I need help ASAP thank you

Answer:

0

Step-by-step explanation:

Let n be the first term of this sequence and d the difference between two consecutive terms.

Following the arithmetic sequence formula,

The equation for the 3rd term:

n + 2d = 5

and the equation for the 8th term:

n + 7d = -20

We should start by finding d by subtracting the second equation from the first.

n + 2d - (n + 7d) = 5 - (-20)

-5d = 25

d = -5

We can then find the 1st term by plugging this number into the first equation.

n + 2 * -5 = 5

n - 10 = 5

n = 15

Now, using once again the arithmetic sequence formula, find the equation for the fourth term.

n + (4 - 1)*d

Plug in the values we found previously and solve:

15 + (4 - 1)*-5

= 15 + 3*-5

= 15 + (-15)

= 0

The 4th term is 0.

Remember that this problem is asking for the product of the 4th term and the 2015th term, and anything times zero equals to zero, so we don't even need to solve for the 2015th term!

Therefore, the answer to this problem is 0.

The product of the 4th and 2015th terms is 0 if the third term of an arithmetic sequence is 5 and the eighth term is -20.

It is defined as the systematic way of representing the data that follows a certain rule of arithmetic.

We have:

The third term of an arithmetic sequence is 5 and the eighth term is -20

a + 2d = 5

a + 7d = -20

After solving the equations:

a = 15

d = -5

4th term = 15 + 3(-5) = 0

2015th term = 15 + 2014(-5) = -10055

The product of the 4th and 2015th terms = 0(-10055) = 0

Thus, the product of the 4th and 2015th terms is 0 if the third term of an arithmetic sequence is 5 and the eighth term is -20.

Learn more about the sequence here:

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Answer:

[tex]d=\sqrt{(x_{2}-x_{1})^{2} +(y_{2}-y_{1})^{2} } \\\\=\sqrt{(4-(-1))^{2}+(7-9)^{2} } \\\\=\sqrt{(5)^{2}+(-2)^{2}} \\\\=\sqrt{25+4} \\\\=\sqrt{29}[/tex]

Yeahhhh I ain't dat smart

But that's why I got BRAINLY...

Anyways your welcome

Hope u have a good day

9514 1404 393

Answer:

  13

Step-by-step explanation:

152AB1 is not a square in hexadecimal, so we assume A and B are supposed to represent single digits in decimal.

If A=B=0, √152001 ≈ 389.9

If A=B=9, √152991 ≈ 391.1

The least significant digit of 152AB1 being non-zero, we know it is not the square of 390. Hence, it must be the square of 391.

For 152AB1 to be a perfect square, we must have ...

  152AB1 = 391² = 152881

The sum of the digits of the square root is 3+9+1 = 13.

Answer:

Step-by-step explana

540

Answer:

The answer is below

Step-by-step explanation:

Transformation is the movement of a point from its initial location to a new location. Types of transformation are rotation, reflection, translation and dilation.

If a point A(x, y) is translated a units right and b units up, the new point is at A'(x + a, y + b).

If a point A(x, y) is reflected across the line y = -x, the new point is at A'(-y, -x).

If a point A(x, y) is rotated counterclockwise by 270 degrees, the new point is at A'(y, -x).

Let us assume that triangle ABC has vertices at A(-6, -1), B(-3, -3) and C(-1, -2).

If it is moved 5 units to the right and 2 units up, the new point is at A'(-1, 1), B'(1, -1) and C'(3, 0). If it is reflected across the line y = -x, the vertices are at A"(-1, 1), B"(1, -1) and C"(0, -3). If it is then rotated counterclockwise about the origin by 270°, the new point is at A'"(-1, -1), B"'(1, 1), C"'(3, 0)

Answer:

Q2) 29 degree       as unrounded to nearest degree is 28.95 degree

Q3) 69 degree       as unrounded to nearest degree is 68.56 degree

Step-by-step explanation:

QU 2)

When they speak of plane we see ABCD and also see ABC

So we need the length of AB and BC to find the diagonal CA

AB^2 + BC^2 = CA^2

16.4^2 + 9.1^2 = sqrt 351.77

CA^2 = sqrt 351.77 = 18.8 cm

We know CG = 10.4cm

We identify the hypotenuse for ACG triangle

We do trig tan x = opp/adj for CGA angle

Tan x = tan-1 10.4/18.8 = 28.95099521 degree

Tan x = tan-1 18.8/10.4 = 61.04900479 degree

so we know one is much smaller than the other

We also know ACG angle is 90 degree and that angle from ABCD that meets line AG is the smaller angle.

Answer therefore must be 28.95 degree = or 29 degree

QU 3)

we are basically looking for angle where VB meets BC line or AVB meets ABC we have the slant length, so step 1 is find the height by first dividing square base by 2 then finding the height.

= 7.6/2 = 3.8 cm

Then Pythagoras

BV^2  -  1/2 BC =  height

10.4^2  - 3.8^2 = height

Height = sq rt 93.72 =9.68090905 = 9.7cm

Which means  V to midpoint VC = V to midpoint  AB

They are the same and the midpoints are 90 degree angles.

To find the required angle for VB + BCmidpoint or we wont be able to determine the right angle hypotenuse.

We do the same as last question determine the hypotenuse and where the angle sought is is where we use the trig function = adj/hyp

Because if it was the midpoint angle then it would be opp/adj like the question 1  so this time its cos of x.

cos x = adj/hyp = cos-1 (3.8/ 10.4) = 68.5687455

Answer is 68.56 degree

The reason we show the height is so we can check by doing opp/hyp

= sin of x = sin-1 (9.68090905/3.8) = 23.11171135

and 90 -23.11171135 = 66.8882887

= 67 degree

So we go with the first one and assume 9.68 was already simplified to 9.7cm

= sin-1 (3.8/9.7) = 23 degree  90-23 = 67 degree

but when rounded to 10.4cm for slant we get the same

= sin-1 (3.8/10.4)

So we realise here trig functions -1  doesn't work on the same 90 degree angle for both lines that meet such 90 degree angle.

We try the sin-1 (10.4/ 9.68090905) = 68.5687455 = 69 degree

and that where the lines join away from the 90 degree angle we can always find true answer, and see it is a match with the first cos trig function we did.

This proves that cos line 1/line2  = sin line 1/line 2 are the same when the larger number is numerator for sin representing the hypotenuse slant for sin as shown and when the larger of the sides is numerator for cos di

and smallest side acts as denominator for both trig functions.

Let X(s) and Y(s) denote the Laplace transforms of x(t) and y(t), respectively. Then taking the transform of both sides of both equations gives

LT[dx/dt + 5x + dy/dt] = LT[1]

==>   s X(s) - x (0) + 5 X(s) + s Y(s) - y (0) = 1/s

==>   s X(s) + 5 X(s) + s Y(s) = 1/s

==>   (s + 5) X(s) + s Y(s) = 1/s

LT[dx/dt - x + dy/dt - y] = LT[exp(t )]

==>   s X(s) - x (0) - X(s) + s Y(s) - y (0) - Y(s) = 1/(s - 1)

==>   s X(s) - X(s) + s Y(s) - Y(s) = 1/(s - 1)

==>   (s - 1) X(s) + (s - 1) Y(s) = 1/(s - 1)

Solve for X(s) and Y(s). Using elimination, you would get

X(s) = (1 - 2s) / (5s (s - 1)²)

Y(s) = (7s - 1) / (5s (s - 1)²)

Now take the inverse transforms of each. Start by getting the partial fraction decompositions:

(1 - 2s) / (5s (s - 1)²) = 1/5 (a/s + b/(s - 1) + c/(s - 1)²)

-2s + 1 = a (s - 1)² + bs (s - 1) + cs

-2s + 1 = (a + b) s ² + (-2a - b + c) s + a

==>   a + b = 0, -2a - b + c = -10, a = 5

==>   a = 1, b = -1, c = -1

==>   X(s) = 1/5 (1/s - 1/(s - 1) - 1/(s - 1)²)

Similarly, you would find

Y(s) = -1/5 (1/s - 1/(s - 1) - 6/(s - 1)²)

Now for the inverse transforms:

LT⁻¹ [1/s] = 1

LT⁻¹ [1/(s - 1)] = exp(t )

LT⁻¹ [1/(s - 1)²] = t exp(t )

Putting everything together, we have

LT⁻¹ [X(s)] = x(t) = 1/5 - 1/5 exp(t ) - 1/5 t exp(t )

and

LT⁻¹ [Y(s)] = y(t) = -1/5 + 1/5 exp(t ) + 6/5 t exp(t )

Answer:

27405

Step-by-step explanation:

There are 6 different variants available for each croissant. There are 26 croissants in all out of which 1 is plain. We use combination and permutation technique to identify different ways to choose croissant.

[5 + 26 - 1 ] 26 = 30C26 = 27405.

Answer:

The 99% confidence interval for the true population proportion of people with kids is (0.293, 0.547).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.

[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

In which

z is the z-score that has a p-value of [tex]1 - \frac{\alpha}{2}[/tex].

Out of 100 people sampled, 42 had kids.

This means that [tex]n = 100, \pi = \frac{42}{100} = 0.42[/tex]

99% confidence level

So [tex]\alpha = 0.01[/tex], z is the value of Z that has a p-value of [tex]1 - \frac{0.01}{2} = 0.995[/tex], so [tex]Z = 2.575[/tex].  

The lower limit of this interval is:

[tex]\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.42 - 2.575\sqrt{\frac{0.42*0.58}{100}} = 0.293[/tex]

The upper limit of this interval is:

[tex]\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.42 + 2.575\sqrt{\frac{0.42*0.58}{100}} = 0.547[/tex]

The 99% confidence interval for the true population proportion of people with kids is (0.293, 0.547).

Answer:

I have to go get my car from the doctor office today

Answer:

option b

Step-by-step explanation:

both are rectangles and similar measures  

Yes, because both figures are rectangles and all rectangles are similar

The rectangle EFGH is a result of the dilation of rectangle ABCD

Resizing an item uses a transition called Dilation. Dilation is used to enlarge or contract the items. The result of this transformation is an image with the same shape as the original. However, there is a variation in the shape's size. Dilation transformations ensure that the shape will stay the same and that corresponding angles will be congruent

Given data ,

Let the first rectangle be represented as ABCD

Now , the rectangle is dilated by a scale factor k

And , the transformed rectangle is given by EFGH

where the center of origin is the scale factor of dilation

Now , the ratios of the sides of the rectangles will be similar

So , the rectangles ABCD and EFGH are similar

Hence , the dilated rectangle is EFGH

To learn more about dilation click :

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Answer:

[tex]Given:[/tex] Δ ABC ≈ ΔDEF

[tex]therefor:[/tex] A(ΔABC)/A(ΔDEF)=(BC)²/(EF)²

⇒ 34/A(ΔDEF)=9²/(13.5)²

⇒34/A(ΔDEF)=81/182.25

⇒A(ΔDEF)=34×182.25/81

⇒Area of ΔDEF=76.5 cm²

----------------------------------

Hope it helps...

Have a great day!!!

Answer:

w =-4

Step-by-step explanation:

4w = 2w - 8

Subtract 2w from each side

4w-2w = 2w-2w - 8

2w = -8

Divide by 2

2w/2 = -8/2

w = -4

9514 1404 393

Answer:

  see attached

Step-by-step explanation:

Each point moves to the same distance on the other side of the mirror line. The slope of the mirror line is 1, so the points move along a line perpendicular to that, one with a slope of -1. You can make sure the distances are the same by counting the grid squares.

Answer:

mean ≈ 25.45

Step-by-step explanation:

mean is calculated as

mean = [tex]\frac{sum}{count}[/tex]

We require the sum for both classes

class A

mean = [tex]\frac{sum}{9}[/tex] = 40 ( multiply both sides by 9 )

sum = 9 × 40 = 360

class B

mean = [tex]\frac{sum}{24}[/tex] = 20 ( multiply both sides by 24

sum = 24 × 20 = 480

Total sum for both classes = 360 + 480 = 840 , then mean for both classes is

mean = [tex]\frac{840}{33}[/tex] ≈ 25.45 ( to 2 dec. places )

Answer:

x = -3  or x = 3  or x = 6

Step-by-step explanation:

x3 – 6x2 – 9x + 54 = 0

There is no common factor to factor out. There are 4 terms. We try factoring by grouping. Factor a common factor out of the first two terms. Factor a common factor out of the last two terms.

x^2(x - 6) - 9(x - 6) = 0

x - 6 is a common factor, so we factor it out.

(x^2 - 9)(x - 6) = 0

x^2 - 9 is the difference of 2 squares, so we factor it.

(x + 3)(x - 3)(x - 6) = 0

x + 3 = 0  or  x - 3 = 0  or x - 6 = 0

x = -3  or x = 3  or x = 6

Answer:

x=6     x=3   x=-3

Step-by-step explanation:

x^3 – 6x^2 – 9x + 54 = 0

Factor by grouping

x^3 – 6x^2     – 9x + 54 = 0

x^2(x-6)    -9(x-6 ) =0

Factor out x-6

(x-6)(x^2 -9) =0

Notice x^2 -9 is the difference of squares

(x-6)(x-3)(x+3) = 0

Using the zero product property

x-6 =0    x-3 =0   x+3 =0

x=6     x=3   x=-3

Answer:

arithmetic

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Answer:

35

Step-by-step explanation:

7-7(-4)

Using PEMDAS

Multiply first

7 +28

Then add

35

////////////////////////

===========================================================

Explanation:

Since we have an odd number of values, this tells us that the median is part of the data set. It's the middle most item after we sort the values.

Recall that the mode is the most frequent item. Since the mode and median are the same, this must mean x can only be equal to one of the following

4, 9, 7 or 8

We can only pick one of those values.

----------------------

If x = 4, then the set {4,9,7,8,x} updates to {4,9,7,8,4} which sorts to {4,4,7,8,9}

The middle most item is in slot 3, which would be 7. So the median is 7.

The median 7 does not match with the mode 4.

So we cross x = 4 off the list.

-----------------------

If x = 7, then we have {4,7,7,8,9}

The mode is 7 and the median is 7. So far, so good.

Now let's compute the mean. Add up the values and divide by 5 because there are 5 items.

(4+7+7+8+9)/5 = 35/5 = 7

We've shown that the set {4,7,7,8,9} has mean 7.

Overall, that set has the same mean, median and mode. So the answer is confirmed.

I'll let you check the cases when x = 8 and x = 9.

Answer:

yes

Step-by-step explanation:

3/9  Divide the top and bottom by 3

1/3

5/15 Divide the top and bottom by 5

1/3

They are equal

Answer:

A (1 + i)^n = 1490    time for amount to reach 1490

(1 + i)^n = 1.49    since A = $1000

n log (1 + .06/4) = log 1.49       take log of both sides at 1.5% per quarter

n = log (1.49) / log 1.015  = 26.78 periods or 6.695 years

(compare to 6.843 years compounded annually)

[tex]t = ln(A/P) / n[ln(1 + r/n)]\\t = ln(1,490.00/1,000.00) / ( 4 * [ln(1 + 0.06/4)] )\\t = ln(1,490.00/1,000.00) / ( 4 * [ln(1 + 0.015)] )\\t = 6.7 years[/tex]

It would take around 6 years 8 months to get $1,490 from $1,000 at 6%.

I hope I've helped! :)

Answer:

if you mean 15k as is 15 thousand then the answer would be 15,010

Answer:

[tex]269 \frac{1}{4} [/tex]

Step-by-step explanation:

the solution is found above in the diagram.

AS IN THE PICTURE...........

Answer:

FALSE

Step-by-step explanation:

First, define y and x.

In statistics, we have what we call variables. Variables are items or symbols that can take on various values. We have dependent variables - whose values are derived from other variables in an equation - and independent variables - whose values are given and are used to determine the values of dependent variables.

Usually, y represents the dependent variable while x represents the independent variable. So the simplest form of regression equation is

y = f (x)

Said as "y is a function of x"

A logistic regression equation can be used to calculate y when x values are given.

Here, the independent variable function (the X function) is a logistic function and it is used to find a binary dependent variable (a Y value, out of two possible values).

In logistic regression equations, the value of Y is not numerical like 1, 0.2, 3/4, and so on. It is categorical, e.g.

Black/White, Gain/Lose, Pass/Fail, Eat/Drink, etc.