 + 5
⇒ LM = 23
Hence the required answer is 23 .
I need help ASAP !!!
write an expression for 15 divided by a number
show your work
Answer:
15/X
Step-by-step explanation:
a number divided by 15
15/X
A square pyramid is inscribed in a rectangular prism. A cone is inscribed in a cylinder. The pyramid and the cone have the same volume. Part of the volume of the rectangular prism, 1 V 1 , is not taken up by the square pyramid. Part of the volume of the cylinder, 2 V 2 , is not taken up by the cone. What is the relationship of these two volumes, 1 V 1 and 2 V 2 ?
Answer:
V₂ = V₁
Step-by-step explanation:
Let the height of the rectangular prism = h
Let s represent the side length of the base of the square prism, we have;
The volume of the prism, [tex]V_{prism}[/tex] = s²·h
The volume of the square pyramid, [tex]V_{pyramid}[/tex] = (1/3)·s²·h
∴ V₁ = The area not taken up by the square pyramid = [tex]V_{prism}[/tex] - [tex]V_{pyramid}[/tex]
∴ V₁ = s²·h - (1/3)·s²·h = (2/3)·s²·h
Similarly, for the cylinder, we have;
Let h represent the height of the cylinder
Let r represent the radius of the base of the cone, we have;
Therefore;
The volume of the cylinder, [tex]V_{cylinder}[/tex] = π·r²·h
The volume of the cone, [tex]V_{cone}[/tex] = (1/3)·π·r²·h
∴ V₂ = π·r²·h - (1/3)·π·r²·h = (2/3)·π·r²·h
V₂ = (2/3)·π·r²·h
[tex]V_{cone}[/tex] = [tex]V_{pyramid}[/tex]
Therefore;
(1/3)·π·r²·h = (1/3)·s²·h
∴ π·r² = s²
Therefore, V₂ = (2/3)·π·r²·h = V₂ = (2/3)·s²·h = V₁
V₂ = V₁.
Given a line segment that contains the points A,B, & C in order, if AB = 2x - 2, and BC = 2x + 10, and AC = 32, find x.
Select one: a. 6
b. 24
c. 8
d. - 4
Answer:
a. 6
Step-by-step explanation:
AB +BC =AC
2x-2+2x+10=32
4x+8=32
4x=32-8
4x=24
x=24/4
x=6
[tex] \frac{x}{2} + \frac{6}{x } = 4[/tex]
using quadratic equation....help me if you can
In ΔEFG, the measure of ∠G=90°, GF = 33, FE = 65, and EG = 56. What ratio represents the sine of ∠F?
Work Shown:
sin(angle) = opposite/hypotenuse
sin(F) = EG/FE
sin(F) = 56/65
Refer to the diagram below.
What is the value of x |-16|
Find the measure of the angle indicated.
1
2
4
3
151°
6
8
7
The measure of angle 7 is
............................
...............................................................................................................................................................................................................................................................................................................
which values are soloutions to the inequality -3x - 4 < 2 ? check all of the boxes that apply
Given:
The inequality is:
[tex]-3x-4<2[/tex]
To find:
The values that are solutions to the given inequality.
Solution:
We have,
[tex]-3x-4<2[/tex]
Adding 4 on both sides, we get
[tex]-3x-4+4<2+4[/tex]
[tex]-3x<6[/tex]
Divide both sides by -3 and change the inequality sign because -3 is a negative value.
[tex]\dfrac{-3x}{-3}>\dfrac{6}{-3}[/tex]
[tex]x>-2[/tex]
Therefore, all the real values greater than -2 are the solutions to the given inequality.
280L of water consumed my 7 people. water consumed by 50 people =___L
Step-by-step explanation:
7 people = 280 liters
1 p = 40 liters
50 p = 40 x 50
50 p = 2000 liters
hope it helps.
Also, I think that Brainly is an awesome app, but there's an app which is doing great work for me in maths, named Gauthmath. I will suggest it. Video concepts and answers from real tutors.
The figure below shows the design of a truss to support the weight of a roof. In this truss design, ∠A⩭∠D and ĀF⩭DF.
Answer:
[tex]m\angle A= 30^{\circ}[/tex]
Step-by-step explanation:
In the question, we're given [tex]\angle A\cong \angle D[/tex]. Therefore, the measure of these two angles must be equal.
To find the value of [tex]x[/tex], set these two angles equal to each other:
[tex]4x-26=x+16[/tex]
Add 26 and subtract [tex]x[/tex] from both sides:
[tex]3x=42[/tex]
Divide both sides by 3:
[tex]x=\frac{42}{3}=14[/tex]
Since [tex]\angle A[/tex] was labelled as [tex]4x-26[/tex], substitute [tex]x=14[/tex] to find its measure:
[tex]\angle A=4(14)-26,\\\angle A=56-26,\\\angle A=\boxed{30^{\circ}}[/tex]
You can also substitute [tex]x=14[/tex] into the label of angle D as angle A is congruent to angle D for easier calculations ([tex]14+16=\boxed{30^{\circ}}[/tex]).
Rule 1: Multiply by 2 then add 1 starting from 1.
Rule 2: Divide by 2 then add 4 starting from 40.
Sequence 1
Sequence 2
Ordered Pairs
PLZ ANSWER FOR Brainiest
Answer:
1×2+1=3
3×2+1=7
7×2+1=15
15x2+1=31
31×2+1=63
40÷2+4=24
24÷2+4÷16
16÷2+4=12
12÷2+4=10
10÷2+4=9
Find the area enclosed by the figure.
Answer:
894
Step-by-step explanation:
this can be "split" into 3 rectangles.
their areas can be easily calculated. and then we simply sum them all up for the answer.
rectangle 1 on the top
R1 = 5×9 = 45
rectangle 2 in the middle
R2 = (19+5)×(35-9-15) = 24×11 = 264
rectangle 3 at the bottom
R3 = 39×15 = 585
and all together
45+264+585 = 894