Find the 6th term of each geometric sequence. 9, 45, 225, 1125
Answer:
28125
Step-by-step explanation:
Refer to the image below.
Will Mark Brainlest Help Please ,,,,
[tex]\\ \sf\longmapsto 2x+y=2[/tex]
[tex]\\ \sf\longmapsto 2x=2-y[/tex]
[tex]\\ \sf\longmapsto x=\dfrac{2-y}{2}\dots(1)[/tex]
And
[tex]\\ \sf\longmapsto x+1=y+2[/tex]
[tex]\\ \sf\longmapsto x=y+2-1[/tex]
[tex]\\ \sf\longmapsto x=y+1[/tex]
Put the value[tex]\\ \sf\longmapsto \dfrac{2-y}{2}=y+1[/tex]
[tex]\\ \sf\longmapsto 2-y=2(y+1)[/tex]
[tex]\\ \sf\longmapsto 2-y=2y+2[/tex]
[tex]\\ \sf\longmapsto 2-2=2y+y[/tex]
[tex]\\ \sf\longmapsto 3y=0[/tex]
[tex]\\ \sf\longmapsto y=\dfrac{0}{3}[/tex]
[tex]\\ \sf\longmapsto y=\infty[/tex]
Put in eq(1)[tex]\\ \sf\longmapsto x=\dfrac{2-y}{2}[/tex]
[tex]\\ \sf\longmapsto x=\dfrac{2-\infty}{2}[/tex]
[tex]\\ \sf\longmapsto x=\dfrac{2}{2}[/tex]
[tex]\\ \sf\longmapsto x=1[/tex]
Answer:
x=1 , y=0
Step-by-step explanation:
2x+y=2.......1
x+1=y+2
x-y=2-1
x-y=1...... 2
from equation 2 we get ,
x-y=1
x=1+y
putting the value of x in equation 1 we get,
2*(1+y) +y=2
2+2y+y=2
2+3y=2
3y=2-2
3y=0
y=0/3
y=0
putting the value of y in equation 2 we get,
x-0=1
x=1+0
x=1
hence x=1 , y=0
solve for x.
solve for x.
solve for x.
Answer:
x = 10
Step-by-step explanation:
7(x+1+7)=6(x+5+6)
or, 7(x+8)=6(x+11)
or, 7x+56=6x+66
or, 7x-6x=66-56
or, x=10
Answered by GAUTHMATH
A brick is in the shape of a rectangular prism with a length of 6 inches, a width of 3 inches, and a height of 5.5 inches. The brick has a density of 2.7 grams per cubic centimeter. Find the mass of the brick to the nearest gram.
pls pls pls help
y............. xnxnxnxnxnccncncncnnncncjcjnf
WILL MARK BRAINLIEST!!
Angelica uses the point 4,3 to represent the location of her house and uses the point 10,8 to represent the location of a gas station. Each unit on the graph represents 1 mi. How far is the gas station from Angelica’s house? Show your work.
Answer:
Angelica's house is 11 miles away from the gas station.
Step-by-step explanation:
The most simple path from Angelica's house is 11 blocks away from the gas station and each unit/block is 1 mile. So 11 miles.
Find the area of the figure.
we observe that this figure could be divided into a triangle and a rectangle.
for the area of the triangle, bxh/2, we have 15 x 12/2 = 90
and for the rectangle, we have 5 x 12 = 60
so, 90 + 60 = 150
hope it helps :)
Show all work to solve the equation for x. If a solution is extraneous, be sure to identify it in your final answer.
square root of the quantity x plus 7 end quantity minus 1 equals x
Answer:
x=2 true solution
x=-3 extraneous
Step-by-step explanation:
sqrt(x+7) -1 = x
Add 1 to each side
sqrt(x+7) -1+1 = x+1
sqrt(x+7) = x+1
Square each side
(sqrt(x+7))^2 = (x+1)^2
x+7 = x^2 +2x+1
Subtract x from each side
7 = x^2 +x +1
Subtract 7 from each side
0 = x^2 +x - 6
Factor
0 = (x+3)(x-2)
Using the zero product property
x+3 = 0 x-2 =0
x=-3 x=2
Check solutions
x=-3
sqrt(-3+7) -1 = -3
sqrt(4) -1 = -3
3 =-3 extraneous
x=2
sqrt(2+7) -1 = 2
sqrt(9) -1 = 2
3 -1 =2
2 =2 true
Convert 7 6/7 into an improper fraction.
Answer:
55/7Explanation:
Step 1
Multiply the denominator by the whole number
7 × 7 = 49
Step 2
Add the answer from Step 1 to the numerator
49 + 6 = 55
Step 3
Write answer from Step 2 over the denominator
Answer = 55/7
I hope you are enjoying your day and that this helps you out! Brainliest would be appreciated :)Answer:
55/7
Step-by-step explanation:
To convert 7 6/7 to an improper fraction
Start by multiplying the whole number with the denominator 7 x 7 = 49Then add the numerator to the number you get 49 + 6 = 55 The 55 will be your numerator for your improper fraction. 55/7 The denominator will remain the sameSubtract – 7x2 + 4x + 2 from x2 – 3.
Answer:
8x^2 - 4x - 5
See the steps below for better explanation:
Please Help Asap Its Pre-Calculus
The point (−2, 2) is a solution to which of the following systems?
y > −2x + 2 and y > x + 5
y < x + 2 and y > x − 1
y < 2x + 8 and y ≥ −x − 3
y < 2x + 3 and y ≥ −2x − 5
The point [tex](-2,2)[/tex] is a solution of the system given by [tex]y<2x+8[/tex] and [tex]y \geq -x-3[/tex]
Given point: [tex](-2,2)[/tex]
Given systems:
[tex]y>-2x+2[/tex] and [tex]y>x+5[/tex] [tex]y<x+2[/tex] and [tex]y>x-1[/tex] [tex]y<2x+8[/tex] and [tex]y \geq -x-3[/tex] [tex]y<2x+3[/tex] and [tex]y \geq -2x-5[/tex]To find: The system to which the given point is a solution
If a point is a solution of a system, then the coordinates of the point satisfies all the equation(s) or inequation(s) of the system. So, we can substitute the x & y coordinates of the given point into the inequalities of each of the given systems and check if the inequalities are satisfied by the coordinates of the point.
(1) [tex]y>-2x+2[/tex] and [tex]y>x+5[/tex]
Substitute the coordinates of the point [tex](-2,2)[/tex] into the inequalities of the system.
Put [tex]x=-2,y=2[/tex] in [tex]y>-2x+2[/tex] to get,
[tex]2>-2(-2)+2[/tex]
[tex]2>4+2[/tex]
[tex]2>6[/tex]
The above inequality is clearly impossible and thus, the coordinates of the given point does not satisfy this inequality.
This implies that the given point is not a solution of this system.
(2) [tex]y<x+2[/tex] and [tex]y>x-1[/tex]
Substitute the coordinates of the point [tex](-2,2)[/tex] into the inequalities of the system.
Put [tex]x=-2,y=2[/tex] in [tex]y<x+2[/tex] to get,
[tex]2<-2+2[/tex]
[tex]2<0[/tex]
The above inequality is clearly impossible and thus, the coordinates of the given point does not satisfy this inequality.
This implies that the given point is not a solution of this system.
(3) [tex]y<2x+8[/tex] and [tex]y \geq -x-3[/tex]
Substitute the coordinates of the point [tex](-2,2)[/tex] into the inequalities of the system.
Put [tex]x=-2,y=2[/tex] in [tex]y<2x+8[/tex] to get,
[tex]2<2(-2)+8[/tex]
[tex]2<-4+8[/tex]
[tex]2<4[/tex]
This is a true inequality. Then, the given point satisfies the first inequality of the system.
We will now check if the point satisfies the second inequality of the system.
Put [tex]x=-2,y=2[/tex] in [tex]y \geq -x-3[/tex] to get,
[tex]2 \geq -(-2)-3[/tex]
[tex]2 \geq 2-3[/tex]
[tex]2 \geq -1[/tex]
This is also a true inequality. Then, the given point also satisfies the second inequality of the system.
Thus, the given point is a solution of this system.
(4) [tex]y<2x+3[/tex] and [tex]y \geq -2x-5[/tex]
Substitute the coordinates of the point [tex](-2,2)[/tex] into the inequalities of the system.
Put [tex]x=-2,y=2[/tex] in [tex]y<2x+3[/tex] to get,
[tex]2<2(-2)+3[/tex]
[tex]2<-4+3[/tex]
[tex]2<-1[/tex]
The above inequality is clearly impossible and thus, the coordinates of the given point does not satisfy this inequality.
This implies that the given point is not a solution of this system.
Thus, we can see that the coordinates of the given point [tex](-2,2)[/tex] satisfies the inequalities of the third system only.
Then, the point [tex](-2,2)[/tex] is a solution of the system given by [tex]y<2x+8[/tex] and [tex]y \geq -x-3[/tex].
Learn more about geometric solutions of system of linear inequalities here:
https://brainly.com/question/17174433
PLS HELP ME ON THIS QUESTION I WILL MARK YOU AS BRAINLIEST IF YOU K NOW THE ANSWER!!
The entire group of objects or individuals under consideration in a survey is the ________________.
A. population
B. establishment
C. corporation
D. entity
Answer:
A: population
Step-by-step explanation:
Um its just the definition of the word i think.
Population: a collection of persons, things, or objects under study.
Can someone help me with this please !!
Step-by-step explanation:
I need help to...
I keep putting it in and no one has ever answered it and I'm struggling and getting stressed.
please help, i don't understand the subject so i need an answer to help me out:) i will give brainliest to a good answer.
To be honest, I don't think it has anything to do with the exponent part at all. Instead, I think it has to do with the fact that integers are inherently easier to grasp compared to fractions (which is exactly what rational numbers are).
For instance, it's much easier to say 2+3 = 5 than it is to say 1/2 + 1/4 = 3/4
So going back to the exponent example, it's easier to say
x^2*x^3 = x^(2+3) = x^5
than it is to say
x^(1/2)*x^(1/4) = x^(1/2+1/4) = x^(3/4)
So that's my opinion as to why rational exponents are more tricky to grasp compared to integer exponents. Of course, everyone learns math differently so maybe some find fractions easier than others.
I could really use a hand
Answer : -5a² + 10a
It was way easy ikr ~w~
Answer:
-5a2+10a
Step-by-step explanation:
distribute
-5a(a-2)
-5a2+ 10
Find the coordinate of J' after a reflection of the triangle about the y-axis. Write your answer in the form (a,b)
Answer:
A (3,3)
J (5,2)
L (0,0)
Step-by-step explanation:
.........................
A manufacturer of radio sets produced 600 units in the third year and 700 units in the
seventh year. Assuming the production uniformly increases by a fixed number every year,
the production in the first year is
b) 530
d) 570
a) 500
c) 550
Answer:
Step-by-step explanation:
The easiest way to explain this is to use slope and then writing equations for lines. The reason for that is because we are told that the production uniformly increases. That "uniform increase" is the rate of change, and since the rate of change is constant, we are talking about the slope of a line, where the rate of change is constant throughout the whole length of the line.
Create coordinates from the info given:
In the third year, 600 units were made. Time is always an x thing, so the coordinate is (3, 600). Likewise for the other bit of info. Time is always an x thing, so the coordinate is (7, 700). Applying the slope formula:
[tex]m=\frac{700-600}{7-3}=\frac{100}{4}=25[/tex] which means that 25 units per year are produced. Write the equation to find the number of units produced in any year. I used the point-slope form of a line to do this:
y - 600 = 25(x - 3) and
y - 600 = 25x - 75 so
y = 25x + 525
If we want to know the number of units in the first year, we will replace x with 1 and do the math:
y = 25(1) + 525 so
y = 550 units, choice C.
Given that cos 75 = X, show that cos 105 = −X
Step-by-step explanation:
cos(90) = 0
around this point the cos function "mirrors" with opposite signs. cos(<90) is positive and cos(>90) is negative.
but |cos(90-a)| = |cos(90+a)| for 0 <= a <= 90
75 = 90 - 15
105 = 90 + 15
so, a = 15
and because of
|cos(90-a)| = |cos(90+a)| for 0 <= a <= 90
cos (90-15) = cos(75) = -cos(90+15) = -cos(105)
Find: (6m5 + 3 – m3 – 4m) – (–m5 + 2m3 – 4m + 6)
Answer: 7m⁵ -3m³ - 3
Working:
= (6m⁵ + 3 - m³ - 4m) -(-m⁵ + 2m³- 4m +6)
= 6m⁵ + 3 - m³ - 4m +m⁵-2m³+4m - 6
= 6m⁵ + m⁵-m³ -2m³ -4m + 4m - 6 +3
= 7m⁵ -3m³ - 3
Answered by Gauthmath must click thanks and mark brainliest
1.
Write a function rule for the table.
Answer:
Step-by-step explanation:
If you plot these points on a graph, you would see that this is definitely a line. Let's find the slope of the line first:
[tex]m=\frac{2-1}{6-5}=1[/tex] (I used the last 2 coordinates on the table because I don't like negatives; and since the slope is the same for the whole entire line, it doesn't matter which points you pick to go into your slope formula)
And then use that slope and any other point in the table to write the equation. I am going to use (4, 0), since I like the 0 (less work!)
In point-slope form:
y - 0 = 1(x - 4) and
y = x - 4
That's the function rule (aka equation) for the table.
A chocolate factory has three classifications for the candies that it makes:
Caramels (12 varieties). please help!!!
Milk Chocolate (6 varieties)
Dark Chocolate (9 varieties)
1. Set up the NOTATION to figure out the different ways to choose 7 of the 12 Caramels
2. Set up the NOTATION to figure out the different ways to choose 3 of the 6 Milk Chocolates
3. Set up the NOTATION to figure out the different ways to choose 5 of the 9 Dark Chocolates
4. A customer has ordered an assortment to consist of seven types of caramels, three types of chocolate, and five types of dark chocolates.
How many such assortments are possible?
Answer:
1. 792 2. 20. 3. 126. 4.1995840
Step-by-step explanation:
Use the formula C(n,r)= n!/ r/ (n-r)! where n is total quantity of varieties and r is the quantity uou should choose.
1) n=12 (total quantity); r= 7
C(12,7)= 12!/(7! *(12-7)!)= 8*9*10*11*12/ (5*4*3*2)= 8*9*11= 72*11= 792
2) n=6 r=3
C(6,3)= 6!/ (3! * (6-3)!)= 6!/ (3!)^2= 4*5*6/ 3*2= 20.
3) C(9,5)= 9!/ (5!*4!)= 6*7*8*9/ (4*3*2*1)= 2*63= 126
4) You need to choose the whole set which consists of three components that has been defined. Multiply previous results
792*20*126= 1995840.
An equilateral triangle has a perimeter of 18 feet. If a square whose sides have the same length as one side of the triangle is built, what will be the area of the square?
Answer:
36 ft²
Step-by-step explanation:
equilateral means all sides are equally long.
a triangle has 3 sides.
in our case they are all equally long.
and their sum (all 3 sides together) is the perimeter
P = 18 = 3 × side length
side length = 18/3 = 6 ft
a square with the same side length (6) had then an area of
side length × side length = 6×6 = 6² = 36 ft²
it is important to remember : a length is measured e.g. in feet (ft). an area is then meshed in square-feet (ft²). it is important to add this to the calculated numbers to express the right dimension of these numbers.
Question 10 The hypotenuse of a right triangle is I m longer than the longer leg. The other leg is 7 m shorter than the longer leg. Determine the lengths of the three sides of the triangle. (3 marks)
Answer:
5, 12, 13
Step-by-step explanation:
let x be the longer leg then x + 1 is the hypotenuse and x - 7 the shorter leg
Using Pythagoras' identity in the right triangle
x² + (x - 7)² = (x + 1)² ← expand using FOIL
x² + x² - 14x + 49 = x² + 2x + 1
2x² - 14x + 49 = x² + 2x + 1 ( subtract x² + 2x + 1 from both sides )
x² - 16x + 48 = 0 ← in standard form
(x - 4)(x - 12) = 0 ← in factored form
Equate each factor to zero and solve for x
x - 4 = 0 ⇒ x = 4
x - 12 = 0 ⇒ x = 12
x = 4 , then x - 7 = 4 - 7 = - 3 ← not possible
x = 12, then x - 7 = 12 - 7 = 5 and x + 1 = 12 + 1 = 13
The lengths of the 3 sides are
longer leg = 12 m , shorter leg = 5 m and hypotenuse = 13 m
How to you write 1/25 using exponents
Answer:
[tex]5^{-2}[/tex]
Step-by-step explanation:
Using the rule of exponents
[tex]a^{-m}[/tex] ⇔ [tex]\frac{1}{a^{m} }[/tex] , then
[tex]\frac{1}{25}[/tex] = [tex]\frac{1}{5^{2} }[/tex] = [tex]5^{-2}[/tex]
In exponent form, it should be written as [tex]5^{-2}[/tex].
Given that,
The fraction is [tex]\frac{1}{25}[/tex]We need to write in the exponent form
Based on the above information, the calculation is as follows:
[tex]a^{-m} = \frac{1}{a^{m}} \\\\\frac{1}{25} = \frac{1}{5^{2}}[/tex]
[tex]5^{-2}[/tex]
Learn more: brainly.com/question/17429689
Find an explicit formula for the geometric sequence \dfrac12\,,-4\,,\,32\,,-256,.. 2 1 ,−4,32,−256,..start fraction, 1, divided by, 2, end fraction, comma, minus, 4, comma, 32, comma, minus, 256, comma, point, point. Note: the first term should be \textit{a(1)}a(1)start text, a, left parenthesis, 1, right parenthesis, end text. a(n)=a(n)=a, left parenthesis, n, right parenthesis, equals
Answer:
a(n)= 1/2 * (-8) n-1
Step-by-step explanation:
In a geometric sequence, the ratio between successive terms is constant. This means that we can move from any term to the next one by multiplying by a constant value. Let's calculate this ratio over the first few terms:
\dfrac{-256}{32}=\dfrac{32}{-4}=\dfrac{-4}{\frac12}=\blue{-8}
32
−256
=
−4
32
=
2
1
−4
=−8start fraction, minus, 256, divided by, 32, end fraction, equals, start fraction, 32, divided by, minus, 4, end fraction, equals, start fraction, minus, 4, divided by, start fraction, 1, divided by, 2, end fraction, end fraction, equals, start color #6495ed, minus, 8, end color #6495ed
We see that the constant ratio between successive terms is \blue{-8}−8start color #6495ed, minus, 8, end color #6495ed. In other words, we can find any term by starting with the first term and multiplying by \blue{-8}−8start color #6495ed, minus, 8, end color #6495ed repeatedly until we get to the desired term.
Let's look at the first few terms expressed as products:
nn 111 222 333 444
h(n)\!\!\!\!\!h(n)h, left parenthesis, n, right parenthesis \red{\dfrac12}\cdot\!\!\!\left(\blue{-8}\right)^{\,\large0}\!\!\!\!\!\!
2
1
⋅(−8)
0
start color #df0030, start fraction, 1, divided by, 2, end fraction, end color #df0030, dot, left parenthesis, start color #6495ed, minus, 8, end color #6495ed, right parenthesis, start superscript, 0, end superscript \red{\dfrac12}\cdot\!\!\!\left(\blue{-8}\right)^{\,\large1}\!\!\!\!\!\!
2
1
⋅(−8)
1
start color #df0030, start fraction, 1, divided by, 2, end fraction, end color #df0030, dot, left parenthesis, start color #6495ed, minus, 8, end color #6495ed, right parenthesis, start superscript, 1, end superscript \red{\dfrac12}\cdot\!\!\!\left(\blue{-8}\right)^{\,\large2}\!\!\!\!\!\!
2
1
⋅(−8)
2
start color #df0030, start fraction, 1, divided by, 2, end fraction, end color #df0030, dot, left parenthesis, start color #6495ed, minus, 8, end color #6495ed, right parenthesis, squared \red{\dfrac12}\cdot\!\!\!\left(\blue{-8}\right)^{\,\large3}
2
1
⋅(−8)
3
start color #df0030, start fraction, 1, divided by, 2, end fraction, end color #df0030, dot, left parenthesis, start color #6495ed, minus, 8, end color #6495ed, right parenthesis, cubed
We can see that every term is the product of the first term, \red{\dfrac12}
2
1
start color #df0030, start fraction, 1, divided by, 2, end fraction, end color #df0030, and a power of the constant ratio, \blue{-8}−8start color #6495ed, minus, 8, end color #6495ed. Note that this power is always one less than the term number nnn. This is because the first term is the product of itself and plainly 111, which is like taking the constant ratio to the zeroth power.
Thus, we arrive at the following explicit formula (Note that \red{\dfrac12}
2
1
start color #df0030, start fraction, 1, divided by, 2, end fraction, end color #df0030 is the first term and \blue{-8}−8start color #6495ed, minus, 8, end color #6495ed is the constant ratio):
a(n)=\red{\dfrac12}\cdot\left(\blue{-8}\right)^{\large{\,n-1}}a(n)=
2
1
⋅(−8)
n−1
a, left parenthesis, n, right parenthesis, equals, start color #df0030, start fraction, 1, divided by, 2, end fraction, end color #df0030, dot, left parenthesis, start color #6495ed, minus, 8, end color #6495ed, right parenthesis, start superscript, n, minus, 1, end superscript
Note that this solution strategy results in this formula; however, an equally correct solution can be written in other equivalent forms as well.
Please help will give brainliest, pls don’t just guess
Answer:
B = multiply both sides by 2y+1
Step-by-step explanation:
Answer:
B. multiply both sides by the equation 2y + 1
What is the intersecting point of these two lines?
1. y = 3/4x + 6
2. y = x + 1
Answer pls……………………….
Answer:
D
Step-by-step explanation:
x^2=y^3
Then x^6=y^9 but x^3z=z^9 so 3z=6, z=2
Answer:
z = 2
Step-by-step explanation:
[tex]x^{3z} = y^{9}\\\\x^{3z} =y^{3*3} \\\\x^{3z}= (y^{3})^{3}\\\\x^{3z}=(x^{2})^{3}\\\\x^{3z} = x^{6}[/tex]
As bases are same, compare the powers
3z = 6
z = 6/3
z = 2
Factor the polynomial and explain answer
Hi there!
[tex]\large\boxed{(n - 8)(n + 5)}[/tex]
n² - 3n - 40
Find two numbers that sum up to -3 and multiply into -40. We get:
-8, 5
Thus:
(n - 8)(n + 5)
Can someone help me on this please
The choices :
Three
B , E , D
Ba đường phân giác của tam giác ABC gặp nhau tại O phát biểu nào sau đây đúng
A Ao luôn vuông góc với BC
B OA=OB=OC
C Ao luôn đi qua trung điểm BC
D O cách đều ba cạnh của tam giác
Answer:
D
Step-by-step explanation:
từ O hạ đường vuông góc xuống các cạnh AB, AC, BC các đường vuông góc đó sẽ bằng nhau